Optimal. Leaf size=261 \[ -\frac {1}{2} \sqrt {\frac {1}{2} \left (2-\sqrt {2}\right )} \tan ^{-1}\left (\frac {\sqrt {2+\sqrt {2}} x \sqrt [4]{x^6-1}}{\sqrt {x^6-1}-x^2}\right )+\frac {1}{2} \sqrt {\frac {1}{2} \left (2+\sqrt {2}\right )} \tan ^{-1}\left (\frac {\left (\sqrt {\frac {2}{2-\sqrt {2}}}-\frac {2}{\sqrt {2-\sqrt {2}}}\right ) x \sqrt [4]{x^6-1}}{\sqrt {x^6-1}-x^2}\right )-\frac {1}{2} \sqrt {\frac {1}{2} \left (2+\sqrt {2}\right )} \tanh ^{-1}\left (\frac {\sqrt {2-\sqrt {2}} x \sqrt [4]{x^6-1}}{\sqrt {x^6-1}+x^2}\right )-\frac {1}{2} \sqrt {\frac {1}{2} \left (2-\sqrt {2}\right )} \tanh ^{-1}\left (\frac {\sqrt {2+\sqrt {2}} x \sqrt [4]{x^6-1}}{\sqrt {x^6-1}+x^2}\right ) \]
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Rubi [F] time = 1.38, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {\left (2+x^6\right ) \left (-1+x^4+x^6\right )}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )} \, dx \end {gather*}
Verification is not applicable to the result.
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\begin {align*} \int \frac {\left (2+x^6\right ) \left (-1+x^4+x^6\right )}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )} \, dx &=\int \left (\frac {1}{\sqrt [4]{-1+x^6}}-\frac {3-2 x^4-3 x^6+x^8-x^{10}}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )}\right ) \, dx\\ &=\int \frac {1}{\sqrt [4]{-1+x^6}} \, dx-\int \frac {3-2 x^4-3 x^6+x^8-x^{10}}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )} \, dx\\ &=\frac {\sqrt [4]{1-x^6} \int \frac {1}{\sqrt [4]{1-x^6}} \, dx}{\sqrt [4]{-1+x^6}}-\int \left (\frac {3}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )}-\frac {2 x^4}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )}-\frac {3 x^6}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )}+\frac {x^8}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )}-\frac {x^{10}}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )}\right ) \, dx\\ &=\frac {x \sqrt [4]{1-x^6} \, _2F_1\left (\frac {1}{6},\frac {1}{4};\frac {7}{6};x^6\right )}{\sqrt [4]{-1+x^6}}+2 \int \frac {x^4}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )} \, dx-3 \int \frac {1}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )} \, dx+3 \int \frac {x^6}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )} \, dx-\int \frac {x^8}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )} \, dx+\int \frac {x^{10}}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )} \, dx\\ \end {align*}
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Mathematica [F] time = 0.31, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (2+x^6\right ) \left (-1+x^4+x^6\right )}{\sqrt [4]{-1+x^6} \left (1-2 x^6+x^8+x^{12}\right )} \, dx \end {gather*}
Verification is not applicable to the result.
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IntegrateAlgebraic [A] time = 16.40, size = 241, normalized size = 0.92 \begin {gather*} -\frac {1}{2} \sqrt {\frac {1}{2} \left (2+\sqrt {2}\right )} \tan ^{-1}\left (\frac {\sqrt {2-\sqrt {2}} x \sqrt [4]{-1+x^6}}{-x^2+\sqrt {-1+x^6}}\right )-\frac {1}{2} \sqrt {\frac {1}{2} \left (2-\sqrt {2}\right )} \tan ^{-1}\left (\frac {\sqrt {2+\sqrt {2}} x \sqrt [4]{-1+x^6}}{-x^2+\sqrt {-1+x^6}}\right )-\frac {1}{2} \sqrt {\frac {1}{2} \left (2+\sqrt {2}\right )} \tanh ^{-1}\left (\frac {\sqrt {2-\sqrt {2}} x \sqrt [4]{-1+x^6}}{x^2+\sqrt {-1+x^6}}\right )-\frac {1}{2} \sqrt {\frac {1}{2} \left (2-\sqrt {2}\right )} \tanh ^{-1}\left (\frac {\sqrt {2+\sqrt {2}} x \sqrt [4]{-1+x^6}}{x^2+\sqrt {-1+x^6}}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (x^{6} + x^{4} - 1\right )} {\left (x^{6} + 2\right )}}{{\left (x^{12} + x^{8} - 2 \, x^{6} + 1\right )} {\left (x^{6} - 1\right )}^{\frac {1}{4}}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 31.65, size = 684, normalized size = 2.62
method | result | size |
