3.83 \(\int e^{-b^2 x^2} \text {erf}(b x) \, dx\)

Optimal. Leaf size=18 \[ \frac {\sqrt {\pi } \text {erf}(b x)^2}{4 b} \]

[Out]

1/4*erf(b*x)^2*Pi^(1/2)/b

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Rubi [A]  time = 0.02, antiderivative size = 18, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {6373, 30} \[ \frac {\sqrt {\pi } \text {Erf}(b x)^2}{4 b} \]

Antiderivative was successfully verified.

[In]

Int[Erf[b*x]/E^(b^2*x^2),x]

[Out]

(Sqrt[Pi]*Erf[b*x]^2)/(4*b)

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 6373

Int[E^((c_.) + (d_.)*(x_)^2)*Erf[(b_.)*(x_)]^(n_.), x_Symbol] :> Dist[(E^c*Sqrt[Pi])/(2*b), Subst[Int[x^n, x],
x, Erf[b*x]], x] /; FreeQ[{b, c, d, n}, x] && EqQ[d, -b^2]

Rubi steps

\begin {align*} \int e^{-b^2 x^2} \text {erf}(b x) \, dx &=\frac {\sqrt {\pi } \operatorname {Subst}(\int x \, dx,x,\text {erf}(b x))}{2 b}\\ &=\frac {\sqrt {\pi } \text {erf}(b x)^2}{4 b}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 18, normalized size = 1.00 \[ \frac {\sqrt {\pi } \text {erf}(b x)^2}{4 b} \]

Antiderivative was successfully verified.

[In]

Integrate[Erf[b*x]/E^(b^2*x^2),x]

[Out]

(Sqrt[Pi]*Erf[b*x]^2)/(4*b)

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fricas [A]  time = 0.39, size = 14, normalized size = 0.78 \[ \frac {\sqrt {\pi } \operatorname {erf}\left (b x\right )^{2}}{4 \, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(erf(b*x)/exp(b^2*x^2),x, algorithm="fricas")

[Out]

1/4*sqrt(pi)*erf(b*x)^2/b

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \operatorname {erf}\left (b x\right ) e^{\left (-b^{2} x^{2}\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(erf(b*x)/exp(b^2*x^2),x, algorithm="giac")

[Out]

integrate(erf(b*x)*e^(-b^2*x^2), x)

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maple [A]  time = 0.04, size = 15, normalized size = 0.83 \[ \frac {\erf \left (b x \right )^{2} \sqrt {\pi }}{4 b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(erf(b*x)/exp(b^2*x^2),x)

[Out]

1/4*erf(b*x)^2*Pi^(1/2)/b

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maxima [A]  time = 0.31, size = 14, normalized size = 0.78 \[ \frac {\sqrt {\pi } \operatorname {erf}\left (b x\right )^{2}}{4 \, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(erf(b*x)/exp(b^2*x^2),x, algorithm="maxima")

[Out]

1/4*sqrt(pi)*erf(b*x)^2/b

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mupad [B]  time = 0.20, size = 41, normalized size = 2.28 \[ \frac {\sqrt {\pi }\,\mathrm {erf}\left (x\,\sqrt {b^2}\right )\,\mathrm {erf}\left (b\,x\right )}{2\,\sqrt {b^2}}-\frac {\sqrt {\pi }\,{\mathrm {erf}\left (x\,\sqrt {b^2}\right )}^2}{4\,b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(-b^2*x^2)*erf(b*x),x)

[Out]

(pi^(1/2)*erf(x*(b^2)^(1/2))*erf(b*x))/(2*(b^2)^(1/2)) - (pi^(1/2)*erf(x*(b^2)^(1/2))^2)/(4*b)

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sympy [A]  time = 0.99, size = 15, normalized size = 0.83 \[ \begin {cases} \frac {\sqrt {\pi } \operatorname {erf}^{2}{\left (b x \right )}}{4 b} & \text {for}\: b \neq 0 \\0 & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(erf(b*x)/exp(b**2*x**2),x)

[Out]

Piecewise((sqrt(pi)*erf(b*x)**2/(4*b), Ne(b, 0)), (0, True))

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