3.14.70 \(\int \frac {-1+x}{(-2-2 x+x^2) \sqrt {-1+x^3}} \, dx\)

Optimal. Leaf size=99 \[ \frac {1}{6} \sqrt {3+2 \sqrt {3}} \tan ^{-1}\left (\frac {\sqrt {2 \sqrt {3}-3} \sqrt {x^3-1}}{x^2+x+1}\right )-\frac {1}{6} \sqrt {2 \sqrt {3}-3} \tanh ^{-1}\left (\frac {\sqrt {3+2 \sqrt {3}} \sqrt {x^3-1}}{x^2+x+1}\right ) \]

________________________________________________________________________________________

Rubi [A]  time = 0.62, antiderivative size = 97, normalized size of antiderivative = 0.98, number of steps used = 10, number of rules used = 6, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.261, Rules used = {6728, 2135, 219, 2140, 206, 203} \begin {gather*} \frac {\tanh ^{-1}\left (\frac {\sqrt {3+2 \sqrt {3}} (1-x)}{\sqrt {x^3-1}}\right )}{2 \sqrt {3 \left (3+2 \sqrt {3}\right )}}-\frac {\tan ^{-1}\left (\frac {\sqrt {2 \sqrt {3}-3} (1-x)}{\sqrt {x^3-1}}\right )}{2 \sqrt {3 \left (2 \sqrt {3}-3\right )}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(-1 + x)/((-2 - 2*x + x^2)*Sqrt[-1 + x^3]),x]

[Out]

-1/2*ArcTan[(Sqrt[-3 + 2*Sqrt[3]]*(1 - x))/Sqrt[-1 + x^3]]/Sqrt[3*(-3 + 2*Sqrt[3])] + ArcTanh[(Sqrt[3 + 2*Sqrt
[3]]*(1 - x))/Sqrt[-1 + x^3]]/(2*Sqrt[3*(3 + 2*Sqrt[3])])

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 219

Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[(2*Sqr
t[2 - Sqrt[3]]*(s + r*x)*Sqrt[(s^2 - r*s*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]*EllipticF[ArcSin[((1 + Sqrt[3
])*s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]])/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[-((s*(s + r*x))/((1 - S
qrt[3])*s + r*x)^2)]), x]] /; FreeQ[{a, b}, x] && NegQ[a]

Rule 2135

Int[1/(((c_) + (d_.)*(x_))*Sqrt[(a_) + (b_.)*(x_)^3]), x_Symbol] :> Dist[(-6*a*d^3)/(c*(b*c^3 - 28*a*d^3)), In
t[1/Sqrt[a + b*x^3], x], x] + Dist[1/(c*(b*c^3 - 28*a*d^3)), Int[Simp[c*(b*c^3 - 22*a*d^3) + 6*a*d^4*x, x]/((c
+ d*x)*Sqrt[a + b*x^3]), x], x] /; FreeQ[{a, b, c, d}, x] && EqQ[b^2*c^6 - 20*a*b*c^3*d^3 - 8*a^2*d^6, 0]

Rule 2140

Int[((e_) + (f_.)*(x_))/(((c_) + (d_.)*(x_))*Sqrt[(a_) + (b_.)*(x_)^3]), x_Symbol] :> With[{k = Simplify[(d*e
+ 2*c*f)/(c*f)]}, Dist[((1 + k)*e)/d, Subst[Int[1/(1 + (3 + 2*k)*a*x^2), x], x, (1 + ((1 + k)*d*x)/c)/Sqrt[a +
b*x^3]], x]] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[d*e - c*f, 0] && EqQ[b^2*c^6 - 20*a*b*c^3*d^3 - 8*a^2*d^6
, 0] && EqQ[6*a*d^4*e - c*f*(b*c^3 - 22*a*d^3), 0]

Rule 6728

Int[(u_)/((a_.) + (b_.)*(x_)^(n_.) + (c_.)*(x_)^(n2_.)), x_Symbol] :> With[{v = RationalFunctionExpand[u/(a +
b*x^n + c*x^(2*n)), x]}, Int[v, x] /; SumQ[v]] /; FreeQ[{a, b, c}, x] && EqQ[n2, 2*n] && IGtQ[n, 0]

