3.120 \(\int (c+d x) \text {erfc}(a+b x) \, dx\)

Optimal. Leaf size=119 \[ \frac {(b c-a d)^2 \text {erf}(a+b x)}{2 b^2 d}-\frac {e^{-(a+b x)^2} (b c-a d)}{\sqrt {\pi } b^2}+\frac {d \text {erf}(a+b x)}{4 b^2}-\frac {d e^{-(a+b x)^2} (a+b x)}{2 \sqrt {\pi } b^2}+\frac {(c+d x)^2 \text {erfc}(a+b x)}{2 d} \]

[Out]

1/4*d*erf(b*x+a)/b^2+1/2*(-a*d+b*c)^2*erf(b*x+a)/b^2/d+1/2*(d*x+c)^2*erfc(b*x+a)/d+(a*d-b*c)/b^2/exp((b*x+a)^2
)/Pi^(1/2)-1/2*d*(b*x+a)/b^2/exp((b*x+a)^2)/Pi^(1/2)

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Rubi [A]  time = 0.12, antiderivative size = 119, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {6362, 2226, 2205, 2209, 2212} \[ \frac {(b c-a d)^2 \text {Erf}(a+b x)}{2 b^2 d}-\frac {e^{-(a+b x)^2} (b c-a d)}{\sqrt {\pi } b^2}+\frac {d \text {Erf}(a+b x)}{4 b^2}-\frac {d e^{-(a+b x)^2} (a+b x)}{2 \sqrt {\pi } b^2}+\frac {(c+d x)^2 \text {Erfc}(a+b x)}{2 d} \]

Antiderivative was successfully verified.

[In]

Int[(c + d*x)*Erfc[a + b*x],x]

[Out]

-((b*c - a*d)/(b^2*E^(a + b*x)^2*Sqrt[Pi])) - (d*(a + b*x))/(2*b^2*E^(a + b*x)^2*Sqrt[Pi]) + (d*Erf[a + b*x])/
(4*b^2) + ((b*c - a*d)^2*Erf[a + b*x])/(2*b^2*d) + ((c + d*x)^2*Erfc[a + b*x])/(2*d)

Rule 2205

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erf[(c + d*x)*Rt[-(b*Log[F]),
2]])/(2*d*Rt[-(b*Log[F]), 2]), x] /; FreeQ[{F, a, b, c, d}, x] && NegQ[b]

Rule 2209

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Simp[((e + f*x)^n*
F^(a + b*(c + d*x)^n))/(b*f*n*(c + d*x)^n*Log[F]), x] /; FreeQ[{F, a, b, c, d, e, f, n}, x] && EqQ[m, n - 1] &
& EqQ[d*e - c*f, 0]

Rule 2212

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[((c + d*x)^(m
- n + 1)*F^(a + b*(c + d*x)^n))/(b*d*n*Log[F]), x] - Dist[(m - n + 1)/(b*n*Log[F]), Int[(c + d*x)^(m - n)*F^(
a + b*(c + d*x)^n), x], x] /; FreeQ[{F, a, b, c, d}, x] && IntegerQ[(2*(m + 1))/n] && LtQ[0, (m + 1)/n, 5] &&
IntegerQ[n] && (LtQ[0, n, m + 1] || LtQ[m, n, 0])

Rule 2226

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^(n_))*(u_), x_Symbol] :> Int[ExpandLinearProduct[F^(a + b*(c + d*
x)^n), u, c, d, x], x] /; FreeQ[{F, a, b, c, d, n}, x] && PolynomialQ[u, x]

Rule 6362

Int[Erfc[(a_.) + (b_.)*(x_)]*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Simp[((c + d*x)^(m + 1)*Erfc[a + b*x])/(
d*(m + 1)), x] + Dist[(2*b)/(Sqrt[Pi]*d*(m + 1)), Int[(c + d*x)^(m + 1)/E^(a + b*x)^2, x], x] /; FreeQ[{a, b,
c, d, m}, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int (c+d x) \text {erfc}(a+b x) \, dx &=\frac {(c+d x)^2 \text {erfc}(a+b x)}{2 d}+\frac {b \int e^{-(a+b x)^2} (c+d x)^2 \, dx}{d \sqrt {\pi }}\\ &=\frac {(c+d x)^2 \text {erfc}(a+b x)}{2 d}+\frac {b \int \left (\frac {(b c-a d)^2 e^{-(a+b x)^2}}{b^2}+\frac {2 d (b c-a d) e^{-(a+b x)^2} (a+b x)}{b^2}+\frac {d^2 e^{-(a+b x)^2} (a+b x)^2}{b^2}\right ) \, dx}{d \sqrt {\pi }}\\ &=\frac {(c+d x)^2 \text {erfc}(a+b x)}{2 d}+\frac {d \int e^{-(a+b x)^2} (a+b x)^2 \, dx}{b \sqrt {\pi }}+\frac {(2 (b c-a d)) \int e^{-(a+b x)^2} (a+b x) \, dx}{b \sqrt {\pi }}+\frac {(b c-a d)^2 \int e^{-(a+b x)^2} \, dx}{b d \sqrt {\pi }}\\ &=-\frac {(b c-a d) e^{-(a+b x)^2}}{b^2 \sqrt {\pi }}-\frac {d e^{-(a+b x)^2} (a+b x)}{2 b^2 \sqrt {\pi }}+\frac {(b c-a d)^2 \text {erf}(a+b x)}{2 b^2 d}+\frac {(c+d x)^2 \text {erfc}(a+b x)}{2 d}+\frac {d \int e^{-(a+b x)^2} \, dx}{2 b \sqrt {\pi }}\\ &=-\frac {(b c-a d) e^{-(a+b x)^2}}{b^2 \sqrt {\pi }}-\frac {d e^{-(a+b x)^2} (a+b x)}{2 b^2 \sqrt {\pi }}+\frac {d \text {erf}(a+b x)}{4 b^2}+\frac {(b c-a d)^2 \text {erf}(a+b x)}{2 b^2 d}+\frac {(c+d x)^2 \text {erfc}(a+b x)}{2 d}\\ \end {align*}

