3.278 \(\int x (a+b \coth ^{-1}(c x)) (d+e \log (f+g x^2)) \, dx\)

Optimal. Leaf size=512 \[ \frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {e \left (f+g x^2\right ) \log \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right )}{2 g}-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}+\frac {b e \left (c^2 f+g\right ) \text {Li}_2\left (1-\frac {2}{c x+1}\right )}{2 c^2 g}-\frac {b e \left (c^2 f+g\right ) \text {Li}_2\left (1-\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{\left (c \sqrt {-f}-\sqrt {g}\right ) (c x+1)}\right )}{4 c^2 g}-\frac {b e \left (c^2 f+g\right ) \text {Li}_2\left (1-\frac {2 c \left (\sqrt {g} x+\sqrt {-f}\right )}{\left (\sqrt {-f} c+\sqrt {g}\right ) (c x+1)}\right )}{4 c^2 g}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (f+g x^2\right )}{2 c^2 g}-\frac {b e \left (c^2 f+g\right ) \log \left (\frac {2}{c x+1}\right ) \tanh ^{-1}(c x)}{c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{(c x+1) \left (c \sqrt {-f}-\sqrt {g}\right )}\right )}{2 c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}+\sqrt {g} x\right )}{(c x+1) \left (c \sqrt {-f}+\sqrt {g}\right )}\right )}{2 c^2 g}+\frac {b x (d-e)}{2 c}+\frac {b e x \log \left (f+g x^2\right )}{2 c}+\frac {b e \sqrt {f} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{c \sqrt {g}}-\frac {b e x}{c} \]

[Out]

1/2*b*(d-e)*x/c-b*e*x/c+1/2*d*x^2*(a+b*arccoth(c*x))-1/2*e*x^2*(a+b*arccoth(c*x))-1/2*b*(d-e)*arctanh(c*x)/c^2
-b*e*(c^2*f+g)*arctanh(c*x)*ln(2/(c*x+1))/c^2/g+1/2*b*e*x*ln(g*x^2+f)/c+1/2*e*(g*x^2+f)*(a+b*arccoth(c*x))*ln(
g*x^2+f)/g-1/2*b*e*(c^2*f+g)*arctanh(c*x)*ln(g*x^2+f)/c^2/g+1/2*b*e*(c^2*f+g)*arctanh(c*x)*ln(2*c*((-f)^(1/2)-
x*g^(1/2))/(c*x+1)/(c*(-f)^(1/2)-g^(1/2)))/c^2/g+1/2*b*e*(c^2*f+g)*arctanh(c*x)*ln(2*c*((-f)^(1/2)+x*g^(1/2))/
(c*x+1)/(c*(-f)^(1/2)+g^(1/2)))/c^2/g+1/2*b*e*(c^2*f+g)*polylog(2,1-2/(c*x+1))/c^2/g-1/4*b*e*(c^2*f+g)*polylog
(2,1-2*c*((-f)^(1/2)-x*g^(1/2))/(c*x+1)/(c*(-f)^(1/2)-g^(1/2)))/c^2/g-1/4*b*e*(c^2*f+g)*polylog(2,1-2*c*((-f)^
(1/2)+x*g^(1/2))/(c*x+1)/(c*(-f)^(1/2)+g^(1/2)))/c^2/g+b*e*arctan(x*g^(1/2)/f^(1/2))*f^(1/2)/c/g^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.77, antiderivative size = 512, normalized size of antiderivative = 1.00, number of steps used = 22, number of rules used = 17, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.773, Rules used = {2454, 2389, 2295, 6084, 321, 207, 517, 2528, 2448, 205, 2470, 12, 5992, 5920, 2402, 2315, 2447} \[ \frac {b e \left (c^2 f+g\right ) \text {PolyLog}\left (2,1-\frac {2}{c x+1}\right )}{2 c^2 g}-\frac {b e \left (c^2 f+g\right ) \text {PolyLog}\left (2,1-\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{(c x+1) \left (c \sqrt {-f}-\sqrt {g}\right )}\right )}{4 c^2 g}-\frac {b e \left (c^2 f+g\right ) \text {PolyLog}\left (2,1-\frac {2 c \left (\sqrt {-f}+\sqrt {g} x\right )}{(c x+1) \left (c \sqrt {-f}+\sqrt {g}\right )}\right )}{4 c^2 g}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {e \left (f+g x^2\right ) \log \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right )}{2 g}-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (f+g x^2\right )}{2 c^2 g}-\frac {b e \left (c^2 f+g\right ) \log \left (\frac {2}{c x+1}\right ) \tanh ^{-1}(c x)}{c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{(c x+1) \left (c \sqrt {-f}-\sqrt {g}\right )}\right )}{2 c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}+\sqrt {g} x\right )}{(c x+1) \left (c \sqrt {-f}+\sqrt {g}\right )}\right )}{2 c^2 g}+\frac {b x (d-e)}{2 c}+\frac {b e x \log \left (f+g x^2\right )}{2 c}+\frac {b e \sqrt {f} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{c \sqrt {g}}-\frac {b e x}{c} \]