Rubi steps

\begin {align*} \int \frac {-1+x}{\left (-2-2 x+x^2\right ) \sqrt {-1+x^3}} \, dx &=\int \left (\frac {1}{\left (-2-2 \sqrt {3}+2 x\right ) \sqrt {-1+x^3}}+\frac {1}{\left (-2+2 \sqrt {3}+2 x\right ) \sqrt {-1+x^3}}\right ) \, dx\\ &=\int \frac {1}{\left (-2-2 \sqrt {3}+2 x\right ) \sqrt {-1+x^3}} \, dx+\int \frac {1}{\left (-2+2 \sqrt {3}+2 x\right ) \sqrt {-1+x^3}} \, dx\\ &=-\frac {\int \frac {96 \left (1-\sqrt {3}\right )-96 x}{\left (-2-2 \sqrt {3}+2 x\right ) \sqrt {-1+x^3}} \, dx}{192 \sqrt {3}}+\frac {\int \frac {96 \left (1+\sqrt {3}\right )-96 x}{\left (-2+2 \sqrt {3}+2 x\right ) \sqrt {-1+x^3}} \, dx}{192 \sqrt {3}}\\ &=-\frac {\operatorname {Subst}\left (\int \frac {1}{1-\left (3-2 \sqrt {3}\right ) x^2} \, dx,x,\frac {1+\frac {2 \left (1-\sqrt {3}\right ) x}{-2+2 \sqrt {3}}}{\sqrt {-1+x^3}}\right )}{2 \sqrt {3}}+\frac {\operatorname {Subst}\left (\int \frac {1}{1-\left (3+2 \sqrt {3}\right ) x^2} \, dx,x,\frac {1+\frac {2 \left (1+\sqrt {3}\right ) x}{-2-2 \sqrt {3}}}{\sqrt {-1+x^3}}\right )}{2 \sqrt {3}}\\ &=-\frac {\tan ^{-1}\left (\frac {\sqrt {-3+2 \sqrt {3}} (1-x)}{\sqrt {-1+x^3}}\right )}{2 \sqrt {3 \left (-3+2 \sqrt {3}\right )}}+\frac {\tanh ^{-1}\left (\frac {\sqrt {3+2 \sqrt {3}} (1-x)}{\sqrt {-1+x^3}}\right )}{2 \sqrt {3 \left (3+2 \sqrt {3}\right )}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [C]  time = 0.23, size = 220, normalized size = 2.22 \begin {gather*} -\frac {\sqrt {\frac {1-x}{1+\sqrt [3]{-1}}} \sqrt {x^2+x+1} \left (\left (3+(2+i) \sqrt {3}\right ) \Pi \left (\frac {2 \sqrt {3}}{-3 i+(1+2 i) \sqrt {3}};\sin ^{-1}\left (\sqrt {-\frac {\left (i+\sqrt {3}\right ) x+2 i}{-3 i+\sqrt {3}}}\right )|\frac {1}{2} \left (1+i \sqrt {3}\right )\right )+\left (3-(2-i) \sqrt {3}\right ) \Pi \left (\frac {2 i \sqrt {3}}{3+(2+i) \sqrt {3}};\sin ^{-1}\left (\sqrt {-\frac {\left (i+\sqrt {3}\right ) x+2 i}{-3 i+\sqrt {3}}}\right )|\frac {1}{2} \left (1+i \sqrt {3}\right )\right )\right )}{3 \left (\sqrt {3}+i\right ) \sqrt {x^3-1}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(-1 + x)/((-2 - 2*x + x^2)*Sqrt[-1 + x^3]),x]

[Out]

-1/3*(Sqrt[(1 - x)/(1 + (-1)^(1/3))]*Sqrt[1 + x + x^2]*((3 + (2 + I)*Sqrt[3])*EllipticPi[(2*Sqrt[3])/(-3*I + (
1 + 2*I)*Sqrt[3]), ArcSin[Sqrt[-((2*I + (I + Sqrt[3])*x)/(-3*I + Sqrt[3]))]], (1 + I*Sqrt[3])/2] + (3 - (2 - I
)*Sqrt[3])*EllipticPi[((2*I)*Sqrt[3])/(3 + (2 + I)*Sqrt[3]), ArcSin[Sqrt[-((2*I + (I + Sqrt[3])*x)/(-3*I + Sqr
t[3]))]], (1 + I*Sqrt[3])/2]))/((I + Sqrt[3])*Sqrt[-1 + x^3])