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Mathematica [A]  time = 0.15, size = 104, normalized size = 0.87 \[ \frac {e^{-(a+b x)^2} \left (\sqrt {\pi } e^{(a+b x)^2} \left (2 a^2 d-4 a b c+d\right ) \text {erf}(a+b x)+2 \sqrt {\pi } b^2 x e^{(a+b x)^2} (2 c+d x) \text {erfc}(a+b x)+2 a d-4 b c-2 b d x\right )}{4 \sqrt {\pi } b^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(c + d*x)*Erfc[a + b*x],x]

[Out]

(-4*b*c + 2*a*d - 2*b*d*x + (-4*a*b*c + d + 2*a^2*d)*E^(a + b*x)^2*Sqrt[Pi]*Erf[a + b*x] + 2*b^2*E^(a + b*x)^2
*Sqrt[Pi]*x*(2*c + d*x)*Erfc[a + b*x])/(4*b^2*E^(a + b*x)^2*Sqrt[Pi])

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fricas [A]  time = 0.53, size = 110, normalized size = 0.92 \[ \frac {2 \, \pi b^{2} d x^{2} + 4 \, \pi b^{2} c x - 2 \, \sqrt {\pi } {\left (b d x + 2 \, b c - a d\right )} e^{\left (-b^{2} x^{2} - 2 \, a b x - a^{2}\right )} - {\left (2 \, \pi b^{2} d x^{2} + 4 \, \pi b^{2} c x + \pi {\left (4 \, a b c - {\left (2 \, a^{2} + 1\right )} d\right )}\right )} \operatorname {erf}\left (b x + a\right )}{4 \, \pi b^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)*erfc(b*x+a),x, algorithm="fricas")

[Out]

1/4*(2*pi*b^2*d*x^2 + 4*pi*b^2*c*x - 2*sqrt(pi)*(b*d*x + 2*b*c - a*d)*e^(-b^2*x^2 - 2*a*b*x - a^2) - (2*pi*b^2
*d*x^2 + 4*pi*b^2*c*x + pi*(4*a*b*c - (2*a^2 + 1)*d))*erf(b*x + a))/(pi*b^2)

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giac [A]  time = 1.30, size = 158, normalized size = 1.33 \[ \frac {1}{2} \, d x^{2} - {\left (x \operatorname {erf}\left (b x + a\right ) - \frac {\frac {\sqrt {\pi } a \operatorname {erf}\left (-b {\left (x + \frac {a}{b}\right )}\right )}{b} - \frac {e^{\left (-b^{2} x^{2} - 2 \, a b x - a^{2}\right )}}{b}}{\sqrt {\pi }}\right )} c - \frac {1}{4} \, {\left (2 \, x^{2} \operatorname {erf}\left (b x + a\right ) + \frac {\frac {\sqrt {\pi } {\left (2 \, a^{2} + 1\right )} \operatorname {erf}\left (-b {\left (x + \frac {a}{b}\right )}\right )}{b} + \frac {2 \, {\left (b {\left (x + \frac {a}{b}\right )} - 2 \, a\right )} e^{\left (-b^{2} x^{2} - 2 \, a b x - a^{2}\right )}}{b}}{\sqrt {\pi } b}\right )} d + c x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)*erfc(b*x+a),x, algorithm="giac")

[Out]

1/2*d*x^2 - (x*erf(b*x + a) - (sqrt(pi)*a*erf(-b*(x + a/b))/b - e^(-b^2*x^2 - 2*a*b*x - a^2)/b)/sqrt(pi))*c -
1/4*(2*x^2*erf(b*x + a) + (sqrt(pi)*(2*a^2 + 1)*erf(-b*(x + a/b))/b + 2*(b*(x + a/b) - 2*a)*e^(-b^2*x^2 - 2*a*
b*x - a^2)/b)/(sqrt(pi)*b))*d + c*x

