3.156 \(\int e^{c+d x^2} x^5 \text {erfc}(b x) \, dx\)

Optimal. Leaf size=283 \[ \frac {b e^c \text {erf}\left (x \sqrt {b^2-d}\right )}{d^3 \sqrt {b^2-d}}-\frac {b e^c \text {erf}\left (x \sqrt {b^2-d}\right )}{2 d^2 \left (b^2-d\right )^{3/2}}+\frac {b x e^{c-x^2 \left (b^2-d\right )}}{\sqrt {\pi } d^2 \left (b^2-d\right )}+\frac {3 b e^c \text {erf}\left (x \sqrt {b^2-d}\right )}{8 d \left (b^2-d\right )^{5/2}}-\frac {3 b x e^{c-x^2 \left (b^2-d\right )}}{4 \sqrt {\pi } d \left (b^2-d\right )^2}-\frac {b x^3 e^{c-x^2 \left (b^2-d\right )}}{2 \sqrt {\pi } d \left (b^2-d\right )}+\frac {\text {erfc}(b x) e^{c+d x^2}}{d^3}-\frac {x^2 \text {erfc}(b x) e^{c+d x^2}}{d^2}+\frac {x^4 \text {erfc}(b x) e^{c+d x^2}}{2 d} \]

[Out]

-1/2*b*exp(c)*erf(x*(b^2-d)^(1/2))/(b^2-d)^(3/2)/d^2+3/8*b*exp(c)*erf(x*(b^2-d)^(1/2))/(b^2-d)^(5/2)/d+exp(d*x
^2+c)*erfc(b*x)/d^3-exp(d*x^2+c)*x^2*erfc(b*x)/d^2+1/2*exp(d*x^2+c)*x^4*erfc(b*x)/d+b*exp(c)*erf(x*(b^2-d)^(1/
2))/d^3/(b^2-d)^(1/2)+b*exp(c-(b^2-d)*x^2)*x/(b^2-d)/d^2/Pi^(1/2)-3/4*b*exp(c-(b^2-d)*x^2)*x/(b^2-d)^2/d/Pi^(1
/2)-1/2*b*exp(c-(b^2-d)*x^2)*x^3/(b^2-d)/d/Pi^(1/2)

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Rubi [A]  time = 0.37, antiderivative size = 283, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 4, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {6386, 6383, 2205, 2212} \[ -\frac {b e^c \text {Erf}\left (x \sqrt {b^2-d}\right )}{2 d^2 \left (b^2-d\right )^{3/2}}+\frac {b e^c \text {Erf}\left (x \sqrt {b^2-d}\right )}{d^3 \sqrt {b^2-d}}+\frac {b x e^{c-x^2 \left (b^2-d\right )}}{\sqrt {\pi } d^2 \left (b^2-d\right )}+\frac {3 b e^c \text {Erf}\left (x \sqrt {b^2-d}\right )}{8 d \left (b^2-d\right )^{5/2}}-\frac {b x^3 e^{c-x^2 \left (b^2-d\right )}}{2 \sqrt {\pi } d \left (b^2-d\right )}-\frac {3 b x e^{c-x^2 \left (b^2-d\right )}}{4 \sqrt {\pi } d \left (b^2-d\right )^2}-\frac {x^2 \text {Erfc}(b x) e^{c+d x^2}}{d^2}+\frac {\text {Erfc}(b x) e^{c+d x^2}}{d^3}+\frac {x^4 \text {Erfc}(b x) e^{c+d x^2}}{2 d} \]

Antiderivative was successfully verified.