trager | \(-\frac {\RootOf \left (\textit {\_Z}^{8}+16\right )^{3} \ln \left (-\frac {-\RootOf \left (\textit {\_Z}^{8}+16\right )^{10} x^{4}+4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{6} x^{6}-4 x^{4} \RootOf \left (\textit {\_Z}^{8}+16\right )^{6}+16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{4} \sqrt {x^{6}-1}\, x^{2}+16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{2} x^{6}+32 \RootOf \left (\textit {\_Z}^{8}+16\right )^{3} \left (x^{6}-1\right )^{\frac {3}{4}} x -4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{6}+64 \RootOf \left (\textit {\_Z}^{8}+16\right ) \left (x^{6}-1\right )^{\frac {1}{4}} x^{3}+64 x^{2} \sqrt {x^{6}-1}-16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{2}}{\RootOf \left (\textit {\_Z}^{8}+16\right )^{4} x^{4}+4 x^{6}-4}\right )}{8}-\frac {\RootOf \left (\textit {\_Z}^{8}+16\right )^{5} \ln \left (\frac {-\RootOf \left (\textit {\_Z}^{8}+16\right )^{8} x^{4}-4 \sqrt {x^{6}-1}\, \RootOf \left (\textit {\_Z}^{8}+16\right )^{6} x^{2}-4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{4} x^{6}+8 \left (x^{6}-1\right )^{\frac {1}{4}} \RootOf \left (\textit {\_Z}^{8}+16\right )^{5} x^{3}-4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{4} x^{4}+16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{3} \left (x^{6}-1\right )^{\frac {3}{4}} x -16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{2} \sqrt {x^{6}-1}\, x^{2}-16 x^{6}+4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{4}+16}{\RootOf \left (\textit {\_Z}^{8}+16\right )^{4} x^{4}-4 x^{6}+4}\right )}{16}+\frac {\RootOf \left (\textit {\_Z}^{8}+16\right ) \ln \left (\frac {-\RootOf \left (\textit {\_Z}^{8}+16\right )^{8} x^{4}+4 \sqrt {x^{6}-1}\, \RootOf \left (\textit {\_Z}^{8}+16\right )^{6} x^{2}-4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{4} x^{6}-8 \left (x^{6}-1\right )^{\frac {1}{4}} \RootOf \left (\textit {\_Z}^{8}+16\right )^{5} x^{3}+4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{4} x^{4}+16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{3} \left (x^{6}-1\right )^{\frac {3}{4}} x -16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{2} \sqrt {x^{6}-1}\, x^{2}+16 x^{6}+4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{4}-16}{\RootOf \left (\textit {\_Z}^{8}+16\right )^{4} x^{4}-4 x^{6}+4}\right )}{4}-\frac {\RootOf \left (\textit {\_Z}^{8}+16\right )^{7} \ln \left (-\frac {-\RootOf \left (\textit {\_Z}^{8}+16\right )^{10} x^{4}+4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{6} x^{6}+4 x^{4} \RootOf \left (\textit {\_Z}^{8}+16\right )^{6}-16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{4} \sqrt {x^{6}-1}\, x^{2}-16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{2} x^{6}+32 \RootOf \left (\textit {\_Z}^{8}+16\right )^{3} \left (x^{6}-1\right )^{\frac {3}{4}} x -4 \RootOf \left (\textit {\_Z}^{8}+16\right )^{6}-64 \RootOf \left (\textit {\_Z}^{8}+16\right ) \left (x^{6}-1\right )^{\frac {1}{4}} x^{3}+64 x^{2} \sqrt {x^{6}-1}+16 \RootOf \left (\textit {\_Z}^{8}+16\right )^{2}}{\RootOf \left (\textit {\_Z}^{8}+16\right )^{4} x^{4}+4 x^{6}-4}\right )}{32}\) | \(684\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {{\left (x^{6} + x^{4} - 1\right )} {\left (x^{6} + 2\right )}}{{\left (x^{12} + x^{8} - 2 \, x^{6} + 1\right )} {\left (x^{6} - 1\right )}^{\frac {1}{4}}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\left (x^6+2\right )\,\left (x^6+x^4-1\right )}{{\left (x^6-1\right )}^{1/4}\,\left (x^{12}+x^8-2\,x^6+1\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (x^{6} + 2\right ) \left (x^{6} + x^{4} - 1\right )}{\sqrt [4]{\left (x - 1\right ) \left (x + 1\right ) \left (x^{2} - x + 1\right ) \left (x^{2} + x + 1\right )} \left (x^{12} + x^{8} - 2 x^{6} + 1\right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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