3.38 \(\int (e x)^m \text {Si}(d (a+b \log (c x^n))) \, dx\)

Optimal. Leaf size=176 \[ -\frac {i x (e x)^m e^{-\frac {a (m+1)}{b n}} \left (c x^n\right )^{-\frac {m+1}{n}} \text {Ei}\left (\frac {(m-i b d n+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 (m+1)}+\frac {i x (e x)^m e^{-\frac {a (m+1)}{b n}} \left (c x^n\right )^{-\frac {m+1}{n}} \text {Ei}\left (\frac {(m+i b d n+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 (m+1)}+\frac {(e x)^{m+1} \text {Si}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (m+1)} \]

[Out]

-1/2*I*x*(e*x)^m*Ei((1+m-I*b*d*n)*(a+b*ln(c*x^n))/b/n)/exp(a*(1+m)/b/n)/(1+m)/((c*x^n)^((1+m)/n))+1/2*I*x*(e*x
)^m*Ei((1+m+I*b*d*n)*(a+b*ln(c*x^n))/b/n)/exp(a*(1+m)/b/n)/(1+m)/((c*x^n)^((1+m)/n))+(e*x)^(1+m)*Si(d*(a+b*ln(
c*x^n)))/e/(1+m)

________________________________________________________________________________________

Rubi [A]  time = 0.31, antiderivative size = 176, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.263, Rules used = {6526, 12, 4497, 2310, 2178} \[ -\frac {i x (e x)^m e^{-\frac {a (m+1)}{b n}} \left (c x^n\right )^{-\frac {m+1}{n}} \text {Ei}\left (\frac {(m-i b d n+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 (m+1)}+\frac {i x (e x)^m e^{-\frac {a (m+1)}{b n}} \left (c x^n\right )^{-\frac {m+1}{n}} \text {Ei}\left (\frac {(m+i b d n+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 (m+1)}+\frac {(e x)^{m+1} \text {Si}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (m+1)} \]

Antiderivative was successfully verified.

[In]

Int[(e*x)^m*SinIntegral[d*(a + b*Log[c*x^n])],x]

[Out]

((-I/2)*x*(e*x)^m*ExpIntegralEi[((1 + m - I*b*d*n)*(a + b*Log[c*x^n]))/(b*n)])/(E^((a*(1 + m))/(b*n))*(1 + m)*
(c*x^n)^((1 + m)/n)) + ((I/2)*x*(e*x)^m*ExpIntegralEi[((1 + m + I*b*d*n)*(a + b*Log[c*x^n]))/(b*n)])/(E^((a*(1
+ m))/(b*n))*(1 + m)*(c*x^n)^((1 + m)/n)) + ((e*x)^(1 + m)*SinIntegral[d*(a + b*Log[c*x^n])])/(e*(1 + m))

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 2178

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(F^(g*(e - (c*f)/d))*ExpIntegral
Ei[(f*g*(c + d*x)*Log[F])/d])/d, x] /; FreeQ[{F, c, d, e, f, g}, x] &&  !$UseGamma === True

Rule 2310

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_)*((d_.)*(x_))^(m_.), x_Symbol] :> Dist[(d*x)^(m + 1)/(d*n*(c*x^n
)^((m + 1)/n)), Subst[Int[E^(((m + 1)*x)/n)*(a + b*x)^p, x], x, Log[c*x^n]], x] /; FreeQ[{a, b, c, d, m, n, p}
, x]

Rule 4497

Int[(((e_.) + Log[(g_.)*(x_)^(m_.)]*(f_.))*(h_.))^(q_.)*((i_.)*(x_))^(r_.)*Sin[((a_.) + Log[(c_.)*(x_)^(n_.)]*
(b_.))*(d_.)], x_Symbol] :> Dist[(I*(i*x)^r)/(E^(I*a*d)*(c*x^n)^(I*b*d)*(2*x^(r - I*b*d*n))), Int[x^(r - I*b*d
*n)*(h*(e + f*Log[g*x^m]))^q, x], x] - Dist[(I*E^(I*a*d)*(i*x)^r*(c*x^n)^(I*b*d))/(2*x^(r + I*b*d*n)), Int[x^(
r + I*b*d*n)*(h*(e + f*Log[g*x^m]))^q, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, i, m, n, q, r}, x]