[In]

Int[E^(c + d*x^2)*x^5*Erfc[b*x],x]

[Out]

(b*E^(c - (b^2 - d)*x^2)*x)/((b^2 - d)*d^2*Sqrt[Pi]) - (3*b*E^(c - (b^2 - d)*x^2)*x)/(4*(b^2 - d)^2*d*Sqrt[Pi]
) - (b*E^(c - (b^2 - d)*x^2)*x^3)/(2*(b^2 - d)*d*Sqrt[Pi]) + (b*E^c*Erf[Sqrt[b^2 - d]*x])/(Sqrt[b^2 - d]*d^3)
- (b*E^c*Erf[Sqrt[b^2 - d]*x])/(2*(b^2 - d)^(3/2)*d^2) + (3*b*E^c*Erf[Sqrt[b^2 - d]*x])/(8*(b^2 - d)^(5/2)*d)
+ (E^(c + d*x^2)*Erfc[b*x])/d^3 - (E^(c + d*x^2)*x^2*Erfc[b*x])/d^2 + (E^(c + d*x^2)*x^4*Erfc[b*x])/(2*d)

Rule 2205

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erf[(c + d*x)*Rt[-(b*Log[F]),
2]])/(2*d*Rt[-(b*Log[F]), 2]), x] /; FreeQ[{F, a, b, c, d}, x] && NegQ[b]

Rule 2212

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[((c + d*x)^(m
- n + 1)*F^(a + b*(c + d*x)^n))/(b*d*n*Log[F]), x] - Dist[(m - n + 1)/(b*n*Log[F]), Int[(c + d*x)^(m - n)*F^(
a + b*(c + d*x)^n), x], x] /; FreeQ[{F, a, b, c, d}, x] && IntegerQ[(2*(m + 1))/n] && LtQ[0, (m + 1)/n, 5] &&
IntegerQ[n] && (LtQ[0, n, m + 1] || LtQ[m, n, 0])

Rule 6383

Int[E^((c_.) + (d_.)*(x_)^2)*Erfc[(a_.) + (b_.)*(x_)]*(x_), x_Symbol] :> Simp[(E^(c + d*x^2)*Erfc[a + b*x])/(2
*d), x] + Dist[b/(d*Sqrt[Pi]), Int[E^(-a^2 + c - 2*a*b*x - (b^2 - d)*x^2), x], x] /; FreeQ[{a, b, c, d}, x]

Rule 6386

Int[E^((c_.) + (d_.)*(x_)^2)*Erfc[(a_.) + (b_.)*(x_)]*(x_)^(m_), x_Symbol] :> Simp[(x^(m - 1)*E^(c + d*x^2)*Er
fc[a + b*x])/(2*d), x] + (-Dist[(m - 1)/(2*d), Int[x^(m - 2)*E^(c + d*x^2)*Erfc[a + b*x], x], x] + Dist[b/(d*S
qrt[Pi]), Int[x^(m - 1)*E^(-a^2 + c - 2*a*b*x - (b^2 - d)*x^2), x], x]) /; FreeQ[{a, b, c, d}, x] && IGtQ[m, 1
]

