3.608 \(\int e^{-3 \tanh ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^3 \, dx\)

Optimal. Leaf size=262 \[ \frac {1115 \sqrt {x} \sqrt {c-\frac {c}{a x}} \sinh ^{-1}\left (\sqrt {a} \sqrt {x}\right )}{64 a^{7/2} \sqrt {1-a x}}-\frac {1115 x \sqrt {a x+1} \sqrt {c-\frac {c}{a x}}}{64 a^3 \sqrt {1-a x}}+\frac {1115 x^2 \sqrt {a x+1} \sqrt {c-\frac {c}{a x}}}{96 a^2 \sqrt {1-a x}}+\frac {x^4 \sqrt {a x+1} \sqrt {c-\frac {c}{a x}}}{4 \sqrt {1-a x}}+\frac {8 x^4 \sqrt {c-\frac {c}{a x}}}{\sqrt {1-a x} \sqrt {a x+1}}-\frac {223 x^3 \sqrt {a x+1} \sqrt {c-\frac {c}{a x}}}{24 a \sqrt {1-a x}} \]

[Out]

1115/64*arcsinh(a^(1/2)*x^(1/2))*(c-c/a/x)^(1/2)*x^(1/2)/a^(7/2)/(-a*x+1)^(1/2)+8*x^4*(c-c/a/x)^(1/2)/(-a*x+1)
^(1/2)/(a*x+1)^(1/2)-1115/64*x*(c-c/a/x)^(1/2)*(a*x+1)^(1/2)/a^3/(-a*x+1)^(1/2)+1115/96*x^2*(c-c/a/x)^(1/2)*(a
*x+1)^(1/2)/a^2/(-a*x+1)^(1/2)-223/24*x^3*(c-c/a/x)^(1/2)*(a*x+1)^(1/2)/a/(-a*x+1)^(1/2)+1/4*x^4*(c-c/a/x)^(1/
2)*(a*x+1)^(1/2)/(-a*x+1)^(1/2)

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Rubi [A]  time = 0.27, antiderivative size = 262, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.259, Rules used = {6134, 6129, 89, 80, 50, 54, 215} \[ \frac {1115 x^2 \sqrt {a x+1} \sqrt {c-\frac {c}{a x}}}{96 a^2 \sqrt {1-a x}}-\frac {1115 x \sqrt {a x+1} \sqrt {c-\frac {c}{a x}}}{64 a^3 \sqrt {1-a x}}+\frac {1115 \sqrt {x} \sqrt {c-\frac {c}{a x}} \sinh ^{-1}\left (\sqrt {a} \sqrt {x}\right )}{64 a^{7/2} \sqrt {1-a x}}+\frac {x^4 \sqrt {a x+1} \sqrt {c-\frac {c}{a x}}}{4 \sqrt {1-a x}}+\frac {8 x^4 \sqrt {c-\frac {c}{a x}}}{\sqrt {1-a x} \sqrt {a x+1}}-\frac {223 x^3 \sqrt {a x+1} \sqrt {c-\frac {c}{a x}}}{24 a \sqrt {1-a x}} \]

Antiderivative was successfully verified.

[In]

Int[(Sqrt[c - c/(a*x)]*x^3)/E^(3*ArcTanh[a*x]),x]

[Out]

(8*Sqrt[c - c/(a*x)]*x^4)/(Sqrt[1 - a*x]*Sqrt[1 + a*x]) - (1115*Sqrt[c - c/(a*x)]*x*Sqrt[1 + a*x])/(64*a^3*Sqr
t[1 - a*x]) + (1115*Sqrt[c - c/(a*x)]*x^2*Sqrt[1 + a*x])/(96*a^2*Sqrt[1 - a*x]) - (223*Sqrt[c - c/(a*x)]*x^3*S
qrt[1 + a*x])/(24*a*Sqrt[1 - a*x]) + (Sqrt[c - c/(a*x)]*x^4*Sqrt[1 + a*x])/(4*Sqrt[1 - a*x]) + (1115*Sqrt[c -
c/(a*x)]*Sqrt[x]*ArcSinh[Sqrt[a]*Sqrt[x]])/(64*a^(7/2)*Sqrt[1 - a*x])

