Optimal. Leaf size=98 \[ \frac {4 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^3 \log \left (\coth ^{-1}(\tanh (a+b x))\right )}{b^5}+\frac {4 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^2}{b^4}+\frac {2 x^2 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}-\frac {x^4}{b \coth ^{-1}(\tanh (a+b x))}+\frac {4 x^3}{3 b^2} \]
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Rubi [A] time = 0.08, antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {2168, 2159, 2158, 2157, 29} \[ \frac {2 x^2 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}+\frac {4 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^2}{b^4}+\frac {4 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^3 \log \left (\coth ^{-1}(\tanh (a+b x))\right )}{b^5}-\frac {x^4}{b \coth ^{-1}(\tanh (a+b x))}+\frac {4 x^3}{3 b^2} \]
Antiderivative was successfully verified.
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Rule 29
Rule 2157
Rule 2158
Rule 2159
Rule 2168
Rubi steps
\begin {align*} \int \frac {x^4}{\coth ^{-1}(\tanh (a+b x))^2} \, dx &=-\frac {x^4}{b \coth ^{-1}(\tanh (a+b x))}+\frac {4 \int \frac {x^3}{\coth ^{-1}(\tanh (a+b x))} \, dx}{b}\\ &=\frac {4 x^3}{3 b^2}-\frac {x^4}{b \coth ^{-1}(\tanh (a+b x))}-\frac {\left (4 \left (-b x+\coth ^{-1}(\tanh (a+b x))\right )\right ) \int \frac {x^2}{\coth ^{-1}(\tanh (a+b x))} \, dx}{b^2}\\ &=\frac {4 x^3}{3 b^2}+\frac {2 x^2 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}-\frac {x^4}{b \coth ^{-1}(\tanh (a+b x))}+\frac {\left (4 \left (-b x+\coth ^{-1}(\tanh (a+b x))\right )^2\right ) \int \frac {x}{\coth ^{-1}(\tanh (a+b x))} \, dx}{b^3}\\ &=\frac {4 x^3}{3 b^2}+\frac {2 x^2 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}+\frac {4 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^2}{b^4}-\frac {x^4}{b \coth ^{-1}(\tanh (a+b x))}-\frac {\left (4 \left (-b x+\coth ^{-1}(\tanh (a+b x))\right )^3\right ) \int \frac {1}{\coth ^{-1}(\tanh (a+b x))} \, dx}{b^4}\\ &=\frac {4 x^3}{3 b^2}+\frac {2 x^2 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}+\frac {4 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^2}{b^4}-\frac {x^4}{b \coth ^{-1}(\tanh (a+b x))}-\frac {\left (4 \left (-b x+\coth ^{-1}(\tanh (a+b x))\right )^3\right ) \operatorname {Subst}\left (\int \frac {1}{x} \, dx,x,\coth ^{-1}(\tanh (a+b x))\right )}{b^5}\\ &=\frac {4 x^3}{3 b^2}+\frac {2 x^2 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )}{b^3}+\frac {4 x \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^2}{b^4}-\frac {x^4}{b \coth ^{-1}(\tanh (a+b x))}+\frac {4 \left (b x-\coth ^{-1}(\tanh (a+b x))\right )^3 \log \left (\coth ^{-1}(\tanh (a+b x))\right )}{b^5}\\ \end {align*}
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Mathematica [A] time = 0.09, size = 106, normalized size = 1.08 \[ -\frac {\left (\coth ^{-1}(\tanh (a+b x))-b x\right )^4}{b^5 \coth ^{-1}(\tanh (a+b x))}-\frac {4 \left (\coth ^{-1}(\tanh (a+b x))-b x\right )^3 \log \left (\coth ^{-1}(\tanh (a+b x))\right )}{b^5}+\frac {3 x \left (\coth ^{-1}(\tanh (a+b x))-b x\right )^2}{b^4}-\frac {x^2 \left (\coth ^{-1}(\tanh (a+b x))-b x\right )}{b^3}+\frac {x^3}{3 b^2} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.52, size = 326, normalized size = 3.33 \[ \frac {16 \, b^{5} x^{5} - 16 \, a