Antiderivative was successfully verified.

[In]

Int[x*(a + b*ArcCoth[c*x])*(d + e*Log[f + g*x^2]),x]

[Out]

(b*(d - e)*x)/(2*c) - (b*e*x)/c + (d*x^2*(a + b*ArcCoth[c*x]))/2 - (e*x^2*(a + b*ArcCoth[c*x]))/2 + (b*e*Sqrt[
f]*ArcTan[(Sqrt[g]*x)/Sqrt[f]])/(c*Sqrt[g]) - (b*(d - e)*ArcTanh[c*x])/(2*c^2) - (b*e*(c^2*f + g)*ArcTanh[c*x]
*Log[2/(1 + c*x)])/(c^2*g) + (b*e*(c^2*f + g)*ArcTanh[c*x]*Log[(2*c*(Sqrt[-f] - Sqrt[g]*x))/((c*Sqrt[-f] - Sqr
t[g])*(1 + c*x))])/(2*c^2*g) + (b*e*(c^2*f + g)*ArcTanh[c*x]*Log[(2*c*(Sqrt[-f] + Sqrt[g]*x))/((c*Sqrt[-f] + S
qrt[g])*(1 + c*x))])/(2*c^2*g) + (b*e*x*Log[f + g*x^2])/(2*c) + (e*(f + g*x^2)*(a + b*ArcCoth[c*x])*Log[f + g*
x^2])/(2*g) - (b*e*(c^2*f + g)*ArcTanh[c*x]*Log[f + g*x^2])/(2*c^2*g) + (b*e*(c^2*f + g)*PolyLog[2, 1 - 2/(1 +
c*x)])/(2*c^2*g) - (b*e*(c^2*f + g)*PolyLog[2, 1 - (2*c*(Sqrt[-f] - Sqrt[g]*x))/((c*Sqrt[-f] - Sqrt[g])*(1 +
c*x))])/(4*c^2*g) - (b*e*(c^2*f + g)*PolyLog[2, 1 - (2*c*(Sqrt[-f] + Sqrt[g]*x))/((c*Sqrt[-f] + Sqrt[g])*(1 +
c*x))])/(4*c^2*g)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 207

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTanh[(Rt[b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 321

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^n
)^(p + 1))/(b*(m + n*p + 1)), x] - Dist[(a*c^n*(m - n + 1))/(b*(m + n*p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
c, n, m, p, x]

Rule 517

Int[(u_.)*((c_) + (d_.)*(x_)^(n_.))^(q_.)*((a1_) + (b1_.)*(x_)^(non2_.))^(p_.)*((a2_) + (b2_.)*(x_)^(non2_.))^
(p_.), x_Symbol] :> Int[u*(a1*a2 + b1*b2*x^n)^p*(c + d*x^n)^q, x] /; FreeQ[{a1, b1, a2, b2, c, d, n, p, q}, x]
&& EqQ[non2, n/2] && EqQ[a2*b1 + a1*b2, 0] && (IntegerQ[p] || (GtQ[a1, 0] && GtQ[a2, 0]))

