3.169 \(\int e^{2 \coth ^{-1}(a x)} (c-a c x)^4 \, dx\)

Optimal. Leaf size=37 \[ \frac {c^4 (1-a x)^4}{2 a}-\frac {c^4 (1-a x)^5}{5 a} \]

[Out]

1/2*c^4*(-a*x+1)^4/a-1/5*c^4*(-a*x+1)^5/a

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Rubi [A]  time = 0.06, antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {6167, 6129, 43} \[ \frac {c^4 (1-a x)^4}{2 a}-\frac {c^4 (1-a x)^5}{5 a} \]

Antiderivative was successfully verified.

[In]

Int[E^(2*ArcCoth[a*x])*(c - a*c*x)^4,x]

[Out]

(c^4*(1 - a*x)^4)/(2*a) - (c^4*(1 - a*x)^5)/(5*a)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 6129

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_))^(p_.), x_Symbol] :> Dist[c^p, Int[(u*(1 + (d*x)/c)
^p*(1 + a*x)^(n/2))/(1 - a*x)^(n/2), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] && (IntegerQ
[p] || GtQ[c, 0])

Rule 6167

Int[E^(ArcCoth[(a_.)*(x_)]*(n_))*(u_.), x_Symbol] :> Dist[(-1)^(n/2), Int[u*E^(n*ArcTanh[a*x]), x], x] /; Free
Q[a, x] && IntegerQ[n/2]

Rubi steps

\begin {align*} \int e^{2 \coth ^{-1}(a x)} (c-a c x)^4 \, dx &=-\int e^{2 \tanh ^{-1}(a x)} (c-a c x)^4 \, dx\\ &=-\left (c^4 \int (1-a x)^3 (1+a x) \, dx\right )\\ &=-\left (c^4 \int \left (2 (1-a x)^3-(1-a x)^4\right ) \, dx\right )\\ &=\frac {c^4 (1-a x)^4}{2 a}-\frac {c^4 (1-a x)^5}{5 a}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 30, normalized size = 0.81 \[ \frac {1}{10} c^4 x \left (2 a^4 x^4-5 a^3 x^3+10 a x-10\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[E^(2*ArcCoth[a*x])*(c - a*c*x)^4,x]

[Out]

(c^4*x*(-10 + 10*a*x - 5*a^3*x^3 + 2*a^4*x^4))/10

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fricas [A]  time = 0.63, size = 37, normalized size = 1.00 \[ \frac {1}{5} \, a^{4} c^{4} x^{5} - \frac {1}{2} \, a^{3} c^{4} x^{4} + a c^{4} x^{2} - c^{4} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x-1)*(a*x+1)*(-a*c*x+c)^4,x, algorithm="fricas")

[Out]

1/5*a^4*c^4*x^5 - 1/2*a^3*c^4*x^4 + a*c^4*x^2 - c^4*x

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giac [A]  time = 0.14, size = 37, normalized size = 1.00 \[ \frac {1}{5} \, a^{4} c^{4} x^{5} - \frac {1}{2} \, a^{3} c^{4} x^{4} + a c^{4} x^{2} - c^{4} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x-1)*(a*x+1)*(-a*c*x+c)^4,x, algorithm="giac")

[Out]

1/5*a^4*c^4*x^5 - 1/2*a^3*c^4*x^4 + a*c^4*x^2 - c^4*x

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maple [A]  time = 0.03, size = 30, normalized size = 0.81 \[ c^{4} \left (\frac {1}{5} a^{4} x^{5}-\frac {1}{2} x^{4} a^{3}+a \,x^{2}-x \right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)/(a*x-1)*(-a*c*x+c)^4,x)

[Out]

c^4*(1/5*a^4*x^5-1/2*x^4*a^3+a*x^2-x)

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maxima [A]  time = 0.30, size = 37, normalized size = 1.00 \[ \frac {1}{5} \, a^{4} c^{4} x^{5} - \frac {1}{2} \, a^{3} c^{4} x^{4} + a c^{4} x^{2} - c^{4} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x-1)*(a*x+1)*(-a*c*x+c)^4,x, algorithm="maxima")

[Out]

1/5*a^4*c^4*x^5 - 1/2*a^3*c^4*x^4 + a*c^4*x^2 - c^4*x

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mupad [B]  time = 0.05, size = 37, normalized size = 1.00 \[ \frac {a^4\,c^4\,x^5}{5}-\frac {a^3\,c^4\,x^4}{2}+a\,c^4\,x^2-c^4\,x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((c - a*c*x)^4*(a*x + 1))/(a*x - 1),x)

[Out]

a*c^4*x^2 - c^4*x - (a^3*c^4*x^4)/2 + (a^4*c^4*x^5)/5

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sympy [A]  time = 0.07, size = 36, normalized size = 0.97 \[ \frac {a^{4} c^{4} x^{5}}{5} - \frac {a^{3} c^{4} x^{4}}{2} + a c^{4} x^{2} - c^{4} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(a*x-1)*(a*x+1)*(-a*c*x+c)**4,x)

[Out]

a**4*c**4*x**5/5 - a**3*c**4*x**4/2 + a*c**4*x**2 - c**4*x

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