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 80

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(c + d*x)
^(n + 1)*(e + f*x)^(p + 1))/(d*f*(n + p + 2)), x] + Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(
d*f*(n + p + 2)), Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2,
0]

Rule 89

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c - a*
d)^2*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d^2*(d*e - c*f)*(n + 1)), x] - Dist[1/(d^2*(d*e - c*f)*(n + 1)), In
t[(c + d*x)^(n + 1)*(e + f*x)^p*Simp[a^2*d^2*f*(n + p + 2) + b^2*c*(d*e*(n + 1) + c*f*(p + 1)) - 2*a*b*d*(d*e*
(n + 1) + c*f*(p + 1)) - b^2*d*(d*e - c*f)*(n + 1)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && (LtQ
[n, -1] || (EqQ[n + p + 3, 0] && NeQ[n, -1] && (SumSimplerQ[n, 1] ||  !SumSimplerQ[p, 1])))

Rule 215

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[(Rt[b, 2]*x)/Sqrt[a]]/Rt[b, 2], x] /; FreeQ[{a, b},
x] && GtQ[a, 0] && PosQ[b]

Rule 6129

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_))^(p_.), x_Symbol] :> Dist[c^p, Int[(u*(1 + (d*x)/c)
^p*(1 + a*x)^(n/2))/(1 - a*x)^(n/2), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] && (IntegerQ
[p] || GtQ[c, 0])

Rule 6134

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)/(x_))^(p_), x_Symbol] :> Dist[(x^p*(c + d/x)^p)/(1 + (c*
x)/d)^p, Int[(u*(1 + (c*x)/d)^p*E^(n*ArcTanh[a*x]))/x^p, x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[c^2 - a^2*
d^2, 0] &&  !IntegerQ[p]

