3.691 \(\int \frac {e^{\tanh ^{-1}(a x)}}{\sqrt {c-\frac {c}{a^2 x^2}}} \, dx\)

Optimal. Leaf size=79 \[ -\frac {\sqrt {1-a^2 x^2}}{a \sqrt {c-\frac {c}{a^2 x^2}}}-\frac {\sqrt {1-a^2 x^2} \log (1-a x)}{a^2 x \sqrt {c-\frac {c}{a^2 x^2}}} \]

[Out]

-(-a^2*x^2+1)^(1/2)/a/(c-c/a^2/x^2)^(1/2)-ln(-a*x+1)*(-a^2*x^2+1)^(1/2)/a^2/x/(c-c/a^2/x^2)^(1/2)

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Rubi [A]  time = 0.12, antiderivative size = 79, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {6160, 6150, 43} \[ -\frac {\sqrt {1-a^2 x^2}}{a \sqrt {c-\frac {c}{a^2 x^2}}}-\frac {\sqrt {1-a^2 x^2} \log (1-a x)}{a^2 x \sqrt {c-\frac {c}{a^2 x^2}}} \]

Antiderivative was successfully verified.

[In]

Int[E^ArcTanh[a*x]/Sqrt[c - c/(a^2*x^2)],x]

[Out]

-(Sqrt[1 - a^2*x^2]/(a*Sqrt[c - c/(a^2*x^2)])) - (Sqrt[1 - a^2*x^2]*Log[1 - a*x])/(a^2*Sqrt[c - c/(a^2*x^2)]*x
)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 6150

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[c^p, Int[x^m*(1 -
a*x)^(p - n/2)*(1 + a*x)^(p + n/2), x], x] /; FreeQ[{a, c, d, m, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p
] || GtQ[c, 0])

Rule 6160

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_)^2)^(p_), x_Symbol] :> Dist[(x^(2*p)*(c + d/x^2)^p)/
(1 + (c*x^2)/d)^p, Int[(u*(1 + (c*x^2)/d)^p*E^(n*ArcTanh[a*x]))/x^(2*p), x], x] /; FreeQ[{a, c, d, n, p}, x] &
& EqQ[c + a^2*d, 0] &&  !IntegerQ[p] &&  !IntegerQ[n/2]

Rubi steps

\begin {align*} \int \frac {e^{\tanh ^{-1}(a x)}}{\sqrt {c-\frac {c}{a^2 x^2}}} \, dx &=\frac {\sqrt {1-a^2 x^2} \int \frac {e^{\tanh ^{-1}(a x)} x}{\sqrt {1-a^2 x^2}} \, dx}{\sqrt {c-\frac {c}{a^2 x^2}} x}\\ &=\frac {\sqrt {1-a^2 x^2} \int \frac {x}{1-a x} \, dx}{\sqrt {c-\frac {c}{a^2 x^2}} x}\\ &=\frac {\sqrt {1-a^2 x^2} \int \left (-\frac {1}{a}-\frac {1}{a (-1+a x)}\right ) \, dx}{\sqrt {c-\frac {c}{a^2 x^2}} x}\\ &=-\frac {\sqrt {1-a^2 x^2}}{a \sqrt {c-\frac {c}{a^2 x^2}}}-\frac {\sqrt {1-a^2 x^2} \log (1-a x)}{a^2 \sqrt {c-\frac {c}{a^2 x^2}} x}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 48, normalized size = 0.61 \[ -\frac {\sqrt {1-a^2 x^2} (a x+\log (1-a x))}{a^2 x \sqrt {c-\frac {c}{a^2 x^2}}} \]

Antiderivative was successfully verified.

[In]

Integrate[E^ArcTanh[a*x]/Sqrt[c - c/(a^2*x^2)],x]

[Out]

-((Sqrt[1 - a^2*x^2]*(a*x + Log[1 - a*x]))/(a^2*Sqrt[c - c/(a^2*x^2)]*x))

