Optimal. Leaf size=217 \[ \frac {531 S\left (\sqrt {2} b x\right )}{16 \sqrt {2} \pi ^4 b^8}+\frac {4 x^3}{\pi ^3 b^5}+\frac {x^6 S(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {48 S(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi ^4 b^8}-\frac {147 x \sin \left (\pi b^2 x^2\right )}{16 \pi ^4 b^7}-\frac {24 x^2 S(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi ^3 b^6}+\frac {17 x^3 \cos \left (\pi b^2 x^2\right )}{8 \pi ^3 b^5}+\frac {6 x^4 S(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi ^2 b^4}+\frac {x^5 \sin \left (\pi b^2 x^2\right )}{4 \pi ^2 b^3}-\frac {x^7}{14 \pi b} \]
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Rubi [A] time = 0.27, antiderivative size = 217, normalized size of antiderivative = 1.00, number of steps used = 18, number of rules used = 8, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {6462, 3391, 30, 3386, 3385, 3351, 6454, 6452} \[ \frac {x^6 S(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi b^2}-\frac {24 x^2 S(b x) \sin \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi ^3 b^6}+\frac {6 x^4 S(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi ^2 b^4}-\frac {48 S(b x) \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{\pi ^4 b^8}+\frac {531 S\left (\sqrt {2} b x\right )}{16 \sqrt {2} \pi ^4 b^8}+\frac {4 x^3}{\pi ^3 b^5}+\frac {x^5 \sin \left (\pi b^2 x^2\right )}{4 \pi ^2 b^3}-\frac {147 x \sin \left (\pi b^2 x^2\right )}{16 \pi ^4 b^7}+\frac {17 x^3 \cos \left (\pi b^2 x^2\right )}{8 \pi ^3 b^5}-\frac {x^7}{14 \pi b} \]
Antiderivative was successfully verified.
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Rule 30
Rule 3351
Rule 3385
Rule 3386
Rule 3391
Rule 6452
Rule 6454
Rule 6462
Rubi steps
\begin {align*} \int x^7 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x) \, dx &=\frac {x^6 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^2 \pi }-\frac {6 \int x^5 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right ) \, dx}{b^2 \pi }-\frac {\int x^6 \sin ^2\left (\frac {1}{2} b^2 \pi x^2\right ) \, dx}{b \pi }\\ &=\frac {6 x^4 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{b^4 \pi ^2}+\frac {x^6 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^2 \pi }-\frac {24 \int x^3 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x) \, dx}{b^4 \pi ^2}-\frac {3 \int x^4 \sin \left (b^2 \pi x^2\right ) \, dx}{b^3 \pi ^2}-\frac {\int x^6 \, dx}{2 b \pi }+\frac {\int x^6 \cos \left (b^2 \pi x^2\right ) \, dx}{2 b \pi }\\ &=-\frac {x^7}{14 b \pi }+\frac {3 x^3 \cos \left (b^2 \pi x^2\right )}{2 b^5 \pi ^3}+\frac {6 x^4 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{b^4 \pi ^2}-\frac {24 x^2 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^6 \pi ^3}+\frac {x^6 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^2 \pi }+\frac {x^5 \sin \left (b^2 \pi x^2\right )}{4 b^3 \pi ^2}+\frac {48 \int x S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right ) \, dx}{b^6 \pi ^3}-\frac {9 \int x^2 \cos \left (b^2 \pi x^2\right ) \, dx}{2 b^5 \pi ^3}+\frac {24 \int x^2 \sin ^2\left (\frac {1}{2} b^2 \pi x^2\right ) \, dx}{b^5 \pi ^3}-\frac {5 \int x^4 \sin \left (b^2 \pi x^2\right ) \, dx}{4 b^3 \pi ^2}\\ &=-\frac {x^7}{14 b \pi }+\frac {17 x^3 \cos \left (b^2 \pi x^2\right )}{8 b^5 \pi ^3}-\frac {48 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{b^8 \pi ^4}+\frac {6 x^4 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{b^4 \pi ^2}-\frac {24 x^2 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^6 \pi ^3}+\frac {x^6 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^2 \pi }-\frac {9 x \sin \left (b^2 \pi x^2\right )}{4 b^7 \pi ^4}+\frac {x^5 \sin \left (b^2 \pi x^2\right )}{4 b^3 \pi ^2}+\frac {9 \int \sin \left (b^2 \pi x^2\right ) \, dx}{4 b^7 \pi ^4}+\frac {24 \int \sin \left (b^2 \pi x^2\right ) \, dx}{b^7 \pi ^4}-\frac {15 \int x^2 \cos \left (b^2 \pi x^2\right ) \, dx}{8 b^5 \pi ^3}+\frac {12 \int x^2 \, dx}{b^5 \pi ^3}-\frac {12 \int x^2 \cos \left (b^2 \pi x^2\right ) \, dx}{b^5 \pi ^3}\\ &=\frac {4 x^3}{b^5 \pi ^3}-\frac {x^7}{14 b \pi }+\frac {17 x^3 \cos \left (b^2 \pi x^2\right )}{8 b^5 \pi ^3}-\frac {48 