3.1288 \(\int \frac {e^{\frac {1}{2} \tanh ^{-1}(a x)}}{(1-a^2 x^2)^{9/2}} \, dx\)

Optimal. Leaf size=149 \[ -\frac {2 (1-14 a x) e^{\frac {1}{2} \tanh ^{-1}(a x)}}{195 a \left (1-a^2 x^2\right )^{7/2}}-\frac {2048 (1-2 a x) e^{\frac {1}{2} \tanh ^{-1}(a x)}}{6435 a \sqrt {1-a^2 x^2}}-\frac {256 (1-6 a x) e^{\frac {1}{2} \tanh ^{-1}(a x)}}{6435 a \left (1-a^2 x^2\right )^{3/2}}-\frac {112 (1-10 a x) e^{\frac {1}{2} \tanh ^{-1}(a x)}}{6435 a \left (1-a^2 x^2\right )^{5/2}} \]

[Out]

-2/195*((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)*(-14*a*x+1)/a/(-a^2*x^2+1)^(7/2)-112/6435*((a*x+1)/(-a^2*x^2+1)^(1/2
))^(1/2)*(-10*a*x+1)/a/(-a^2*x^2+1)^(5/2)-256/6435*((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)*(-6*a*x+1)/a/(-a^2*x^2+1
)^(3/2)-2048/6435*((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)*(-2*a*x+1)/a/(-a^2*x^2+1)^(1/2)

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Rubi [A]  time = 0.17, antiderivative size = 149, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.080, Rules used = {6136, 6135} \[ -\frac {2 (1-14 a x) e^{\frac {1}{2} \tanh ^{-1}(a x)}}{195 a \left (1-a^2 x^2\right )^{7/2}}-\frac {2048 (1-2 a x) e^{\frac {1}{2} \tanh ^{-1}(a x)}}{6435 a \sqrt {1-a^2 x^2}}-\frac {256 (1-6 a x) e^{\frac {1}{2} \tanh ^{-1}(a x)}}{6435 a \left (1-a^2 x^2\right )^{3/2}}-\frac {112 (1-10 a x) e^{\frac {1}{2} \tanh ^{-1}(a x)}}{6435 a \left (1-a^2 x^2\right )^{5/2}} \]

Antiderivative was successfully verified.

[In]

Int[E^(ArcTanh[a*x]/2)/(1 - a^2*x^2)^(9/2),x]

[Out]

(-2*E^(ArcTanh[a*x]/2)*(1 - 14*a*x))/(195*a*(1 - a^2*x^2)^(7/2)) - (112*E^(ArcTanh[a*x]/2)*(1 - 10*a*x))/(6435
*a*(1 - a^2*x^2)^(5/2)) - (256*E^(ArcTanh[a*x]/2)*(1 - 6*a*x))/(6435*a*(1 - a^2*x^2)^(3/2)) - (2048*E^(ArcTanh
[a*x]/2)*(1 - 2*a*x))/(6435*a*Sqrt[1 - a^2*x^2])

Rule 6135

Int[E^(ArcTanh[(a_.)*(x_)]*(n_))/((c_) + (d_.)*(x_)^2)^(3/2), x_Symbol] :> Simp[((n - a*x)*E^(n*ArcTanh[a*x]))
/(a*c*(n^2 - 1)*Sqrt[c + d*x^2]), x] /; FreeQ[{a, c, d, n}, x] && EqQ[a^2*c + d, 0] &&  !IntegerQ[n]

Rule 6136

Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*((c_) + (d_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((n + 2*a*(p + 1)*x)*(c + d*x^2
)^(p + 1)*E^(n*ArcTanh[a*x]))/(a*c*(n^2 - 4*(p + 1)^2)), x] - Dist[(2*(p + 1)*(2*p + 3))/(c*(n^2 - 4*(p + 1)^2
)), Int[(c + d*x^2)^(p + 1)*E^(n*ArcTanh[a*x]), x], x] /; FreeQ[{a, c, d, n}, x] && EqQ[a^2*c + d, 0] && LtQ[p
, -1] &&  !IntegerQ[n] && NeQ[n^2 - 4*(p + 1)^2, 0] && IntegerQ[2*p]