Rule 2295

Int[Log[(c_.)*(x_)^(n_.)], x_Symbol] :> Simp[x*Log[c*x^n], x] - Simp[n*x, x] /; FreeQ[{c, n}, x]

Rule 2315

Int[Log[(c_.)*(x_)]/((d_) + (e_.)*(x_)), x_Symbol] :> -Simp[PolyLog[2, 1 - c*x]/e, x] /; FreeQ[{c, d, e}, x] &
& EqQ[e + c*d, 0]

Rule 2389

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.), x_Symbol] :> Dist[1/e, Subst[Int[(a + b*Log[c*
x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, n, p}, x]

Rule 2402

Int[Log[(c_.)/((d_) + (e_.)*(x_))]/((f_) + (g_.)*(x_)^2), x_Symbol] :> -Dist[e/g, Subst[Int[Log[2*d*x]/(1 - 2*
d*x), x], x, 1/(d + e*x)], x] /; FreeQ[{c, d, e, f, g}, x] && EqQ[c, 2*d] && EqQ[e^2*f + d^2*g, 0]

Rule 2447

Int[Log[u_]*(Pq_)^(m_.), x_Symbol] :> With[{C = FullSimplify[(Pq^m*(1 - u))/D[u, x]]}, Simp[C*PolyLog[2, 1 - u
], x] /; FreeQ[C, x]] /; IntegerQ[m] && PolyQ[Pq, x] && RationalFunctionQ[u, x] && LeQ[RationalFunctionExponen
ts[u, x][[2]], Expon[Pq, x]]

Rule 2448

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)], x_Symbol] :> Simp[x*Log[c*(d + e*x^n)^p], x] - Dist[e*n*p, Int[
x^n/(d + e*x^n), x], x] /; FreeQ[{c, d, e, n, p}, x]

Rule 2454

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.), x_Symbol] :> Dist[1/n, Subst[I
nt[x^(Simplify[(m + 1)/n] - 1)*(a + b*Log[c*(d + e*x)^p])^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p,
q}, x] && IntegerQ[Simplify[(m + 1)/n]] && (GtQ[(m + 1)/n, 0] || IGtQ[q, 0]) &&  !(EqQ[q, 1] && ILtQ[n, 0] &&
IGtQ[m, 0])

Rule 2470

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))/((f_) + (g_.)*(x_)^2), x_Symbol] :> With[{u = In
tHide[1/(f + g*x^2), x]}, Simp[u*(a + b*Log[c*(d + e*x^n)^p]), x] - Dist[b*e*n*p, Int[(u*x^(n - 1))/(d + e*x^n
), x], x]] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && IntegerQ[n]

Rule 2528

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*(RGx_), x_Symbol] :> With[{u = ExpandIntegrand[(a + b*Log[c*
RFx^p])^n, RGx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, p}, x] && RationalFunctionQ[RFx, x] && RationalF
unctionQ[RGx, x] && IGtQ[n, 0]

Rule 5920

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))/((d_) + (e_.)*(x_)), x_Symbol] :> -Simp[((a + b*ArcTanh[c*x])*Log[2/(1
+ c*x)])/e, x] + (Dist[(b*c)/e, Int[Log[2/(1 + c*x)]/(1 - c^2*x^2), x], x] - Dist[(b*c)/e, Int[Log[(2*c*(d +
e*x))/((c*d + e)*(1 + c*x))]/(1 - c^2*x^2), x], x] + Simp[((a + b*ArcTanh[c*x])*Log[(2*c*(d + e*x))/((c*d + e)
*(1 + c*x))])/e, x]) /; FreeQ[{a, b, c, d, e}, x] && NeQ[c^2*d^2 - e^2, 0]

Rule 5992

Int[(((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))*(x_)^(m_.))/((d_) + (e_.)*(x_)^2), x_Symbol] :> Int[ExpandIntegrand[a
+ b*ArcTanh[c*x], x^m/(d + e*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] && IntegerQ[m] &&  !(EqQ[m, 1] && NeQ[
a, 0])

