3.19.40 \(\int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx\)

Optimal. Leaf size=125 \[ \frac {2}{3} \left (x^4-1\right )^{3/4}+\tan ^{-1}\left (\frac {\sqrt [4]{x^4-1}}{x}\right )+\frac {\tan ^{-1}\left (\frac {\frac {\sqrt {x^4-1}}{\sqrt {2}}-\frac {1}{\sqrt {2}}}{\sqrt [4]{x^4-1}}\right )}{2 \sqrt {2}}-\tanh ^{-1}\left (\frac {\sqrt [4]{x^4-1}}{x}\right )-\frac {\tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{x^4-1}}{\sqrt {x^4-1}+1}\right )}{2 \sqrt {2}} \]

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Rubi [A]  time = 0.14, antiderivative size = 170, normalized size of antiderivative = 1.36, number of steps used = 18, number of rules used = 14, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.609, Rules used = {1833, 240, 212, 206, 203, 446, 80, 63, 297, 1162, 617, 204, 1165, 628} \begin {gather*} \frac {2}{3} \left (x^4-1\right )^{3/4}+\frac {\log \left (\sqrt {x^4-1}-\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{4 \sqrt {2}}-\frac {\log \left (\sqrt {x^4-1}+\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{4 \sqrt {2}}-\tan ^{-1}\left (\frac {x}{\sqrt [4]{x^4-1}}\right )-\frac {\tan ^{-1}\left (1-\sqrt {2} \sqrt [4]{x^4-1}\right )}{2 \sqrt {2}}+\frac {\tan ^{-1}\left (\sqrt {2} \sqrt [4]{x^4-1}+1\right )}{2 \sqrt {2}}-\tanh ^{-1}\left (\frac {x}{\sqrt [4]{x^4-1}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 - 2*x + 2*x^4)/(x*(-1 + x^4)^(1/4)),x]

[Out]

(2*(-1 + x^4)^(3/4))/3 - ArcTan[x/(-1 + x^4)^(1/4)] - ArcTan[1 - Sqrt[2]*(-1 + x^4)^(1/4)]/(2*Sqrt[2]) + ArcTa
n[1 + Sqrt[2]*(-1 + x^4)^(1/4)]/(2*Sqrt[2]) - ArcTanh[x/(-1 + x^4)^(1/4)] + Log[1 - Sqrt[2]*(-1 + x^4)^(1/4) +
Sqrt[-1 + x^4]]/(4*Sqrt[2]) - Log[1 + Sqrt[2]*(-1 + x^4)^(1/4) + Sqrt[-1 + x^4]]/(4*Sqrt[2])

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 80

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(c + d*x)
^(n + 1)*(e + f*x)^(p + 1))/(d*f*(n + p + 2)), x] + Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(
d*f*(n + p + 2)), Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2,
0]

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 212

Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[-(a/b), 2]], s = Denominator[Rt[-(a/b), 2]
]}, Dist[r/(2*a), Int[1/(r - s*x^2), x], x] + Dist[r/(2*a), Int[1/(r + s*x^2), x], x]] /; FreeQ[{a, b}, x] &&
!GtQ[a/b, 0]

Rule 240

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[a^(p + 1/n), Subst[Int[1/(1 - b*x^n)^(p + 1/n + 1), x], x
, x/(a + b*x^n)^(1/n)], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[-1, p, 0] && NeQ[p, -2^(-1)] && IntegerQ[p
+ 1/n]

Rule 297

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
b]]))

Rule 446

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] &&
NeQ[b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1162

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(2*d)/e, 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1165

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(-2*d)/e, 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rule 1833

Int[(Pq_)*((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Module[{q = Expon[Pq, x], j, k}, Int[
Sum[((c*x)^(m + j)*Sum[Coeff[Pq, x, j + (k*n)/2]*x^((k*n)/2), {k, 0, (2*(q - j))/n + 1}]*(a + b*x^n)^p)/c^j, {
j, 0, n/2 - 1}], x]] /; FreeQ[{a, b, c, m, p}, x] && PolyQ[Pq, x] && IGtQ[n/2, 0] &&  !PolyQ[Pq, x^(n/2)]

