3.27.83 \(\int \frac {x}{\sqrt [3]{x^2 (-a+x)} (a^2 d-2 a d x+(-1+d) x^2)} \, dx\)

Optimal. Leaf size=243 \[ \frac {\log \left (x-\sqrt [6]{d} \sqrt [3]{x^3-a x^2}\right )}{2 a \sqrt [3]{d}}+\frac {\log \left (\sqrt [6]{d} \sqrt [3]{x^3-a x^2}+x\right )}{2 a \sqrt [3]{d}}-\frac {\log \left (-\sqrt [6]{d} x \sqrt [3]{x^3-a x^2}+\sqrt [3]{d} \left (x^3-a x^2\right )^{2/3}+x^2\right )}{4 a \sqrt [3]{d}}-\frac {\log \left (\sqrt [6]{d} x \sqrt [3]{x^3-a x^2}+\sqrt [3]{d} \left (x^3-a x^2\right )^{2/3}+x^2\right )}{4 a \sqrt [3]{d}}+\frac {\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} x^2}{2 \sqrt [3]{d} \left (x^3-a x^2\right )^{2/3}+x^2}\right )}{2 a \sqrt [3]{d}} \]

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Rubi [A]  time = 0.61, antiderivative size = 418, normalized size of antiderivative = 1.72, number of steps used = 9, number of rules used = 5, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {6719, 911, 105, 59, 91} \begin {gather*} -\frac {x^{2/3} \sqrt [3]{x-a} \log \left (-2 a \sqrt {d} \left (\sqrt {d}+1\right )-2 (1-d) x\right )}{4 a \sqrt [3]{d} \sqrt [3]{-\left (x^2 (a-x)\right )}}-\frac {x^{2/3} \sqrt [3]{x-a} \log \left (2 (1-d) x-2 a \left (1-\sqrt {d}\right ) \sqrt {d}\right )}{4 a \sqrt [3]{d} \sqrt [3]{-\left (x^2 (a-x)\right )}}+\frac {3 x^{2/3} \sqrt [3]{x-a} \log \left (-\sqrt [6]{d} \sqrt [3]{x-a}-\sqrt [3]{x}\right )}{4 a \sqrt [3]{d} \sqrt [3]{-\left (x^2 (a-x)\right )}}+\frac {3 x^{2/3} \sqrt [3]{x-a} \log \left (\sqrt [6]{d} \sqrt [3]{x-a}-\sqrt [3]{x}\right )}{4 a \sqrt [3]{d} \sqrt [3]{-\left (x^2 (a-x)\right )}}+\frac {\sqrt {3} x^{2/3} \sqrt [3]{x-a} \tan ^{-1}\left (\frac {1}{\sqrt {3}}-\frac {2 \sqrt [6]{d} \sqrt [3]{x-a}}{\sqrt {3} \sqrt [3]{x}}\right )}{2 a \sqrt [3]{d} \sqrt [3]{-\left (x^2 (a-x)\right )}}+\frac {\sqrt {3} x^{2/3} \sqrt [3]{x-a} \tan ^{-1}\left (\frac {2 \sqrt [6]{d} \sqrt [3]{x-a}}{\sqrt {3} \sqrt [3]{x}}+\frac {1}{\sqrt {3}}\right )}{2 a \sqrt [3]{d} \sqrt [3]{-\left (x^2 (a-x)\right )}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x/((x^2*(-a + x))^(1/3)*(a^2*d - 2*a*d*x + (-1 + d)*x^2)),x]

[Out]

