3.866 \(\int \frac {e^{-3 \tanh ^{-1}(a+b x)}}{x^3} \, dx\)

Optimal. Leaf size=200 \[ -\frac {3 (3-2 a) b^2 \tanh ^{-1}\left (\frac {\sqrt {1-a} \sqrt {a+b x+1}}{\sqrt {a+1} \sqrt {-a-b x+1}}\right )}{(a+1)^3 \sqrt {1-a^2}}-\frac {(-a-b x+1)^{5/2}}{2 \left (1-a^2\right ) x^2 \sqrt {a+b x+1}}+\frac {3 (3-2 a) b^2 \sqrt {-a-b x+1}}{(1-a) (a+1)^3 \sqrt {a+b x+1}}+\frac {(3-2 a) b (-a-b x+1)^{3/2}}{2 (1-a) (a+1)^2 x \sqrt {a+b x+1}} \]

[Out]

-3*(3-2*a)*b^2*arctanh((1-a)^(1/2)*(b*x+a+1)^(1/2)/(1+a)^(1/2)/(-b*x-a+1)^(1/2))/(1+a)^3/(-a^2+1)^(1/2)+1/2*(3
-2*a)*b*(-b*x-a+1)^(3/2)/(1-a)/(1+a)^2/x/(b*x+a+1)^(1/2)-1/2*(-b*x-a+1)^(5/2)/(-a^2+1)/x^2/(b*x+a+1)^(1/2)+3*(
3-2*a)*b^2*(-b*x-a+1)^(1/2)/(1-a)/(1+a)^3/(b*x+a+1)^(1/2)

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Rubi [A]  time = 0.13, antiderivative size = 200, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {6163, 96, 94, 93, 208} \[ -\frac {3 (3-2 a) b^2 \tanh ^{-1}\left (\frac {\sqrt {1-a} \sqrt {a+b x+1}}{\sqrt {a+1} \sqrt {-a-b x+1}}\right )}{(a+1)^3 \sqrt {1-a^2}}-\frac {(-a-b x+1)^{5/2}}{2 \left (1-a^2\right ) x^2 \sqrt {a+b x+1}}+\frac {3 (3-2 a) b^2 \sqrt {-a-b x+1}}{(1-a) (a+1)^3 \sqrt {a+b x+1}}+\frac {(3-2 a) b (-a-b x+1)^{3/2}}{2 (1-a) (a+1)^2 x \sqrt {a+b x+1}} \]

Antiderivative was successfully verified.

[In]

Int[1/(E^(3*ArcTanh[a + b*x])*x^3),x]

[Out]

(3*(3 - 2*a)*b^2*Sqrt[1 - a - b*x])/((1 - a)*(1 + a)^3*Sqrt[1 + a + b*x]) + ((3 - 2*a)*b*(1 - a - b*x)^(3/2))/
(2*(1 - a)*(1 + a)^2*x*Sqrt[1 + a + b*x]) - (1 - a - b*x)^(5/2)/(2*(1 - a^2)*x^2*Sqrt[1 + a + b*x]) - (3*(3 -
2*a)*b^2*ArcTanh[(Sqrt[1 - a]*Sqrt[1 + a + b*x])/(Sqrt[1 + a]*Sqrt[1 - a - b*x])])/((1 + a)^3*Sqrt[1 - a^2])

Rule 93

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 94

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a + b
*x)^(m + 1)*(c + d*x)^n*(e + f*x)^(p + 1))/((m + 1)*(b*e - a*f)), x] - Dist[(n*(d*e - c*f))/((m + 1)*(b*e - a*
f)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && EqQ[
m + n + p + 2, 0] && GtQ[n, 0] &&  !(SumSimplerQ[p, 1] &&  !SumSimplerQ[m, 1])

Rule 96

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(a +
 b*x)^(m + 1)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)), x] + Dist[(a*d*f*(m + 1)
 + b*c*f*(n + 1) + b*d*e*(p + 1))/((m + 1)*(b*c - a*d)*(b*e - a*f)), Int[(a + b*x)^(m + 1)*(c + d*x)^n*(e + f*
x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && EqQ[Simplify[m + n + p + 3], 0] && (LtQ[m, -1] || Sum
SimplerQ[m, 1])

