3.169 \(\int e^{2 \tanh ^{-1}(a x)} (c-a c x)^4 \, dx\)

Optimal. Leaf size=37 \[ \frac {c^4 (1-a x)^5}{5 a}-\frac {c^4 (1-a x)^4}{2 a} \]

[Out]

-1/2*c^4*(-a*x+1)^4/a+1/5*c^4*(-a*x+1)^5/a

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Rubi [A]  time = 0.03, antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {6129, 43} \[ \frac {c^4 (1-a x)^5}{5 a}-\frac {c^4 (1-a x)^4}{2 a} \]

Antiderivative was successfully verified.

[In]

Int[E^(2*ArcTanh[a*x])*(c - a*c*x)^4,x]

[Out]

-(c^4*(1 - a*x)^4)/(2*a) + (c^4*(1 - a*x)^5)/(5*a)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 6129

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*(u_.)*((c_) + (d_.)*(x_))^(p_.), x_Symbol] :> Dist[c^p, Int[(u*(1 + (d*x)/c)
^p*(1 + a*x)^(n/2))/(1 - a*x)^(n/2), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c^2 - d^2, 0] && (IntegerQ
[p] || GtQ[c, 0])

Rubi steps

\begin {align*} \int e^{2 \tanh ^{-1}(a x)} (c-a c x)^4 \, dx &=c^4 \int (1-a x)^3 (1+a x) \, dx\\ &=c^4 \int \left (2 (1-a x)^3-(1-a x)^4\right ) \, dx\\ &=-\frac {c^4 (1-a x)^4}{2 a}+\frac {c^4 (1-a x)^5}{5 a}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 32, normalized size = 0.86 \[ c^4 \left (-\frac {1}{5} a^4 x^5+\frac {a^3 x^4}{2}-a x^2+x\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[E^(2*ArcTanh[a*x])*(c - a*c*x)^4,x]

[Out]

c^4*(x - a*x^2 + (a^3*x^4)/2 - (a^4*x^5)/5)

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fricas [A]  time = 0.77, size = 37, normalized size = 1.00 \[ -\frac {1}{5} \, a^{4} c^{4} x^{5} + \frac {1}{2} \, a^{3} c^{4} x^{4} - a c^{4} x^{2} + c^{4} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a*c*x+c)^4,x, algorithm="fricas")

[Out]

-1/5*a^4*c^4*x^5 + 1/2*a^3*c^4*x^4 - a*c^4*x^2 + c^4*x

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giac [A]  time = 0.16, size = 37, normalized size = 1.00 \[ -\frac {1}{5} \, a^{4} c^{4} x^{5} + \frac {1}{2} \, a^{3} c^{4} x^{4} - a c^{4} x^{2} + c^{4} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a*c*x+c)^4,x, algorithm="giac")

[Out]

-1/5*a^4*c^4*x^5 + 1/2*a^3*c^4*x^4 - a*c^4*x^2 + c^4*x

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maple [A]  time = 0.02, size = 29, normalized size = 0.78 \[ c^{4} \left (-\frac {1}{5} a^{4} x^{5}+\frac {1}{2} x^{4} a^{3}-a \,x^{2}+x \right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)^2/(-a^2*x^2+1)*(-a*c*x+c)^4,x)

[Out]

c^4*(-1/5*a^4*x^5+1/2*x^4*a^3-a*x^2+x)

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maxima [A]  time = 0.34, size = 37, normalized size = 1.00 \[ -\frac {1}{5} \, a^{4} c^{4} x^{5} + \frac {1}{2} \, a^{3} c^{4} x^{4} - a c^{4} x^{2} + c^{4} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a*c*x+c)^4,x, algorithm="maxima")

[Out]

-1/5*a^4*c^4*x^5 + 1/2*a^3*c^4*x^4 - a*c^4*x^2 + c^4*x

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mupad [B]  time = 0.05, size = 37, normalized size = 1.00 \[ -\frac {a^4\,c^4\,x^5}{5}+\frac {a^3\,c^4\,x^4}{2}-a\,c^4\,x^2+c^4\,x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-((c - a*c*x)^4*(a*x + 1)^2)/(a^2*x^2 - 1),x)

[Out]

c^4*x - a*c^4*x^2 + (a^3*c^4*x^4)/2 - (a^4*c^4*x^5)/5

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sympy [A]  time = 0.08, size = 36, normalized size = 0.97 \[ - \frac {a^{4} c^{4} x^{5}}{5} + \frac {a^{3} c^{4} x^{4}}{2} - a c^{4} x^{2} + c^{4} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)**2/(-a**2*x**2+1)*(-a*c*x+c)**4,x)

[Out]

-a**4*c**4*x**5/5 + a**3*c**4*x**4/2 - a*c**4*x**2 + c**4*x

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