Optimal. Leaf size=150 \[ -\frac {3 x^{m+1} \, _2F_1\left (\frac {1}{2},\frac {1}{2} (-m-1);\frac {1-m}{2};\frac {1}{a^2 x^2}\right )}{m+1}+\frac {4 x^{m+1} \, _2F_1\left (\frac {3}{2},\frac {1}{2} (-m-1);\frac {1-m}{2};\frac {1}{a^2 x^2}\right )}{m+1}+\frac {x^m \, _2F_1\left (\frac {1}{2},-\frac {m}{2};1-\frac {m}{2};\frac {1}{a^2 x^2}\right )}{a m}-\frac {4 x^m \, _2F_1\left (\frac {3}{2},-\frac {m}{2};1-\frac {m}{2};\frac {1}{a^2 x^2}\right )}{a m} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 1.05, antiderivative size = 150, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 5, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {6172, 6742, 364, 850, 808} \[ \frac {x^m \, _2F_1\left (\frac {1}{2},-\frac {m}{2};1-\frac {m}{2};\frac {1}{a^2 x^2}\right )}{a m}-\frac {4 x^m \, _2F_1\left (\frac {3}{2},-\frac {m}{2};1-\frac {m}{2};\frac {1}{a^2 x^2}\right )}{a m}-\frac {3 x^{m+1} \, _2F_1\left (\frac {1}{2},\frac {1}{2} (-m-1);\frac {1-m}{2};\frac {1}{a^2 x^2}\right )}{m+1}+\frac {4 x^{m+1} \, _2F_1\left (\frac {3}{2},\frac {1}{2} (-m-1);\frac {1-m}{2};\frac {1}{a^2 x^2}\right )}{m+1} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 364
Rule 808
Rule 850
Rule 6172
Rule 6742
Rubi steps
\begin {align*} \int e^{-3 \coth ^{-1}(a x)} x^m \, dx &=-\left (\left (\left (\frac {1}{x}\right )^m x^m\right ) \operatorname {Subst}\left (\int \frac {x^{-2-m} \left (1-\frac {x}{a}\right )^2}{\left (1+\frac {x}{a}\right ) \sqrt {1-\frac {x^2}{a^2}}} \, dx,x,\frac {1}{x}\right )\right )\\ &=-\left (\left (\left (\frac {1}{x}\right )^m x^m\right ) \operatorname {Subst}\left (\int \left (-\frac {3 x^{-2-m}}{\sqrt {1-\frac {x^2}{a^2}}}+\frac {x^{-1-m}}{a \sqrt {1-\frac {x^2}{a^2}}}+\frac {4 x^{-2-m}}{\left (1+\frac {x}{a}\right ) \sqrt {1-\frac {x^2}{a^2}}}\right ) \, dx,x,\frac {1}{x}\right )\right )\\ &=\left (3 \left (\frac {1}{x}\right )^m x^m\right ) \operatorname {Subst}\left (\int \frac {x^{-2-m}}{\sqrt {1-\frac {x^2}{a^2}}} \, dx,x,\frac {1}{x}\right )-\left (4 \left (\frac {1}{x}\right )^m x^m\right ) \operatorname {Subst}\left (\int \frac {x^{-2-m}}{\left (1+\frac {x}{a}\right ) \sqrt {1-\frac {x^2}{a^2}}} \, dx,x,\frac {1}{x}\right )-\frac {\left (\left (\frac {1}{x}\right )^m x^m\right ) \operatorname {Subst}\left (\int \frac {x^{-1-m}}{\sqrt {1-\frac {x^2}{a^2}}} \, dx,x,\frac {1}{x}\right )}{a}\\ &=-\frac {3 x^{1+m} \, _2F_1\left (\frac {1}{2},\frac {1}{2} (-1-m);\frac {1-m}{2};\frac {1}{a^2 x^2}\right )}{1+m}+\frac {x^m \, _2F_1\left (\frac {1}{2},-\frac {m}{2};1-\frac {m}{2};\frac {1}{a^2 x^2}\right )}{a m}-\left (4 \left (\frac {1}{x}\right )^m x^m\right ) \operatorname {Subst}\left (\int \frac {x^{-2-m} \left (1-\frac {x}{a}\right )}{\left (1-\frac {x^2}{a^2}\right )^{3/2}} \, dx,x,\frac {1}{x}\right )\\ &=-\frac {3 x^{1+m} \, _2F_1\left (\frac {1}{2},\frac {1}{2} (-1-m);\frac {1-m}{2};\frac {1}{a^2 x^2}\right )}{1+m}+\frac {x^m \, _2F_1\left (\frac {1}{2},-\frac {m}{2};1-\frac {m}{2};\frac {1}{a^2 x^2}\right )}{a m}-\left (4 \left (\frac {1}{x}\right )^m x^m\right ) \operatorname {Subst}\left (\int \frac {x^{-2-m}}{\left (1-\frac {x^2}{a^2}\right )^{3/2}} \, dx,x,\frac {1}{x}\right )+\frac {\left (4 \left (\frac {1}{x}\right )^m x^m\right ) \operatorname {Subst}\left (\int \frac {x^{-1-m}}{\left (1-\frac {x^2}{a^2}\right )^{3/2}} \, dx,x,\frac {1}{x}\right )}{a}\\ &=-\frac {3 x^{1+m} \, _2F_1\left (\frac {1}{2},\frac {1}{2} (-1-m);\frac {1-m}{2};\frac {1}{a^2 x^2}\right )}{1+m}+\frac {x^m \, _2F_1\left (\frac {1}{2},-\frac {m}{2};1-\frac {m}{2};\frac {1}{a^2 x^2}\right )}{a m}+\frac {4 x^{1+m} \, _2F_1\left (\frac {3}{2},\frac {1}{2} (-1-m);\frac {1-m}{2};\frac {1}{a^2 x^2}\right )}{1+m}-\frac {4 x^m \, _2F_1\left (\frac {3}{2},-\frac {m}{2};1-\frac {m}{2};\frac {1}{a^2 x^2}\right )}{a m}\\ \end {align*}
________________________________________________________________________________________
Mathematica [C] time = 0.27, size = 192, normalized size = 1.28 \[ \frac {x^{m+1} \left (-3 (m+1) \sqrt {1-\frac {1}{a^2 x^2}} \sqrt {\frac {a x-1}{a^2}} F_1\left (m;-\frac {1}{2},\frac {1}{2};m+1;a x,-a x\right )+2 (m+1) \sqrt {1-\frac {1}{a^2 x^2}} \sqrt {\frac {a x-1}{a^2}} F_1\left (m;-\frac {1}{2},\frac {3}{2};m+1;a x,-a x\right )+m \sqrt {1-a x} \sqrt {x^2-\frac {1}{a^2}} \, _2F_1\left (-\frac {1}{2},-\frac {m}{2}-\frac {1}{2};\frac {1}{2}-\frac {m}{2};\frac {1}{a^2 x^2}\right )\right )}{m (m+1) \sqrt {1-a x} \sqrt {x^2-\frac {1}{a^2}}} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
________________________________________________________________________________________
fricas [F] time = 0.89, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (a x - 1\right )} x^{m} \sqrt {\frac {a x - 1}{a x + 1}}}{a x + 1}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [F] time = 0.05, size = 0, normalized size = 0.00 \[ \int x^{m} \left (\frac {a x -1}{a x +1}\right )^{\frac {3}{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{m} \left (\frac {a x - 1}{a x + 1}\right )^{\frac {3}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int x^m\,{\left (\frac {a\,x-1}{a\,x+1}\right )}^{3/2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________