3.133 \(\int x^2 \text {erfc}(b x)^2 \, dx\)

Optimal. Leaf size=113 \[ -\frac {5 \text {erf}\left (\sqrt {2} b x\right )}{6 \sqrt {2 \pi } b^3}-\frac {2 x^2 e^{-b^2 x^2} \text {erfc}(b x)}{3 \sqrt {\pi } b}+\frac {x e^{-2 b^2 x^2}}{3 \pi b^2}-\frac {2 e^{-b^2 x^2} \text {erfc}(b x)}{3 \sqrt {\pi } b^3}+\frac {1}{3} x^3 \text {erfc}(b x)^2 \]

[Out]

1/3*x/b^2/exp(2*b^2*x^2)/Pi+1/3*x^3*erfc(b*x)^2-2/3*erfc(b*x)/b^3/exp(b^2*x^2)/Pi^(1/2)-2/3*x^2*erfc(b*x)/b/ex
p(b^2*x^2)/Pi^(1/2)-5/12*erf(b*x*2^(1/2))/b^3*2^(1/2)/Pi^(1/2)

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Rubi [A]  time = 0.13, antiderivative size = 113, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6365, 6386, 6383, 2205, 2212} \[ -\frac {5 \text {Erf}\left (\sqrt {2} b x\right )}{6 \sqrt {2 \pi } b^3}-\frac {2 x^2 e^{-b^2 x^2} \text {Erfc}(b x)}{3 \sqrt {\pi } b}-\frac {2 e^{-b^2 x^2} \text {Erfc}(b x)}{3 \sqrt {\pi } b^3}+\frac {x e^{-2 b^2 x^2}}{3 \pi b^2}+\frac {1}{3} x^3 \text {Erfc}(b x)^2 \]

Antiderivative was successfully verified.

[In]

Int[x^2*Erfc[b*x]^2,x]

[Out]

x/(3*b^2*E^(2*b^2*x^2)*Pi) - (5*Erf[Sqrt[2]*b*x])/(6*b^3*Sqrt[2*Pi]) - (2*Erfc[b*x])/(3*b^3*E^(b^2*x^2)*Sqrt[P
i]) - (2*x^2*Erfc[b*x])/(3*b*E^(b^2*x^2)*Sqrt[Pi]) + (x^3*Erfc[b*x]^2)/3

Rule 2205

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erf[(c + d*x)*Rt[-(b*Log[F]),
 2]])/(2*d*Rt[-(b*Log[F]), 2]), x] /; FreeQ[{F, a, b, c, d}, x] && NegQ[b]

Rule 2212

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[((c + d*x)^(m
 - n + 1)*F^(a + b*(c + d*x)^n))/(b*d*n*Log[F]), x] - Dist[(m - n + 1)/(b*n*Log[F]), Int[(c + d*x)^(m - n)*F^(
a + b*(c + d*x)^n), x], x] /; FreeQ[{F, a, b, c, d}, x] && IntegerQ[(2*(m + 1))/n] && LtQ[0, (m + 1)/n, 5] &&
IntegerQ[n] && (LtQ[0, n, m + 1] || LtQ[m, n, 0])

Rule 6365

Int[Erfc[(b_.)*(x_)]^2*(x_)^(m_.), x_Symbol] :> Simp[(x^(m + 1)*Erfc[b*x]^2)/(m + 1), x] + Dist[(4*b)/(Sqrt[Pi
]*(m + 1)), Int[(x^(m + 1)*Erfc[b*x])/E^(b^2*x^2), x], x] /; FreeQ[b, x] && (IGtQ[m, 0] || ILtQ[(m + 1)/2, 0])

Rule 6383

Int[E^((c_.) + (d_.)*(x_)^2)*Erfc[(a_.) + (b_.)*(x_)]*(x_), x_Symbol] :> Simp[(E^(c + d*x^2)*Erfc[a + b*x])/(2
*d), x] + Dist[b/(d*Sqrt[Pi]), Int[E^(-a^2 + c - 2*a*b*x - (b^2 - d)*x^2), x], x] /; FreeQ[{a, b, c, d}, x]

Rule 6386

Int[E^((c_.) + (d_.)*(x_)^2)*Erfc[(a_.) + (b_.)*(x_)]*(x_)^(m_), x_Symbol] :> Simp[(x^(m - 1)*E^(c + d*x^2)*Er
fc[a + b*x])/(2*d), x] + (-Dist[(m - 1)/(2*d), Int[x^(m - 2)*E^(c + d*x^2)*Erfc[a + b*x], x], x] + Dist[b/(d*S
qrt[Pi]), Int[x^(m - 1)*E^(-a^2 + c - 2*a*b*x - (b^2 - d)*x^2), x], x]) /; FreeQ[{a, b, c, d}, x] && IGtQ[m, 1
]