Rubi steps

\begin {align*} \int \frac {1-2 x+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx &=\int \left (-\frac {2}{\sqrt [4]{-1+x^4}}+\frac {1+2 x^4}{x \sqrt [4]{-1+x^4}}\right ) \, dx\\ &=-\left (2 \int \frac {1}{\sqrt [4]{-1+x^4}} \, dx\right )+\int \frac {1+2 x^4}{x \sqrt [4]{-1+x^4}} \, dx\\ &=\frac {1}{4} \operatorname {Subst}\left (\int \frac {1+2 x}{\sqrt [4]{-1+x} x} \, dx,x,x^4\right )-2 \operatorname {Subst}\left (\int \frac {1}{1-x^4} \, dx,x,\frac {x}{\sqrt [4]{-1+x^4}}\right )\\ &=\frac {2}{3} \left (-1+x^4\right )^{3/4}+\frac {1}{4} \operatorname {Subst}\left (\int \frac {1}{\sqrt [4]{-1+x} x} \, dx,x,x^4\right )-\operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {x}{\sqrt [4]{-1+x^4}}\right )-\operatorname {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {x}{\sqrt [4]{-1+x^4}}\right )\\ &=\frac {2}{3} \left (-1+x^4\right )^{3/4}-\tan ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\tanh ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )+\operatorname {Subst}\left (\int \frac {x^2}{1+x^4} \, dx,x,\sqrt [4]{-1+x^4}\right )\\ &=\frac {2}{3} \left (-1+x^4\right )^{3/4}-\tan ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\tanh ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\frac {1}{2} \operatorname {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\sqrt [4]{-1+x^4}\right )+\frac {1}{2} \operatorname {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\sqrt [4]{-1+x^4}\right )\\ &=\frac {2}{3} \left (-1+x^4\right )^{3/4}-\tan ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\tanh ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )+\frac {1}{4} \operatorname {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\sqrt [4]{-1+x^4}\right )+\frac {1}{4} \operatorname {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\sqrt [4]{-1+x^4}\right )+\frac {\operatorname {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\sqrt [4]{-1+x^4}\right )}{4 \sqrt {2}}+\frac {\operatorname {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\sqrt [4]{-1+x^4}\right )}{4 \sqrt {2}}\\ &=\frac {2}{3} \left (-1+x^4\right )^{3/4}-\tan ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\tanh ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )+\frac {\log \left (1-\sqrt {2} \sqrt [4]{-1+x^4}+\sqrt {-1+x^4}\right )}{4 \sqrt {2}}-\frac {\log \left (1+\sqrt {2} \sqrt [4]{-1+x^4}+\sqrt {-1+x^4}\right )}{4 \sqrt {2}}+\frac {\operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} \sqrt [4]{-1+x^4}\right )}{2 \sqrt {2}}-\frac {\operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\sqrt {2} \sqrt [4]{-1+x^4}\right )}{2 \sqrt {2}}\\ &=\frac {2}{3} \left (-1+x^4\right )^{3/4}-\tan ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )-\frac {\tan ^{-1}\left (1-\sqrt {2} \sqrt [4]{-1+x^4}\right )}{2 \sqrt {2}}+\frac {\tan ^{-1}\left (1+\sqrt {2} \sqrt [4]{-1+x^4}\right )}{2 \sqrt {2}}-\tanh ^{-1}\left (\frac {x}{\sqrt [4]{-1+x^4}}\right )+\frac {\log \left (1-\sqrt {2} \sqrt [4]{-1+x^4}+\sqrt {-1+x^4}\right )}{4 \sqrt {2}}-\frac {\log \left (1+\sqrt {2} \sqrt [4]{-1+x^4}+\sqrt {-1+x^4}\right )}{4 \sqrt {2}}\\ \end {align*}

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Mathematica [C]  time = 0.04, size = 70, normalized size = 0.56 \begin {gather*} \frac {1}{3} \left (x^4-1\right )^{3/4} \, _2F_1\left (\frac {3}{4},1;\frac {7}{4};1-x^4\right )+\frac {2}{3} \left (x^4-1\right )^{3/4}-\tan ^{-1}\left (\frac {x}{\sqrt [4]{x^4-1}}\right )-\tanh ^{-1}\left (\frac {x}{\sqrt [4]{x^4-1}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 - 2*x + 2*x^4)/(x*(-1 + x^4)^(1/4)),x]