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 1.28, size = 99, normalized size = 1.00 \begin {gather*} \frac {1}{6} \sqrt {3+2 \sqrt {3}} \tan ^{-1}\left (\frac {\sqrt {-3+2 \sqrt {3}} \sqrt {-1+x^3}}{1+x+x^2}\right )-\frac {1}{6} \sqrt {-3+2 \sqrt {3}} \tanh ^{-1}\left (\frac {\sqrt {3+2 \sqrt {3}} \sqrt {-1+x^3}}{1+x+x^2}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(-1 + x)/((-2 - 2*x + x^2)*Sqrt[-1 + x^3]),x]

[Out]

(Sqrt[3 + 2*Sqrt[3]]*ArcTan[(Sqrt[-3 + 2*Sqrt[3]]*Sqrt[-1 + x^3])/(1 + x + x^2)])/6 - (Sqrt[-3 + 2*Sqrt[3]]*Ar
cTanh[(Sqrt[3 + 2*Sqrt[3]]*Sqrt[-1 + x^3])/(1 + x + x^2)])/6

________________________________________________________________________________________

fricas [B]  time = 1.04, size = 233, normalized size = 2.35 \begin {gather*} -\frac {1}{6} \, \sqrt {2 \, \sqrt {3} + 3} \arctan \left (\frac {\sqrt {x^{3} - 1} \sqrt {2 \, \sqrt {3} + 3} {\left (\sqrt {3} - 2\right )}}{x^{2} + x + 1}\right ) - \frac {1}{24} \, \sqrt {2 \, \sqrt {3} - 3} \log \left (\frac {x^{4} + 2 \, x^{3} + 6 \, x^{2} + 2 \, \sqrt {x^{3} - 1} {\left (2 \, x^{2} + \sqrt {3} {\left (x^{2} + 2 \, x\right )} + 2 \, x + 2\right )} \sqrt {2 \, \sqrt {3} - 3} + 4 \, \sqrt {3} {\left (x^{3} - 1\right )} - 4 \, x + 4}{x^{4} - 4 \, x^{3} + 8 \, x + 4}\right ) + \frac {1}{24} \, \sqrt {2 \, \sqrt {3} - 3} \log \left (\frac {x^{4} + 2 \, x^{3} + 6 \, x^{2} - 2 \, \sqrt {x^{3} - 1} {\left (2 \, x^{2} + \sqrt {3} {\left (x^{2} + 2 \, x\right )} + 2 \, x + 2\right )} \sqrt {2 \, \sqrt {3} - 3} + 4 \, \sqrt {3} {\left (x^{3} - 1\right )} - 4 \, x + 4}{x^{4} - 4 \, x^{3} + 8 \, x + 4}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-1+x)/(x^2-2*x-2)/(x^3-1)^(1/2),x, algorithm="fricas")

[Out]

-1/6*sqrt(2*sqrt(3) + 3)*arctan(sqrt(x^3 - 1)*sqrt(2*sqrt(3) + 3)*(sqrt(3) - 2)/(x^2 + x + 1)) - 1/24*sqrt(2*s
qrt(3) - 3)*log((x^4 + 2*x^3 + 6*x^2 + 2*sqrt(x^3 - 1)*(2*x^2 + sqrt(3)*(x^2 + 2*x) + 2*x + 2)*sqrt(2*sqrt(3)
- 3) + 4*sqrt(3)*(x^3 - 1) - 4*x + 4)/(x^4 - 4*x^3 + 8*x + 4)) + 1/24*sqrt(2*sqrt(3) - 3)*log((x^4 + 2*x^3 + 6
*x^2 - 2*sqrt(x^3 - 1)*(2*x^2 + sqrt(3)*(x^2 + 2*x) + 2*x + 2)*sqrt(2*sqrt(3) - 3) + 4*sqrt(3)*(x^3 - 1) - 4*x
+ 4)/(x^4 - 4*x^3 + 8*x + 4))

