Optimal. Leaf size=156 \[ -\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {a c^2 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}-\frac {a^2 c^2 \left (1-a^2 x^2\right )^{3/2}}{8 x^4}+\frac {1}{16} a^6 c^2 \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right )-\frac {a^4 c^2 \sqrt {1-a^2 x^2}}{16 x^2}+\frac {2 a^3 c^2 \left (1-a^2 x^2\right )^{3/2}}{15 x^3} \]
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Rubi [A] time = 0.17, antiderivative size = 156, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.368, Rules used = {6128, 835, 807, 266, 47, 63, 208} \[ -\frac {a^4 c^2 \sqrt {1-a^2 x^2}}{16 x^2}+\frac {2 a^3 c^2 \left (1-a^2 x^2\right )^{3/2}}{15 x^3}-\frac {a^2 c^2 \left (1-a^2 x^2\right )^{3/2}}{8 x^4}+\frac {a c^2 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}-\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {1}{16} a^6 c^2 \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right ) \]
Antiderivative was successfully verified.
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Rule 47
Rule 63
Rule 208
Rule 266
Rule 807
Rule 835
Rule 6128
Rubi steps
\begin {align*} \int \frac {e^{\tanh ^{-1}(a x)} (c-a c x)^2}{x^7} \, dx &=c \int \frac {(c-a c x) \sqrt {1-a^2 x^2}}{x^7} \, dx\\ &=-\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}-\frac {1}{6} c \int \frac {\left (6 a c-3 a^2 c x\right ) \sqrt {1-a^2 x^2}}{x^6} \, dx\\ &=-\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {a c^2 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}+\frac {1}{30} c \int \frac {\left (15 a^2 c-12 a^3 c x\right ) \sqrt {1-a^2 x^2}}{x^5} \, dx\\ &=-\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {a c^2 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}-\frac {a^2 c^2 \left (1-a^2 x^2\right )^{3/2}}{8 x^4}-\frac {1}{120} c \int \frac {\left (48 a^3 c-15 a^4 c x\right ) \sqrt {1-a^2 x^2}}{x^4} \, dx\\ &=-\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {a c^2 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}-\frac {a^2 c^2 \left (1-a^2 x^2\right )^{3/2}}{8 x^4}+\frac {2 a^3 c^2 \left (1-a^2 x^2\right )^{3/2}}{15 x^3}+\frac {1}{8} \left (a^4 c^2\right ) \int \frac {\sqrt {1-a^2 x^2}}{x^3} \, dx\\ &=-\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {a c^2 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}-\frac {a^2 c^2 \left (1-a^2 x^2\right )^{3/2}}{8 x^4}+\frac {2 a^3 c^2 \left (1-a^2 x^2\right )^{3/2}}{15 x^3}+\frac {1}{16} \left (a^4 c^2\right ) \operatorname {Subst}\left (\int \frac {\sqrt {1-a^2 x}}{x^2} \, dx,x,x^2\right )\\ &=-\frac {a^4 c^2 \sqrt {1-a^2 x^2}}{16 x^2}-\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {a c^2 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}-\frac {a^2 c^2 \left (1-a^2 x^2\right )^{3/2}}{8 x^4}+\frac {2 a^3 c^2 \left (1-a^2 x^2\right )^{3/2}}{15 x^3}-\frac {1}{32} \left (a^6 c^2\right ) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {1-a^2 x}} \, dx,x,x^2\right )\\ &=-\frac {a^4 c^2 \sqrt {1-a^2 x^2}}{16 x^2}-\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {a c^2 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}-\frac {a^2 c^2 \left (1-a^2 x^2\right )^{3/2}}{8 x^4}+\frac {2 a^3 c^2 \left (1-a^2 x^2\right )^{3/2}}{15 x^3}+\frac {1}{16} \left (a^4 c^2\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {1}{a^2}-\frac {x^2}{a^2}} \, dx,x,\sqrt {1-a^2 x^2}\right )\\ &=-\frac {a^4 c^2 \sqrt {1-a^2 x^2}}{16 x^2}-\frac {c^2 \left (1-a^2 x^2\right )^{3/2}}{6 x^6}+\frac {a c^2 \left (1-a^2 x^2\right )^{3/2}}{5 x^5}-\frac {a^2 c^2 \left (1-a^2 x^2\right )^{3/2}}{8 x^4}+\frac {2 a^3 c^2 \left (1-a^2 x^2\right )^{3/2}}{15 x^3}+\frac {1}{16} a^6 c^2 \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right )\\ \end {align*}