[Out]

(2*(-1 + x^4)^(3/4))/3 - ArcTan[x/(-1 + x^4)^(1/4)] - ArcTanh[x/(-1 + x^4)^(1/4)] + ((-1 + x^4)^(3/4)*Hypergeo
metric2F1[3/4, 1, 7/4, 1 - x^4])/3

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IntegrateAlgebraic [A]  time = 4.46, size = 120, normalized size = 0.96 \begin {gather*} \frac {2}{3} \left (-1+x^4\right )^{3/4}+\tan ^{-1}\left (\frac {\sqrt [4]{-1+x^4}}{x}\right )-\frac {\tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{-1+x^4}}{-1+\sqrt {-1+x^4}}\right )}{2 \sqrt {2}}-\tanh ^{-1}\left (\frac {\sqrt [4]{-1+x^4}}{x}\right )-\frac {\tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{-1+x^4}}{1+\sqrt {-1+x^4}}\right )}{2 \sqrt {2}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(1 - 2*x + 2*x^4)/(x*(-1 + x^4)^(1/4)),x]

[Out]

(2*(-1 + x^4)^(3/4))/3 + ArcTan[(-1 + x^4)^(1/4)/x] - ArcTan[(Sqrt[2]*(-1 + x^4)^(1/4))/(-1 + Sqrt[-1 + x^4])]
/(2*Sqrt[2]) - ArcTanh[(-1 + x^4)^(1/4)/x] - ArcTanh[(Sqrt[2]*(-1 + x^4)^(1/4))/(1 + Sqrt[-1 + x^4])]/(2*Sqrt[
2])

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fricas [B]  time = 18.12, size = 517, normalized size = 4.14 \begin {gather*} \frac {1}{4} \, \sqrt {2} \arctan \left (-\frac {x^{8} + 4 \, \sqrt {x^{4} - 1} x^{4} + 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {3}{4}} {\left (x^{4} - 4\right )} + 2 \, \sqrt {2} {\left (3 \, x^{4} - 4\right )} {\left (x^{4} - 1\right )}^{\frac {1}{4}} - {\left (4 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}} x^{4} + 2 \, \sqrt {2} \sqrt {x^{4} - 1} {\left (x^{4} - 4\right )} + \sqrt {2} {\left (x^{8} - 10 \, x^{4} + 8\right )} + 16 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}}\right )} \sqrt {\frac {x^{4} + 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {3}{4}} + 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + 4 \, \sqrt {x^{4} - 1}}{x^{4}}}}{x^{8} - 16 \, x^{4} + 16}\right ) - \frac {1}{4} \, \sqrt {2} \arctan \left (-\frac {x^{8} + 4 \, \sqrt {x^{4} - 1} x^{4} - 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {3}{4}} {\left (x^{4} - 4\right )} - 2 \, \sqrt {2} {\left (3 \, x^{4} - 4\right )} {\left (x^{4} - 1\right )}^{\frac {1}{4}} - {\left (4 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}} x^{4} - 2 \, \sqrt {2} \sqrt {x^{4} - 1} {\left (x^{4} - 4\right )} - \sqrt {2} {\left (x^{8} - 10 \, x^{4} + 8\right )} + 16 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}}\right )} \sqrt {\frac {x^{4} - 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {3}{4}} - 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + 4 \, \sqrt {x^{4} - 1}}{x^{4}}}}{x^{8} - 16 \, x^{4} + 16}\right ) - \frac {1}{16} \, \sqrt {2} \log \left (\frac {4 \, {\left (x^{4} + 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {3}{4}} + 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + 4 \, \sqrt {x^{4} - 1}\right )}}{x^{4}}\right ) + \frac {1}{16} \, \sqrt {2} \log \left (\frac {4 \, {\left (x^{4} - 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {3}{4}} - 2 \, \sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + 4 \, \sqrt {x^{4} - 1}\right )}}{x^{4}}\right ) + \frac {2}{3} \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} + \frac {1}{2} \, \arctan \left (2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}} x^{3} + 2 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} x\right ) + \frac {1}{2} \, \log \left (-2 \, x^{4} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}} x^{3} - 2 \, \sqrt {x^{4} - 1} x^{2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} x + 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*x^4-2*x+1)/x/(x^4-1)^(1/4),x, algorithm="fricas")