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x - 1}{\sqrt {x^{3} - 1} {\left (x^{2} - 2 \, x - 2\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-1+x)/(x^2-2*x-2)/(x^3-1)^(1/2),x, algorithm="giac")

[Out]

integrate((x - 1)/(sqrt(x^3 - 1)*(x^2 - 2*x - 2)), x)

________________________________________________________________________________________

maple [C]  time = 1.02, size = 702, normalized size = 7.09

method	result	size
default	\(\frac {\sqrt {-\frac {1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {1}{3-i \sqrt {3}}-\frac {i \sqrt {3}}{2 \left (\frac {3}{2}-\frac {i \sqrt {3}}{2}\right )}}\, \sqrt {\frac {x}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}+\frac {1}{3+i \sqrt {3}}+\frac {i \sqrt {3}}{3+i \sqrt {3}}}\, \EllipticPi \left (\sqrt {\frac {-1+x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, -\frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right ) \sqrt {3}}{2 \sqrt {x^{3}-1}}+\frac {i \sqrt {-\frac {1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {1}{3-i \sqrt {3}}-\frac {i \sqrt {3}}{2 \left (\frac {3}{2}-\frac {i \sqrt {3}}{2}\right )}}\, \sqrt {\frac {x}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}+\frac {1}{3+i \sqrt {3}}+\frac {i \sqrt {3}}{3+i \sqrt {3}}}\, \EllipticPi \left (\sqrt {\frac {-1+x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, -\frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{2 \sqrt {x^{3}-1}}-\frac {\sqrt {-\frac {1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {1}{3-i \sqrt {3}}-\frac {i \sqrt {3}}{2 \left (\frac {3}{2}-\frac {i \sqrt {3}}{2}\right )}}\, \sqrt {\frac {x}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}+\frac {1}{3+i \sqrt {3}}+\frac {i \sqrt {3}}{3+i \sqrt {3}}}\, \EllipticPi \left (\sqrt {\frac {-1+x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right ) \sqrt {3}}{2 \sqrt {x^{3}-1}}-\frac {i \sqrt {-\frac {1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {1}{3-i \sqrt {3}}-\frac {i \sqrt {3}}{2 \left (\frac {3}{2}-\frac {i \sqrt {3}}{2}\right )}}\, \sqrt {\frac {x}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}+\frac {1}{3+i \sqrt {3}}+\frac {i \sqrt {3}}{3+i \sqrt {3}}}\, \EllipticPi \left (\sqrt {\frac {-1+x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{2 \sqrt {x^{3}-1}}\)	\(702\)
elliptic	\(\frac {\sqrt {-\frac {1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {1}{3-i \sqrt {3}}-\frac {i \sqrt {3}}{2 \left (\frac {3}{2}-\frac {i \sqrt {3}}{2}\right )}}\, \sqrt {\frac {x}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}+\frac {1}{3+i \sqrt {3}}+\frac {i \sqrt {3}}{3+i \sqrt {3}}}\, \EllipticPi \left (\sqrt {\frac {-1+x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, -\frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right ) \sqrt {3}}{2 \sqrt {x^{3}-1}}+\frac {i \sqrt {-\frac {1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {1}{3-i \sqrt {3}}-\frac {i \sqrt {3}}{2 \left (\frac {3}{2}-\frac {i \sqrt {3}}{2}\right )}}\, \sqrt {\frac {x}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}+\frac {1}{3+i \sqrt {3}}+\frac {i \sqrt {3}}{3+i \sqrt {3}}}\, \EllipticPi \left (\sqrt {\frac {-1+x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, -\frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{2 \sqrt {x^{3}-1}}-\frac {\sqrt {-\frac {1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {1}{3-i \sqrt {3}}-\frac {i \sqrt {3}}{2 \left (\frac {3}{2}-\frac {i \sqrt {3}}{2}\right )}}\, \sqrt {\frac {x}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}+\frac {1}{3+i \sqrt {3}}+\frac {i \sqrt {3}}{3+i \sqrt {3}}}\, \EllipticPi \left (\sqrt {\frac {-1+x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right ) \sqrt {3}}{2 \sqrt {x^{3}-1}}-\frac {i \sqrt {-\frac {1}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\, \sqrt {\frac {x}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}+\frac {1}{3-i \sqrt {3}}-\frac {i \sqrt {3}}{2 \left (\frac {3}{2}-\frac {i \sqrt {3}}{2}\right )}}\, \sqrt {\frac {x}{\frac {3}{2}+\frac {i \sqrt {3}}{2}}+\frac {1}{3+i \sqrt {3}}+\frac {i \sqrt {3}}{3+i \sqrt {3}}}\, \EllipticPi \left (\sqrt {\frac {-1+x}{-\frac {3}{2}-\frac {i \sqrt {3}}{2}}}, \frac {\left (\frac {3}{2}+\frac {i \sqrt {3}}{2}\right ) \sqrt {3}}{3}, \sqrt {\frac {\frac {3}{2}+\frac {i \sqrt {3}}{2}}{\frac {3}{2}-\frac {i \sqrt {3}}{2}}}\right )}{2 \sqrt {x^{3}-1}}\)	\(702\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-1+x)/(x^2-2*x-2)/(x^3-1)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/2*(-1/(-3/2-1/2*I*3^(1/2))+1/(-3/2-1/2*I*3^(1/2))*x)^(1/2)*(1/(3/2-1/2*I*3^(1/2))*x+1/2/(3/2-1/2*I*3^(1/2))-
1/2*I/(3/2-1/2*I*3^(1/2))*3^(1/2))^(1/2)*(1/(3/2+1/2*I*3^(1/2))*x+1/2/(3/2+1/2*I*3^(1/2))+1/2*I/(3/2+1/2*I*3^(
1/2))*3^(1/2))^(1/2)/(x^3-1)^(1/2)*EllipticPi(((-1+x)/(-3/2-1/2*I*3^(1/2)))^(1/2),-1/3*(3/2+1/2*I*3^(1/2))*3^(
1/2),((3/2+1/2*I*3^(1/2))/(3/2-1/2*I*3^(1/2)))^(1/2))*3^(1/2)+1/2*I*(-1/(-3/2-1/2*I*3^(1/2))+1/(-3/2-1/2*I*3^(
1/2))*x)^(1/2)*(1/(3/2-1/2*I*3^(1/2))*x+1/2/(3/2-1/2*I*3^(1/2))-1/2*I/(3/2-1/2*I*3^(1/2))*3^(1/2))^(1/2)*(1/(3
/2+1/2*I*3^(1/2))*x+1/2/(3/2+1/2*I*3^(1/2))+1/2*I/(3/2+1/2*I*3^(1/2))*3^(1/2))^(1/2)/(x^3-1)^(1/2)*EllipticPi(
((-1+x)/(-3/2-1/2*I*3^(1/2)))^(1/2),-1/3*(3/2+1/2*I*3^(1/2))*3^(1/2),((3/2+1/2*I*3^(1/2))/(3/2-1/2*I*3^(1/2)))
^(1/2))-1/2*(-1/(-3/2-1/2*I*3^(1/2))+1/(-3/2-1/2*I*3^(1/2))*x)^(1/2)*(1/(3/2-1/2*I*3^(1/2))*x+1/2/(3/2-1/2*I*3
^(1/2))-1/2*I/(3/2-1/2*I*3^(1/2))*3^(1/2))^(1/2)*(1/(3/2+1/2*I*3^(1/2))*x+1/2/(3/2+1/2*I*3^(1/2))+1/2*I/(3/2+1
/2*I*3^(1/2))*3^(1/2))^(1/2)/(x^3-1)^(1/2)*EllipticPi(((-1+x)/(-3/2-1/2*I*3^(1/2)))^(1/2),1/3*(3/2+1/2*I*3^(1/
2))*3^(1/2),((3/2+1/2*I*3^(1/2))/(3/2-1/2*I*3^(1/2)))^(1/2))*3^(1/2)-1/2*I*(-1/(-3/2-1/2*I*3^(1/2))+1/(-3/2-1/
2*I*3^(1/2))*x)^(1/2)*(1/(3/2-1/2*I*3^(1/2))*x+1/2/(3/2-1/2*I*3^(1/2))-1/2*I/(3/2-1/2*I*3^(1/2))*3^(1/2))^(1/2
)*(1/(3/2+1/2*I*3^(1/2))*x+1/2/(3/2+1/2*I*3^(1/2))+1/2*I/(3/2+1/2*I*3^(1/2))*3^(1/2))^(1/2)/(x^3-1)^(1/2)*Elli
pticPi(((-1+x)/(-3/2-1/2*I*3^(1/2)))^(1/2),1/3*(3/2+1/2*I*3^(1/2))*3^(1/2),((3/2+1/2*I*3^(1/2))/(3/2-1/2*I*3^(
1/2)))^(1/2))