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 6163

Int[E^(ArcTanh[(c_.)*((a_) + (b_.)*(x_))]*(n_.))*((d_.) + (e_.)*(x_))^(m_.), x_Symbol] :> Int[((d + e*x)^m*(1
+ a*c + b*c*x)^(n/2))/(1 - a*c - b*c*x)^(n/2), x] /; FreeQ[{a, b, c, d, e, m, n}, x]

Rubi steps

\begin {align*} \int \frac {e^{-3 \tanh ^{-1}(a+b x)}}{x^3} \, dx &=\int \frac {(1-a-b x)^{3/2}}{x^3 (1+a+b x)^{3/2}} \, dx\\ &=-\frac {(1-a-b x)^{5/2}}{2 \left (1-a^2\right ) x^2 \sqrt {1+a+b x}}-\frac {((3-2 a) b) \int \frac {(1-a-b x)^{3/2}}{x^2 (1+a+b x)^{3/2}} \, dx}{2 \left (1-a^2\right )}\\ &=\frac {(3-2 a) b (1-a-b x)^{3/2}}{2 (1-a) (1+a)^2 x \sqrt {1+a+b x}}-\frac {(1-a-b x)^{5/2}}{2 \left (1-a^2\right ) x^2 \sqrt {1+a+b x}}+\frac {\left (3 (3-2 a) b^2\right ) \int \frac {\sqrt {1-a-b x}}{x (1+a+b x)^{3/2}} \, dx}{2 (1-a) (1+a)^2}\\ &=\frac {3 (3-2 a) b^2 \sqrt {1-a-b x}}{(1-a) (1+a)^3 \sqrt {1+a+b x}}+\frac {(3-2 a) b (1-a-b x)^{3/2}}{2 (1-a) (1+a)^2 x \sqrt {1+a+b x}}-\frac {(1-a-b x)^{5/2}}{2 \left (1-a^2\right ) x^2 \sqrt {1+a+b x}}+\frac {\left (3 (3-2 a) b^2\right ) \int \frac {1}{x \sqrt {1-a-b x} \sqrt {1+a+b x}} \, dx}{2 (1+a)^3}\\ &=\frac {3 (3-2 a) b^2 \sqrt {1-a-b x}}{(1-a) (1+a)^3 \sqrt {1+a+b x}}+\frac {(3-2 a) b (1-a-b x)^{3/2}}{2 (1-a) (1+a)^2 x \sqrt {1+a+b x}}-\frac {(1-a-b x)^{5/2}}{2 \left (1-a^2\right ) x^2 \sqrt {1+a+b x}}+\frac {\left (3 (3-2 a) b^2\right ) \operatorname {Subst}\left (\int \frac {1}{-1-a-(-1+a) x^2} \, dx,x,\frac {\sqrt {1+a+b x}}{\sqrt {1-a-b x}}\right )}{(1+a)^3}\\ &=\frac {3 (3-2 a) b^2 \sqrt {1-a-b x}}{(1-a) (1+a)^3 \sqrt {1+a+b x}}+\frac {(3-2 a) b (1-a-b x)^{3/2}}{2 (1-a) (1+a)^2 x \sqrt {1+a+b x}}-\frac {(1-a-b x)^{5/2}}{2 \left (1-a^2\right ) x^2 \sqrt {1+a+b x}}-\frac {3 (3-2 a) b^2 \tanh ^{-1}\left (\frac {\sqrt {1-a} \sqrt {1+a+b x}}{\sqrt {1+a} \sqrt {1-a-b x}}\right )}{(1+a)^3 \sqrt {1-a^2}}\\ \end {align*}

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Mathematica [A]  time = 0.16, size = 139, normalized size = 0.70 \[ \frac {\sqrt {-a-b x+1} \left (a^3+a^2-a \left (b^2 x^2-5 b x+1\right )+14 b^2 x^2+5 b x-1\right )}{2 (a+1)^3 x^2 \sqrt {a+b x+1}}+\frac {3 (2 a-3) b^2 \tanh ^{-1}\left (\frac {\sqrt {-a-1} \sqrt {-a-b x+1}}{\sqrt {a-1} \sqrt {a+b x+1}}\right )}{(-a-1)^{7/2} \sqrt {a-1}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[1/(E^(3*ArcTanh[a + b*x])*x^3),x]

[Out]

