Optimal. Leaf size=99 \[ \frac {4}{27} \log \left (\sqrt [3]{x^3-1}+1\right )-\frac {2}{27} \log \left (\left (x^3-1\right )^{2/3}-\sqrt [3]{x^3-1}+1\right )-\frac {4 \tan ^{-1}\left (\frac {1}{\sqrt {3}}-\frac {2 \sqrt [3]{x^3-1}}{\sqrt {3}}\right )}{9 \sqrt {3}}+\frac {\sqrt [3]{x^3-1} \left (-5 x^3-3\right )}{18 x^6} \]
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Rubi [A] time = 0.06, antiderivative size = 84, normalized size of antiderivative = 0.85, number of steps used = 7, number of rules used = 7, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.389, Rules used = {446, 78, 47, 58, 618, 204, 31} \begin {gather*} -\frac {4 \sqrt [3]{x^3-1}}{9 x^3}+\frac {2}{9} \log \left (\sqrt [3]{x^3-1}+1\right )-\frac {4 \tan ^{-1}\left (\frac {1-2 \sqrt [3]{x^3-1}}{\sqrt {3}}\right )}{9 \sqrt {3}}+\frac {\left (x^3-1\right )^{4/3}}{6 x^6}-\frac {2 \log (x)}{9} \end {gather*}
Antiderivative was successfully verified.
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Rule 31
Rule 47
Rule 58
Rule 78
Rule 204
Rule 446
Rule 618
Rubi steps
\begin {align*} \int \frac {\sqrt [3]{-1+x^3} \left (1+x^3\right )}{x^7} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {\sqrt [3]{-1+x} (1+x)}{x^3} \, dx,x,x^3\right )\\ &=\frac {\left (-1+x^3\right )^{4/3}}{6 x^6}+\frac {4}{9} \operatorname {Subst}\left (\int \frac {\sqrt [3]{-1+x}}{x^2} \, dx,x,x^3\right )\\ &=-\frac {4 \sqrt [3]{-1+x^3}}{9 x^3}+\frac {\left (-1+x^3\right )^{4/3}}{6 x^6}+\frac {4}{27} \operatorname {Subst}\left (\int \frac {1}{(-1+x)^{2/3} x} \, dx,x,x^3\right )\\ &=-\frac {4 \sqrt [3]{-1+x^3}}{9 x^3}+\frac {\left (-1+x^3\right )^{4/3}}{6 x^6}-\frac {2 \log (x)}{9}+\frac {2}{9} \operatorname {Subst}\left (\int \frac {1}{1+x} \, dx,x,\sqrt [3]{-1+x^3}\right )+\frac {2}{9} \operatorname {Subst}\left (\int \frac {1}{1-x+x^2} \, dx,x,\sqrt [3]{-1+x^3}\right )\\ &=-\frac {4 \sqrt [3]{-1+x^3}}{9 x^3}+\frac {\left (-1+x^3\right )^{4/3}}{6 x^6}-\frac {2 \log (x)}{9}+\frac {2}{9} \log \left (1+\sqrt [3]{-1+x^3}\right )-\frac {4}{9} \operatorname {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,-1+2 \sqrt [3]{-1+x^3}\right )\\ &=-\frac {4 \sqrt [3]{-1+x^3}}{9 x^3}+\frac {\left (-1+x^3\right )^{4/3}}{6 x^6}-\frac {4 \tan ^{-1}\left (\frac {1-2 \sqrt [3]{-1+x^3}}{\sqrt {3}}\right )}{9 \sqrt {3}}-\frac {2 \log (x)}{9}+\frac {2}{9} \log \left (1+\sqrt [3]{-1+x^3}\right )\\ \end {align*}
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Mathematica [C] time = 0.01, size = 38, normalized size = 0.38 \begin {gather*} \frac {\left (x^3-1\right )^{4/3} \left (2 x^6 \, _2F_1\left (\frac {4}{3},2;\frac {7}{3};1-x^3\right )+1\right )}{6 x^6} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.11, size = 99, normalized size = 1.00 \begin {gather*} \frac {\left (-3-5 x^3\right ) \sqrt [3]{-1+x^3}}{18 x^6}-\frac {4 \tan ^{-1}\left (\frac {1}{\sqrt {3}}-\frac {2 \sqrt [3]{-1+x^3}}{\sqrt {3}}\right )}{9 \sqrt {3}}+\frac {4}{27} \log \left (1+\sqrt [3]{-1+x^3}\right )-\frac {2}{27} \log \left (1-\sqrt [3]{-1+x^3}+\left (-1+x^3\right )^{2/3}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.43, size = 88, normalized size = 0.89 \begin {gather*} \frac {8 \, \sqrt {3} x^{6} \arctan \left (\frac {2}{3} \, \sqrt {3} {\left (x^{3} - 1\right )}^{\frac {1}{3}} - \frac {1}{3} \, \sqrt {3}\right ) - 4 \, x^{6} \log \left ({\left (x^{3} - 1\right )}^{\frac {2}{3}} - {\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) + 8 \, x^{6} \log \left ({\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) - 3 \, {\left (5 \, x^{3} + 3\right )} {\left (x^{3} - 1\right )}^{\frac {1}{3}}}{54 \, x^{6}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.18, size = 81, normalized size = 0.82 \begin {gather*} \frac {4}{27} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}} - 1\right )}\right ) - \frac {5 \, {\left (x^{3} - 1\right )}^{\frac {4}{3}} + 8 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}}}{18 \, x^{6}} - \frac {2}{27} \, \log \left ({\left (x^{3} - 1\right )}^{\frac {2}{3}} - {\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) + \frac {4}{27} \, \log \left ({\left | {\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1 \right |}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 3.00, size = 91, normalized size = 0.92
method | result | size |
risch | \(-\frac {5 x^{6}-2 x^{3}-3}{18 x^{6} \left (x^{3}-1\right )^{\frac {2}{3}}}+\frac {4 \left (-\mathrm {signum}\left (x^{3}-1\right )\right )^{\frac {2}{3}} \left (\frac {2 \Gamma \left (\frac {2}{3}\right ) x^{3} \hypergeom \left (\left [1, 1, \frac {5}{3}\right ], \left [2, 2\right ], x^{3}\right )}{3}+\left (\frac {\pi \sqrt {3}}{6}-\frac {3 \ln \relax (3)}{2}+3 \ln \relax (x )+i \pi \right ) \Gamma \left (\frac {2}{3}\right )\right )}{27 \Gamma \left (\frac {2}{3}\right ) \mathrm {signum}\left (x^{3}-1\right )^{\frac {2}{3}}}\) | \(91\) |
meijerg | \(\frac {\mathrm {signum}\left (x^{3}-1\right )^{\frac {1}{3}} \left (-\frac {\Gamma \left (\frac {2}{3}\right ) x^{3} \hypergeom \left (\left [1, 1, \frac {5}{3}\right ], \left [2, 3\right ], x^{3}\right )}{3}-\left (\frac {\pi \sqrt {3}}{6}-\frac {3 \ln \relax (3)}{2}-1+3 \ln \relax (x )+i \pi \right ) \Gamma \left (\frac {2}{3}\right )-\frac {3 \Gamma \left (\frac {2}{3}\right )}{x^{3}}\right )}{9 \Gamma \left (\frac {2}{3}\right ) \left (-\mathrm {signum}\left (x^{3}-1\right )\right )^{\frac {1}{3}}}-\frac {\mathrm {signum}\left (x^{3}-1\right )^{\frac {1}{3}} \left (\frac {5 \Gamma \left (\frac {2}{3}\right ) x^{3} \hypergeom \left (\left [1, 1, \frac {8}{3}\right ], \left [2, 4\right ], x^{3}\right )}{27}+\frac {\left (\frac {\pi \sqrt {3}}{6}-\frac {3 \ln \relax (3)}{2}+3 \ln \relax (x )+i \pi \right ) \Gamma \left (\frac {2}{3}\right )}{3}+\frac {3 \Gamma \left (\frac {2}{3}\right )}{2 x^{6}}-\frac {\Gamma \left (\frac {2}{3}\right )}{x^{3}}\right )}{9 \Gamma \left (\frac {2}{3}\right ) \left (-\mathrm {signum}\left (x^{3}-1\right )\right )^{\frac {1}{3}}}\) | \(156\) |
trager | \(-\frac {\left (5 x^{3}+3\right ) \left (x^{3}-1\right )^{\frac {1}{3}}}{18 x^{6}}+\frac {4 \ln \left (-\frac {32768 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2} x^{3}+4416 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) x^{3}+2496 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) \left (x^{3}-1\right )^{\frac {2}{3}}+91 x^{3}-262144 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2}-6720 \left (x^{3}-1\right )^{\frac {1}{3}} \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )+144 \left (x^{3}-1\right )^{\frac {2}{3}}-13312 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )+39 \left (x^{3}-1\right )^{\frac {1}{3}}-169}{x^{3}}\right )}{27}-\frac {4 \ln \left (\frac {6754304 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2} x^{3}-619712 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) x^{3}-352128 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) \left (x^{3}-1\right )^{\frac {2}{3}}-1266 x^{3}-54034432 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2}+911808 \left (x^{3}-1\right )^{\frac {1}{3}} \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )-19749 \left (x^{3}-1\right )^{\frac {2}{3}}+419648 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )-5502 \left (x^{3}-1\right )^{\frac {1}{3}}+1055}{x^{3}}\right )}{27}-\frac {256 \ln \left (\frac {6754304 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2} x^{3}-619712 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) x^{3}-352128 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right ) \left (x^{3}-1\right )^{\frac {2}{3}}-1266 x^{3}-54034432 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )^{2}+911808 \left (x^{3}-1\right )^{\frac {1}{3}} \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )-19749 \left (x^{3}-1\right )^{\frac {2}{3}}+419648 \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )-5502 \left (x^{3}-1\right )^{\frac {1}{3}}+1055}{x^{3}}\right ) \RootOf \left (4096 \textit {\_Z}^{2}+64 \textit {\_Z} +1\right )}{27}\) | \(435\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.48, size = 103, normalized size = 1.04 \begin {gather*} \frac {4}{27} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}} - 1\right )}\right ) + \frac {{\left (x^{3} - 1\right )}^{\frac {4}{3}} - 2 \, {\left (x^{3} - 1\right )}^{\frac {1}{3}}}{18 \, {\left (2 \, x^{3} + {\left (x^{3} - 1\right )}^{2} - 1\right )}} - \frac {{\left (x^{3} - 1\right )}^{\frac {1}{3}}}{3 \, x^{3}} - \frac {2}{27} \, \log \left ({\left (x^{3} - 1\right )}^{\frac {2}{3}} - {\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) + \frac {4}{27} \, \log \left ({\left (x^{3} - 1\right )}^{\frac {1}{3}} + 1\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.04, size = 186, normalized size = 1.88 \begin {gather*} \frac {\ln \left (\frac {{\left (x^3-1\right )}^{1/3}}{9}+\frac {1}{9}\right )}{9}+\frac {\ln \left (\frac {{\left (x^3-1\right )}^{1/3}}{81}+\frac {1}{81}\right )}{27}-\frac {\frac {{\left (x^3-1\right )}^{1/3}}{9}-\frac {{\left (x^3-1\right )}^{4/3}}{18}}{{\left (x^3-1\right )}^2+2\,x^3-1}+\ln \left ({\left (x^3-1\right )}^{1/3}-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (-\frac {1}{18}+\frac {\sqrt {3}\,1{}\mathrm {i}}{18}\right )-\frac {{\left (x^3-1\right )}^{1/3}}{3\,x^3}-\ln \left (\frac {1}{2}-{\left (x^3-1\right )}^{1/3}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {1}{18}+\frac {\sqrt {3}\,1{}\mathrm {i}}{18}\right )-\ln \left (\frac {1}{6}-\frac {{\left (x^3-1\right )}^{1/3}}{3}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right )\,\left (\frac {1}{54}+\frac {\sqrt {3}\,1{}\mathrm {i}}{54}\right )+\ln \left (\frac {{\left (x^3-1\right )}^{1/3}}{3}-\frac {1}{6}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right )\,\left (-\frac {1}{54}+\frac {\sqrt {3}\,1{}\mathrm {i}}{54}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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