(Sqrt[3]*x^(2/3)*(-a + x)^(1/3)*ArcTan[1/Sqrt[3] - (2*d^(1/6)*(-a + x)^(1/3))/(Sqrt[3]*x^(1/3))])/(2*a*d^(1/3)
*(-((a - x)*x^2))^(1/3)) + (Sqrt[3]*x^(2/3)*(-a + x)^(1/3)*ArcTan[1/Sqrt[3] + (2*d^(1/6)*(-a + x)^(1/3))/(Sqrt
[3]*x^(1/3))])/(2*a*d^(1/3)*(-((a - x)*x^2))^(1/3)) - (x^(2/3)*(-a + x)^(1/3)*Log[-2*a*(1 + Sqrt[d])*Sqrt[d] -
2*(1 - d)*x])/(4*a*d^(1/3)*(-((a - x)*x^2))^(1/3)) - (x^(2/3)*(-a + x)^(1/3)*Log[-2*a*(1 - Sqrt[d])*Sqrt[d] +
2*(1 - d)*x])/(4*a*d^(1/3)*(-((a - x)*x^2))^(1/3)) + (3*x^(2/3)*(-a + x)^(1/3)*Log[-x^(1/3) - d^(1/6)*(-a + x
)^(1/3)])/(4*a*d^(1/3)*(-((a - x)*x^2))^(1/3)) + (3*x^(2/3)*(-a + x)^(1/3)*Log[-x^(1/3) + d^(1/6)*(-a + x)^(1/
3)])/(4*a*d^(1/3)*(-((a - x)*x^2))^(1/3))

Rule 59

Int[1/(((a_.) + (b_.)*(x_))^(1/3)*((c_.) + (d_.)*(x_))^(2/3)), x_Symbol] :> With[{q = Rt[d/b, 3]}, -Simp[(Sqrt
[3]*q*ArcTan[(2*q*(a + b*x)^(1/3))/(Sqrt[3]*(c + d*x)^(1/3)) + 1/Sqrt[3]])/d, x] + (-Simp[(3*q*Log[(q*(a + b*x
)^(1/3))/(c + d*x)^(1/3) - 1])/(2*d), x] - Simp[(q*Log[c + d*x])/(2*d), x])] /; FreeQ[{a, b, c, d}, x] && NeQ[
b*c - a*d, 0] && PosQ[d/b]

Rule 91

Int[1/(((a_.) + (b_.)*(x_))^(1/3)*((c_.) + (d_.)*(x_))^(2/3)*((e_.) + (f_.)*(x_))), x_Symbol] :> With[{q = Rt[
(d*e - c*f)/(b*e - a*f), 3]}, -Simp[(Sqrt[3]*q*ArcTan[1/Sqrt[3] + (2*q*(a + b*x)^(1/3))/(Sqrt[3]*(c + d*x)^(1/
3))])/(d*e - c*f), x] + (Simp[(q*Log[e + f*x])/(2*(d*e - c*f)), x] - Simp[(3*q*Log[q*(a + b*x)^(1/3) - (c + d*
x)^(1/3)])/(2*(d*e - c*f)), x])] /; FreeQ[{a, b, c, d, e, f}, x]

Rule 105

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> Dist[b/f, Int[(a
+ b*x)^(m - 1)*(c + d*x)^n, x], x] - Dist[(b*e - a*f)/f, Int[((a + b*x)^(m - 1)*(c + d*x)^n)/(e + f*x), x], x]
/; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[Simplify[m + n + 1], 0] && (GtQ[m, 0] || ( !RationalQ[m] && (Su
mSimplerQ[m, -1] ||  !SumSimplerQ[n, -1])))

Rule 911

Int[(((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> In
t[ExpandIntegrand[(d + e*x)^m*(f + g*x)^n, 1/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e, f, g, m, n}, x
] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] &&  !IntegerQ[m] &&  !IntegerQ[n]

Rule 6719

Int[(u_.)*((a_.)*(v_)^(m_.)*(w_)^(n_.))^(p_), x_Symbol] :> Dist[(a^IntPart[p]*(a*v^m*w^n)^FracPart[p])/(v^(m*F
racPart[p])*w^(n*FracPart[p])), Int[u*v^(m*p)*w^(n*p), x], x] /; FreeQ[{a, m, n, p}, x] &&  !IntegerQ[p] &&  !
FreeQ[v, x] &&  !FreeQ[w, x]