(Sqrt[1 - a - b*x]*(-1 + a^2 + a^3 + 5*b*x + 14*b^2*x^2 - a*(1 - 5*b*x + b^2*x^2)))/(2*(1 + a)^3*x^2*Sqrt[1 +
a + b*x]) + (3*(-3 + 2*a)*b^2*ArcTanh[(Sqrt[-1 - a]*Sqrt[1 - a - b*x])/(Sqrt[-1 + a]*Sqrt[1 + a + b*x])])/((-1
 - a)^(7/2)*Sqrt[-1 + a])

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fricas [A]  time = 0.66, size = 520, normalized size = 2.60 \[ \left [-\frac {3 \, {\left ({\left (2 \, a - 3\right )} b^{3} x^{3} + {\left (2 \, a^{2} - a - 3\right )} b^{2} x^{2}\right )} \sqrt {-a^{2} + 1} \log \left (\frac {{\left (2 \, a^{2} - 1\right )} b^{2} x^{2} + 2 \, a^{4} + 4 \, {\left (a^{3} - a\right )} b x - 2 \, \sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left (a b x + a^{2} - 1\right )} \sqrt {-a^{2} + 1} - 4 \, a^{2} + 2}{x^{2}}\right ) - 2 \, {\left (a^{5} - {\left (a^{3} - 14 \, a^{2} - a + 14\right )} b^{2} x^{2} + a^{4} - 2 \, a^{3} + 5 \, {\left (a^{3} + a^{2} - a - 1\right )} b x - 2 \, a^{2} + a + 1\right )} \sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{4 \, {\left ({\left (a^{5} + 3 \, a^{4} + 2 \, a^{3} - 2 \, a^{2} - 3 \, a - 1\right )} b x^{3} + {\left (a^{6} + 4 \, a^{5} + 5 \, a^{4} - 5 \, a^{2} - 4 \, a - 1\right )} x^{2}\right )}}, -\frac {3 \, {\left ({\left (2 \, a - 3\right )} b^{3} x^{3} + {\left (2 \, a^{2} - a - 3\right )} b^{2} x^{2}\right )} \sqrt {a^{2} - 1} \arctan \left (\frac {\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left (a b x + a^{2} - 1\right )} \sqrt {a^{2} - 1}}{{\left (a^{2} - 1\right )} b^{2} x^{2} + a^{4} + 2 \, {\left (a^{3} - a\right )} b x - 2 \, a^{2} + 1}\right ) - {\left (a^{5} - {\left (a^{3} - 14 \, a^{2} - a + 14\right )} b^{2} x^{2} + a^{4} - 2 \, a^{3} + 5 \, {\left (a^{3} + a^{2} - a - 1\right )} b x - 2 \, a^{2} + a + 1\right )} \sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1}}{2 \, {\left ({\left (a^{5} + 3 \, a^{4} + 2 \, a^{3} - 2 \, a^{2} - 3 \, a - 1\right )} b x^{3} + {\left (a^{6} + 4 \, a^{5} + 5 \, a^{4} - 5 \, a^{2} - 4 \, a - 1\right )} x^{2}\right )}}\right ] \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a+1)^3*(1-(b*x+a)^2)^(3/2)/x^3,x, algorithm="fricas")

[Out]

[-1/4*(3*((2*a - 3)*b^3*x^3 + (2*a^2 - a - 3)*b^2*x^2)*sqrt(-a^2 + 1)*log(((2*a^2 - 1)*b^2*x^2 + 2*a^4 + 4*(a^
3 - a)*b*x - 2*sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*(a*b*x + a^2 - 1)*sqrt(-a^2 + 1) - 4*a^2 + 2)/x^2) - 2*(a^5
- (a^3 - 14*a^2 - a + 14)*b^2*x^2 + a^4 - 2*a^3 + 5*(a^3 + a^2 - a - 1)*b*x - 2*a^2 + a + 1)*sqrt(-b^2*x^2 - 2
*a*b*x - a^2 + 1))/((a^5 + 3*a^4 + 2*a^3 - 2*a^2 - 3*a - 1)*b*x^3 + (a^6 + 4*a^5 + 5*a^4 - 5*a^2 - 4*a - 1)*x^
2), -1/2*(3*((2*a - 3)*b^3*x^3 + (2*a^2 - a - 3)*b^2*x^2)*sqrt(a^2 - 1)*arctan(sqrt(-b^2*x^2 - 2*a*b*x - a^2 +
 1)*(a*b*x + a^2 - 1)*sqrt(a^2 - 1)/((a^2 - 1)*b^2*x^2 + a^4 + 2*(a^3 - a)*b*x - 2*a^2 + 1)) - (a^5 - (a^3 - 1
4*a^2 - a + 14)*b^2*x^2 + a^4 - 2*a^3 + 5*(a^3 + a^2 - a - 1)*b*x - 2*a^2 + a + 1)*sqrt(-b^2*x^2 - 2*a*b*x - a
^2 + 1))/((a^5 + 3*a^4 + 2*a^3 - 2*a^2 - 3*a - 1)*b*x^3 + (a^6 + 4*a^5 + 5*a^4 - 5*a^2 - 4*a - 1)*x^2)]