Rubi steps

\begin {align*} \int e^{-3 \tanh ^{-1}(a x)} \sqrt {c-\frac {c}{a x}} x^3 \, dx &=\frac {\left (\sqrt {c-\frac {c}{a x}} \sqrt {x}\right ) \int e^{-3 \tanh ^{-1}(a x)} x^{5/2} \sqrt {1-a x} \, dx}{\sqrt {1-a x}}\\ &=\frac {\left (\sqrt {c-\frac {c}{a x}} \sqrt {x}\right ) \int \frac {x^{5/2} (1-a x)^2}{(1+a x)^{3/2}} \, dx}{\sqrt {1-a x}}\\ &=\frac {8 \sqrt {c-\frac {c}{a x}} x^4}{\sqrt {1-a x} \sqrt {1+a x}}-\frac {\left (2 \sqrt {c-\frac {c}{a x}} \sqrt {x}\right ) \int \frac {x^{5/2} \left (\frac {27 a^2}{2}-\frac {a^3 x}{2}\right )}{\sqrt {1+a x}} \, dx}{a^2 \sqrt {1-a x}}\\ &=\frac {8 \sqrt {c-\frac {c}{a x}} x^4}{\sqrt {1-a x} \sqrt {1+a x}}+\frac {\sqrt {c-\frac {c}{a x}} x^4 \sqrt {1+a x}}{4 \sqrt {1-a x}}-\frac {\left (223 \sqrt {c-\frac {c}{a x}} \sqrt {x}\right ) \int \frac {x^{5/2}}{\sqrt {1+a x}} \, dx}{8 \sqrt {1-a x}}\\ &=\frac {8 \sqrt {c-\frac {c}{a x}} x^4}{\sqrt {1-a x} \sqrt {1+a x}}-\frac {223 \sqrt {c-\frac {c}{a x}} x^3 \sqrt {1+a x}}{24 a \sqrt {1-a x}}+\frac {\sqrt {c-\frac {c}{a x}} x^4 \sqrt {1+a x}}{4 \sqrt {1-a x}}+\frac {\left (1115 \sqrt {c-\frac {c}{a x}} \sqrt {x}\right ) \int \frac {x^{3/2}}{\sqrt {1+a x}} \, dx}{48 a \sqrt {1-a x}}\\ &=\frac {8 \sqrt {c-\frac {c}{a x}} x^4}{\sqrt {1-a x} \sqrt {1+a x}}+\frac {1115 \sqrt {c-\frac {c}{a x}} x^2 \sqrt {1+a x}}{96 a^2 \sqrt {1-a x}}-\frac {223 \sqrt {c-\frac {c}{a x}} x^3 \sqrt {1+a x}}{24 a \sqrt {1-a x}}+\frac {\sqrt {c-\frac {c}{a x}} x^4 \sqrt {1+a x}}{4 \sqrt {1-a x}}-\frac {\left (1115 \sqrt {c-\frac {c}{a x}} \sqrt {x}\right ) \int \frac {\sqrt {x}}{\sqrt {1+a x}} \, dx}{64 a^2 \sqrt {1-a x}}\\ &=\frac {8 \sqrt {c-\frac {c}{a x}} x^4}{\sqrt {1-a x} \sqrt {1+a x}}-\frac {1115 \sqrt {c-\frac {c}{a x}} x \sqrt {1+a x}}{64 a^3 \sqrt {1-a x}}+\frac {1115 \sqrt {c-\frac {c}{a x}} x^2 \sqrt {1+a x}}{96 a^2 \sqrt {1-a x}}-\frac {223 \sqrt {c-\frac {c}{a x}} x^3 \sqrt {1+a x}}{24 a \sqrt {1-a x}}+\frac {\sqrt {c-\frac {c}{a x}} x^4 \sqrt {1+a x}}{4 \sqrt {1-a x}}+\frac {\left (1115 \sqrt {c-\frac {c}{a x}} \sqrt {x}\right ) \int \frac {1}{\sqrt {x} \sqrt {1+a x}} \, dx}{128 a^3 \sqrt {1-a x}}\\ &=\frac {8 \sqrt {c-\frac {c}{a x}} x^4}{\sqrt {1-a x} \sqrt {1+a x}}-\frac {1115 \sqrt {c-\frac {c}{a x}} x \sqrt {1+a x}}{64 a^3 \sqrt {1-a x}}+\frac {1115 \sqrt {c-\frac {c}{a x}} x^2 \sqrt {1+a x}}{96 a^2 \sqrt {1-a x}}-\frac {223 \sqrt {c-\frac {c}{a x}} x^3 \sqrt {1+a x}}{24 a \sqrt {1-a x}}+\frac {\sqrt {c-\frac {c}{a x}} x^4 \sqrt {1+a x}}{4 \sqrt {1-a x}}+\frac {\left (1115 \sqrt {c-\frac {c}{a x}} \sqrt {x}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1+a x^2}} \, dx,x,\sqrt {x}\right )}{64 a^3 \sqrt {1-a x}}\\ &=\frac {8 \sqrt {c-\frac {c}{a x}} x^4}{\sqrt {1-a x} \sqrt {1+a x}}-\frac {1115 \sqrt {c-\frac {c}{a x}} x \sqrt {1+a x}}{64 a^3 \sqrt {1-a x}}+\frac {1115 \sqrt {c-\frac {c}{a x}} x^2 \sqrt {1+a x}}{96 a^2 \sqrt {1-a x}}-\frac {223 \sqrt {c-\frac {c}{a x}} x^3 \sqrt {1+a x}}{24 a \sqrt {1-a x}}+\frac {\sqrt {c-\frac {c}{a x}} x^4 \sqrt {1+a x}}{4 \sqrt {1-a x}}+\frac {1115 \sqrt {c-\frac {c}{a x}} \sqrt {x} \sinh ^{-1}\left (\sqrt {a} \sqrt {x}\right )}{64 a^{7/2} \sqrt {1-a x}}\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 108, normalized size = 0.41 \[ \frac {\sqrt {x} \sqrt {c-\frac {c}{a x}} \left (\sqrt {a} \sqrt {x} \left (48 a^4 x^4-200 a^3 x^3+446 a^2 x^2-1115 a x-3345\right )+3345 \sqrt {a x+1} \sinh ^{-1}\left (\sqrt {a} \sqrt {x}\right )\right )}{192 a^{7/2} \sqrt {1-a^2 x^2}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(Sqrt[c - c/(a*x)]*x^3)/E^(3*ArcTanh[a*x]),x]