[Out]

1/4*sqrt(2)*arctan(-(x^8 + 4*sqrt(x^4 - 1)*x^4 + 2*sqrt(2)*(x^4 - 1)^(3/4)*(x^4 - 4) + 2*sqrt(2)*(3*x^4 - 4)*(
x^4 - 1)^(1/4) - (4*(x^4 - 1)^(1/4)*x^4 + 2*sqrt(2)*sqrt(x^4 - 1)*(x^4 - 4) + sqrt(2)*(x^8 - 10*x^4 + 8) + 16*
(x^4 - 1)^(3/4))*sqrt((x^4 + 2*sqrt(2)*(x^4 - 1)^(3/4) + 2*sqrt(2)*(x^4 - 1)^(1/4) + 4*sqrt(x^4 - 1))/x^4))/(x
^8 - 16*x^4 + 16)) - 1/4*sqrt(2)*arctan(-(x^8 + 4*sqrt(x^4 - 1)*x^4 - 2*sqrt(2)*(x^4 - 1)^(3/4)*(x^4 - 4) - 2*
sqrt(2)*(3*x^4 - 4)*(x^4 - 1)^(1/4) - (4*(x^4 - 1)^(1/4)*x^4 - 2*sqrt(2)*sqrt(x^4 - 1)*(x^4 - 4) - sqrt(2)*(x^
8 - 10*x^4 + 8) + 16*(x^4 - 1)^(3/4))*sqrt((x^4 - 2*sqrt(2)*(x^4 - 1)^(3/4) - 2*sqrt(2)*(x^4 - 1)^(1/4) + 4*sq
rt(x^4 - 1))/x^4))/(x^8 - 16*x^4 + 16)) - 1/16*sqrt(2)*log(4*(x^4 + 2*sqrt(2)*(x^4 - 1)^(3/4) + 2*sqrt(2)*(x^4
- 1)^(1/4) + 4*sqrt(x^4 - 1))/x^4) + 1/16*sqrt(2)*log(4*(x^4 - 2*sqrt(2)*(x^4 - 1)^(3/4) - 2*sqrt(2)*(x^4 - 1
)^(1/4) + 4*sqrt(x^4 - 1))/x^4) + 2/3*(x^4 - 1)^(3/4) + 1/2*arctan(2*(x^4 - 1)^(1/4)*x^3 + 2*(x^4 - 1)^(3/4)*x
) + 1/2*log(-2*x^4 + 2*(x^4 - 1)^(1/4)*x^3 - 2*sqrt(x^4 - 1)*x^2 + 2*(x^4 - 1)^(3/4)*x + 1)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {2 \, x^{4} - 2 \, x + 1}{{\left (x^{4} - 1\right )}^{\frac {1}{4}} x}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*x^4-2*x+1)/x/(x^4-1)^(1/4),x, algorithm="giac")

[Out]

integrate((2*x^4 - 2*x + 1)/((x^4 - 1)^(1/4)*x), x)

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maple [C]  time = 11.65, size = 142, normalized size = 1.14

