3.120 \(\int \frac {C(b x)}{x^3} \, dx\)

Optimal. Leaf size=44 \[ -\frac {1}{2} \pi b^2 S(b x)-\frac {b \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{2 x}-\frac {C(b x)}{2 x^2} \]

[Out]

-1/2*b*cos(1/2*b^2*Pi*x^2)/x-1/2*FresnelC(b*x)/x^2-1/2*b^2*Pi*FresnelS(b*x)

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Rubi [A]  time = 0.03, antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {6427, 3388, 3351} \[ -\frac {1}{2} \pi b^2 S(b x)-\frac {b \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{2 x}-\frac {\text {FresnelC}(b x)}{2 x^2} \]

Antiderivative was successfully verified.

[In]

Int[FresnelC[b*x]/x^3,x]

[Out]

-(b*Cos[(b^2*Pi*x^2)/2])/(2*x) - FresnelC[b*x]/(2*x^2) - (b^2*Pi*FresnelS[b*x])/2

Rule 3351

Int[Sin[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelS[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rule 3388

Int[Cos[(c_.) + (d_.)*(x_)^(n_)]*((e_.)*(x_))^(m_), x_Symbol] :> Simp[((e*x)^(m + 1)*Cos[c + d*x^n])/(e*(m + 1
)), x] + Dist[(d*n)/(e^n*(m + 1)), Int[(e*x)^(m + n)*Sin[c + d*x^n], x], x] /; FreeQ[{c, d, e}, x] && IGtQ[n,
0] && LtQ[m, -1]

Rule 6427

Int[FresnelC[(b_.)*(x_)]*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*FresnelC[b*x])/(d*(m + 1)), x] -
Dist[b/(d*(m + 1)), Int[(d*x)^(m + 1)*Cos[(Pi*b^2*x^2)/2], x], x] /; FreeQ[{b, d, m}, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {C(b x)}{x^3} \, dx &=-\frac {C(b x)}{2 x^2}+\frac {1}{2} b \int \frac {\cos \left (\frac {1}{2} b^2 \pi x^2\right )}{x^2} \, dx\\ &=-\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{2 x}-\frac {C(b x)}{2 x^2}-\frac {1}{2} \left (b^3 \pi \right ) \int \sin \left (\frac {1}{2} b^2 \pi x^2\right ) \, dx\\ &=-\frac {b \cos \left (\frac {1}{2} b^2 \pi x^2\right )}{2 x}-\frac {C(b x)}{2 x^2}-\frac {1}{2} b^2 \pi S(b x)\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 44, normalized size = 1.00 \[ -\frac {1}{2} \pi b^2 S(b x)-\frac {b \cos \left (\frac {1}{2} \pi b^2 x^2\right )}{2 x}-\frac {C(b x)}{2 x^2} \]

Antiderivative was successfully verified.

[In]

Integrate[FresnelC[b*x]/x^3,x]

[Out]

-1/2*(b*Cos[(b^2*Pi*x^2)/2])/x - FresnelC[b*x]/(2*x^2) - (b^2*Pi*FresnelS[b*x])/2

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fricas [F]  time = 0.40, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\rm fresnelc}\left (b x\right )}{x^{3}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnelc(b*x)/x^3,x, algorithm="fricas")

[Out]

integral(fresnelc(b*x)/x^3, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\rm fresnelc}\left (b x\right )}{x^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnelc(b*x)/x^3,x, algorithm="giac")

[Out]

integrate(fresnelc(b*x)/x^3, x)

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maple [A]  time = 0.01, size = 43, normalized size = 0.98 \[ b^{2} \left (-\frac {\FresnelC \left (b x \right )}{2 b^{2} x^{2}}-\frac {\cos \left (\frac {b^{2} \pi \,x^{2}}{2}\right )}{2 b x}-\frac {\pi \,\mathrm {S}\left (b x \right )}{2}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(FresnelC(b*x)/x^3,x)

[Out]

b^2*(-1/2*FresnelC(b*x)/b^2/x^2-1/2/b/x*cos(1/2*b^2*Pi*x^2)-1/2*Pi*FresnelS(b*x))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\rm fresnelc}\left (b x\right )}{x^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnelc(b*x)/x^3,x, algorithm="maxima")

[Out]

integrate(fresnelc(b*x)/x^3, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {\mathrm {FresnelC}\left (b\,x\right )}{x^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(FresnelC(b*x)/x^3,x)

[Out]

int(FresnelC(b*x)/x^3, x)

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sympy [A]  time = 0.70, size = 51, normalized size = 1.16 \[ \frac {b \Gamma \left (- \frac {1}{4}\right ) \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{3}\left (\begin {matrix} - \frac {1}{4}, \frac {1}{4} \\ \frac {1}{2}, \frac {3}{4}, \frac {5}{4} \end {matrix}\middle | {- \frac {\pi ^{2} b^{4} x^{4}}{16}} \right )}}{16 x \Gamma \left (\frac {3}{4}\right ) \Gamma \left (\frac {5}{4}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(fresnelc(b*x)/x**3,x)

[Out]

b*gamma(-1/4)*gamma(1/4)*hyper((-1/4, 1/4), (1/2, 3/4, 5/4), -pi**2*b**4*x**4/16)/(16*x*gamma(3/4)*gamma(5/4))

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