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maple [A]  time = 0.00, size = 122, normalized size = 1.03 \[ \frac {\frac {\mathrm {erfc}\left (b x +a \right ) \left (b x +a \right )^{2} d}{2 b}-\frac {\mathrm {erfc}\left (b x +a \right ) a d \left (b x +a \right )}{b}+\mathrm {erfc}\left (b x +a \right ) c \left (b x +a \right )+\frac {d \left (-\frac {\left (b x +a \right ) {\mathrm e}^{-\left (b x +a \right )^{2}}}{2}+\frac {\sqrt {\pi }\, \erf \left (b x +a \right )}{4}\right )+a d \,{\mathrm e}^{-\left (b x +a \right )^{2}}-{\mathrm e}^{-\left (b x +a \right )^{2}} b c}{\sqrt {\pi }\, b}}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*x+c)*erfc(b*x+a),x)

[Out]

1/b*(1/2/b*erfc(b*x+a)*(b*x+a)^2*d-1/b*erfc(b*x+a)*a*d*(b*x+a)+erfc(b*x+a)*c*(b*x+a)+1/Pi^(1/2)/b*(d*(-1/2*(b*
x+a)/exp((b*x+a)^2)+1/4*Pi^(1/2)*erf(b*x+a))+a*d/exp((b*x+a)^2)-b*c/exp((b*x+a)^2)))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (d x + c\right )} \operatorname {erfc}\left (b x + a\right )\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)*erfc(b*x+a),x, algorithm="maxima")

[Out]

integrate((d*x + c)*erfc(b*x + a), x)

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mupad [B]  time = 0.22, size = 119, normalized size = 1.00 \[ c\,x\,\mathrm {erfc}\left (a+b\,x\right )-{\mathrm {e}}^{-a^2-2\,a\,b\,x-b^2\,x^2}\,\left (\frac {c}{b\,\sqrt {\pi }}-\frac {a\,d}{2\,b^2\,\sqrt {\pi }}\right )-\frac {\mathrm {erfc}\left (a+b\,x\right )\,\left (\frac {d\,a^2}{2}-b\,c\,a+\frac {d}{4}\right )}{b^2}+\frac {d\,x^2\,\mathrm {erfc}\left (a+b\,x\right )}{2}-\frac {d\,x\,{\mathrm {e}}^{-a^2-2\,a\,b\,x-b^2\,x^2}}{2\,b\,\sqrt {\pi }} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(erfc(a + b*x)*(c + d*x),x)

[Out]

c*x*erfc(a + b*x) - exp(- a^2 - b^2*x^2 - 2*a*b*x)*(c/(b*pi^(1/2)) - (a*d)/(2*b^2*pi^(1/2))) - (erfc(a + b*x)*
(d/4 + (a^2*d)/2 - a*b*c))/b^2 + (d*x^2*erfc(a + b*x))/2 - (d*x*exp(- a^2 - b^2*x^2 - 2*a*b*x))/(2*b*pi^(1/2))

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sympy [A]  time = 1.45, size = 178, normalized size = 1.50 \[ \begin {cases} - \frac {a^{2} d \operatorname {erfc}{\left (a + b x \right )}}{2 b^{2}} + \frac {a c \operatorname {erfc}{\left (a + b x \right )}}{b} + \frac {a d e^{- a^{2}} e^{- b^{2} x^{2}} e^{- 2 a b x}}{2 \sqrt {\pi } b^{2}} + c x \operatorname {erfc}{\left (a + b x \right )} + \frac {d x^{2} \operatorname {erfc}{\left (a + b x \right )}}{2} - \frac {c e^{- a^{2}} e^{- b^{2} x^{2}} e^{- 2 a b x}}{\sqrt {\pi } b} - \frac {d x e^{- a^{2}} e^{- b^{2} x^{2}} e^{- 2 a b x}}{2 \sqrt {\pi } b} - \frac {d \operatorname {erfc}{\left (a + b x \right )}}{4 b^{2}} & \text {for}\: b \neq 0 \\\left (c x + \frac {d x^{2}}{2}\right ) \operatorname {erfc}{\relax (a )} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)*erfc(b*x+a),x)

[Out]

Piecewise((-a**2*d*erfc(a + b*x)/(2*b**2) + a*c*erfc(a + b*x)/b + a*d*exp(-a**2)*exp(-b**2*x**2)*exp(-2*a*b*x)
/(2*sqrt(pi)*b**2) + c*x*erfc(a + b*x) + d*x**2*erfc(a + b*x)/2 - c*exp(-a**2)*exp(-b**2*x**2)*exp(-2*a*b*x)/(
sqrt(pi)*b) - d*x*exp(-a**2)*exp(-b**2*x**2)*exp(-2*a*b*x)/(2*sqrt(pi)*b) - d*erfc(a + b*x)/(4*b**2), Ne(b, 0)
), ((c*x + d*x**2/2)*erfc(a), True))

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