3.176 \(\int \frac {e^{c+b^2 x^2} \text {erfc}(b x)}{x^2} \, dx\)

Optimal. Leaf size=80 \[ -\frac {2 b^3 e^c x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{\sqrt {\pi }}-\frac {e^{b^2 x^2+c} \text {erfc}(b x)}{x}+\sqrt {\pi } b e^c \text {erfi}(b x)-\frac {2 b e^c \log (x)}{\sqrt {\pi }} \]

[Out]

-exp(b^2*x^2+c)*erfc(b*x)/x-2*b^3*exp(c)*x^2*HypergeometricPFQ([1, 1],[3/2, 2],b^2*x^2)/Pi^(1/2)-2*b*exp(c)*ln
(x)/Pi^(1/2)+b*exp(c)*erfi(b*x)*Pi^(1/2)

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Rubi [A]  time = 0.08, antiderivative size = 80, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.316, Rules used = {6392, 6377, 2204, 6376, 12, 29} \[ -\frac {2 b^3 e^c x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{\sqrt {\pi }}-\frac {e^{b^2 x^2+c} \text {Erfc}(b x)}{x}+\sqrt {\pi } b e^c \text {Erfi}(b x)-\frac {2 b e^c \log (x)}{\sqrt {\pi }} \]

Antiderivative was successfully verified.

[In]

Int[(E^(c + b^2*x^2)*Erfc[b*x])/x^2,x]

[Out]

-((E^(c + b^2*x^2)*Erfc[b*x])/x) + b*E^c*Sqrt[Pi]*Erfi[b*x] - (2*b^3*E^c*x^2*HypergeometricPFQ[{1, 1}, {3/2, 2
}, b^2*x^2])/Sqrt[Pi] - (2*b*E^c*Log[x])/Sqrt[Pi]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 29

Int[(x_)^(-1), x_Symbol] :> Simp[Log[x], x]

Rule 2204

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erfi[(c + d*x)*Rt[b*Log[F], 2
]])/(2*d*Rt[b*Log[F], 2]), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 6376

Int[E^((c_.) + (d_.)*(x_)^2)*Erf[(b_.)*(x_)], x_Symbol] :> Simp[(b*E^c*x^2*HypergeometricPFQ[{1, 1}, {3/2, 2},
b^2*x^2])/Sqrt[Pi], x] /; FreeQ[{b, c, d}, x] && EqQ[d, b^2]

Rule 6377

Int[E^((c_.) + (d_.)*(x_)^2)*Erfc[(b_.)*(x_)], x_Symbol] :> Int[E^(c + d*x^2), x] - Int[E^(c + d*x^2)*Erf[b*x]
, x] /; FreeQ[{b, c, d}, x] && EqQ[d, b^2]

Rule 6392

Int[E^((c_.) + (d_.)*(x_)^2)*Erfc[(a_.) + (b_.)*(x_)]*(x_)^(m_), x_Symbol] :> Simp[(x^(m + 1)*E^(c + d*x^2)*Er
fc[a + b*x])/(m + 1), x] + (-Dist[(2*d)/(m + 1), Int[x^(m + 2)*E^(c + d*x^2)*Erfc[a + b*x], x], x] + Dist[(2*b
)/((m + 1)*Sqrt[Pi]), Int[x^(m + 1)*E^(-a^2 + c - 2*a*b*x - (b^2 - d)*x^2), x], x]) /; FreeQ[{a, b, c, d}, x]
&& ILtQ[m, -1]

Rubi steps

\begin {align*} \int \frac {e^{c+b^2 x^2} \text {erfc}(b x)}{x^2} \, dx &=-\frac {e^{c+b^2 x^2} \text {erfc}(b x)}{x}+\left (2 b^2\right ) \int e^{c+b^2 x^2} \text {erfc}(b x) \, dx-\frac {(2 b) \int \frac {e^c}{x} \, dx}{\sqrt {\pi }}\\ &=-\frac {e^{c+b^2 x^2} \text {erfc}(b x)}{x}+\left (2 b^2\right ) \int e^{c+b^2 x^2} \, dx-\left (2 b^2\right ) \int e^{c+b^2 x^2} \text {erf}(b x) \, dx-\frac {\left (2 b e^c\right ) \int \frac {1}{x} \, dx}{\sqrt {\pi }}\\ &=-\frac {e^{c+b^2 x^2} \text {erfc}(b x)}{x}+b e^c \sqrt {\pi } \text {erfi}(b x)-\frac {2 b^3 e^c x^2 \, _2F_2\left (1,1;\frac {3}{2},2;b^2 x^2\right )}{\sqrt {\pi }}-\frac {2 b e^c \log (x)}{\sqrt {\pi }}\\ \end {align*}

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Mathematica [A]  time = 0.31, size = 99, normalized size = 1.24 \[ -\frac {e^c \left (-2 b^3 x^3 \, _2F_2\left (1,1;\frac {3}{2},2;-b^2 x^2\right )+\text {erf}(b x) \left (\pi b x \text {erfi}(b x)-\sqrt {\pi } e^{b^2 x^2}\right )+\sqrt {\pi } e^{b^2 x^2}-\pi b x \text {erfi}(b x)+2 b x \log (x)\right )}{\sqrt {\pi } x} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(E^(c + b^2*x^2)*Erfc[b*x])/x^2,x]

[Out]

-((E^c*(E^(b^2*x^2)*Sqrt[Pi] - b*Pi*x*Erfi[b*x] + Erf[b*x]*(-(E^(b^2*x^2)*Sqrt[Pi]) + b*Pi*x*Erfi[b*x]) - 2*b^
3*x^3*HypergeometricPFQ[{1, 1}, {3/2, 2}, -(b^2*x^2)] + 2*b*x*Log[x]))/(Sqrt[Pi]*x))

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fricas [F]  time = 0.41, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {{\left (\operatorname {erf}\left (b x\right ) - 1\right )} e^{\left (b^{2} x^{2} + c\right )}}{x^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(b^2*x^2+c)*erfc(b*x)/x^2,x, algorithm="fricas")

[Out]

integral(-(erf(b*x) - 1)*e^(b^2*x^2 + c)/x^2, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {erfc}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )}}{x^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(b^2*x^2+c)*erfc(b*x)/x^2,x, algorithm="giac")

[Out]

integrate(erfc(b*x)*e^(b^2*x^2 + c)/x^2, x)

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maple [F]  time = 0.09, size = 0, normalized size = 0.00 \[ \int \frac {{\mathrm e}^{b^{2} x^{2}+c} \mathrm {erfc}\left (b x \right )}{x^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(b^2*x^2+c)*erfc(b*x)/x^2,x)

[Out]

int(exp(b^2*x^2+c)*erfc(b*x)/x^2,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {erfc}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )}}{x^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(b^2*x^2+c)*erfc(b*x)/x^2,x, algorithm="maxima")

[Out]

integrate(erfc(b*x)*e^(b^2*x^2 + c)/x^2, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\mathrm {e}}^{b^2\,x^2+c}\,\mathrm {erfc}\left (b\,x\right )}{x^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((exp(c + b^2*x^2)*erfc(b*x))/x^2,x)

[Out]

int((exp(c + b^2*x^2)*erfc(b*x))/x^2, x)

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sympy [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: AttributeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(b**2*x**2+c)*erfc(b*x)/x**2,x)

[Out]

Exception raised: AttributeError

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