Rule 6084

Int[((a_.) + ArcCoth[(c_.)*(x_)]*(b_.))*((d_.) + Log[(f_.) + (g_.)*(x_)^2]*(e_.))*(x_)^(m_.), x_Symbol] :> Wit
h[{u = IntHide[x^m*(d + e*Log[f + g*x^2]), x]}, Dist[a + b*ArcCoth[c*x], u, x] - Dist[b*c, Int[ExpandIntegrand
[u/(1 - c^2*x^2), x], x], x]] /; FreeQ[{a, b, c, d, e, f, g}, x] && IGtQ[(m + 1)/2, 0]

Rubi steps

\begin {align*} \int x \left (a+b \coth ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right ) \, dx &=\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}-(b c) \int \left (-\frac {(d-e) x^2}{2 \left (-1+c^2 x^2\right )}-\frac {e \left (f+g x^2\right ) \log \left (f+g x^2\right )}{2 g (-1+c x) (1+c x)}\right ) \, dx\\ &=\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}+\frac {1}{2} (b c (d-e)) \int \frac {x^2}{-1+c^2 x^2} \, dx+\frac {(b c e) \int \frac {\left (f+g x^2\right ) \log \left (f+g x^2\right )}{(-1+c x) (1+c x)} \, dx}{2 g}\\ &=\frac {b (d-e) x}{2 c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}+\frac {(b (d-e)) \int \frac {1}{-1+c^2 x^2} \, dx}{2 c}+\frac {(b c e) \int \frac {\left (f+g x^2\right ) \log \left (f+g x^2\right )}{-1+c^2 x^2} \, dx}{2 g}\\ &=\frac {b (d-e) x}{2 c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}+\frac {(b c e) \int \left (\frac {g \log \left (f+g x^2\right )}{c^2}+\frac {\left (c^2 f+g\right ) \log \left (f+g x^2\right )}{c^2 \left (-1+c^2 x^2\right )}\right ) \, dx}{2 g}\\ &=\frac {b (d-e) x}{2 c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}+\frac {(b e) \int \log \left (f+g x^2\right ) \, dx}{2 c}+\frac {\left (b e \left (c^2 f+g\right )\right ) \int \frac {\log \left (f+g x^2\right )}{-1+c^2 x^2} \, dx}{2 c g}\\ &=\frac {b (d-e) x}{2 c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}+\frac {b e x \log \left (f+g x^2\right )}{2 c}+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (f+g x^2\right )}{2 c^2 g}-\frac {(b e g) \int \frac {x^2}{f+g x^2} \, dx}{c}+\frac {\left (b e \left (c^2 f+g\right )\right ) \int \frac {x \tanh ^{-1}(c x)}{c \left (f+g x^2\right )} \, dx}{c}\\ &=\frac {b (d-e) x}{2 c}-\frac {b e x}{c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}+\frac {b e x \log \left (f+g x^2\right )}{2 c}+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (f+g x^2\right )}{2 c^2 g}+\frac {(b e f) \int \frac {1}{f+g x^2} \, dx}{c}+\frac {\left (b e \left (c^2 f+g\right )\right ) \int \frac {x \tanh ^{-1}(c x)}{f+g x^2} \, dx}{c^2}\\ &=\frac {b (d-e) x}{2 c}-\frac {b e x}{c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {b e \sqrt {f} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{c \sqrt {g}}-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}+\frac {b e x \log \left (f+g x^2\right )}{2 c}+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (f+g x^2\right )}{2 c^2 g}+\frac {\left (b e \left (c^2 f+g\right )\right ) \int \left (-\frac {\tanh ^{-1}(c x)}{2 \sqrt {g} \left (\sqrt {-f}-\sqrt {g} x\right )}+\frac {\tanh ^{-1}(c x)}{2 \sqrt {g} \left (\sqrt {-f}+\sqrt {g} x\right )}\right ) \, dx}{c^2}\\ &=\frac {b (d-e) x}{2 c}-\frac {b e x}{c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {b e \sqrt {f} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{c \sqrt {g}}-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}+\frac {b e x \log \left (f+g x^2\right )}{2 c}+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (f+g x^2\right )}{2 c^2 g}-\frac {\left (b e \left (c^2 f+g\right )\right ) \int \frac {\tanh ^{-1}(c x)}{\sqrt {-f}-\sqrt {g} x} \, dx}{2 c^2 \sqrt {g}}+\frac {\left (b e \left (c^2 f+g\right )\right ) \int \frac {\tanh ^{-1}(c x)}{\sqrt {-f}+\sqrt {g} x} \, dx}{2 c^2 \sqrt {g}}\\ &=\frac {b (d-e) x}{2 c}-\frac {b e x}{c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {b e \sqrt {f} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{c \sqrt {g}}-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2}{1+c x}\right )}{c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{\left (c \sqrt {-f}-\sqrt {g}\right ) (1+c x)}\right )}{2 c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}+\sqrt {g} x\right )}{\left (c \sqrt {-f}+\sqrt {g}\right ) (1+c x)}\right )}{2 c^2 g}+\frac {b e x \log \left (f+g x^2\right )}{2 c}+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (f+g x^2\right )}{2 c^2 g}+2 \frac {\left (b e \left (c^2 f+g\right )\right ) \int \frac {\log \left (\frac {2}{1+c x}\right )}{1-c^2 x^2} \, dx}{2 c g}-\frac {\left (b e \left (c^2 f+g\right )\right ) \int \frac {\log \left (\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{\left (c \sqrt {-f}-\sqrt {g}\right ) (1+c x)}\right )}{1-c^2 x^2} \, dx}{2 c g}-\frac {\left (b e \left (c^2 f+g\right )\right ) \int \frac {\log \left (\frac {2 c \left (\sqrt {-f}+\sqrt {g} x\right )}{\left (c \sqrt {-f}+\sqrt {g}\right ) (1+c x)}\right )}{1-c^2 x^2} \, dx}{2 c g}\\ &=\frac {b (d-e) x}{2 c}-\frac {b e x}{c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {b e \sqrt {f} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{c \sqrt {g}}-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2}{1+c x}\right )}{c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{\left (c \sqrt {-f}-\sqrt {g}\right ) (1+c x)}\right )}{2 c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}+\sqrt {g} x\right )}{\left (c \sqrt {-f}+\sqrt {g}\right ) (1+c x)}\right )}{2 c^2 g}+\frac {b e x \log \left (f+g x^2\right )}{2 c}+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (f+g x^2\right )}{2 c^2 g}-\frac {b e \left (c^2 f+g\right ) \text {Li}_2\left (1-\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{\left (c \sqrt {-f}-\sqrt {g}\right ) (1+c x)}\right )}{4 c^2 g}-\frac {b e \left (c^2 f+g\right ) \text {Li}_2\left (1-\frac {2 c \left (\sqrt {-f}+\sqrt {g} x\right )}{\left (c \sqrt {-f}+\sqrt {g}\right ) (1+c x)}\right )}{4 c^2 g}+2 \frac {\left (b e \left (c^2 f+g\right )\right ) \operatorname {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+c x}\right )}{2 c^2 g}\\ &=\frac {b (d-e) x}{2 c}-\frac {b e x}{c}+\frac {1}{2} d x^2 \left (a+b \coth ^{-1}(c x)\right )-\frac {1}{2} e x^2 \left (a+b \coth ^{-1}(c x)\right )+\frac {b e \sqrt {f} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{c \sqrt {g}}-\frac {b (d-e) \tanh ^{-1}(c x)}{2 c^2}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2}{1+c x}\right )}{c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{\left (c \sqrt {-f}-\sqrt {g}\right ) (1+c x)}\right )}{2 c^2 g}+\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (\frac {2 c \left (\sqrt {-f}+\sqrt {g} x\right )}{\left (c \sqrt {-f}+\sqrt {g}\right ) (1+c x)}\right )}{2 c^2 g}+\frac {b e x \log \left (f+g x^2\right )}{2 c}+\frac {e \left (f+g x^2\right ) \left (a+b \coth ^{-1}(c x)\right ) \log \left (f+g x^2\right )}{2 g}-\frac {b e \left (c^2 f+g\right ) \tanh ^{-1}(c x) \log \left (f+g x^2\right )}{2 c^2 g}+\frac {b e \left (c^2 f+g\right ) \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 c^2 g}-\frac {b e \left (c^2 f+g\right ) \text {Li}_2\left (1-\frac {2 c \left (\sqrt {-f}-\sqrt {g} x\right )}{\left (c \sqrt {-f}-\sqrt {g}\right ) (1+c x)}\right )}{4 c^2 g}-\frac {b e \left (c^2 f+g\right ) \text {Li}_2\left (1-\frac {2 c \left (\sqrt {-f}+\sqrt {g} x\right )}{\left (c \sqrt {-f}+\sqrt {g}\right ) (1+c x)}\right )}{4 c^2 g}\\ \end {align*}