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giac [B]  time = 0.44, size = 822, normalized size = 4.11 \[ -\frac {8 \, b^{3}}{{\left (a^{3} {\left | b \right |} + 3 \, a^{2} {\left | b \right |} + 3 \, a {\left | b \right |} + {\left | b \right |}\right )} {\left (\frac {\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b}{b^{2} x + a b} + 1\right )}} - \frac {3 \, {\left (2 \, a b^{3} - 3 \, b^{3}\right )} \arctan \left (\frac {\frac {{\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )} a}{b^{2} x + a b} - 1}{\sqrt {a^{2} - 1}}\right )}{{\left (a^{3} {\left | b \right |} + 3 \, a^{2} {\left | b \right |} + 3 \, a {\left | b \right |} + {\left | b \right |}\right )} \sqrt {a^{2} - 1}} - \frac {\frac {2 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}^{2} a^{4} b^{3}}{{\left (b^{2} x + a b\right )}^{2}} + 2 \, a^{4} b^{3} - \frac {5 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )} a^{3} b^{3}}{b^{2} x + a b} - \frac {6 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}^{2} a^{3} b^{3}}{{\left (b^{2} x + a b\right )}^{2}} - \frac {3 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}^{3} a^{3} b^{3}}{{\left (b^{2} x + a b\right )}^{3}} - 6 \, a^{3} b^{3} + \frac {18 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )} a^{2} b^{3}}{b^{2} x + a b} + \frac {3 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}^{2} a^{2} b^{3}}{{\left (b^{2} x + a b\right )}^{2}} + \frac {6 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}^{3} a^{2} b^{3}}{{\left (b^{2} x + a b\right )}^{3}} - a^{2} b^{3} + \frac {2 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )} a b^{3}}{b^{2} x + a b} - \frac {12 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}^{2} a b^{3}}{{\left (b^{2} x + a b\right )}^{2}} + \frac {2 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}^{3} a b^{3}}{{\left (b^{2} x + a b\right )}^{3}} - \frac {2 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}^{2} b^{3}}{{\left (b^{2} x + a b\right )}^{2}}}{{\left (a^{5} {\left | b \right |} + 3 \, a^{4} {\left | b \right |} + 3 \, a^{3} {\left | b \right |} + a^{2} {\left | b \right |}\right )} {\left (\frac {{\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}^{2} a}{{\left (b^{2} x + a b\right )}^{2}} + a - \frac {2 \, {\left (\sqrt {-b^{2} x^{2} - 2 \, a b x - a^{2} + 1} {\left | b \right |} + b\right )}}{b^{2} x + a b}\right )}^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a+1)^3*(1-(b*x+a)^2)^(3/2)/x^3,x, algorithm="giac")

[Out]