Rubi steps

\begin {align*} \int e^{c+d x^2} x^5 \text {erfc}(b x) \, dx &=\frac {e^{c+d x^2} x^4 \text {erfc}(b x)}{2 d}-\frac {2 \int e^{c+d x^2} x^3 \text {erfc}(b x) \, dx}{d}+\frac {b \int e^{c-\left (b^2-d\right ) x^2} x^4 \, dx}{d \sqrt {\pi }}\\ &=-\frac {b e^{c-\left (b^2-d\right ) x^2} x^3}{2 \left (b^2-d\right ) d \sqrt {\pi }}-\frac {e^{c+d x^2} x^2 \text {erfc}(b x)}{d^2}+\frac {e^{c+d x^2} x^4 \text {erfc}(b x)}{2 d}+\frac {2 \int e^{c+d x^2} x \text {erfc}(b x) \, dx}{d^2}-\frac {(2 b) \int e^{c-\left (b^2-d\right ) x^2} x^2 \, dx}{d^2 \sqrt {\pi }}+\frac {(3 b) \int e^{c+\left (-b^2+d\right ) x^2} x^2 \, dx}{2 \left (b^2-d\right ) d \sqrt {\pi }}\\ &=\frac {b e^{c-\left (b^2-d\right ) x^2} x}{\left (b^2-d\right ) d^2 \sqrt {\pi }}-\frac {3 b e^{c-\left (b^2-d\right ) x^2} x}{4 \left (b^2-d\right )^2 d \sqrt {\pi }}-\frac {b e^{c-\left (b^2-d\right ) x^2} x^3}{2 \left (b^2-d\right ) d \sqrt {\pi }}+\frac {e^{c+d x^2} \text {erfc}(b x)}{d^3}-\frac {e^{c+d x^2} x^2 \text {erfc}(b x)}{d^2}+\frac {e^{c+d x^2} x^4 \text {erfc}(b x)}{2 d}+\frac {(2 b) \int e^{c-\left (b^2-d\right ) x^2} \, dx}{d^3 \sqrt {\pi }}-\frac {b \int e^{c+\left (-b^2+d\right ) x^2} \, dx}{\left (b^2-d\right ) d^2 \sqrt {\pi }}+\frac {(3 b) \int e^{c+\left (-b^2+d\right ) x^2} \, dx}{4 \left (b^2-d\right )^2 d \sqrt {\pi }}\\ &=\frac {b e^{c-\left (b^2-d\right ) x^2} x}{\left (b^2-d\right ) d^2 \sqrt {\pi }}-\frac {3 b e^{c-\left (b^2-d\right ) x^2} x}{4 \left (b^2-d\right )^2 d \sqrt {\pi }}-\frac {b e^{c-\left (b^2-d\right ) x^2} x^3}{2 \left (b^2-d\right ) d \sqrt {\pi }}+\frac {b e^c \text {erf}\left (\sqrt {b^2-d} x\right )}{\sqrt {b^2-d} d^3}-\frac {b e^c \text {erf}\left (\sqrt {b^2-d} x\right )}{2 \left (b^2-d\right )^{3/2} d^2}+\frac {3 b e^c \text {erf}\left (\sqrt {b^2-d} x\right )}{8 \left (b^2-d\right )^{5/2} d}+\frac {e^{c+d x^2} \text {erfc}(b x)}{d^3}-\frac {e^{c+d x^2} x^2 \text {erfc}(b x)}{d^2}+\frac {e^{c+d x^2} x^4 \text {erfc}(b x)}{2 d}\\ \end {align*}

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Mathematica [A]  time = 0.45, size = 138, normalized size = 0.49 \[ \frac {e^c \left (\frac {2 b d x e^{x^2 \left (d-b^2\right )} \left (b^2 \left (4-2 d x^2\right )+d \left (2 d x^2-7\right )\right )}{\sqrt {\pi } \left (b^2-d\right )^2}+\frac {b \left (8 b^4-20 b^2 d+15 d^2\right ) \text {erfi}\left (x \sqrt {d-b^2}\right )}{\left (d-b^2\right )^{5/2}}+4 e^{d x^2} \left (d^2 x^4-2 d x^2+2\right ) \text {erfc}(b x)\right )}{8 d^3} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(c + d*x^2)*x^5*Erfc[b*x],x]

[Out]

(E^c*((2*b*d*E^((-b^2 + d)*x^2)*x*(b^2*(4 - 2*d*x^2) + d*(-7 + 2*d*x^2)))/((b^2 - d)^2*Sqrt[Pi]) + 4*E^(d*x^2)
*(2 - 2*d*x^2 + d^2*x^4)*Erfc[b*x] + (b*(8*b^4 - 20*b^2*d + 15*d^2)*Erfi[Sqrt[-b^2 + d]*x])/(-b^2 + d)^(5/2)))
/(8*d^3)