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Mathematica [A]  time = 4.43, size = 677, normalized size = 1.32 \[ \frac {2 a c^2 d g x^2+2 a c^2 e g x^2 \log \left (f+g x^2\right )+2 a c^2 e f \log \left (f+g x^2\right )-2 a c^2 e g x^2+2 b c^2 d g x^2 \coth ^{-1}(c x)+b c^2 e f \text {Li}_2\left (\frac {e^{2 \coth ^{-1}(c x)} \left (f c^2+g\right )}{f c^2+2 \sqrt {-f} \sqrt {g} c-g}\right )+2 b e \left (c^2 f+g\right ) \text {Li}_2\left (e^{-2 \coth ^{-1}(c x)}\right )+b e \left (c^2 f+g\right ) \text {Li}_2\left (\frac {e^{2 \coth ^{-1}(c x)} \left (f c^2+g\right )}{f c^2-2 \sqrt {-f} \sqrt {g} c-g}\right )+b e g \text {Li}_2\left (\frac {e^{2 \coth ^{-1}(c x)} \left (f c^2+g\right )}{f c^2+2 \sqrt {-f} \sqrt {g} c-g}\right )+2 b c^2 e g x^2 \coth ^{-1}(c x) \log \left (f+g x^2\right )+2 b c^2 e f \coth ^{-1}(c x) \log \left (\frac {\left (c^2 f+g\right ) e^{2 \coth ^{-1}(c x)}}{c^2 (-f)-2 c \sqrt {-f} \sqrt {g}+g}+1\right )+2 b c^2 e f \coth ^{-1}(c x) \log \left (\frac {\left (c^2 f+g\right ) e^{2 \coth ^{-1}(c x)}}{c^2 (-f)+2 c \sqrt {-f} \sqrt {g}+g}+1\right )+2 b e g \coth ^{-1}(c x) \log \left (\frac {\left (c^2 f+g\right ) e^{2 \coth ^{-1}(c x)}}{c^2 (-f)-2 c \sqrt {-f} \sqrt {g}+g}+1\right )+2 b e g \coth ^{-1}(c x) \log \left (\frac {\left (c^2 f+g\right ) e^{2 \coth ^{-1}(c x)}}{c^2 (-f)+2 c \sqrt {-f} \sqrt {g}+g}+1\right )-4 b c^2 e f \coth ^{-1}(c x)^2-4 b c^2 e f \coth ^{-1}(c x) \log \left (1-e^{-2 \coth ^{-1}(c x)}\right )-2 b c^2 e g x^2 \coth ^{-1}(c x)+2 b c d g x-2 b d g \coth ^{-1}(c x)+2 b c e g x \log \left (f+g x^2\right )-2 b e g \coth ^{-1}(c x) \log \left (f+g x^2\right )+4 b c e \sqrt {f} \sqrt {g} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )-6 b c e g x-4 b e g \coth ^{-1}(c x)^2+2 b e g \coth ^{-1}(c x)-4 b e g \coth ^{-1}(c x) \log \left (1-e^{-2 \coth ^{-1}(c x)}\right )}{4 c^2 g} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[x*(a + b*ArcCoth[c*x])*(d + e*Log[f + g*x^2]),x]