Rubi steps

\begin {align*} \int \frac {x}{\sqrt [3]{x^2 (-a+x)} \left (a^2 d-2 a d x+(-1+d) x^2\right )} \, dx &=\frac {\left (x^{2/3} \sqrt [3]{-a+x}\right ) \int \frac {\sqrt [3]{x}}{\sqrt [3]{-a+x} \left (a^2 d-2 a d x+(-1+d) x^2\right )} \, dx}{\sqrt [3]{x^2 (-a+x)}}\\ &=\frac {\left (x^{2/3} \sqrt [3]{-a+x}\right ) \int \left (\frac {(-1+d) \sqrt [3]{x}}{a \sqrt {d} \sqrt [3]{-a+x} \left (-2 a \sqrt {d}-2 a d-2 (1-d) x\right )}+\frac {(-1+d) \sqrt [3]{x}}{a \sqrt {d} \sqrt [3]{-a+x} \left (-2 a \sqrt {d}+2 a d+2 (1-d) x\right )}\right ) \, dx}{\sqrt [3]{x^2 (-a+x)}}\\ &=-\frac {\left ((1-d) x^{2/3} \sqrt [3]{-a+x}\right ) \int \frac {\sqrt [3]{x}}{\sqrt [3]{-a+x} \left (-2 a \sqrt {d}-2 a d-2 (1-d) x\right )} \, dx}{a \sqrt {d} \sqrt [3]{x^2 (-a+x)}}-\frac {\left ((1-d) x^{2/3} \sqrt [3]{-a+x}\right ) \int \frac {\sqrt [3]{x}}{\sqrt [3]{-a+x} \left (-2 a \sqrt {d}+2 a d+2 (1-d) x\right )} \, dx}{a \sqrt {d} \sqrt [3]{x^2 (-a+x)}}\\ &=\frac {\left ((1-d) x^{2/3} \sqrt [3]{-a+x}\right ) \int \frac {1}{x^{2/3} \sqrt [3]{-a+x} \left (-2 a \sqrt {d}-2 a d-2 (1-d) x\right )} \, dx}{\left (1-\sqrt {d}\right ) \sqrt [3]{x^2 (-a+x)}}-\frac {\left ((1-d) x^{2/3} \sqrt [3]{-a+x}\right ) \int \frac {1}{x^{2/3} \sqrt [3]{-a+x} \left (-2 a \sqrt {d}+2 a d+2 (1-d) x\right )} \, dx}{\left (1+\sqrt {d}\right ) \sqrt [3]{x^2 (-a+x)}}\\ &=\frac {\sqrt {3} x^{2/3} \sqrt [3]{-a+x} \tan ^{-1}\left (\frac {1}{\sqrt {3}}-\frac {2 \sqrt [6]{d} \sqrt [3]{-a+x}}{\sqrt {3} \sqrt [3]{x}}\right )}{2 a \sqrt [3]{d} \sqrt [3]{-\left ((a-x) x^2\right )}}+\frac {\sqrt {3} x^{2/3} \sqrt [3]{-a+x} \tan ^{-1}\left (\frac {1}{\sqrt {3}}+\frac {2 \sqrt [6]{d} \sqrt [3]{-a+x}}{\sqrt {3} \sqrt [3]{x}}\right )}{2 a \sqrt [3]{d} \sqrt [3]{-\left ((a-x) x^2\right )}}-\frac {x^{2/3} \sqrt [3]{-a+x} \log \left (-2 a \left (1+\sqrt {d}\right ) \sqrt {d}-2 (1-d) x\right )}{4 a \sqrt [3]{d} \sqrt [3]{-\left ((a-x) x^2\right )}}-\frac {x^{2/3} \sqrt [3]{-a+x} \log \left (-2 a \left (1-\sqrt {d}\right ) \sqrt {d}+2 (1-d) x\right )}{4 a \sqrt [3]{d} \sqrt [3]{-\left ((a-x) x^2\right )}}+\frac {3 x^{2/3} \sqrt [3]{-a+x} \log \left (-\sqrt [3]{x}-\sqrt [6]{d} \sqrt [3]{-a+x}\right )}{4 a \sqrt [3]{d} \sqrt [3]{-\left ((a-x) x^2\right )}}+\frac {3 x^{2/3} \sqrt [3]{-a+x} \log \left (-\sqrt [3]{x}+\sqrt [6]{d} \sqrt [3]{-a+x}\right )}{4 a \sqrt [3]{d} \sqrt [3]{-\left ((a-x) x^2\right )}}\\ \end {align*}