Rule 6526

Int[((e_.)*(x_))^(m_.)*SinIntegral[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)], x_Symbol] :> Simp[((e*x)^(m +
1)*SinIntegral[d*(a + b*Log[c*x^n])])/(e*(m + 1)), x] - Dist[(b*d*n)/(m + 1), Int[((e*x)^m*Sin[d*(a + b*Log[c
*x^n])])/(d*(a + b*Log[c*x^n])), x], x] /; FreeQ[{a, b, c, d, e, m, n}, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int (e x)^m \text {Si}\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx &=\frac {(e x)^{1+m} \text {Si}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)}-\frac {(b d n) \int \frac {(e x)^m \sin \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{d \left (a+b \log \left (c x^n\right )\right )} \, dx}{1+m}\\ &=\frac {(e x)^{1+m} \text {Si}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)}-\frac {(b n) \int \frac {(e x)^m \sin \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{a+b \log \left (c x^n\right )} \, dx}{1+m}\\ &=\frac {(e x)^{1+m} \text {Si}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)}-\frac {\left (i b e^{-i a d} n x^{-m+i b d n} (e x)^m \left (c x^n\right )^{-i b d}\right ) \int \frac {x^{m-i b d n}}{a+b \log \left (c x^n\right )} \, dx}{2 (1+m)}+\frac {\left (i b e^{i a d} n x^{-m-i b d n} (e x)^m \left (c x^n\right )^{i b d}\right ) \int \frac {x^{m+i b d n}}{a+b \log \left (c x^n\right )} \, dx}{2 (1+m)}\\ &=\frac {(e x)^{1+m} \text {Si}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)}-\frac {\left (i b e^{-i a d} x (e x)^m \left (c x^n\right )^{-i b d-\frac {1+m-i b d n}{n}}\right ) \operatorname {Subst}\left (\int \frac {e^{\frac {(1+m-i b d n) x}{n}}}{a+b x} \, dx,x,\log \left (c x^n\right )\right )}{2 (1+m)}+\frac {\left (i b e^{i a d} x (e x)^m \left (c x^n\right )^{i b d-\frac {1+m+i b d n}{n}}\right ) \operatorname {Subst}\left (\int \frac {e^{\frac {(1+m+i b d n) x}{n}}}{a+b x} \, dx,x,\log \left (c x^n\right )\right )}{2 (1+m)}\\ &=-\frac {i e^{-\frac {a (1+m)}{b n}} x (e x)^m \left (c x^n\right )^{-\frac {1+m}{n}} \text {Ei}\left (\frac {(1+m-i b d n) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 (1+m)}+\frac {i e^{-\frac {a (1+m)}{b n}} x (e x)^m \left (c x^n\right )^{-\frac {1+m}{n}} \text {Ei}\left (\frac {(1+m+i b d n) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{2 (1+m)}+\frac {(e x)^{1+m} \text {Si}\left (d \left (a+b \log \left (c x^n\right )\right )\right )}{e (1+m)}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 3.45, size = 128, normalized size = 0.73 \[ \frac {(e x)^m \left (2 x \text {Si}\left (d \left (a+b \log \left (c x^n\right )\right )\right )-i x^{-m} \exp \left (-\frac {(m+1) \left (a+b \log \left (c x^n\right )-b n \log (x)\right )}{b n}\right ) \left (\text {Ei}\left (\frac {(m-i b d n+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )-\text {Ei}\left (\frac {(m+i b d n+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )\right )\right )}{2 (m+1)} \]

Antiderivative was successfully verified.

[In]

Integrate[(e*x)^m*SinIntegral[d*(a + b*Log[c*x^n])],x]

[Out]

((e*x)^m*(((-I)*(ExpIntegralEi[((1 + m - I*b*d*n)*(a + b*Log[c*x^n]))/(b*n)] - ExpIntegralEi[((1 + m + I*b*d*n
)*(a + b*Log[c*x^n]))/(b*n)]))/(E^(((1 + m)*(a - b*n*Log[x] + b*Log[c*x^n]))/(b*n))*x^m) + 2*x*SinIntegral[d*(
a + b*Log[c*x^n])]))/(2*(1 + m))

________________________________________________________________________________________

fricas [F]  time = 0.75, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\left (e x\right )^{m} \operatorname {Si}\left (b d \log \left (c x^{n}\right ) + a d\right ), x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x)^m*Si(d*(a+b*log(c*x^n))),x, algorithm="fricas")

[Out]

integral((e*x)^m*sin_integral(b*d*log(c*x^n) + a*d), x)

________________________________________________________________________________________

giac [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x)^m*Si(d*(a+b*log(c*x^n))),x, algorithm="giac")

[Out]

Timed out

________________________________________________________________________________________

maple [F]  time = 0.06, size = 0, normalized size = 0.00 \[ \int \left (e x \right )^{m} \Si \left (d \left (a +b \ln \left (c \,x^{n}\right )\right )\right )\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x)^m*Si(d*(a+b*ln(c*x^n))),x)

[Out]

int((e*x)^m*Si(d*(a+b*ln(c*x^n))),x)

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (e x\right )^{m} {\rm Si}\left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x)^m*Si(d*(a+b*log(c*x^n))),x, algorithm="maxima")

[Out]

integrate((e*x)^m*Si((b*log(c*x^n) + a)*d), x)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \mathrm {sinint}\left (d\,\left (a+b\,\ln \left (c\,x^n\right )\right )\right )\,{\left (e\,x\right )}^m \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sinint(d*(a + b*log(c*x^n)))*(e*x)^m,x)

[Out]

int(sinint(d*(a + b*log(c*x^n)))*(e*x)^m, x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (e x\right )^{m} \operatorname {Si}{\left (a d + b d \log {\left (c x^{n} \right )} \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x)**m*Si(d*(a+b*ln(c*x**n))),x)

[Out]

Integral((e*x)**m*Si(a*d + b*d*log(c*x**n)), x)

________________________________________________________________________________________