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Mathematica [A] time = 0.04, size = 115, normalized size = 0.74 \[ \frac {c^2 \left (32 a^7 x^7-15 a^6 x^6-16 a^5 x^5+5 a^4 x^4-64 a^3 x^3+50 a^2 x^2+15 a^6 x^6 \sqrt {1-a^2 x^2} \tanh ^{-1}\left (\sqrt {1-a^2 x^2}\right )+48 a x-40\right )}{240 x^6 \sqrt {1-a^2 x^2}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.47, size = 106, normalized size = 0.68 \[ -\frac {15 \, a^{6} c^{2} x^{6} \log \left (\frac {\sqrt {-a^{2} x^{2} + 1} - 1}{x}\right ) + {\left (32 \, a^{5} c^{2} x^{5} - 15 \, a^{4} c^{2} x^{4} + 16 \, a^{3} c^{2} x^{3} - 10 \, a^{2} c^{2} x^{2} - 48 \, a c^{2} x + 40 \, c^{2}\right )} \sqrt {-a^{2} x^{2} + 1}}{240 \, x^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.65, size = 424, normalized size = 2.72 \[ \frac {{\left (5 \, a^{7} c^{2} - \frac {12 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )} a^{5} c^{2}}{x} + \frac {15 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{2} a^{3} c^{2}}{x^{2}} - \frac {20 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{3} a c^{2}}{x^{3}} - \frac {15 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{4} c^{2}}{a x^{4}} + \frac {120 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{5} c^{2}}{a^{3} x^{5}}\right )} a^{12} x^{6}}{1920 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{6} {\left | a \right |}} + \frac {a^{7} c^{2} \log \left (\frac {{\left | -2 \, \sqrt {-a^{2} x^{2} + 1} {\left | a \right |} - 2 \, a \right |}}{2 \, a^{2} {\left | x \right |}}\right )}{16 \, {\left | a \right |}} - \frac {\frac {120 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )} a^{9} c^{2} {\left | a \right |}}{x} - \frac {15 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{2} a^{7} c^{2} {\left | a \right |}}{x^{2}} - \frac {20 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{3} a^{5} c^{2} {\left | a \right |}}{x^{3}} + \frac {15 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{4} a^{3} c^{2} {\left | a \right |}}{x^{4}} - \frac {12 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{5} a c^{2} {\left | a \right |}}{x^{5}} + \frac {5 \, {\left (\sqrt {-a^{2} x^{2} + 1} {\left | a \right |} + a\right )}^{6} c^{2} {\left | a \right |}}{a x^{6}}}{1920 \, a^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 193, normalized size = 1.24 \[ c^{2} \left (a^{3} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{3 x^{3}}-\frac {2 a^{2} \sqrt {-a^{2} x^{2}+1}}{3 x}\right )-\frac {a^{2} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{4 x^{4}}+\frac {3 a^{2} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{2 x^{2}}-\frac {a^{2} \arctanh \left (\frac {1}{\sqrt {-a^{2} x^{2}+1}}\right )}{2}\right )}{4}\right )}{6}-\frac {\sqrt {-a^{2} x^{2}+1}}{6 x^{6}}-a \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{5 x^{5}}+\frac {4 a^{2} \left (-\frac {\sqrt {-a^{2} x^{2}+1}}{3 x^{3}}-\frac {2 a^{2} \sqrt {-a^{2} x^{2}+1}}{3 x}\right )}{5}\right )\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.40, size = 168, normalized size = 1.08 \[ \frac {1}{16} \, a^{6} c^{2} \log \left (\frac {2 \, \sqrt {-a^{2} x^{2} + 