3.154 \(\int \frac {e^{c-b^2 x^2}}{\text {erfc}(b x)^3} \, dx\)

Optimal. Leaf size=21 \[ \frac {\sqrt {\pi } e^c}{4 b \text {erfc}(b x)^2} \]

[Out]

1/4*exp(c)*Pi^(1/2)/b/erfc(b*x)^2

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Rubi [A]  time = 0.03, antiderivative size = 21, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {6374, 30} \[ \frac {\sqrt {\pi } e^c}{4 b \text {Erfc}(b x)^2} \]

Antiderivative was successfully verified.

[In]

Int[E^(c - b^2*x^2)/Erfc[b*x]^3,x]

[Out]

(E^c*Sqrt[Pi])/(4*b*Erfc[b*x]^2)

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 6374

Int[E^((c_.) + (d_.)*(x_)^2)*Erfc[(b_.)*(x_)]^(n_.), x_Symbol] :> -Dist[(E^c*Sqrt[Pi])/(2*b), Subst[Int[x^n, x
], x, Erfc[b*x]], x] /; FreeQ[{b, c, d, n}, x] && EqQ[d, -b^2]

Rubi steps

\begin {align*} \int \frac {e^{c-b^2 x^2}}{\text {erfc}(b x)^3} \, dx &=-\frac {\left (e^c \sqrt {\pi }\right ) \operatorname {Subst}\left (\int \frac {1}{x^3} \, dx,x,\text {erfc}(b x)\right )}{2 b}\\ &=\frac {e^c \sqrt {\pi }}{4 b \text {erfc}(b x)^2}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 21, normalized size = 1.00 \[ \frac {\sqrt {\pi } e^c}{4 b \text {erfc}(b x)^2} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(c - b^2*x^2)/Erfc[b*x]^3,x]

[Out]

(E^c*Sqrt[Pi])/(4*b*Erfc[b*x]^2)

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fricas [A]  time = 1.41, size = 26, normalized size = 1.24 \[ \frac {\sqrt {\pi } e^{c}}{4 \, {\left (b \operatorname {erf}\left (b x\right )^{2} - 2 \, b \operatorname {erf}\left (b x\right ) + b\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(-b^2*x^2+c)/erfc(b*x)^3,x, algorithm="fricas")

[Out]

1/4*sqrt(pi)*e^c/(b*erf(b*x)^2 - 2*b*erf(b*x) + b)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {e^{\left (-b^{2} x^{2} + c\right )}}{\operatorname {erfc}\left (b x\right )^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(-b^2*x^2+c)/erfc(b*x)^3,x, algorithm="giac")

[Out]

integrate(e^(-b^2*x^2 + c)/erfc(b*x)^3, x)

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maple [F]  time = 0.36, size = 0, normalized size = 0.00 \[ \int \frac {{\mathrm e}^{-b^{2} x^{2}+c}}{\mathrm {erfc}\left (b x \right )^{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(-b^2*x^2+c)/erfc(b*x)^3,x)

[Out]

int(exp(-b^2*x^2+c)/erfc(b*x)^3,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {e^{\left (-b^{2} x^{2} + c\right )}}{\operatorname {erfc}\left (b x\right )^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(-b^2*x^2+c)/erfc(b*x)^3,x, algorithm="maxima")

[Out]

integrate(e^(-b^2*x^2 + c)/erfc(b*x)^3, x)

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mupad [B]  time = 0.09, size = 16, normalized size = 0.76 \[ \frac {\sqrt {\pi }\,{\mathrm {e}}^c}{4\,b\,{\mathrm {erfc}\left (b\,x\right )}^2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(c - b^2*x^2)/erfc(b*x)^3,x)

[Out]

(pi^(1/2)*exp(c))/(4*b*erfc(b*x)^2)

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sympy [A]  time = 2.06, size = 22, normalized size = 1.05 \[ \begin {cases} \frac {\sqrt {\pi } e^{c}}{4 b \operatorname {erfc}^{2}{\left (b x \right )}} & \text {for}\: b \neq 0 \\x e^{c} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(-b**2*x**2+c)/erfc(b*x)**3,x)

[Out]

Piecewise((sqrt(pi)*exp(c)/(4*b*erfc(b*x)**2), Ne(b, 0)), (x*exp(c), True))

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