[Out]

(Sqrt[c - c/(a*x)]*Sqrt[x]*(Sqrt[a]*Sqrt[x]*(-3345 - 1115*a*x + 446*a^2*x^2 - 200*a^3*x^3 + 48*a^4*x^4) + 3345
*Sqrt[1 + a*x]*ArcSinh[Sqrt[a]*Sqrt[x]]))/(192*a^(7/2)*Sqrt[1 - a^2*x^2])

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fricas [A]  time = 0.69, size = 336, normalized size = 1.28 \[ \left [\frac {3345 \, {\left (a^{2} x^{2} - 1\right )} \sqrt {-c} \log \left (-\frac {8 \, a^{3} c x^{3} - 7 \, a c x + 4 \, {\left (2 \, a^{2} x^{2} + a x\right )} \sqrt {-a^{2} x^{2} + 1} \sqrt {-c} \sqrt {\frac {a c x - c}{a x}} - c}{a x - 1}\right ) - 4 \, {\left (48 \, a^{5} x^{5} - 200 \, a^{4} x^{4} + 446 \, a^{3} x^{3} - 1115 \, a^{2} x^{2} - 3345 \, a x\right )} \sqrt {-a^{2} x^{2} + 1} \sqrt {\frac {a c x - c}{a x}}}{768 \, {\left (a^{6} x^{2} - a^{4}\right )}}, -\frac {3345 \, {\left (a^{2} x^{2} - 1\right )} \sqrt {c} \arctan \left (\frac {2 \, \sqrt {-a^{2} x^{2} + 1} a \sqrt {c} x \sqrt {\frac {a c x - c}{a x}}}{2 \, a^{2} c x^{2} - a c x - c}\right ) + 2 \, {\left (48 \, a^{5} x^{5} - 200 \, a^{4} x^{4} + 446 \, a^{3} x^{3} - 1115 \, a^{2} x^{2} - 3345 \, a x\right )} \sqrt {-a^{2} x^{2} + 1} \sqrt {\frac {a c x - c}{a x}}}{384 \, {\left (a^{6} x^{2} - a^{4}\right )}}\right ] \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(c-c/a/x)^(1/2)/(a*x+1)^3*(-a^2*x^2+1)^(3/2),x, algorithm="fricas")

[Out]

[1/768*(3345*(a^2*x^2 - 1)*sqrt(-c)*log(-(8*a^3*c*x^3 - 7*a*c*x + 4*(2*a^2*x^2 + a*x)*sqrt(-a^2*x^2 + 1)*sqrt(
-c)*sqrt((a*c*x - c)/(a*x)) - c)/(a*x - 1)) - 4*(48*a^5*x^5 - 200*a^4*x^4 + 446*a^3*x^3 - 1115*a^2*x^2 - 3345*
a*x)*sqrt(-a^2*x^2 + 1)*sqrt((a*c*x - c)/(a*x)))/(a^6*x^2 - a^4), -1/384*(3345*(a^2*x^2 - 1)*sqrt(c)*arctan(2*
sqrt(-a^2*x^2 + 1)*a*sqrt(c)*x*sqrt((a*c*x - c)/(a*x))/(2*a^2*c*x^2 - a*c*x - c)) + 2*(48*a^5*x^5 - 200*a^4*x^
4 + 446*a^3*x^3 - 1115*a^2*x^2 - 3345*a*x)*sqrt(-a^2*x^2 + 1)*sqrt((a*c*x - c)/(a*x)))/(a^6*x^2 - a^4)]

