3.1 \(\int x^m \text {Si}(b x) \, dx\)

Optimal. Leaf size=86 \[ \frac {x^{m+1} \text {Si}(b x)}{m+1}+\frac {x^m (-i b x)^{-m} \Gamma (m+1,-i b x)}{2 b (m+1)}+\frac {x^m (i b x)^{-m} \Gamma (m+1,i b x)}{2 b (m+1)} \]

[Out]

1/2*x^m*GAMMA(1+m,-I*b*x)/b/(1+m)/((-I*b*x)^m)+1/2*x^m*GAMMA(1+m,I*b*x)/b/(1+m)/((I*b*x)^m)+x^(1+m)*Si(b*x)/(1
+m)

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Rubi [A]  time = 0.07, antiderivative size = 86, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6503, 12, 3308, 2181} \[ \frac {x^m (-i b x)^{-m} \text {Gamma}(m+1,-i b x)}{2 b (m+1)}+\frac {x^m (i b x)^{-m} \text {Gamma}(m+1,i b x)}{2 b (m+1)}+\frac {x^{m+1} \text {Si}(b x)}{m+1} \]

Antiderivative was successfully verified.

[In]

Int[x^m*SinIntegral[b*x],x]

[Out]

(x^m*Gamma[1 + m, (-I)*b*x])/(2*b*(1 + m)*((-I)*b*x)^m) + (x^m*Gamma[1 + m, I*b*x])/(2*b*(1 + m)*(I*b*x)^m) +
(x^(1 + m)*SinIntegral[b*x])/(1 + m)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 2181

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> -Simp[(F^(g*(e - (c*f)/d))*(c +
d*x)^FracPart[m]*Gamma[m + 1, (-((f*g*Log[F])/d))*(c + d*x)])/(d*(-((f*g*Log[F])/d))^(IntPart[m] + 1)*(-((f*g*
Log[F]*(c + d*x))/d))^FracPart[m]), x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rule 3308

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/E^(I*(e + f*x))
, x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d, e, f, m}, x]

Rule 6503

Int[((c_.) + (d_.)*(x_))^(m_.)*SinIntegral[(a_.) + (b_.)*(x_)], x_Symbol] :> Simp[((c + d*x)^(m + 1)*SinIntegr
al[a + b*x])/(d*(m + 1)), x] - Dist[b/(d*(m + 1)), Int[((c + d*x)^(m + 1)*Sin[a + b*x])/(a + b*x), x], x] /; F
reeQ[{a, b, c, d, m}, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int x^m \text {Si}(b x) \, dx &=\frac {x^{1+m} \text {Si}(b x)}{1+m}-\frac {b \int \frac {x^m \sin (b x)}{b} \, dx}{1+m}\\ &=\frac {x^{1+m} \text {Si}(b x)}{1+m}-\frac {\int x^m \sin (b x) \, dx}{1+m}\\ &=\frac {x^{1+m} \text {Si}(b x)}{1+m}-\frac {i \int e^{-i b x} x^m \, dx}{2 (1+m)}+\frac {i \int e^{i b x} x^m \, dx}{2 (1+m)}\\ &=\frac {x^m (-i b x)^{-m} \Gamma (1+m,-i b x)}{2 b (1+m)}+\frac {x^m (i b x)^{-m} \Gamma (1+m,i b x)}{2 b (1+m)}+\frac {x^{1+m} \text {Si}(b x)}{1+m}\\ \end {align*}

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Mathematica [A]  time = 0.07, size = 82, normalized size = 0.95 \[ \frac {x^m \left (b^2 x^2\right )^{-m} \left (2 b x \left (b^2 x^2\right )^m \text {Si}(b x)+(-i b x)^m \Gamma (m+1,i b x)+(i b x)^m \Gamma (m+1,-i b x)\right )}{2 b (m+1)} \]

Antiderivative was successfully verified.

[In]

Integrate[x^m*SinIntegral[b*x],x]

[Out]

(x^m*((I*b*x)^m*Gamma[1 + m, (-I)*b*x] + ((-I)*b*x)^m*Gamma[1 + m, I*b*x] + 2*b*x*(b^2*x^2)^m*SinIntegral[b*x]
))/(2*b*(1 + m)*(b^2*x^2)^m)

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fricas [F]  time = 0.57, size = 0, normalized size = 0.00 \[ {\rm integral}\left (x^{m} \operatorname {Si}\left (b x\right ), x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*Si(b*x),x, algorithm="fricas")

[Out]

integral(x^m*sin_integral(b*x), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{m} {\rm Si}\left (b x\right )\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*Si(b*x),x, algorithm="giac")

[Out]

integrate(x^m*Si(b*x), x)

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maple [C]  time = 0.08, size = 37, normalized size = 0.43 \[ \frac {b \,x^{m +2} \hypergeom \left (\left [\frac {1}{2}, 1+\frac {m}{2}\right ], \left [\frac {3}{2}, \frac {3}{2}, 2+\frac {m}{2}\right ], -\frac {b^{2} x^{2}}{4}\right )}{m +2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m*Si(b*x),x)

[Out]

b/(m+2)*x^(m+2)*hypergeom([1/2,1+1/2*m],[3/2,3/2,2+1/2*m],-1/4*b^2*x^2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{m} {\rm Si}\left (b x\right )\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m*Si(b*x),x, algorithm="maxima")

[Out]

integrate(x^m*Si(b*x), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int x^m\,\mathrm {sinint}\left (b\,x\right ) \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m*sinint(b*x),x)

[Out]

int(x^m*sinint(b*x), x)

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sympy [A]  time = 0.87, size = 46, normalized size = 0.53 \[ \frac {b x^{2} x^{m} \Gamma \left (\frac {m}{2} + 1\right ) {{}_{2}F_{3}\left (\begin {matrix} \frac {1}{2}, \frac {m}{2} + 1 \\ \frac {3}{2}, \frac {3}{2}, \frac {m}{2} + 2 \end {matrix}\middle | {- \frac {b^{2} x^{2}}{4}} \right )}}{2 \Gamma \left (\frac {m}{2} + 2\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**m*Si(b*x),x)

[Out]

b*x**2*x**m*gamma(m/2 + 1)*hyper((1/2, m/2 + 1), (3/2, 3/2, m/2 + 2), -b**2*x**2/4)/(2*gamma(m/2 + 2))

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