3.279 \(\int e^{n \tanh ^{-1}(a x)} (c-a c x)^{5/2} \, dx\)

Optimal. Leaf size=81 \[ -\frac {2^{\frac {n}{2}+1} (c-a c x)^{7/2} (1-a x)^{-n/2} \, _2F_1\left (\frac {7-n}{2},-\frac {n}{2};\frac {9-n}{2};\frac {1}{2} (1-a x)\right )}{a c (7-n)} \]

[Out]

-2^(1+1/2*n)*(-a*c*x+c)^(7/2)*hypergeom([-1/2*n, 7/2-1/2*n],[9/2-1/2*n],-1/2*a*x+1/2)/a/c/(7-n)/((-a*x+1)^(1/2
*n))

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Rubi [A]  time = 0.07, antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {6130, 23, 69} \[ -\frac {2^{\frac {n}{2}+1} (c-a c x)^{7/2} (1-a x)^{-n/2} \, _2F_1\left (\frac {7-n}{2},-\frac {n}{2};\frac {9-n}{2};\frac {1}{2} (1-a x)\right )}{a c (7-n)} \]

Antiderivative was successfully verified.

[In]

Int[E^(n*ArcTanh[a*x])*(c - a*c*x)^(5/2),x]

[Out]

-((2^(1 + n/2)*(c - a*c*x)^(7/2)*Hypergeometric2F1[(7 - n)/2, -n/2, (9 - n)/2, (1 - a*x)/2])/(a*c*(7 - n)*(1 -
 a*x)^(n/2)))

Rule 23

Int[(u_.)*((a_) + (b_.)*(v_))^(m_)*((c_) + (d_.)*(v_))^(n_), x_Symbol] :> Dist[(a + b*v)^m/(c + d*v)^m, Int[u*
(c + d*v)^(m + n), x], x] /; FreeQ[{a, b, c, d, m, n}, x] && EqQ[b*c - a*d, 0] &&  !(IntegerQ[m] || IntegerQ[n
] || GtQ[b/d, 0])

Rule 69

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*Hypergeometric2F1[
-n, m + 1, m + 2, -((d*(a + b*x))/(b*c - a*d))])/(b*(m + 1)*(b/(b*c - a*d))^n), x] /; FreeQ[{a, b, c, d, m, n}
, x] && NeQ[b*c - a*d, 0] &&  !IntegerQ[m] &&  !IntegerQ[n] && GtQ[b/(b*c - a*d), 0] && (RationalQ[m] ||  !(Ra
tionalQ[n] && GtQ[-(d/(b*c - a*d)), 0]))

Rule 6130

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_))^(p_.), x_Symbol] :> Int[(u*(c + d*x)^p*(1 + a*x)^(
n/2))/(1 - a*x)^(n/2), x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] &&  !(IntegerQ[p] || GtQ[c, 0]
)

Rubi steps

\begin {align*} \int e^{n \tanh ^{-1}(a x)} (c-a c x)^{5/2} \, dx &=\int (1-a x)^{-n/2} (1+a x)^{n/2} (c-a c x)^{5/2} \, dx\\ &=\left ((1-a x)^{-n/2} (c-a c x)^{n/2}\right ) \int (1+a x)^{n/2} (c-a c x)^{\frac {5}{2}-\frac {n}{2}} \, dx\\ &=-\frac {2^{1+\frac {n}{2}} (1-a x)^{-n/2} (c-a c x)^{7/2} \, _2F_1\left (\frac {7-n}{2},-\frac {n}{2};\frac {9-n}{2};\frac {1}{2} (1-a x)\right )}{a c (7-n)}\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 80, normalized size = 0.99 \[ \frac {c^2 2^{\frac {n}{2}+1} \sqrt {c-a c x} (1-a x)^{3-\frac {n}{2}} \, _2F_1\left (\frac {7}{2}-\frac {n}{2},-\frac {n}{2};\frac {9}{2}-\frac {n}{2};\frac {1}{2}-\frac {a x}{2}\right )}{a (n-7)} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(n*ArcTanh[a*x])*(c - a*c*x)^(5/2),x]

[Out]

(2^(1 + n/2)*c^2*(1 - a*x)^(3 - n/2)*Sqrt[c - a*c*x]*Hypergeometric2F1[7/2 - n/2, -1/2*n, 9/2 - n/2, 1/2 - (a*
x)/2])/(a*(-7 + n))

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fricas [F]  time = 0.54, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (a^{2} c^{2} x^{2} - 2 \, a c^{2} x + c^{2}\right )} \sqrt {-a c x + c} \left (\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(n*arctanh(a*x))*(-a*c*x+c)^(5/2),x, algorithm="fricas")

[Out]

integral((a^2*c^2*x^2 - 2*a*c^2*x + c^2)*sqrt(-a*c*x + c)*((a*x + 1)/(a*x - 1))^(1/2*n), x)

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(n*arctanh(a*x))*(-a*c*x+c)^(5/2),x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,x):;OUTPUT:Unab
le to divide, perhaps due to rounding error%%%{-1,[0,6,1,0,0]%%%}+%%%{3,[0,4,1,1,0]%%%}+%%%{-3,[0,2,1,2,0]%%%}
+%%%{1,[0,0,1,3,0]%%%} / %%%{1,[0,0,0,3,3]%%%} Error: Bad Argument Value

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maple [F]  time = 0.21, size = 0, normalized size = 0.00 \[ \int {\mathrm e}^{n \arctanh \left (a x \right )} \left (-a c x +c \right )^{\frac {5}{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(n*arctanh(a*x))*(-a*c*x+c)^(5/2),x)

[Out]

int(exp(n*arctanh(a*x))*(-a*c*x+c)^(5/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (-a c x + c\right )}^{\frac {5}{2}} \left (\frac {a x + 1}{a x - 1}\right )^{\frac {1}{2} \, n}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(n*arctanh(a*x))*(-a*c*x+c)^(5/2),x, algorithm="maxima")

[Out]

integrate((-a*c*x + c)^(5/2)*((a*x + 1)/(a*x - 1))^(1/2*n), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int {\mathrm {e}}^{n\,\mathrm {atanh}\left (a\,x\right )}\,{\left (c-a\,c\,x\right )}^{5/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(exp(n*atanh(a*x))*(c - a*c*x)^(5/2),x)

[Out]

int(exp(n*atanh(a*x))*(c - a*c*x)^(5/2), x)

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sympy [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: HeuristicGCDFailed} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(exp(n*atanh(a*x))*(-a*c*x+c)**(5/2),x)

[Out]

Exception raised: HeuristicGCDFailed

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