Optimal. Leaf size=34 \[ \frac {x \tanh ^{-1}(\tanh (a+b x))^4}{4 b}-\frac {\tanh ^{-1}(\tanh (a+b x))^5}{20 b^2} \]
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Rubi [A] time = 0.01, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {2168, 2157, 30} \[ \frac {x \tanh ^{-1}(\tanh (a+b x))^4}{4 b}-\frac {\tanh ^{-1}(\tanh (a+b x))^5}{20 b^2} \]
Antiderivative was successfully verified.
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Rule 30
Rule 2157
Rule 2168
Rubi steps
\begin {align*} \int x \tanh ^{-1}(\tanh (a+b x))^3 \, dx &=\frac {x \tanh ^{-1}(\tanh (a+b x))^4}{4 b}-\frac {\int \tanh ^{-1}(\tanh (a+b x))^4 \, dx}{4 b}\\ &=\frac {x \tanh ^{-1}(\tanh (a+b x))^4}{4 b}-\frac {\operatorname {Subst}\left (\int x^4 \, dx,x,\tanh ^{-1}(\tanh (a+b x))\right )}{4 b^2}\\ &=\frac {x \tanh ^{-1}(\tanh (a+b x))^4}{4 b}-\frac {\tanh ^{-1}(\tanh (a+b x))^5}{20 b^2}\\ \end {align*}
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Mathematica [B] time = 0.08, size = 99, normalized size = 2.91 \[ \frac {(a+b x) \left (10 \left (2 a^2+a b x-b^2 x^2\right ) \tanh ^{-1}(\tanh (a+b x))^2+(4 a-b x) (a+b x)^3-5 (3 a-b x) (a+b x)^2 \tanh ^{-1}(\tanh (a+b x))-10 (a-b x) \tanh ^{-1}(\tanh (a+b x))^3\right )}{20 b^2} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.50, size = 34, normalized size = 1.00 \[ \frac {1}{5} \, b^{3} x^{5} + \frac {3}{4} \, a b^{2} x^{4} + a^{2} b x^{3} + \frac {1}{2} \, a^{3} x^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.17, size = 34, normalized size = 1.00 \[ \frac {1}{5} \, b^{3} x^{5} + \frac {3}{4} \, a b^{2} x^{4} + a^{2} b x^{3} + \frac {1}{2} \, a^{3} x^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.15, size = 56, normalized size = 1.65 \[ \frac {x^{2} \arctanh \left (\tanh \left (b x +a \right )\right )^{3}}{2}-\frac {3 b \left (\frac {x^{3} \arctanh \left (\tanh \left (b x +a \right )\right )^{2}}{3}-\frac {2 b \left (\frac {x^{4} \arctanh \left (\tanh \left (b x +a \right )\right )}{4}-\frac {b \,x^{5}}{20}\right )}{3}\right )}{2} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.52, size = 54, normalized size = 1.59 \[ -\frac {1}{2} \, b x^{3} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{2} + \frac {1}{2} \, x^{2} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{3} - \frac {1}{20} \, {\left (b^{2} x^{5} - 5 \, b x^{4} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )\right )} b \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.98, size = 53, normalized size = 1.56 \[ -\frac {b^3\,x^5}{20}+\frac {b^2\,x^4\,\mathrm {atanh}\left (\mathrm {tanh}\left (a+b\,x\right )\right )}{4}-\frac {b\,x^3\,{\mathrm {atanh}\left (\mathrm {tanh}\left (a+b\,x\right )\right )}^2}{2}+\frac {x^2\,{\mathrm {atanh}\left (\mathrm {tanh}\left (a+b\,x\right )\right )}^3}{2} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.20, size = 41, normalized size = 1.21 \[ \begin {cases} \frac {x \operatorname {atanh}^{4}{\left (\tanh {\left (a + b x \right )} \right )}}{4 b} - \frac {\operatorname {atanh}^{5}{\left (\tanh {\left (a + b x \right )} \right )}}{20 b^{2}} & \text {for}\: b \neq 0 \\\frac {x^{2} \operatorname {atanh}^{3}{\left (\tanh {\relax (a )} \right )}}{2} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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