[Out]

(2*b*c*d*g*x - 6*b*c*e*g*x + 2*a*c^2*d*g*x^2 - 2*a*c^2*e*g*x^2 - 2*b*d*g*ArcCoth[c*x] + 2*b*e*g*ArcCoth[c*x] +
2*b*c^2*d*g*x^2*ArcCoth[c*x] - 2*b*c^2*e*g*x^2*ArcCoth[c*x] - 4*b*c^2*e*f*ArcCoth[c*x]^2 - 4*b*e*g*ArcCoth[c*
x]^2 + 4*b*c*e*Sqrt[f]*Sqrt[g]*ArcTan[(Sqrt[g]*x)/Sqrt[f]] - 4*b*c^2*e*f*ArcCoth[c*x]*Log[1 - E^(-2*ArcCoth[c*
x])] - 4*b*e*g*ArcCoth[c*x]*Log[1 - E^(-2*ArcCoth[c*x])] + 2*b*c^2*e*f*ArcCoth[c*x]*Log[1 + (E^(2*ArcCoth[c*x]
)*(c^2*f + g))/(-(c^2*f) - 2*c*Sqrt[-f]*Sqrt[g] + g)] + 2*b*e*g*ArcCoth[c*x]*Log[1 + (E^(2*ArcCoth[c*x])*(c^2*
f + g))/(-(c^2*f) - 2*c*Sqrt[-f]*Sqrt[g] + g)] + 2*b*c^2*e*f*ArcCoth[c*x]*Log[1 + (E^(2*ArcCoth[c*x])*(c^2*f +
g))/(-(c^2*f) + 2*c*Sqrt[-f]*Sqrt[g] + g)] + 2*b*e*g*ArcCoth[c*x]*Log[1 + (E^(2*ArcCoth[c*x])*(c^2*f + g))/(-
(c^2*f) + 2*c*Sqrt[-f]*Sqrt[g] + g)] + 2*a*c^2*e*f*Log[f + g*x^2] + 2*b*c*e*g*x*Log[f + g*x^2] + 2*a*c^2*e*g*x
^2*Log[f + g*x^2] - 2*b*e*g*ArcCoth[c*x]*Log[f + g*x^2] + 2*b*c^2*e*g*x^2*ArcCoth[c*x]*Log[f + g*x^2] + 2*b*e*
(c^2*f + g)*PolyLog[2, E^(-2*ArcCoth[c*x])] + b*e*(c^2*f + g)*PolyLog[2, (E^(2*ArcCoth[c*x])*(c^2*f + g))/(c^2
*f - 2*c*Sqrt[-f]*Sqrt[g] - g)] + b*c^2*e*f*PolyLog[2, (E^(2*ArcCoth[c*x])*(c^2*f + g))/(c^2*f + 2*c*Sqrt[-f]*
Sqrt[g] - g)] + b*e*g*PolyLog[2, (E^(2*ArcCoth[c*x])*(c^2*f + g))/(c^2*f + 2*c*Sqrt[-f]*Sqrt[g] - g)])/(4*c^2*
g)

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fricas [F]  time = 0.60, size = 0, normalized size = 0.00 \[ {\rm integral}\left (b d x \operatorname {arcoth}\left (c x\right ) + a d x + {\left (b e x \operatorname {arcoth}\left (c x\right ) + a e x\right )} \log \left (g x^{2} + f\right ), x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*arccoth(c*x))*(d+e*log(g*x^2+f)),x, algorithm="fricas")

[Out]

integral(b*d*x*arccoth(c*x) + a*d*x + (b*e*x*arccoth(c*x) + a*e*x)*log(g*x^2 + f), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \operatorname {arcoth}\left (c x\right ) + a\right )} {\left (e \log \left (g x^{2} + f\right ) + d\right )} x\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*arccoth(c*x))*(d+e*log(g*x^2+f)),x, algorithm="giac")

