3.1103 \(\int \frac {e^{2 \tanh ^{-1}(a x)} (c-a^2 c x^2)^{5/2}}{x^2} \, dx\)

Optimal. Leaf size=141 \[ -\frac {9}{8} a c^{5/2} \tan ^{-1}\left (\frac {a \sqrt {c} x}{\sqrt {c-a^2 c x^2}}\right )-2 a c^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c-a^2 c x^2}}{\sqrt {c}}\right )+\frac {1}{8} a c^2 (16-9 a x) \sqrt {c-a^2 c x^2}+\frac {1}{12} a c (8-9 a x) \left (c-a^2 c x^2\right )^{3/2}-\frac {\left (c-a^2 c x^2\right )^{5/2}}{x} \]

[Out]

1/12*a*c*(-9*a*x+8)*(-a^2*c*x^2+c)^(3/2)-(-a^2*c*x^2+c)^(5/2)/x-9/8*a*c^(5/2)*arctan(a*x*c^(1/2)/(-a^2*c*x^2+c
)^(1/2))-2*a*c^(5/2)*arctanh((-a^2*c*x^2+c)^(1/2)/c^(1/2))+1/8*a*c^2*(-9*a*x+16)*(-a^2*c*x^2+c)^(1/2)

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Rubi [A]  time = 0.33, antiderivative size = 141, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 9, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {6151, 1807, 815, 844, 217, 203, 266, 63, 208} \[ \frac {1}{8} a c^2 (16-9 a x) \sqrt {c-a^2 c x^2}-\frac {9}{8} a c^{5/2} \tan ^{-1}\left (\frac {a \sqrt {c} x}{\sqrt {c-a^2 c x^2}}\right )-2 a c^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c-a^2 c x^2}}{\sqrt {c}}\right )+\frac {1}{12} a c (8-9 a x) \left (c-a^2 c x^2\right )^{3/2}-\frac {\left (c-a^2 c x^2\right )^{5/2}}{x} \]

Antiderivative was successfully verified.

[In]

Int[(E^(2*ArcTanh[a*x])*(c - a^2*c*x^2)^(5/2))/x^2,x]

[Out]

(a*c^2*(16 - 9*a*x)*Sqrt[c - a^2*c*x^2])/8 + (a*c*(8 - 9*a*x)*(c - a^2*c*x^2)^(3/2))/12 - (c - a^2*c*x^2)^(5/2
)/x - (9*a*c^(5/2)*ArcTan[(a*Sqrt[c]*x)/Sqrt[c - a^2*c*x^2]])/8 - 2*a*c^(5/2)*ArcTanh[Sqrt[c - a^2*c*x^2]/Sqrt
[c]]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 203

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTan[(Rt[b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[b, 2]), x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 815

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[((d + e*x)^(
m + 1)*(c*e*f*(m + 2*p + 2) - g*c*d*(2*p + 1) + g*c*e*(m + 2*p + 1)*x)*(a + c*x^2)^p)/(c*e^2*(m + 2*p + 1)*(m
+ 2*p + 2)), x] + Dist[(2*p)/(c*e^2*(m + 2*p + 1)*(m + 2*p + 2)), Int[(d + e*x)^m*(a + c*x^2)^(p - 1)*Simp[f*a
*c*e^2*(m + 2*p + 2) + a*c*d*e*g*m - (c^2*f*d*e*(m + 2*p + 2) - g*(c^2*d^2*(2*p + 1) + a*c*e^2*(m + 2*p + 1)))
*x, x], x], x] /; FreeQ[{a, c, d, e, f, g, m}, x] && NeQ[c*d^2 + a*e^2, 0] && GtQ[p, 0] && (IntegerQ[p] ||  !R
ationalQ[m] || (GeQ[m, -1] && LtQ[m, 0])) &&  !ILtQ[m + 2*p, 0] && (IntegerQ[m] || IntegerQ[p] || IntegersQ[2*
m, 2*p])

Rule 844

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[g/e, Int[(d
+ e*x)^(m + 1)*(a + c*x^2)^p, x], x] + Dist[(e*f - d*g)/e, Int[(d + e*x)^m*(a + c*x^2)^p, x], x] /; FreeQ[{a,
c, d, e, f, g, m, p}, x] && NeQ[c*d^2 + a*e^2, 0] &&  !IGtQ[m, 0]