b^{4} x^{4} + 9 \, \pi ^{4} a + 24 \, \pi ^{2} a^{3} - 48 \, a^{5} - 32 \, {\left (\pi ^{2} b^{3} - 2 \, a^{2} b^{3}\right )} x^{3} - 12 \, {\left (7 \, \pi ^{2} a b^{2} - 20 \, a^{3} b^{2}\right )} x^{2} - 12 \, {\left (\pi ^{4} b - 6 \, \pi ^{2} a^{2} b - 8 \, a^{4} b\right )} x - 12 \, {\left (\pi ^{5} - 8 \, \pi ^{3} a^{2} - 48 \, \pi a^{4} + 4 \, {\left (\pi ^{3} b^{2} - 12 \, \pi a^{2} b^{2}\right )} x^{2} + 8 \, {\left (\pi ^{3} a b - 12 \, \pi a^{3} b\right )} x\right )} \arctan \left (-\frac {2 \, b x + 2 \, a - \sqrt {4 \, b^{2} x^{2} + 8 \, a b x + \pi ^{2} + 4 \, a^{2}}}{\pi }\right ) + 6 \, {\left (3 \, \pi ^{4} a + 8 \, \pi ^{2} a^{3} - 16 \, a^{5} + 4 \, {\left (3 \, \pi ^{2} a b^{2} - 4 \, a^{3} b^{2}\right )} x^{2} + 8 \, {\left (3 \, \pi ^{2} a^{2} b - 4 \, a^{4} b\right )} x\right )} \log \left (4 \, b^{2} x^{2} + 8 \, a b x + \pi ^{2} + 4 \, a^{2}\right )}{12 \, {\left (4 \, b^{7} x^{2} + 8 \, a b^{6} x + \pi ^{2} b^{5} + 4 \, a^{2} b^{5}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{4}}{\operatorname {arcoth}\left (\tanh \left (b x + a\right )\right )^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 5.95, size = 131085, normalized size = 1337.60 \[ \text {output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [C] time = 0.77, size = 178, normalized size = 1.82 \[ \frac {4 \, {\left (16 \, b^{4} x^{4} - 3 \, \pi ^{4} - 24 i \, \pi ^{3} a + 72 \, \pi ^{2} a^{2} + 96 i \, \pi a^{3} - 48 \, a^{4} + {\left (16 i \, \pi b^{3} - 32 \, a b^{3}\right )} x^{3} - {\left (24 \, \pi ^{2} b^{2} + 96 i \, \pi a b^{2} - 96 \, a^{2} b^{2}\right )} x^{2} + {\left (18 i \, \pi ^{3} b - 108 \, \pi ^{2} a b - 216 i \, \pi a^{2} b + 144 \, a^{3} b\right )} x\right )}}{192 \, b^{6} x - 96 i \, \pi b^{5} + 192 \, a b^{5}} - \frac {{\left (i \, \pi ^{3} - 6 \, \pi ^{2} a - 12 i \, \pi a^{2} + 8 \, a^{3}\right )} \log \left (-i \, \pi + 2 \, b x + 2 \, a\right )}{2 \, b^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.29, size = 669, normalized size = 6.83 \[ \frac {x^3}{3\,b^2}-\frac {{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^4+24\,a^2\,{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^2+16\,a^4-8\,a\,{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^3-32\,a^3\,\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}{2\,b\,\left (8\,a\,b^4+8\,b^5\,x-4\,b^4\,\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )\right )}+\frac {x^2\,\left (\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}{2\,b^3}+\frac {3\,x\,{\left (\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^2}{4\,b^4}+\frac {\ln \left (\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )-\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )\right )\,\left ({\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^3-8\,a^3-6\,a\,{\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )}^2+12\,a^2\,\left (2\,a-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+\ln \left (-\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}-1}\right )+2\,b\,x\right )\right )}{2\,b^5} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{4}}{\operatorname {acoth}^{2}{\left (\tanh {\left (a + b x \right )} \right )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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