3.304 \(\int e^{2 \coth ^{-1}(a x)} \sqrt {c-a c x} \, dx\)

Optimal. Leaf size=38 \[ \frac {4 \sqrt {c-a c x}}{a}-\frac {2 (c-a c x)^{3/2}}{3 a c} \]

[Out]

-2/3*(-a*c*x+c)^(3/2)/a/c+4*(-a*c*x+c)^(1/2)/a

________________________________________________________________________________________

Rubi [A]  time = 0.08, antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {6167, 6130, 21, 43} \[ \frac {4 \sqrt {c-a c x}}{a}-\frac {2 (c-a c x)^{3/2}}{3 a c} \]

Antiderivative was successfully verified.

[In]

Int[E^(2*ArcCoth[a*x])*Sqrt[c - a*c*x],x]

[Out]

(4*Sqrt[c - a*c*x])/a - (2*(c - a*c*x)^(3/2))/(3*a*c)

Rule 21

Int[(u_.)*((a_) + (b_.)*(v_))^(m_.)*((c_) + (d_.)*(v_))^(n_.), x_Symbol] :> Dist[(b/d)^m, Int[u*(c + d*v)^(m +
 n), x], x] /; FreeQ[{a, b, c, d, n}, x] && EqQ[b*c - a*d, 0] && IntegerQ[m] && ( !IntegerQ[n] || SimplerQ[c +
 d*x, a + b*x])

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 6130

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_))^(p_.), x_Symbol] :> Int[(u*(c + d*x)^p*(1 + a*x)^(
n/2))/(1 - a*x)^(n/2), x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] &&  !(IntegerQ[p] || GtQ[c, 0]
)

Rule 6167

Int[E^(ArcCoth[(a_.)*(x_)]*(n_))*(u_.), x_Symbol] :> Dist[(-1)^(n/2), Int[u*E^(n*ArcTanh[a*x]), x], x] /; Free
Q[a, x] && IntegerQ[n/2]

Rubi steps

\begin {align*} \int e^{2 \coth ^{-1}(a x)} \sqrt {c-a c x} \, dx &=-\int e^{2 \tanh ^{-1}(a x)} \sqrt {c-a c x} \, dx\\ &=-\int \frac {(1+a x) \sqrt {c-a c x}}{1-a x} \, dx\\ &=-\left (c \int \frac {1+a x}{\sqrt {c-a c x}} \, dx\right )\\ &=-\left (c \int \left (\frac {2}{\sqrt {c-a c x}}-\frac {\sqrt {c-a c x}}{c}\right ) \, dx\right )\\ &=\frac {4 \sqrt {c-a c x}}{a}-\frac {2 (c-a c x)^{3/2}}{3 a c}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.03, size = 23, normalized size = 0.61 \[ \frac {2 (a x+5) \sqrt {c-a c x}}{3 a} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(2*ArcCoth[a*x])*Sqrt[c - a*c*x],x]

[Out]

(2*(5 + a*x)*Sqrt[c - a*c*x])/(3*a)

________________________________________________________________________________________

fricas [A]  time = 0.46, size = 19, normalized size = 0.50 \[ \frac {2 \, \sqrt {-a c x + c} {\left (a x + 5\right )}}{3 \, a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x-1)*(a*x+1)*(-a*c*x+c)^(1/2),x, algorithm="fricas")

[Out]

2/3*sqrt(-a*c*x + c)*(a*x + 5)/a

________________________________________________________________________________________

giac [A]  time = 0.14, size = 44, normalized size = 1.16 \[ \frac {2 \, {\left (3 \, \sqrt {-a c x + c} - \frac {{\left (-a c x + c\right )}^{\frac {3}{2}} - 3 \, \sqrt {-a c x + c} c}{c}\right )}}{3 \, a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x-1)*(a*x+1)*(-a*c*x+c)^(1/2),x, algorithm="giac")

[Out]

2/3*(3*sqrt(-a*c*x + c) - ((-a*c*x + c)^(3/2) - 3*sqrt(-a*c*x + c)*c)/c)/a

________________________________________________________________________________________

maple [A]  time = 0.03, size = 20, normalized size = 0.53 \[ \frac {2 \sqrt {-a c x +c}\, \left (a x +5\right )}{3 a} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)/(a*x-1)*(-a*c*x+c)^(1/2),x)

[Out]

2/3*(-a*c*x+c)^(1/2)*(a*x+5)/a

________________________________________________________________________________________

maxima [A]  time = 0.32, size = 30, normalized size = 0.79 \[ -\frac {2 \, {\left ({\left (-a c x + c\right )}^{\frac {3}{2}} - 6 \, \sqrt {-a c x + c} c\right )}}{3 \, a c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x-1)*(a*x+1)*(-a*c*x+c)^(1/2),x, algorithm="maxima")

[Out]

-2/3*((-a*c*x + c)^(3/2) - 6*sqrt(-a*c*x + c)*c)/(a*c)

________________________________________________________________________________________

mupad [B]  time = 0.00, size = 32, normalized size = 0.84 \[ \frac {4\,\sqrt {c-a\,c\,x}}{a}-\frac {2\,{\left (c-a\,c\,x\right )}^{3/2}}{3\,a\,c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((c - a*c*x)^(1/2)*(a*x + 1))/(a*x - 1),x)

[Out]

(4*(c - a*c*x)^(1/2))/a - (2*(c - a*c*x)^(3/2))/(3*a*c)

________________________________________________________________________________________

sympy [A]  time = 2.90, size = 31, normalized size = 0.82 \[ - \frac {2 \left (- 2 c \sqrt {- a c x + c} + \frac {\left (- a c x + c\right )^{\frac {3}{2}}}{3}\right )}{a c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x-1)*(a*x+1)*(-a*c*x+c)**(1/2),x)

[Out]

-2*(-2*c*sqrt(-a*c*x + c) + (-a*c*x + c)**(3/2)/3)/(a*c)

________________________________________________________________________________________