Rubi steps

\begin {align*} \int \frac {e^{\frac {1}{2} \tanh ^{-1}(a x)}}{\left (1-a^2 x^2\right )^{9/2}} \, dx &=-\frac {2 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-14 a x)}{195 a \left (1-a^2 x^2\right )^{7/2}}+\frac {56}{65} \int \frac {e^{\frac {1}{2} \tanh ^{-1}(a x)}}{\left (1-a^2 x^2\right )^{7/2}} \, dx\\ &=-\frac {2 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-14 a x)}{195 a \left (1-a^2 x^2\right )^{7/2}}-\frac {112 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-10 a x)}{6435 a \left (1-a^2 x^2\right )^{5/2}}+\frac {896 \int \frac {e^{\frac {1}{2} \tanh ^{-1}(a x)}}{\left (1-a^2 x^2\right )^{5/2}} \, dx}{1287}\\ &=-\frac {2 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-14 a x)}{195 a \left (1-a^2 x^2\right )^{7/2}}-\frac {112 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-10 a x)}{6435 a \left (1-a^2 x^2\right )^{5/2}}-\frac {256 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-6 a x)}{6435 a \left (1-a^2 x^2\right )^{3/2}}+\frac {1024 \int \frac {e^{\frac {1}{2} \tanh ^{-1}(a x)}}{\left (1-a^2 x^2\right )^{3/2}} \, dx}{2145}\\ &=-\frac {2 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-14 a x)}{195 a \left (1-a^2 x^2\right )^{7/2}}-\frac {112 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-10 a x)}{6435 a \left (1-a^2 x^2\right )^{5/2}}-\frac {256 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-6 a x)}{6435 a \left (1-a^2 x^2\right )^{3/2}}-\frac {2048 e^{\frac {1}{2} \tanh ^{-1}(a x)} (1-2 a x)}{6435 a \sqrt {1-a^2 x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 80, normalized size = 0.54 \[ -\frac {2 \left (2048 a^7 x^7-1024 a^6 x^6-6912 a^5 x^5+3200 a^4 x^4+8240 a^3 x^3-3384 a^2 x^2-3838 a x+1241\right )}{6435 a (1-a x)^{15/4} (a x+1)^{13/4}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[E^(ArcTanh[a*x]/2)/(1 - a^2*x^2)^(9/2),x]

[Out]

(-2*(1241 - 3838*a*x - 3384*a^2*x^2 + 8240*a^3*x^3 + 3200*a^4*x^4 - 6912*a^5*x^5 - 1024*a^6*x^6 + 2048*a^7*x^7
))/(6435*a*(1 - a*x)^(15/4)*(1 + a*x)^(13/4))

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fricas [A]  time = 1.67, size = 126, normalized size = 0.85 \[ -\frac {2 \, {\left (2048 \, a^{7} x^{7} - 1024 \, a^{6} x^{6} - 6912 \, a^{5} x^{5} + 3200 \, a^{4} x^{4} + 8240 \, a^{3} x^{3} - 3384 \, a^{2} x^{2} - 3838 \, a x + 1241\right )} \sqrt {-a^{2} x^{2} + 1} \sqrt {-\frac {\sqrt {-a^{2} x^{2} + 1}}{a x - 1}}}{6435 \, {\left (a^{9} x^{8} - 4 \, a^{7} x^{6} + 6 \, a^{5} x^{4} - 4 \, a^{3} x^{2} + a\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/(-a^2*x^2+1)^(9/2),x, algorithm="fricas")

[Out]

-2/6435*(2048*a^7*x^7 - 1024*a^6*x^6 - 6912*a^5*x^5 + 3200*a^4*x^4 + 8240*a^3*x^3 - 3384*a^2*x^2 - 3838*a*x +
1241)*sqrt(-a^2*x^2 + 1)*sqrt(-sqrt(-a^2*x^2 + 1)/(a*x - 1))/(a^9*x^8 - 4*a^7*x^6 + 6*a^5*x^4 - 4*a^3*x^2 + a)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {\frac {a x + 1}{\sqrt {-a^{2} x^{2} + 1}}}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac {9}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/(-a^2*x^2+1)^(9/2),x, algorithm="giac")