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x - 1}{\sqrt {x^{3} - 1} {\left (x^{2} - 2 \, x - 2\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-1+x)/(x^2-2*x-2)/(x^3-1)^(1/2),x, algorithm="maxima")

[Out]

integrate((x - 1)/(sqrt(x^3 - 1)*(x^2 - 2*x - 2)), x)

________________________________________________________________________________________

mupad [B]  time = 0.23, size = 221, normalized size = 2.23 \begin {gather*} -\frac {\left (\Pi \left (\sqrt {3}\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right );\mathrm {asin}\left (\sqrt {-\frac {x-1}{\frac {3}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}}\right )\middle |-\frac {\frac {3}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}{-\frac {3}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}\right )-\Pi \left (-\sqrt {3}\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{6}\right );\mathrm {asin}\left (\sqrt {-\frac {x-1}{\frac {3}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}}\right )\middle |-\frac {\frac {3}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}{-\frac {3}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}\right )\right )\,\sqrt {-\frac {x+\frac {1}{2}-\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}{-\frac {3}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}}\,\sqrt {\frac {x+\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}{\frac {3}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}}\,\sqrt {-\frac {x-1}{\frac {3}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}}}\,\left (\sqrt {3}+1{}\mathrm {i}\right )}{2\,\sqrt {x^3+\left (-\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )-1\right )\,x+\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(x - 1)/((x^3 - 1)^(1/2)*(2*x - x^2 + 2)),x)

[Out]

-((ellipticPi(3^(1/2)*((3^(1/2)*1i)/6 + 1/2), asin((-(x - 1)/((3^(1/2)*1i)/2 + 3/2))^(1/2)), -((3^(1/2)*1i)/2
+ 3/2)/((3^(1/2)*1i)/2 - 3/2)) - ellipticPi(-3^(1/2)*((3^(1/2)*1i)/6 + 1/2), asin((-(x - 1)/((3^(1/2)*1i)/2 +
3/2))^(1/2)), -((3^(1/2)*1i)/2 + 3/2)/((3^(1/2)*1i)/2 - 3/2)))*(-(x - (3^(1/2)*1i)/2 + 1/2)/((3^(1/2)*1i)/2 -
3/2))^(1/2)*((x + (3^(1/2)*1i)/2 + 1/2)/((3^(1/2)*1i)/2 + 3/2))^(1/2)*(-(x - 1)/((3^(1/2)*1i)/2 + 3/2))^(1/2)*
(3^(1/2) + 1i))/(2*(((3^(1/2)*1i)/2 - 1/2)*((3^(1/2)*1i)/2 + 1/2) - x*(((3^(1/2)*1i)/2 - 1/2)*((3^(1/2)*1i)/2
+ 1/2) + 1) + x^3)^(1/2))

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x - 1}{\sqrt {\left (x - 1\right ) \left (x^{2} + x + 1\right )} \left (x^{2} - 2 x - 2\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-1+x)/(x**2-2*x-2)/(x**3-1)**(1/2),x)

[Out]

Integral((x - 1)/(sqrt((x - 1)*(x**2 + x + 1))*(x**2 - 2*x - 2)), x)

________________________________________________________________________________________