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{b^8 \pi ^4}+\frac {6 x^4 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{b^4 \pi ^2}+\frac {9 S\left (\sqrt {2} b x\right )}{4 \sqrt {2} b^8 \pi ^4}+\frac {12 \sqrt {2} S\left (\sqrt {2} b x\right )}{b^8 \pi ^4}-\frac {24 x^2 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^6 \pi ^3}+\frac {x^6 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^2 \pi }-\frac {147 x \sin \left (b^2 \pi x^2\right )}{16 b^7 \pi ^4}+\frac {x^5 \sin \left (b^2 \pi x^2\right )}{4 b^3 \pi ^2}+\frac {15 \int \sin \left (b^2 \pi x^2\right ) \, dx}{16 b^7 \pi ^4}+\frac {6 \int \sin \left (b^2 \pi x^2\right ) \, dx}{b^7 \pi ^4}\\ &=\frac {4 x^3}{b^5 \pi ^3}-\frac {x^7}{14 b \pi }+\frac {17 x^3 \cos \left (b^2 \pi x^2\right )}{8 b^5 \pi ^3}-\frac {48 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{b^8 \pi ^4}+\frac {6 x^4 \cos \left (\frac {1}{2} b^2 \pi x^2\right ) S(b x)}{b^4 \pi ^2}+\frac {51 S\left (\sqrt {2} b x\right )}{16 \sqrt {2} b^8 \pi ^4}+\frac {15 \sqrt {2} S\left (\sqrt {2} b x\right )}{b^8 \pi ^4}-\frac {24 x^2 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^6 \pi ^3}+\frac {x^6 S(b x) \sin \left (\frac {1}{2} b^2 \pi x^2\right )}{b^2 \pi }-\frac {147 x \sin \left (b^2 \pi x^2\right )}{16 b^7 \pi ^4}+\frac {x^5 \sin \left (b^2 \pi x^2\right )}{4 b^3 \pi ^2}\\ \end {align*}
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Mathematica [A] time = 0.21, size = 163, normalized size = 0.75 \[ \frac {-16 \pi ^3 b^7 x^7+896 \pi b^3 x^3-2058 b x \sin \left (\pi b^2 x^2\right )+56 \pi ^2 b^5 x^5 \sin \left (\pi b^2 x^2\right )+224 S(b x) \left (\pi b^2 x^2 \left (\pi ^2 b^4 x^4-24\right ) \sin \left (\frac {1}{2} \pi b^2 x^2\right )+6 \left (\pi ^2 b^4 x^4-8\right ) \cos \left (\frac {1}{2} \pi b^2 x^2\right )\right )+476 \pi b^3 x^3 \cos \left (\pi b^2 x^2\right )+3717 \sqrt {2} S\left (\sqrt {2} b x\right )}{224 \pi ^4 b^8} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.48, size = 0, normalized size = 0.00 \[ {\rm integral}\left (x^{7} \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) {\rm fresnels}\left (b x\right ), x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{7} \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) {\rm fresnels}\left (b x\right )\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.07, size = 321, normalized size = 1.48 \[ \frac {\frac {\mathrm {S}\left (b x \right ) \left (\frac {b^{6} x^{6} \sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{\pi }-\frac {6 \left (-\frac {b^{4} x^{4} \cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{\pi }+\frac {\frac {4 b^{2} x^{2} \sin \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{\pi }+\frac {8 \cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{\pi ^{2}}}{\pi }\right )}{\pi }\right )}{b^{7}}-\frac {\frac {\frac {1}{7} \pi ^{2} b^{7} x^{7}-8 b^{3} x^{3}}{2 \pi ^{3}}+\frac {-\frac {3 \pi \,b^{3} x^{3} \cos \left (b^{2} \pi \,x^{2}\right )}{2}+\frac {9 \pi \left (\frac {b x \sin \left (b^{2} \pi \,x^{2}\right )}{2 \pi }-\frac {\sqrt {2}\, \mathrm {S}\left (b x \sqrt {2}\right )}{4 \pi }\right )}{2}-12 \sqrt {2}\, \mathrm {S}\left (b x \sqrt {2}\right )}{\pi ^{4}}-\frac {\frac {\pi \,b^{5} x^{5} \sin \left (b^{2} \pi \,x^{2}\right )}{2}-\frac {5 \pi \left (-\frac {b^{3} x^{3} \cos \left (b^{2} \pi \,x^{2}\right )}{2 \pi }+\frac {\frac {3 b x \sin \left (b^{2} \pi \,x^{2}\right )}{4 \pi }-\frac {3 \sqrt {2}\, \mathrm {S}\left (b x \sqrt {2}\right )}{8 \pi }}{\pi }\right )}{2}-\frac {12 b x \sin \left (b^{2} \pi \,x^{2}\right )}{\pi }+\frac {6 \sqrt {2}\, \mathrm {S}\left (b x \sqrt {2}\right )}{\pi }}{2 \pi ^{3}}}{b^{7}}}{b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{7} \cos \left (\frac {1}{2} \, \pi b^{2} x^{2}\right ) {\rm fresnels}\left (b x\right )\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int x^7\,\mathrm {FresnelS}\left (b\,x\right )\,\cos \left (\frac {\Pi \,b^2\,x^2}{2}\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{7} \cos {\left (\frac {\pi b^{2} x^{2}}{2} \right )} S\left (b x\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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