Rule 1807

Int[(Pq_)*((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{Q = PolynomialQuotient[Pq, c*x, x],
R = PolynomialRemainder[Pq, c*x, x]}, Simp[(R*(c*x)^(m + 1)*(a + b*x^2)^(p + 1))/(a*c*(m + 1)), x] + Dist[1/(
a*c*(m + 1)), Int[(c*x)^(m + 1)*(a + b*x^2)^p*ExpandToSum[a*c*(m + 1)*Q - b*R*(m + 2*p + 3)*x, x], x], x]] /;
FreeQ[{a, b, c, p}, x] && PolyQ[Pq, x] && LtQ[m, -1] && (IntegerQ[2*p] || NeQ[Expon[Pq, x], 1])

Rule 6151

Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*(x_)^(m_.)*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[c^(n/2), Int[x^m*(c
+ d*x^2)^(p - n/2)*(1 + a*x)^n, x], x] /; FreeQ[{a, c, d, m, p}, x] && EqQ[a^2*c + d, 0] &&  !(IntegerQ[p] ||
GtQ[c, 0]) && IGtQ[n/2, 0]

Rubi steps

\begin {align*} \int \frac {e^{2 \tanh ^{-1}(a x)} \left (c-a^2 c x^2\right )^{5/2}}{x^2} \, dx &=c \int \frac {(1+a x)^2 \left (c-a^2 c x^2\right )^{3/2}}{x^2} \, dx\\ &=-\frac {\left (c-a^2 c x^2\right )^{5/2}}{x}-\int \frac {\left (-2 a c+3 a^2 c x\right ) \left (c-a^2 c x^2\right )^{3/2}}{x} \, dx\\ &=\frac {1}{12} a c (8-9 a x) \left (c-a^2 c x^2\right )^{3/2}-\frac {\left (c-a^2 c x^2\right )^{5/2}}{x}+\frac {\int \frac {\left (8 a^3 c^3-9 a^4 c^3 x\right ) \sqrt {c-a^2 c x^2}}{x} \, dx}{4 a^2 c}\\ &=\frac {1}{8} a c^2 (16-9 a x) \sqrt {c-a^2 c x^2}+\frac {1}{12} a c (8-9 a x) \left (c-a^2 c x^2\right )^{3/2}-\frac {\left (c-a^2 c x^2\right )^{5/2}}{x}-\frac {\int \frac {-16 a^5 c^5+9 a^6 c^5 x}{x \sqrt {c-a^2 c x^2}} \, dx}{8 a^4 c^2}\\ &=\frac {1}{8} a c^2 (16-9 a x) \sqrt {c-a^2 c x^2}+\frac {1}{12} a c (8-9 a x) \left (c-a^2 c x^2\right )^{3/2}-\frac {\left (c-a^2 c x^2\right )^{5/2}}{x}+\left (2 a c^3\right ) \int \frac {1}{x \sqrt {c-a^2 c x^2}} \, dx-\frac {1}{8} \left (9 a^2 c^3\right ) \int \frac {1}{\sqrt {c-a^2 c x^2}} \, dx\\ &=\frac {1}{8} a c^2 (16-9 a x) \sqrt {c-a^2 c x^2}+\frac {1}{12} a c (8-9 a x) \left (c-a^2 c x^2\right )^{3/2}-\frac {\left (c-a^2 c x^2\right )^{5/2}}{x}+\left (a c^3\right ) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {c-a^2 c x}} \, dx,x,x^2\right )-\frac {1}{8} \left (9 a^2 c^3\right ) \operatorname {Subst}\left (\int \frac {1}{1+a^2 c x^2} \, dx,x,\frac {x}{\sqrt {c-a^2 c x^2}}\right )\\ &=\frac {1}{8} a c^2 (16-9 a x) \sqrt {c-a^2 c x^2}+\frac {1}{12} a c (8-9 a x) \left (c-a^2 c x^2\right )^{3/2}-\frac {\left (c-a^2 c x^2\right )^{5/2}}{x}-\frac {9}{8} a c^{5/2} \tan ^{-1}\left (\frac {a \sqrt {c} x}{\sqrt {c-a^2 c x^2}}\right )-\frac {\left (2 c^2\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {1}{a^2}-\frac {x^2}{a^2 c}} \, dx,x,\sqrt {c-a^2 c x^2}\right )}{a}\\ &=\frac {1}{8} a c^2 (16-9 a x) \sqrt {c-a^2 c x^2}+\frac {1}{12} a c (8-9 a x) \left (c-a^2 c x^2\right )^{3/2}-\frac {\left (c-a^2 c x^2\right )^{5/2}}{x}-\frac {9}{8} a c^{5/2} \tan ^{-1}\left (\frac {a \sqrt {c} x}{\sqrt {c-a^2 c x^2}}\right )-2 a c^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c-a^2 c x^2}}{\sqrt {c}}\right )\\ \end {align*}