-8*b^3/((a^3*abs(b) + 3*a^2*abs(b) + 3*a*abs(b) + abs(b))*((sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)/(b^
2*x + a*b) + 1)) - 3*(2*a*b^3 - 3*b^3)*arctan(((sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)*a/(b^2*x + a*b)
 - 1)/sqrt(a^2 - 1))/((a^3*abs(b) + 3*a^2*abs(b) + 3*a*abs(b) + abs(b))*sqrt(a^2 - 1)) - (2*(sqrt(-b^2*x^2 - 2
*a*b*x - a^2 + 1)*abs(b) + b)^2*a^4*b^3/(b^2*x + a*b)^2 + 2*a^4*b^3 - 5*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*ab
s(b) + b)*a^3*b^3/(b^2*x + a*b) - 6*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^2*a^3*b^3/(b^2*x + a*b)^2
- 3*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^3*a^3*b^3/(b^2*x + a*b)^3 - 6*a^3*b^3 + 18*(sqrt(-b^2*x^2
- 2*a*b*x - a^2 + 1)*abs(b) + b)*a^2*b^3/(b^2*x + a*b) + 3*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^2*a
^2*b^3/(b^2*x + a*b)^2 + 6*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^3*a^2*b^3/(b^2*x + a*b)^3 - a^2*b^3
 + 2*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)*a*b^3/(b^2*x + a*b) - 12*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 +
 1)*abs(b) + b)^2*a*b^3/(b^2*x + a*b)^2 + 2*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^3*a*b^3/(b^2*x + a
*b)^3 - 2*(sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^2*b^3/(b^2*x + a*b)^2)/((a^5*abs(b) + 3*a^4*abs(b) +
 3*a^3*abs(b) + a^2*abs(b))*((sqrt(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)^2*a/(b^2*x + a*b)^2 + a - 2*(sqrt
(-b^2*x^2 - 2*a*b*x - a^2 + 1)*abs(b) + b)/(b^2*x + a*b))^2)

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maple [B]  time = 0.06, size = 2848, normalized size = 14.24 \[ \text {output too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x+a+1)^3*(1-(b*x+a)^2)^(3/2)/x^3,x)

[Out]

