Optimal. Leaf size=69 \[ \frac {16}{429} b^2 x^{13/2} \tanh ^{-1}(\tanh (a+b x))-\frac {4}{33} b x^{11/2} \tanh ^{-1}(\tanh (a+b x))^2+\frac {2}{9} x^{9/2} \tanh ^{-1}(\tanh (a+b x))^3-\frac {32 b^3 x^{15/2}}{6435} \]
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Rubi [A] time = 0.04, antiderivative size = 69, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {2168, 30} \[ \frac {16}{429} b^2 x^{13/2} \tanh ^{-1}(\tanh (a+b x))-\frac {4}{33} b x^{11/2} \tanh ^{-1}(\tanh (a+b x))^2+\frac {2}{9} x^{9/2} \tanh ^{-1}(\tanh (a+b x))^3-\frac {32 b^3 x^{15/2}}{6435} \]
Antiderivative was successfully verified.
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Rule 30
Rule 2168
Rubi steps
\begin {align*} \int x^{7/2} \tanh ^{-1}(\tanh (a+b x))^3 \, dx &=\frac {2}{9} x^{9/2} \tanh ^{-1}(\tanh (a+b x))^3-\frac {1}{3} (2 b) \int x^{9/2} \tanh ^{-1}(\tanh (a+b x))^2 \, dx\\ &=-\frac {4}{33} b x^{11/2} \tanh ^{-1}(\tanh (a+b x))^2+\frac {2}{9} x^{9/2} \tanh ^{-1}(\tanh (a+b x))^3+\frac {1}{33} \left (8 b^2\right ) \int x^{11/2} \tanh ^{-1}(\tanh (a+b x)) \, dx\\ &=\frac {16}{429} b^2 x^{13/2} \tanh ^{-1}(\tanh (a+b x))-\frac {4}{33} b x^{11/2} \tanh ^{-1}(\tanh (a+b x))^2+\frac {2}{9} x^{9/2} \tanh ^{-1}(\tanh (a+b x))^3-\frac {1}{429} \left (16 b^3\right ) \int x^{13/2} \, dx\\ &=-\frac {32 b^3 x^{15/2}}{6435}+\frac {16}{429} b^2 x^{13/2} \tanh ^{-1}(\tanh (a+b x))-\frac {4}{33} b x^{11/2} \tanh ^{-1}(\tanh (a+b x))^2+\frac {2}{9} x^{9/2} \tanh ^{-1}(\tanh (a+b x))^3\\ \end {align*}
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Mathematica [A] time = 0.03, size = 57, normalized size = 0.83 \[ -\frac {2 x^{9/2} \left (-120 b^2 x^2 \tanh ^{-1}(\tanh (a+b x))+390 b x \tanh ^{-1}(\tanh (a+b x))^2-715 \tanh ^{-1}(\tanh (a+b x))^3+16 b^3 x^3\right )}{6435} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.43, size = 40, normalized size = 0.58 \[ \frac {2}{6435} \, {\left (429 \, b^{3} x^{7} + 1485 \, a b^{2} x^{6} + 1755 \, a^{2} b x^{5} + 715 \, a^{3} x^{4}\right )} \sqrt {x} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.42, size = 35, normalized size = 0.51 \[ \frac {2}{15} \, b^{3} x^{\frac {15}{2}} + \frac {6}{13} \, a b^{2} x^{\frac {13}{2}} + \frac {6}{11} \, a^{2} b x^{\frac {11}{2}} + \frac {2}{9} \, a^{3} x^{\frac {9}{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.29, size = 56, normalized size = 0.81 \[ \frac {2 x^{\frac {9}{2}} \arctanh \left (\tanh \left (b x +a \right )\right )^{3}}{9}-\frac {4 b \left (\frac {x^{\frac {11}{2}} \arctanh \left (\tanh \left (b x +a \right )\right )^{2}}{11}-\frac {4 b \left (\frac {x^{\frac {13}{2}} \arctanh \left (\tanh \left (b x +a \right )\right )}{13}-\frac {2 x^{\frac {15}{2}} b}{195}\right )}{11}\right )}{3} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.36, size = 55, normalized size = 0.80 \[ -\frac {4}{33} \, b x^{\frac {11}{2}} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{2} + \frac {2}{9} \, x^{\frac {9}{2}} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{3} - \frac {16}{6435} \, {\left (2 \, b^{2} x^{\frac {15}{2}} - 15 \, b x^{\frac {13}{2}} \operatorname {artanh}\left (\tanh \left (b x + a\right )\right )\right )} b \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.17, size = 182, normalized size = 2.64 \[ \frac {2\,b^3\,x^{15/2}}{15}-\frac {x^{9/2}\,{\left (\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}^3}{36}+\frac {3\,b\,x^{11/2}\,{\left (\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}^2}{22}-\frac {3\,b^2\,x^{13/2}\,\left (\ln \left (\frac {2}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )-\ln \left (\frac {2\,{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )+2\,b\,x\right )}{13} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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