Rubi steps

\begin {align*} \int x^2 \text {erfc}(b x)^2 \, dx &=\frac {1}{3} x^3 \text {erfc}(b x)^2+\frac {(4 b) \int e^{-b^2 x^2} x^3 \text {erfc}(b x) \, dx}{3 \sqrt {\pi }}\\ &=-\frac {2 e^{-b^2 x^2} x^2 \text {erfc}(b x)}{3 b \sqrt {\pi }}+\frac {1}{3} x^3 \text {erfc}(b x)^2-\frac {4 \int e^{-2 b^2 x^2} x^2 \, dx}{3 \pi }+\frac {4 \int e^{-b^2 x^2} x \text {erfc}(b x) \, dx}{3 b \sqrt {\pi }}\\ &=\frac {e^{-2 b^2 x^2} x}{3 b^2 \pi }-\frac {2 e^{-b^2 x^2} \text {erfc}(b x)}{3 b^3 \sqrt {\pi }}-\frac {2 e^{-b^2 x^2} x^2 \text {erfc}(b x)}{3 b \sqrt {\pi }}+\frac {1}{3} x^3 \text {erfc}(b x)^2-\frac {\int e^{-2 b^2 x^2} \, dx}{3 b^2 \pi }-\frac {4 \int e^{-2 b^2 x^2} \, dx}{3 b^2 \pi }\\ &=\frac {e^{-2 b^2 x^2} x}{3 b^2 \pi }-\frac {\sqrt {\frac {2}{\pi }} \text {erf}\left (\sqrt {2} b x\right )}{3 b^3}-\frac {\text {erf}\left (\sqrt {2} b x\right )}{6 b^3 \sqrt {2 \pi }}-\frac {2 e^{-b^2 x^2} \text {erfc}(b x)}{3 b^3 \sqrt {\pi }}-\frac {2 e^{-b^2 x^2} x^2 \text {erfc}(b x)}{3 b \sqrt {\pi }}+\frac {1}{3} x^3 \text {erfc}(b x)^2\\ \end {align*}

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Mathematica [A]  time = 0.10, size = 88, normalized size = 0.78 \[ \frac {4 \pi b^3 x^3 \text {erfc}(b x)^2-8 \sqrt {\pi } e^{-b^2 x^2} \left (b^2 x^2+1\right ) \text {erfc}(b x)+4 b x e^{-2 b^2 x^2}-5 \sqrt {2 \pi } \text {erf}\left (\sqrt {2} b x\right )}{12 \pi b^3} \]

Antiderivative was successfully verified.

[In]

Integrate[x^2*Erfc[b*x]^2,x]

[Out]

((4*b*x)/E^(2*b^2*x^2) - 5*Sqrt[2*Pi]*Erf[Sqrt[2]*b*x] - (8*Sqrt[Pi]*(1 + b^2*x^2)*Erfc[b*x])/E^(b^2*x^2) + 4*
b^3*Pi*x^3*Erfc[b*x]^2)/(12*b^3*Pi)

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fricas [A]  time = 0.39, size = 123, normalized size = 1.09 \[ \frac {4 \, \pi b^{4} x^{3} \operatorname {erf}\left (b x\right )^{2} - 8 \, \pi b^{4} x^{3} \operatorname {erf}\left (b x\right ) + 4 \, \pi b^{4} x^{3} + 4 \, b^{2} x e^{\left (-2 \, b^{2} x^{2}\right )} - 5 \, \sqrt {2} \sqrt {\pi } \sqrt {b^{2}} \operatorname {erf}\left (\sqrt {2} \sqrt {b^{2}} x\right ) - 8 \, \sqrt {\pi } {\left (b^{3} x^{2} - {\left (b^{3} x^{2} + b\right )} \operatorname {erf}\left (b x\right ) + b\right )} e^{\left (-b^{2} x^{2}\right )}}{12 \, \pi b^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*erfc(b*x)^2,x, algorithm="fricas")

[Out]

1/12*(4*pi*b^4*x^3*erf(b*x)^2 - 8*pi*b^4*x^3*erf(b*x) + 4*pi*b^4*x^3 + 4*b^2*x*e^(-2*b^2*x^2) - 5*sqrt(2)*sqrt
(pi)*sqrt(b^2)*erf(sqrt(2)*sqrt(b^2)*x) - 8*sqrt(pi)*(b^3*x^2 - (b^3*x^2 + b)*erf(b*x) + b)*e^(-b^2*x^2))/(pi*
b^4)