method	result	size
meijerg	\(\frac {\sqrt {2}\, \Gamma \left (\frac {3}{4}\right ) \left (-\mathrm {signum}\left (x^{4}-1\right )\right )^{\frac {1}{4}} \left (\frac {\pi \sqrt {2}\, x^{4} \hypergeom \left (\left [1, 1, \frac {5}{4}\right ], \left [2, 2\right ], x^{4}\right )}{4 \Gamma \left (\frac {3}{4}\right )}+\frac {\left (-3 \ln \relax (2)-\frac {\pi }{2}+4 \ln \relax (x )+i \pi \right ) \pi \sqrt {2}}{\Gamma \left (\frac {3}{4}\right )}\right )}{8 \pi \mathrm {signum}\left (x^{4}-1\right )^{\frac {1}{4}}}+\frac {\left (-\mathrm {signum}\left (x^{4}-1\right )\right )^{\frac {1}{4}} x^{4} \hypergeom \left (\left [\frac {1}{4}, 1\right ], \relax [2], x^{4}\right )}{2 \mathrm {signum}\left (x^{4}-1\right )^{\frac {1}{4}}}-\frac {2 \left (-\mathrm {signum}\left (x^{4}-1\right )\right )^{\frac {1}{4}} x \hypergeom \left (\left [\frac {1}{4}, \frac {1}{4}\right ], \left [\frac {5}{4}\right ], x^{4}\right )}{\mathrm {signum}\left (x^{4}-1\right )^{\frac {1}{4}}}\)	\(142\)
trager	\(\frac {2 \left (x^{4}-1\right )^{\frac {3}{4}}}{3}+\frac {\RootOf \left (\textit {\_Z}^{4}+1\right )^{3} \ln \left (\frac {-\RootOf \left (\textit {\_Z}^{4}+1\right )^{3} x^{4}+2 \left (x^{4}-1\right )^{\frac {3}{4}}+2 \sqrt {x^{4}-1}\, \RootOf \left (\textit {\_Z}^{4}+1\right )+2 \left (x^{4}-1\right )^{\frac {1}{4}} \RootOf \left (\textit {\_Z}^{4}+1\right )^{2}+2 \RootOf \left (\textit {\_Z}^{4}+1\right )^{3}}{x^{4}}\right )}{4}+\frac {\RootOf \left (\textit {\_Z}^{4}+1\right ) \ln \left (-\frac {2 \sqrt {x^{4}-1}\, \RootOf \left (\textit {\_Z}^{4}+1\right )^{3}-\RootOf \left (\textit {\_Z}^{4}+1\right ) x^{4}+2 \left (x^{4}-1\right )^{\frac {3}{4}}-2 \left (x^{4}-1\right )^{\frac {1}{4}} \RootOf \left (\textit {\_Z}^{4}+1\right )^{2}+2 \RootOf \left (\textit {\_Z}^{4}+1\right )}{x^{4}}\right )}{4}+\frac {\RootOf \left (\textit {\_Z}^{4}+1\right )^{2} \ln \left (2 \sqrt {x^{4}-1}\, \RootOf \left (\textit {\_Z}^{4}+1\right )^{2} x^{2}-2 \RootOf \left (\textit {\_Z}^{4}+1\right )^{2} x^{4}+2 \left (x^{4}-1\right )^{\frac {3}{4}} x -2 x^{3} \left (x^{4}-1\right )^{\frac {1}{4}}+\RootOf \left (\textit {\_Z}^{4}+1\right )^{2}\right )}{2}+\frac {\ln \left (2 \left (x^{4}-1\right )^{\frac {3}{4}} x -2 x^{2} \sqrt {x^{4}-1}+2 x^{3} \left (x^{4}-1\right )^{\frac {1}{4}}-2 x^{4}+1\right )}{2}\)	\(287\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*x^4-2*x+1)/x/(x^4-1)^(1/4),x,method=_RETURNVERBOSE)

[Out]

1/8/Pi*2^(1/2)*GAMMA(3/4)/signum(x^4-1)^(1/4)*(-signum(x^4-1))^(1/4)*(1/4*Pi*2^(1/2)/GAMMA(3/4)*x^4*hypergeom(
[1,1,5/4],[2,2],x^4)+(-3*ln(2)-1/2*Pi+4*ln(x)+I*Pi)*Pi*2^(1/2)/GAMMA(3/4))+1/2/signum(x^4-1)^(1/4)*(-signum(x^
4-1))^(1/4)*x^4*hypergeom([1/4,1],[2],x^4)-2/signum(x^4-1)^(1/4)*(-signum(x^4-1))^(1/4)*x*hypergeom([1/4,1/4],
[5/4],x^4)