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(c-c/a/x)^(1/2)/(a*x+1)^3*(-a^2*x^2+1)^(3/2),x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,x):;OUTPUT:Warn
ing, integration of abs or sign assumes constant sign by intervals (correct if the argument is real):Check [ab
s(x)]sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

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maple [A]  time = 0.06, size = 194, normalized size = 0.74 \[ -\frac {\sqrt {\frac {c \left (a x -1\right )}{a x}}\, x \left (96 a^{\frac {9}{2}} \sqrt {-\left (a x +1\right ) x}\, x^{4}-400 a^{\frac {7}{2}} x^{3} \sqrt {-\left (a x +1\right ) x}+892 a^{\frac {5}{2}} x^{2} \sqrt {-\left (a x +1\right ) x}-2230 a^{\frac {3}{2}} x \sqrt {-\left (a x +1\right ) x}-3345 \arctan \left (\frac {2 a x +1}{2 \sqrt {a}\, \sqrt {-\left (a x +1\right ) x}}\right ) x a -6690 \sqrt {a}\, \sqrt {-\left (a x +1\right ) x}-3345 \arctan \left (\frac {2 a x +1}{2 \sqrt {a}\, \sqrt {-\left (a x +1\right ) x}}\right )\right ) \sqrt {-a^{2} x^{2}+1}}{384 a^{\frac {7}{2}} \left (a x +1\right ) \sqrt {-\left (a x +1\right ) x}\, \left (a x -1\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(c-c/a/x)^(1/2)/(a*x+1)^3*(-a^2*x^2+1)^(3/2),x)

[Out]

-1/384*(c*(a*x-1)/a/x)^(1/2)*x*(96*a^(9/2)*(-(a*x+1)*x)^(1/2)*x^4-400*a^(7/2)*x^3*(-(a*x+1)*x)^(1/2)+892*a^(5/
2)*x^2*(-(a*x+1)*x)^(1/2)-2230*a^(3/2)*x*(-(a*x+1)*x)^(1/2)-3345*arctan(1/2/a^(1/2)*(2*a*x+1)/(-(a*x+1)*x)^(1/
2))*x*a-6690*a^(1/2)*(-(a*x+1)*x)^(1/2)-3345*arctan(1/2/a^(1/2)*(2*a*x+1)/(-(a*x+1)*x)^(1/2)))*(-a^2*x^2+1)^(1
/2)/a^(7/2)/(a*x+1)/(-(a*x+1)*x)^(1/2)/(a*x-1)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}} \sqrt {c - \frac {c}{a x}} x^{3}}{{\left (a x + 1\right )}^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(c-c/a/x)^(1/2)/(a*x+1)^3*(-a^2*x^2+1)^(3/2),x, algorithm="maxima")

[Out]

integrate((-a^2*x^2 + 1)^(3/2)*sqrt(c - c/(a*x))*x^3/(a*x + 1)^3, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {x^3\,\sqrt {c-\frac {c}{a\,x}}\,{\left (1-a^2\,x^2\right )}^{3/2}}{{\left (a\,x+1\right )}^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^3*(c - c/(a*x))^(1/2)*(1 - a^2*x^2)^(3/2))/(a*x + 1)^3,x)

[Out]

int((x^3*(c - c/(a*x))^(1/2)*(1 - a^2*x^2)^(3/2))/(a*x + 1)^3, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{3} \sqrt {- c \left (-1 + \frac {1}{a x}\right )} \left (- \left (a x - 1\right ) \left (a x + 1\right )\right )^{\frac {3}{2}}}{\left (a x + 1\right )^{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(c-c/a/x)**(1/2)/(a*x+1)**3*(-a**2*x**2+1)**(3/2),x)

[Out]

Integral(x**3*sqrt(-c*(-1 + 1/(a*x)))*(-(a*x - 1)*(a*x + 1))**(3/2)/(a*x + 1)**3, x)

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