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giac [A]  time = 0.69, size = 151, normalized size = 1.34 \[ \frac {1}{3} \, x^{3} \operatorname {erf}\left (b x\right )^{2} - \frac {2}{3} \, x^{3} \operatorname {erf}\left (b x\right ) + \frac {1}{3} \, x^{3} + \frac {b {\left (\frac {8 \, {\left (b^{2} x^{2} + 1\right )} \operatorname {erf}\left (b x\right ) e^{\left (-b^{2} x^{2}\right )}}{b^{4}} + \frac {b^{2} {\left (\frac {4 \, x e^{\left (-2 \, b^{2} x^{2}\right )}}{b^{2}} + \frac {\sqrt {2} \sqrt {\pi } \operatorname {erf}\left (-\sqrt {2} b x\right )}{b^{3}}\right )} + \frac {4 \, \sqrt {2} \sqrt {\pi } \operatorname {erf}\left (-\sqrt {2} b x\right )}{b}}{\sqrt {\pi } b^{3}}\right )}}{12 \, \sqrt {\pi }} - \frac {2 \, {\left (b^{2} x^{2} + 1\right )} e^{\left (-b^{2} x^{2}\right )}}{3 \, \sqrt {\pi } b^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*erfc(b*x)^2,x, algorithm="giac")

[Out]

1/3*x^3*erf(b*x)^2 - 2/3*x^3*erf(b*x) + 1/3*x^3 + 1/12*b*(8*(b^2*x^2 + 1)*erf(b*x)*e^(-b^2*x^2)/b^4 + (b^2*(4*
x*e^(-2*b^2*x^2)/b^2 + sqrt(2)*sqrt(pi)*erf(-sqrt(2)*b*x)/b^3) + 4*sqrt(2)*sqrt(pi)*erf(-sqrt(2)*b*x)/b)/(sqrt
(pi)*b^3))/sqrt(pi) - 2/3*(b^2*x^2 + 1)*e^(-b^2*x^2)/(sqrt(pi)*b^3)

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maple [A]  time = 0.01, size = 151, normalized size = 1.34 \[ \frac {\frac {b^{3} x^{3}}{3}-\frac {2 b^{3} x^{3} \erf \left (b x \right )}{3}+\frac {-\frac {2 \,{\mathrm e}^{-b^{2} x^{2}} b^{2} x^{2}}{3}-\frac {2 \,{\mathrm e}^{-b^{2} x^{2}}}{3}}{\sqrt {\pi }}+\frac {b^{3} x^{3} \erf \left (b x \right )^{2}}{3}-\frac {4 \erf \left (b x \right ) \left (-\frac {{\mathrm e}^{-b^{2} x^{2}} b^{2} x^{2}}{2}-\frac {{\mathrm e}^{-b^{2} x^{2}}}{2}\right )}{3 \sqrt {\pi }}+\frac {-\frac {5 \sqrt {2}\, \sqrt {\pi }\, \erf \left (b x \sqrt {2}\right )}{12}+\frac {{\mathrm e}^{-2 b^{2} x^{2}} b x}{3}}{\pi }}{b^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*erfc(b*x)^2,x)

[Out]

1/b^3*(1/3*b^3*x^3-2/3*b^3*x^3*erf(b*x)+4/3/Pi^(1/2)*(-1/2/exp(b^2*x^2)*b^2*x^2-1/2/exp(b^2*x^2))+1/3*b^3*x^3*
erf(b*x)^2-4/3*erf(b*x)/Pi^(1/2)*(-1/2/exp(b^2*x^2)*b^2*x^2-1/2/exp(b^2*x^2))+4/3/Pi*(-5/16*2^(1/2)*Pi^(1/2)*e
rf(b*x*2^(1/2))+1/4/exp(b^2*x^2)^2*b*x))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{2} \operatorname {erfc}\left (b x\right )^{2}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*erfc(b*x)^2,x, algorithm="maxima")

[Out]

integrate(x^2*erfc(b*x)^2, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int x^2\,{\mathrm {erfc}\left (b\,x\right )}^2 \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*erfc(b*x)^2,x)

[Out]

int(x^2*erfc(b*x)^2, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{2} \operatorname {erfc}^{2}{\left (b x \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*erfc(b*x)**2,x)

[Out]

Integral(x**2*erfc(b*x)**2, x)

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