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maxima [A]  time = 0.43, size = 155, normalized size = 1.24 \begin {gather*} \frac {1}{4} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right )}\right ) + \frac {1}{4} \, \sqrt {2} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, {\left (x^{4} - 1\right )}^{\frac {1}{4}}\right )}\right ) - \frac {1}{8} \, \sqrt {2} \log \left (\sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + \sqrt {x^{4} - 1} + 1\right ) + \frac {1}{8} \, \sqrt {2} \log \left (-\sqrt {2} {\left (x^{4} - 1\right )}^{\frac {1}{4}} + \sqrt {x^{4} - 1} + 1\right ) + \frac {2}{3} \, {\left (x^{4} - 1\right )}^{\frac {3}{4}} + \arctan \left (\frac {{\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x}\right ) - \frac {1}{2} \, \log \left (\frac {{\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x} + 1\right ) + \frac {1}{2} \, \log \left (\frac {{\left (x^{4} - 1\right )}^{\frac {1}{4}}}{x} - 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*x^4-2*x+1)/x/(x^4-1)^(1/4),x, algorithm="maxima")

[Out]

1/4*sqrt(2)*arctan(1/2*sqrt(2)*(sqrt(2) + 2*(x^4 - 1)^(1/4))) + 1/4*sqrt(2)*arctan(-1/2*sqrt(2)*(sqrt(2) - 2*(
x^4 - 1)^(1/4))) - 1/8*sqrt(2)*log(sqrt(2)*(x^4 - 1)^(1/4) + sqrt(x^4 - 1) + 1) + 1/8*sqrt(2)*log(-sqrt(2)*(x^
4 - 1)^(1/4) + sqrt(x^4 - 1) + 1) + 2/3*(x^4 - 1)^(3/4) + arctan((x^4 - 1)^(1/4)/x) - 1/2*log((x^4 - 1)^(1/4)/
x + 1) + 1/2*log((x^4 - 1)^(1/4)/x - 1)

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mupad [B]  time = 1.30, size = 81, normalized size = 0.65 \begin {gather*} \frac {2\,{\left (x^4-1\right )}^{3/4}}{3}-\frac {2\,x\,{\left (1-x^4\right )}^{1/4}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{4},\frac {1}{4};\ \frac {5}{4};\ x^4\right )}{{\left (x^4-1\right )}^{1/4}}+\sqrt {2}\,\mathrm {atan}\left (\sqrt {2}\,{\left (x^4-1\right )}^{1/4}\,\left (\frac {1}{2}-\frac {1}{2}{}\mathrm {i}\right )\right )\,\left (\frac {1}{4}-\frac {1}{4}{}\mathrm {i}\right )+\sqrt {2}\,\mathrm {atan}\left (\sqrt {2}\,{\left (x^4-1\right )}^{1/4}\,\left (\frac {1}{2}+\frac {1}{2}{}\mathrm {i}\right )\right )\,\left (\frac {1}{4}+\frac {1}{4}{}\mathrm {i}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2*x^4 - 2*x + 1)/(x*(x^4 - 1)^(1/4)),x)

[Out]

2^(1/2)*atan(2^(1/2)*(x^4 - 1)^(1/4)*(1/2 - 1i/2))*(1/4 - 1i/4) + 2^(1/2)*atan(2^(1/2)*(x^4 - 1)^(1/4)*(1/2 +
1i/2))*(1/4 + 1i/4) + (2*(x^4 - 1)^(3/4))/3 - (2*x*(1 - x^4)^(1/4)*hypergeom([1/4, 1/4], 5/4, x^4))/(x^4 - 1)^
(1/4)

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sympy [C]  time = 3.18, size = 71, normalized size = 0.57 \begin {gather*} - \frac {x e^{- \frac {i \pi }{4}} \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {1}{4} \\ \frac {5}{4} \end {matrix}\middle | {x^{4}} \right )}}{2 \Gamma \left (\frac {5}{4}\right )} + \frac {2 \left (x^{4} - 1\right )^{\frac {3}{4}}}{3} - \frac {\Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {1}{4} \\ \frac {5}{4} \end {matrix}\middle | {\frac {e^{2 i \pi }}{x^{4}}} \right )}}{4 x \Gamma \left (\frac {5}{4}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2*x**4-2*x+1)/x/(x**4-1)**(1/4),x)

[Out]

-x*exp(-I*pi/4)*gamma(1/4)*hyper((1/4, 1/4), (5/4,), x**4)/(2*gamma(5/4)) + 2*(x**4 - 1)**(3/4)/3 - gamma(1/4)
*hyper((1/4, 1/4), (5/4,), exp_polar(2*I*pi)/x**4)/(4*x*gamma(5/4))

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