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fricas [B]  time = 1.41, size = 366, normalized size = 4.63 \[ \left [-\frac {2 \, \sqrt {-a^{2} x^{2} + 1} a^{2} x^{2} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}} + {\left (a^{2} x^{2} - 1\right )} \sqrt {-c} \log \left (\frac {a^{6} c x^{6} - 4 \, a^{5} c x^{5} + 5 \, a^{4} c x^{4} - 4 \, a^{2} c x^{2} + 4 \, a c x - {\left (a^{5} x^{5} - 4 \, a^{4} x^{4} + 6 \, a^{3} x^{3} - 4 \, a^{2} x^{2}\right )} \sqrt {-a^{2} x^{2} + 1} \sqrt {-c} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}} - 2 \, c}{a^{4} x^{4} - 2 \, a^{3} x^{3} + 2 \, a x - 1}\right )}{2 \, {\left (a^{3} c x^{2} - a c\right )}}, -\frac {\sqrt {-a^{2} x^{2} + 1} a^{2} x^{2} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}} + {\left (a^{2} x^{2} - 1\right )} \sqrt {c} \arctan \left (\frac {{\left (a^{2} x^{2} - 2 \, a x + 2\right )} \sqrt {-a^{2} x^{2} + 1} \sqrt {c} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}}}{a^{3} c x^{3} - 2 \, a^{2} c x^{2} - a c x + 2 \, c}\right )}{a^{3} c x^{2} - a c}\right ] \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^(1/2),x, algorithm="fricas")

[Out]

[-1/2*(2*sqrt(-a^2*x^2 + 1)*a^2*x^2*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) + (a^2*x^2 - 1)*sqrt(-c)*log((a^6*c*x^6 -
4*a^5*c*x^5 + 5*a^4*c*x^4 - 4*a^2*c*x^2 + 4*a*c*x - (a^5*x^5 - 4*a^4*x^4 + 6*a^3*x^3 - 4*a^2*x^2)*sqrt(-a^2*x^
2 + 1)*sqrt(-c)*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) - 2*c)/(a^4*x^4 - 2*a^3*x^3 + 2*a*x - 1)))/(a^3*c*x^2 - a*c),
-(sqrt(-a^2*x^2 + 1)*a^2*x^2*sqrt((a^2*c*x^2 - c)/(a^2*x^2)) + (a^2*x^2 - 1)*sqrt(c)*arctan((a^2*x^2 - 2*a*x +
2)*sqrt(-a^2*x^2 + 1)*sqrt(c)*sqrt((a^2*c*x^2 - c)/(a^2*x^2))/(a^3*c*x^3 - 2*a^2*c*x^2 - a*c*x + 2*c)))/(a^3*
c*x^2 - a*c)]

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {a x + 1}{\sqrt {-a^{2} x^{2} + 1} \sqrt {c - \frac {c}{a^{2} x^{2}}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^(1/2),x, algorithm="giac")

[Out]

integrate((a*x + 1)/(sqrt(-a^2*x^2 + 1)*sqrt(c - c/(a^2*x^2))), x)

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maple [A]  time = 0.04, size = 50, normalized size = 0.63 \[ -\frac {\sqrt {-a^{2} x^{2}+1}\, \left (a x +\ln \left (a x -1\right )\right )}{\sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2} x^{2}}}\, x \,a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)/(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^(1/2),x)

[Out]

-(-a^2*x^2+1)^(1/2)*(a*x+ln(a*x-1))/(c*(a^2*x^2-1)/a^2/x^2)^(1/2)/x/a^2

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maxima [C]  time = 0.43, size = 21, normalized size = 0.27 \[ -\frac {i \, x}{\sqrt {c}} - \frac {i \, \log \left (a x - 1\right )}{a \sqrt {c}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)/(-a^2*x^2+1)^(1/2)/(c-c/a^2/x^2)^(1/2),x, algorithm="maxima")

[Out]

-I*x/sqrt(c) - I*log(a*x - 1)/(a*sqrt(c))

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {a\,x+1}{\sqrt {c-\frac {c}{a^2\,x^2}}\,\sqrt {1-a^2\,x^2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x + 1)/((c - c/(a^2*x^2))^(1/2)*(1 - a^2*x^2)^(1/2)),x)

[Out]

int((a*x + 1)/((c - c/(a^2*x^2))^(1/2)*(1 - a^2*x^2)^(1/2)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {a x + 1}{\sqrt {- \left (a x - 1\right ) \left (a x + 1\right )} \sqrt {- c \left (-1 + \frac {1}{a x}\right ) \left (1 + \frac {1}{a x}\right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)/(-a**2*x**2+1)**(1/2)/(c-c/a**2/x**2)**(1/2),x)

[Out]

Integral((a*x + 1)/(sqrt(-(a*x - 1)*(a*x + 1))*sqrt(-c*(-1 + 1/(a*x))*(1 + 1/(a*x)))), x)

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