3/(1+a)^3*b^3/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+(1+a)/b-1/b)/(-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(1/2))-9/4/(
1+a)^3*a^4*b^2/(-a^2+1)^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)+9/4/(1+a)^3*a^2*b^2/(-a^2+1)^2*(-b^2*x^2-2*a*b*x-a^2+
1)^(1/2)+3/2/(1+a)^3*a^4*b^2/(-a^2+1)^(3/2)*ln((-2*a^2+2-2*a*b*x+2*(-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/
2))/x)-3/2/(1+a)^3*a^2*b^2/(-a^2+1)^(3/2)*ln((-2*a^2+2-2*a*b*x+2*(-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)
)/x)+9/4/(1+a)^3*b^2/(-a^2+1)*a^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-3/2/(1+a)^3*b^2/(-a^2+1)^(1/2)*ln((-2*a^2+2-2
*a*b*x+2*(-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x)*a^2+27/2/(1+a)^4*b^2*a/(-a^2+1)*(-b^2*x^2-2*a*b*x-a
^2+1)^(1/2)+9/(1+a)^4*b^2*a^3/(-a^2+1)^(1/2)*ln((-2*a^2+2-2*a*b*x+2*(-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1
/2))/x)-9/(1+a)^4*b^2*a/(-a^2+1)^(1/2)*ln((-2*a^2+2-2*a*b*x+2*(-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x
)+3/(1+a)^4*b^3/(-a^2+1)*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2)*x+9/2/(1+a)^4*b^3/(-a^2+1)*(-b^2*x^2-2*a*b*x-a^2+1)^(1
/2)*x+9/2/(1+a)^4*b^3/(-a^2+1)/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))+6/(1+a)^
5*b^3*a^3/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))+6/(1+a)^5*b^2*(-a^2+1)^(1/2)*
ln((-2*a^2+2-2*a*b*x+2*(-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x)*a^2+3/2/(1+a)^3*b^2/(-a^2+1)^(1/2)*ln
((-2*a^2+2-2*a*b*x+2*(-a^2+1)^(1/2)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x)+1/(1+a)^3/b/(x+1/b+a/b)^3*(-(x+(1+a)/b)
^2*b^2+2*b*(x+(1+a)/b))^(5/2)+3/(1+a)^3*b^3*(-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(1/2)*x+3/(1+a)^3*b^2*(-(x+(1
+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(1/2)*a-9/2/(1+a)^4*b^3/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+(1+a)/b-1/b)/(-(x+(1+a
)/b)^2*b^2+2*b*(x+(1+a)/b))^(1/2))-1/2/(1+a)^3/(-a^2+1)/x^2*(-b^2*x^2-2*a*b*x-a^2+1)^(5/2)-1/2/(1+a)^3*b^2/(-a
^2+1)*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2)-3/2/(1+a)^3*b^2/(-a^2+1)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-9/2/(1+a)^4*b^2*(
-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(1/2)*a-6/(1+a)^5*b^2*(-a^2+1)^(1/2)*ln((-2*a^2+2-2*a*b*x+2*(-a^2+1)^(1/2)
*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))/x)-3/(1+a)^5*b^3*(-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(1/2)*x-3/(1+a)^5*b^2*(
-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(1/2)*a-3/(1+a)^5*b^3/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+(1+a)/b-1/b)/(-(x+
(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(1/2))-9/2/(1+a)^4*b^3*(-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(1/2)*x-9/(1+a)^5*
b^2*a^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)-9/2/(1+a)^4*b^3*a^2/(-a^2+1)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)*x-27/2/(1+a
)^4*b^3*a^2/(-a^2+1)/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))+9/(1+a)^4*b^3*a^4/
(-a^2+1)/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))+1/2/(1+a)^3*a*b/(-a^2+1)^2/x*(
-b^2*x^2-2*a*b*x-a^2+1)^(5/2)-3/4/(1+a)^3*a^3*b^3/(-a^2+1)^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)*x-9/4/(1+a)^3*a^3*
b^3/(-a^2+1)^2/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))+3/2/(1+a)^3*a^5*b^3/(-a^
2+1)^2/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))+1/2/(1+a)^3*a*b^3/(-a^2+1)^2*(-b
^2*x^2-2*a*b*x-a^2+1)^(3/2)*x+3/4/(1+a)^3*a*b^3/(-a^2+1)^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)*x+3/4/(1+a)^3*a*b^3/
(-a^2+1)^2/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))+3/4/(1+a)^3*b^3/(-a^2+1)*a*(
-b^2*x^2-2*a*b*x-a^2+1)^(1/2)*x+9/4/(1+a)^3*b^3/(-a^2+1)*a/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*
a*b*x-a^2+1)^(1/2))-3/2/(1+a)^3*b^3/(-a^2+1)*a^3/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*a*b*x-a^2+
1)^(1/2))-2/(1+a)^5*b^2*(-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(3/2)+2/(1+a)^5*b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2
)+6/(1+a)^5*b^2*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)+2/(1+a)^3/(x+1/b+a/b)^2*(-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(5
/2)+2/(1+a)^3*b^2*(-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(3/2)-3/(1+a)^4/(x+1/b+a/b)^2*(-(x+(1+a)/b)^2*b^2+2*b*(
x+(1+a)/b))^(5/2)-3/(1+a)^4*b^2*(-(x+(1+a)/b)^2*b^2+2*b*(x+(1+a)/b))^(3/2)-3/(1+a)^5*b^3*a*(-b^2*x^2-2*a*b*x-a
^2+1)^(1/2)*x-9/(1+a)^5*b^3*a/(b^2)^(1/2)*arctan((b^2)^(1/2)*(x+a/b)/(-b^2*x^2-2*a*b*x-a^2+1)^(1/2))+3/(1+a)^4
*b/(-a^2+1)/x*(-b^2*x^2-2*a*b*x-a^2+1)^(5/2)+6/(1+a)^4*b^2*a/(-a^2+1)*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2)-27/2/(1+a
)^4*b^2*a^3/(-a^2+1)*(-b^2*x^2-2*a*b*x-a^2+1)^(1/2)+1/(1+a)^3*a^2*b^2/(-a^2+1)^2*(-b^2*x^2-2*a*b*x-a^2+1)^(3/2
)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (-{\left (b x + a\right )}^{2} + 1\right )}^{\frac {3}{2}}}{{\left (b x + a + 1\right )}^{3} x^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a+1)^3*(1-(b*x+a)^2)^(3/2)/x^3,x, algorithm="maxima")

[Out]

integrate((-(b*x + a)^2 + 1)^(3/2)/((b*x + a + 1)^3*x^3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (1-{\left (a+b\,x\right )}^2\right )}^{3/2}}{x^3\,{\left (a+b\,x+1\right )}^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1 - (a + b*x)^2)^(3/2)/(x^3*(a + b*x + 1)^3),x)

[Out]

int((1 - (a + b*x)^2)^(3/2)/(x^3*(a + b*x + 1)^3), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a+1)**3*(1-(b*x+a)**2)**(3/2)/x**3,x)

[Out]

Timed out

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