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fricas [A]  time = 0.44, size = 356, normalized size = 1.26 \[ \frac {\pi {\left (8 \, b^{5} - 20 \, b^{3} d + 15 \, b d^{2}\right )} \sqrt {b^{2} - d} \operatorname {erf}\left (\sqrt {b^{2} - d} x\right ) e^{c} - 2 \, \sqrt {\pi } {\left (2 \, {\left (b^{5} d^{2} - 2 \, b^{3} d^{3} + b d^{4}\right )} x^{3} - {\left (4 \, b^{5} d - 11 \, b^{3} d^{2} + 7 \, b d^{3}\right )} x\right )} e^{\left (-b^{2} x^{2} + d x^{2} + c\right )} + 4 \, {\left (\pi {\left (b^{6} d^{2} - 3 \, b^{4} d^{3} + 3 \, b^{2} d^{4} - d^{5}\right )} x^{4} - 2 \, \pi {\left (b^{6} d - 3 \, b^{4} d^{2} + 3 \, b^{2} d^{3} - d^{4}\right )} x^{2} + 2 \, \pi {\left (b^{6} - 3 \, b^{4} d + 3 \, b^{2} d^{2} - d^{3}\right )} - {\left (\pi {\left (b^{6} d^{2} - 3 \, b^{4} d^{3} + 3 \, b^{2} d^{4} - d^{5}\right )} x^{4} - 2 \, \pi {\left (b^{6} d - 3 \, b^{4} d^{2} + 3 \, b^{2} d^{3} - d^{4}\right )} x^{2} + 2 \, \pi {\left (b^{6} - 3 \, b^{4} d + 3 \, b^{2} d^{2} - d^{3}\right )}\right )} \operatorname {erf}\left (b x\right )\right )} e^{\left (d x^{2} + c\right )}}{8 \, \pi {\left (b^{6} d^{3} - 3 \, b^{4} d^{4} + 3 \, b^{2} d^{5} - d^{6}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(d*x^2+c)*x^5*erfc(b*x),x, algorithm="fricas")

[Out]

1/8*(pi*(8*b^5 - 20*b^3*d + 15*b*d^2)*sqrt(b^2 - d)*erf(sqrt(b^2 - d)*x)*e^c - 2*sqrt(pi)*(2*(b^5*d^2 - 2*b^3*
d^3 + b*d^4)*x^3 - (4*b^5*d - 11*b^3*d^2 + 7*b*d^3)*x)*e^(-b^2*x^2 + d*x^2 + c) + 4*(pi*(b^6*d^2 - 3*b^4*d^3 +
3*b^2*d^4 - d^5)*x^4 - 2*pi*(b^6*d - 3*b^4*d^2 + 3*b^2*d^3 - d^4)*x^2 + 2*pi*(b^6 - 3*b^4*d + 3*b^2*d^2 - d^3
) - (pi*(b^6*d^2 - 3*b^4*d^3 + 3*b^2*d^4 - d^5)*x^4 - 2*pi*(b^6*d - 3*b^4*d^2 + 3*b^2*d^3 - d^4)*x^2 + 2*pi*(b
^6 - 3*b^4*d + 3*b^2*d^2 - d^3))*erf(b*x))*e^(d*x^2 + c))/(pi*(b^6*d^3 - 3*b^4*d^4 + 3*b^2*d^5 - d^6))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{5} \operatorname {erfc}\left (b x\right ) e^{\left (d x^{2} + c\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(d*x^2+c)*x^5*erfc(b*x),x, algorithm="giac")

[Out]

integrate(x^5*erfc(b*x)*e^(d*x^2 + c), x)