[Out]

integrate((b*arccoth(c*x) + a)*(e*log(g*x^2 + f) + d)*x, x)

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maple [C]  time = 3.14, size = 8491, normalized size = 16.58 \[ \text {output too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a+b*arccoth(c*x))*(d+e*ln(g*x^2+f)),x)

[Out]

result too large to display

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{2} \, a d x^{2} + \frac {1}{4} \, {\left (2 \, x^{2} \operatorname {arcoth}\left (c x\right ) + c {\left (\frac {2 \, x}{c^{2}} - \frac {\log \left (c x + 1\right )}{c^{3}} + \frac {\log \left (c x - 1\right )}{c^{3}}\right )}\right )} b d - \frac {1}{4} \, {\left (2 \, c^{2} g \int \frac {x^{3} \log \left (c x + 1\right )}{c^{2} g x^{2} + c^{2} f}\,{d x} - 2 \, c^{2} g \int \frac {x^{3} \log \left (c x - 1\right )}{c^{2} g x^{2} + c^{2} f}\,{d x} - 2 \, c g {\left (-\frac {i \, f {\left (\log \left (\frac {i \, g x}{\sqrt {f g}} + 1\right ) - \log \left (-\frac {i \, g x}{\sqrt {f g}} + 1\right )\right )}}{\sqrt {f g} c^{2} g} - \frac {2 \, x}{c^{2} g}\right )} - 2 \, g \int \frac {x \log \left (c x + 1\right )}{c^{2} g x^{2} + c^{2} f}\,{d x} + 2 \, g \int \frac {x \log \left (c x - 1\right )}{c^{2} g x^{2} + c^{2} f}\,{d x} - \frac {{\left (2 \, c x + {\left (c^{2} x^{2} - 1\right )} \log \left (c x + 1\right ) - {\left (c^{2} x^{2} - 1\right )} \log \left (c x - 1\right )\right )} \log \left (g x^{2} + f\right )}{c^{2}}\right )} b e - \frac {{\left (g x^{2} - {\left (g x^{2} + f\right )} \log \left (g x^{2} + f\right ) + f\right )} a e}{2 \, g} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*arccoth(c*x))*(d+e*log(g*x^2+f)),x, algorithm="maxima")

[Out]

1/2*a*d*x^2 + 1/4*(2*x^2*arccoth(c*x) + c*(2*x/c^2 - log(c*x + 1)/c^3 + log(c*x - 1)/c^3))*b*d - 1/4*(2*c^2*g*
integrate(x^3*log(c*x + 1)/(c^2*g*x^2 + c^2*f), x) - 2*c^2*g*integrate(x^3*log(c*x - 1)/(c^2*g*x^2 + c^2*f), x
) - 2*c*g*(-I*f*(log(I*g*x/sqrt(f*g) + 1) - log(-I*g*x/sqrt(f*g) + 1))/(sqrt(f*g)*c^2*g) - 2*x/(c^2*g)) - 2*g*
integrate(x*log(c*x + 1)/(c^2*g*x^2 + c^2*f), x) + 2*g*integrate(x*log(c*x - 1)/(c^2*g*x^2 + c^2*f), x) - (2*c
*x + (c^2*x^2 - 1)*log(c*x + 1) - (c^2*x^2 - 1)*log(c*x - 1))*log(g*x^2 + f)/c^2)*b*e - 1/2*(g*x^2 - (g*x^2 +
f)*log(g*x^2 + f) + f)*a*e/g

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int x\,\left (a+b\,\mathrm {acoth}\left (c\,x\right )\right )\,\left (d+e\,\ln \left (g\,x^2+f\right )\right ) \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a + b*acoth(c*x))*(d + e*log(f + g*x^2)),x)

[Out]

int(x*(a + b*acoth(c*x))*(d + e*log(f + g*x^2)), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+b*acoth(c*x))*(d+e*ln(g*x**2+f)),x)

[Out]

Timed out

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