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Mathematica [C]  time = 0.13, size = 73, normalized size = 0.30 \begin {gather*} \frac {3 x \left (\, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {x}{\sqrt {d} (a-x)}\right )-\, _2F_1\left (\frac {1}{3},1;\frac {4}{3};\frac {x}{\sqrt {d} (x-a)}\right )\right )}{2 a \sqrt {d} \sqrt [3]{x^2 (x-a)}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x/((x^2*(-a + x))^(1/3)*(a^2*d - 2*a*d*x + (-1 + d)*x^2)),x]

[Out]

(3*x*(Hypergeometric2F1[1/3, 1, 4/3, x/(Sqrt[d]*(a - x))] - Hypergeometric2F1[1/3, 1, 4/3, x/(Sqrt[d]*(-a + x)
)]))/(2*a*Sqrt[d]*(x^2*(-a + x))^(1/3))

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IntegrateAlgebraic [A]  time = 0.56, size = 243, normalized size = 1.00 \begin {gather*} \frac {\sqrt {3} \tan ^{-1}\left (\frac {\sqrt {3} x^2}{x^2+2 \sqrt [3]{d} \left (-a x^2+x^3\right )^{2/3}}\right )}{2 a \sqrt [3]{d}}+\frac {\log \left (x-\sqrt [6]{d} \sqrt [3]{-a x^2+x^3}\right )}{2 a \sqrt [3]{d}}+\frac {\log \left (x+\sqrt [6]{d} \sqrt [3]{-a x^2+x^3}\right )}{2 a \sqrt [3]{d}}-\frac {\log \left (x^2-\sqrt [6]{d} x \sqrt [3]{-a x^2+x^3}+\sqrt [3]{d} \left (-a x^2+x^3\right )^{2/3}\right )}{4 a \sqrt [3]{d}}-\frac {\log \left (x^2+\sqrt [6]{d} x \sqrt [3]{-a x^2+x^3}+\sqrt [3]{d} \left (-a x^2+x^3\right )^{2/3}\right )}{4 a \sqrt [3]{d}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x/((x^2*(-a + x))^(1/3)*(a^2*d - 2*a*d*x + (-1 + d)*x^2)),x]

[Out]

(Sqrt[3]*ArcTan[(Sqrt[3]*x^2)/(x^2 + 2*d^(1/3)*(-(a*x^2) + x^3)^(2/3))])/(2*a*d^(1/3)) + Log[x - d^(1/6)*(-(a*
x^2) + x^3)^(1/3)]/(2*a*d^(1/3)) + Log[x + d^(1/6)*(-(a*x^2) + x^3)^(1/3)]/(2*a*d^(1/3)) - Log[x^2 - d^(1/6)*x
*(-(a*x^2) + x^3)^(1/3) + d^(1/3)*(-(a*x^2) + x^3)^(2/3)]/(4*a*d^(1/3)) - Log[x^2 + d^(1/6)*x*(-(a*x^2) + x^3)
^(1/3) + d^(1/3)*(-(a*x^2) + x^3)^(2/3)]/(4*a*d^(1/3))