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maple [A]  time = 0.08, size = 376, normalized size = 1.33 \[ \frac {\frac {{\mathrm e}^{c} \left (\frac {{\mathrm e}^{d \,x^{2}} b^{6} x^{4}}{2 d}-\frac {2 b^{2} \left (\frac {b^{4} x^{2} {\mathrm e}^{d \,x^{2}}}{2 d}-\frac {b^{4} {\mathrm e}^{d \,x^{2}}}{2 d^{2}}\right )}{d}\right )}{b^{5}}-\frac {\erf \left (b x \right ) {\mathrm e}^{c} \left (\frac {{\mathrm e}^{d \,x^{2}} b^{6} x^{4}}{2 d}-\frac {2 b^{2} \left (\frac {b^{4} x^{2} {\mathrm e}^{d \,x^{2}}}{2 d}-\frac {b^{4} {\mathrm e}^{d \,x^{2}}}{2 d^{2}}\right )}{d}\right )}{b^{5}}+\frac {{\mathrm e}^{c} \left (\frac {b^{2} \left (\frac {b^{3} x^{3} {\mathrm e}^{\left (-1+\frac {d}{b^{2}}\right ) b^{2} x^{2}}}{-2+\frac {2 d}{b^{2}}}-\frac {3 \left (\frac {b x \,{\mathrm e}^{\left (-1+\frac {d}{b^{2}}\right ) b^{2} x^{2}}}{-2+\frac {2 d}{b^{2}}}-\frac {\sqrt {\pi }\, \erf \left (\sqrt {1-\frac {d}{b^{2}}}\, b x \right )}{4 \left (-1+\frac {d}{b^{2}}\right ) \sqrt {1-\frac {d}{b^{2}}}}\right )}{2 \left (-1+\frac {d}{b^{2}}\right )}\right )}{d}+\frac {b^{6} \sqrt {\pi }\, \erf \left (\sqrt {1-\frac {d}{b^{2}}}\, b x \right )}{d^{3} \sqrt {1-\frac {d}{b^{2}}}}-\frac {2 b^{4} \left (\frac {b x \,{\mathrm e}^{\left (-1+\frac {d}{b^{2}}\right ) b^{2} x^{2}}}{-2+\frac {2 d}{b^{2}}}-\frac {\sqrt {\pi }\, \erf \left (\sqrt {1-\frac {d}{b^{2}}}\, b x \right )}{4 \left (-1+\frac {d}{b^{2}}\right ) \sqrt {1-\frac {d}{b^{2}}}}\right )}{d^{2}}\right )}{\sqrt {\pi }\, b^{5}}}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(d*x^2+c)*x^5*erfc(b*x),x)

[Out]

(1/b^5*exp(c)*(1/2*exp(d*x^2)*b^6*x^4/d-2/d*b^2*(1/2/d*b^4*x^2*exp(d*x^2)-1/2/d^2*b^4*exp(d*x^2)))-erf(b*x)/b^
5*exp(c)*(1/2*exp(d*x^2)*b^6*x^4/d-2/d*b^2*(1/2/d*b^4*x^2*exp(d*x^2)-1/2/d^2*b^4*exp(d*x^2)))+1/Pi^(1/2)/b^5*e
xp(c)*(1/d*b^2*(1/2/(-1+d/b^2)*b^3*x^3*exp((-1+d/b^2)*b^2*x^2)-3/2/(-1+d/b^2)*(1/2/(-1+d/b^2)*b*x*exp((-1+d/b^
2)*b^2*x^2)-1/4/(-1+d/b^2)*Pi^(1/2)/(1-d/b^2)^(1/2)*erf((1-d/b^2)^(1/2)*b*x)))+1/d^3*b^6*Pi^(1/2)/(1-d/b^2)^(1
/2)*erf((1-d/b^2)^(1/2)*b*x)-2/d^2*b^4*(1/2/(-1+d/b^2)*b*x*exp((-1+d/b^2)*b^2*x^2)-1/4/(-1+d/b^2)*Pi^(1/2)/(1-
d/b^2)^(1/2)*erf((1-d/b^2)^(1/2)*b*x))))/b

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{5} \operatorname {erfc}\left (b x\right ) e^{\left (d x^{2} + c\right )}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(d*x^2+c)*x^5*erfc(b*x),x, algorithm="maxima")

[Out]

integrate(x^5*erfc(b*x)*e^(d*x^2 + c), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int x^5\,{\mathrm {e}}^{d\,x^2+c}\,\mathrm {erfc}\left (b\,x\right ) \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5*exp(c + d*x^2)*erfc(b*x),x)

[Out]

int(x^5*exp(c + d*x^2)*erfc(b*x), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(d*x**2+c)*x**5*erfc(b*x),x)

[Out]

Timed out

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