1}}{{\left | x \right |}} + \frac {2}{{\left | x \right |}}\right ) - \frac {2 \, \sqrt {-a^{2} x^{2} + 1} a^{5} c^{2}}{15 \, x} + \frac {\sqrt {-a^{2} x^{2} + 1} a^{4} c^{2}}{16 \, x^{2}} - \frac {\sqrt {-a^{2} x^{2} + 1} a^{3} c^{2}}{15 \, x^{3}} + \frac {\sqrt {-a^{2} x^{2} + 1} a^{2} c^{2}}{24 \, x^{4}} + \frac {\sqrt {-a^{2} x^{2} + 1} a c^{2}}{5 \, x^{5}} - \frac {\sqrt {-a^{2} x^{2} + 1} c^{2}}{6 \, x^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.05, size = 159, normalized size = 1.02 \[ \frac {a\,c^2\,\sqrt {1-a^2\,x^2}}{5\,x^5}-\frac {c^2\,\sqrt {1-a^2\,x^2}}{6\,x^6}+\frac {a^2\,c^2\,\sqrt {1-a^2\,x^2}}{24\,x^4}-\frac {a^3\,c^2\,\sqrt {1-a^2\,x^2}}{15\,x^3}+\frac {a^4\,c^2\,\sqrt {1-a^2\,x^2}}{16\,x^2}-\frac {2\,a^5\,c^2\,\sqrt {1-a^2\,x^2}}{15\,x}-\frac {a^6\,c^2\,\mathrm {atan}\left (\sqrt {1-a^2\,x^2}\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{16} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 11.61, size = 644, normalized size = 4.13 \[ a^{3} c^{2} \left (\begin {cases} - \frac {2 i a^{2} \sqrt {a^{2} x^{2} - 1}}{3 x} - \frac {i \sqrt {a^{2} x^{2} - 1}}{3 x^{3}} & \text {for}\: \left |{a^{2} x^{2}}\right | > 1 \\- \frac {2 a^{2} \sqrt {- a^{2} x^{2} + 1}}{3 x} - \frac {\sqrt {- a^{2} x^{2} + 1}}{3 x^{3}} & \text {otherwise} \end {cases}\right ) - a^{2} c^{2} \left (\begin {cases} - \frac {3 a^{4} \operatorname {acosh}{\left (\frac {1}{a x} \right )}}{8} + \frac {3 a^{3}}{8 x \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {a}{8 x^{3} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {1}{4 a x^{5} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} & \text {for}\: \frac {1}{\left |{a^{2} x^{2}}\right |} > 1 \\\frac {3 i a^{4} \operatorname {asin}{\left (\frac {1}{a x} \right )}}{8} - \frac {3 i a^{3}}{8 x \sqrt {1 - \frac {1}{a^{2} x^{2}}}} + \frac {i a}{8 x^{3} \sqrt {1 - \frac {1}{a^{2} x^{2}}}} + \frac {i}{4 a x^{5} \sqrt {1 - \frac {1}{a^{2} x^{2}}}} & \text {otherwise} \end {cases}\right ) - a c^{2} \left (\begin {cases} - \frac {8 a^{5} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}}{15} - \frac {4 a^{3} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}}{15 x^{2}} - \frac {a \sqrt {-1 + \frac {1}{a^{2} x^{2}}}}{5 x^{4}} & \text {for}\: \frac {1}{\left |{a^{2} x^{2}}\right |} > 1 \\- \frac {8 i a^{5} \sqrt {1 - \frac {1}{a^{2} x^{2}}}}{15} - \frac {4 i a^{3} \sqrt {1 - \frac {1}{a^{2} x^{2}}}}{15 x^{2}} - \frac {i a \sqrt {1 - \frac {1}{a^{2} x^{2}}}}{5 x^{4}} & \text {otherwise} \end {cases}\right ) + c^{2} \left (\begin {cases} - \frac {5 a^{6} \operatorname {acosh}{\left (\frac {1}{a x} \right )}}{16} + \frac {5 a^{5}}{16 x \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {5 a^{3}}{48 x^{3} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {a}{24 x^{5} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} - \frac {1}{6 a x^{7} \sqrt {-1 + \frac {1}{a^{2} x^{2}}}} & \text {for}\: \frac {1}{\left |{a^{2} x^{2}}\right |} > 1 \\\frac {5 i a^{6} \operatorname {asin}{\left (\frac {1}{a x} \right )}}{16} - \frac {5 i a^{5}}{16 x \sqrt {1 - \frac {1}{a^{2} x^{2}}}} + \frac {5 i a^{3}}{48 x^{3} \sqrt {1 - \frac {1}{a^{2} x^{2}}}} + \frac {i a}{24 x^{5} \sqrt {1 - \frac {1}{a^{2} x^{2}}}} + \frac {i}{6 a x^{7} \sqrt {1 - \frac {1}{a^{2} x^{2}}}} & \text {otherwise} \end {cases}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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