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fricas [A]  time = 0.53, size = 372, normalized size = 1.53 \begin {gather*} \left [\frac {\sqrt {3} d \sqrt {-\frac {1}{d^{\frac {2}{3}}}} \log \left (\frac {2 \, a^{2} d - 4 \, a d x + {\left (2 \, d + 1\right )} x^{2} + \sqrt {3} {\left (d^{\frac {1}{3}} x^{2} + 2 \, {\left (-a x^{2} + x^{3}\right )}^{\frac {1}{3}} {\left (a d - d x\right )} + {\left (-a x^{2} + x^{3}\right )}^{\frac {2}{3}} d^{\frac {2}{3}}\right )} \sqrt {-\frac {1}{d^{\frac {2}{3}}}} - 3 \, {\left (-a x^{2} + x^{3}\right )}^{\frac {2}{3}} d^{\frac {1}{3}}}{a^{2} d - 2 \, a d x + {\left (d - 1\right )} x^{2}}\right ) + 2 \, d^{\frac {2}{3}} \log \left (-\frac {d^{\frac {2}{3}} x^{2} - {\left (-a x^{2} + x^{3}\right )}^{\frac {2}{3}} d}{x^{2}}\right ) - d^{\frac {2}{3}} \log \left (\frac {d^{\frac {1}{3}} x^{2} - {\left (-a x^{2} + x^{3}\right )}^{\frac {1}{3}} {\left (a d - d x\right )} + {\left (-a x^{2} + x^{3}\right )}^{\frac {2}{3}} d^{\frac {2}{3}}}{x^{2}}\right )}{4 \, a d}, -\frac {2 \, \sqrt {3} d^{\frac {2}{3}} \arctan \left (\frac {\sqrt {3} {\left (d^{\frac {1}{3}} x^{2} + 2 \, {\left (-a x^{2} + x^{3}\right )}^{\frac {2}{3}} d^{\frac {2}{3}}\right )}}{3 \, d^{\frac {1}{3}} x^{2}}\right ) - 2 \, d^{\frac {2}{3}} \log \left (-\frac {d^{\frac {2}{3}} x^{2} - {\left (-a x^{2} + x^{3}\right )}^{\frac {2}{3}} d}{x^{2}}\right ) + d^{\frac {2}{3}} \log \left (\frac {d^{\frac {1}{3}} x^{2} - {\left (-a x^{2} + x^{3}\right )}^{\frac {1}{3}} {\left (a d - d x\right )} + {\left (-a x^{2} + x^{3}\right )}^{\frac {2}{3}} d^{\frac {2}{3}}}{x^{2}}\right )}{4 \, a d}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(x^2*(-a+x))^(1/3)/(a^2*d-2*a*d*x+(-1+d)*x^2),x, algorithm="fricas")

[Out]

[1/4*(sqrt(3)*d*sqrt(-1/d^(2/3))*log((2*a^2*d - 4*a*d*x + (2*d + 1)*x^2 + sqrt(3)*(d^(1/3)*x^2 + 2*(-a*x^2 + x
^3)^(1/3)*(a*d - d*x) + (-a*x^2 + x^3)^(2/3)*d^(2/3))*sqrt(-1/d^(2/3)) - 3*(-a*x^2 + x^3)^(2/3)*d^(1/3))/(a^2*
d - 2*a*d*x + (d - 1)*x^2)) + 2*d^(2/3)*log(-(d^(2/3)*x^2 - (-a*x^2 + x^3)^(2/3)*d)/x^2) - d^(2/3)*log((d^(1/3
)*x^2 - (-a*x^2 + x^3)^(1/3)*(a*d - d*x) + (-a*x^2 + x^3)^(2/3)*d^(2/3))/x^2))/(a*d), -1/4*(2*sqrt(3)*d^(2/3)*
arctan(1/3*sqrt(3)*(d^(1/3)*x^2 + 2*(-a*x^2 + x^3)^(2/3)*d^(2/3))/(d^(1/3)*x^2)) - 2*d^(2/3)*log(-(d^(2/3)*x^2
- (-a*x^2 + x^3)^(2/3)*d)/x^2) + d^(2/3)*log((d^(1/3)*x^2 - (-a*x^2 + x^3)^(1/3)*(a*d - d*x) + (-a*x^2 + x^3)
^(2/3)*d^(2/3))/x^2))/(a*d)]