[Out]

integrate(sqrt((a*x + 1)/sqrt(-a^2*x^2 + 1))/(-a^2*x^2 + 1)^(9/2), x)

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maple [A]  time = 0.03, size = 102, normalized size = 0.68 \[ \frac {2 \left (a x -1\right ) \left (a x +1\right ) \left (2048 a^{7} x^{7}-1024 x^{6} a^{6}-6912 x^{5} a^{5}+3200 x^{4} a^{4}+8240 x^{3} a^{3}-3384 a^{2} x^{2}-3838 a x +1241\right ) \sqrt {\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}}}{6435 a \left (-a^{2} x^{2}+1\right )^{\frac {9}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/(-a^2*x^2+1)^(9/2),x)

[Out]

2/6435*(a*x-1)*(a*x+1)*(2048*a^7*x^7-1024*a^6*x^6-6912*a^5*x^5+3200*a^4*x^4+8240*a^3*x^3-3384*a^2*x^2-3838*a*x
+1241)*((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/a/(-a^2*x^2+1)^(9/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {\frac {a x + 1}{\sqrt {-a^{2} x^{2} + 1}}}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac {9}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((a*x+1)/(-a^2*x^2+1)^(1/2))^(1/2)/(-a^2*x^2+1)^(9/2),x, algorithm="maxima")

[Out]

integrate(sqrt((a*x + 1)/sqrt(-a^2*x^2 + 1))/(-a^2*x^2 + 1)^(9/2), x)

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mupad [B]  time = 1.46, size = 211, normalized size = 1.42 \[ -\frac {\sqrt {\frac {a\,x+1}{\sqrt {1-a^2\,x^2}}}\,\left (\frac {2482\,\sqrt {1-a^2\,x^2}}{6435\,a^9}-\frac {7676\,x\,\sqrt {1-a^2\,x^2}}{6435\,a^8}+\frac {4096\,x^7\,\sqrt {1-a^2\,x^2}}{6435\,a^2}-\frac {2048\,x^6\,\sqrt {1-a^2\,x^2}}{6435\,a^3}-\frac {1536\,x^5\,\sqrt {1-a^2\,x^2}}{715\,a^4}+\frac {1280\,x^4\,\sqrt {1-a^2\,x^2}}{1287\,a^5}+\frac {3296\,x^3\,\sqrt {1-a^2\,x^2}}{1287\,a^6}-\frac {752\,x^2\,\sqrt {1-a^2\,x^2}}{715\,a^7}\right )}{\frac {1}{a^8}+x^8-\frac {4\,x^6}{a^2}+\frac {6\,x^4}{a^4}-\frac {4\,x^2}{a^6}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a*x + 1)/(1 - a^2*x^2)^(1/2))^(1/2)/(1 - a^2*x^2)^(9/2),x)

[Out]

-(((a*x + 1)/(1 - a^2*x^2)^(1/2))^(1/2)*((2482*(1 - a^2*x^2)^(1/2))/(6435*a^9) - (7676*x*(1 - a^2*x^2)^(1/2))/
(6435*a^8) + (4096*x^7*(1 - a^2*x^2)^(1/2))/(6435*a^2) - (2048*x^6*(1 - a^2*x^2)^(1/2))/(6435*a^3) - (1536*x^5
*(1 - a^2*x^2)^(1/2))/(715*a^4) + (1280*x^4*(1 - a^2*x^2)^(1/2))/(1287*a^5) + (3296*x^3*(1 - a^2*x^2)^(1/2))/(
1287*a^6) - (752*x^2*(1 - a^2*x^2)^(1/2))/(715*a^7)))/(1/a^8 + x^8 - (4*x^6)/a^2 + (6*x^4)/a^4 - (4*x^2)/a^6)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((a*x+1)/(-a**2*x**2+1)**(1/2))**(1/2)/(-a**2*x**2+1)**(9/2),x)

[Out]

Timed out

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