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giac [A]  time = 0.50, size = 108, normalized size = 0.44 \begin {gather*} -\frac {\sqrt {3} {\left | d \right |}^{\frac {2}{3}} \arctan \left (\frac {1}{3} \, \sqrt {3} d^{\frac {1}{3}} {\left (2 \, {\left (-\frac {a}{x} + 1\right )}^{\frac {2}{3}} + \frac {1}{d^{\frac {1}{3}}}\right )}\right )}{2 \, a d} - \frac {{\left | d \right |}^{\frac {2}{3}} \log \left ({\left (-\frac {a}{x} + 1\right )}^{\frac {4}{3}} + \frac {{\left (-\frac {a}{x} + 1\right )}^{\frac {2}{3}}}{d^{\frac {1}{3}}} + \frac {1}{d^{\frac {2}{3}}}\right )}{4 \, a d} + \frac {\log \left ({\left | {\left (-\frac {a}{x} + 1\right )}^{\frac {2}{3}} - \frac {1}{d^{\frac {1}{3}}} \right |}\right )}{2 \, a d^{\frac {1}{3}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(x^2*(-a+x))^(1/3)/(a^2*d-2*a*d*x+(-1+d)*x^2),x, algorithm="giac")

[Out]

-1/2*sqrt(3)*abs(d)^(2/3)*arctan(1/3*sqrt(3)*d^(1/3)*(2*(-a/x + 1)^(2/3) + 1/d^(1/3)))/(a*d) - 1/4*abs(d)^(2/3
)*log((-a/x + 1)^(4/3) + (-a/x + 1)^(2/3)/d^(1/3) + 1/d^(2/3))/(a*d) + 1/2*log(abs((-a/x + 1)^(2/3) - 1/d^(1/3
)))/(a*d^(1/3))

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maple [F]  time = 0.18, size = 0, normalized size = 0.00 \[\int \frac {x}{\left (x^{2} \left (-a +x \right )\right )^{\frac {1}{3}} \left (a^{2} d -2 a d x +\left (-1+d \right ) x^{2}\right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(x^2*(-a+x))^(1/3)/(a^2*d-2*a*d*x+(-1+d)*x^2),x)

[Out]

int(x/(x^2*(-a+x))^(1/3)/(a^2*d-2*a*d*x+(-1+d)*x^2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x}{{\left (a^{2} d - 2 \, a d x + {\left (d - 1\right )} x^{2}\right )} \left (-{\left (a - x\right )} x^{2}\right )^{\frac {1}{3}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(x^2*(-a+x))^(1/3)/(a^2*d-2*a*d*x+(-1+d)*x^2),x, algorithm="maxima")

[Out]

integrate(x/((a^2*d - 2*a*d*x + (d - 1)*x^2)*(-(a - x)*x^2)^(1/3)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x}{{\left (-x^2\,\left (a-x\right )\right )}^{1/3}\,\left (d\,a^2-2\,d\,a\,x+\left (d-1\right )\,x^2\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/((-x^2*(a - x))^(1/3)*(a^2*d + x^2*(d - 1) - 2*a*d*x)),x)

[Out]

int(x/((-x^2*(a - x))^(1/3)*(a^2*d + x^2*(d - 1) - 2*a*d*x)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x}{\sqrt [3]{x^{2} \left (- a + x\right )} \left (a^{2} d - 2 a d x + d x^{2} - x^{2}\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(x**2*(-a+x))**(1/3)/(a**2*d-2*a*d*x+(-1+d)*x**2),x)

[Out]

Integral(x/((x**2*(-a + x))**(1/3)*(a**2*d - 2*a*d*x + d*x**2 - x**2)), x)

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