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Mathematica [A]  time = 0.24, size = 143, normalized size = 1.01 \[ -2 a c^{5/2} \log \left (\sqrt {c} \sqrt {c-a^2 c x^2}+c\right )+\frac {9}{8} a c^{5/2} \tan ^{-1}\left (\frac {a x \sqrt {c-a^2 c x^2}}{\sqrt {c} \left (a^2 x^2-1\right )}\right )-\frac {c^2 \left (6 a^4 x^4+16 a^3 x^3-3 a^2 x^2-64 a x+24\right ) \sqrt {c-a^2 c x^2}}{24 x}+2 a c^{5/2} \log (x) \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(E^(2*ArcTanh[a*x])*(c - a^2*c*x^2)^(5/2))/x^2,x]

[Out]

-1/24*(c^2*Sqrt[c - a^2*c*x^2]*(24 - 64*a*x - 3*a^2*x^2 + 16*a^3*x^3 + 6*a^4*x^4))/x + (9*a*c^(5/2)*ArcTan[(a*
x*Sqrt[c - a^2*c*x^2])/(Sqrt[c]*(-1 + a^2*x^2))])/8 + 2*a*c^(5/2)*Log[x] - 2*a*c^(5/2)*Log[c + Sqrt[c]*Sqrt[c
- a^2*c*x^2]]

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fricas [A]  time = 0.75, size = 313, normalized size = 2.22 \[ \left [\frac {27 \, a c^{\frac {5}{2}} x \arctan \left (\frac {\sqrt {-a^{2} c x^{2} + c} a \sqrt {c} x}{a^{2} c x^{2} - c}\right ) + 24 \, a c^{\frac {5}{2}} x \log \left (-\frac {a^{2} c x^{2} + 2 \, \sqrt {-a^{2} c x^{2} + c} \sqrt {c} - 2 \, c}{x^{2}}\right ) - {\left (6 \, a^{4} c^{2} x^{4} + 16 \, a^{3} c^{2} x^{3} - 3 \, a^{2} c^{2} x^{2} - 64 \, a c^{2} x + 24 \, c^{2}\right )} \sqrt {-a^{2} c x^{2} + c}}{24 \, x}, -\frac {96 \, a \sqrt {-c} c^{2} x \arctan \left (\frac {\sqrt {-a^{2} c x^{2} + c} \sqrt {-c}}{a^{2} c x^{2} - c}\right ) - 27 \, a \sqrt {-c} c^{2} x \log \left (2 \, a^{2} c x^{2} - 2 \, \sqrt {-a^{2} c x^{2} + c} a \sqrt {-c} x - c\right ) + 2 \, {\left (6 \, a^{4} c^{2} x^{4} + 16 \, a^{3} c^{2} x^{3} - 3 \, a^{2} c^{2} x^{2} - 64 \, a c^{2} x + 24 \, c^{2}\right )} \sqrt {-a^{2} c x^{2} + c}}{48 \, x}\right ] \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^(5/2)/x^2,x, algorithm="fricas")

[Out]

[1/24*(27*a*c^(5/2)*x*arctan(sqrt(-a^2*c*x^2 + c)*a*sqrt(c)*x/(a^2*c*x^2 - c)) + 24*a*c^(5/2)*x*log(-(a^2*c*x^
2 + 2*sqrt(-a^2*c*x^2 + c)*sqrt(c) - 2*c)/x^2) - (6*a^4*c^2*x^4 + 16*a^3*c^2*x^3 - 3*a^2*c^2*x^2 - 64*a*c^2*x
+ 24*c^2)*sqrt(-a^2*c*x^2 + c))/x, -1/48*(96*a*sqrt(-c)*c^2*x*arctan(sqrt(-a^2*c*x^2 + c)*sqrt(-c)/(a^2*c*x^2
- c)) - 27*a*sqrt(-c)*c^2*x*log(2*a^2*c*x^2 - 2*sqrt(-a^2*c*x^2 + c)*a*sqrt(-c)*x - c) + 2*(6*a^4*c^2*x^4 + 16
*a^3*c^2*x^3 - 3*a^2*c^2*x^2 - 64*a*c^2*x + 24*c^2)*sqrt(-a^2*c*x^2 + c))/x]

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giac [A]  time = 0.98, size = 195, normalized size = 1.38 \[ \frac {4 \, a c^{3} \arctan \left (-\frac {\sqrt {-a^{2} c} x - \sqrt {-a^{2} c x^{2} + c}}{\sqrt {-c}}\right )}{\sqrt {-c}} - \frac {9 \, a^{2} \sqrt {-c} c^{2} \log \left ({\left | -\sqrt {-a^{2} c} x + \sqrt {-a^{2} c x^{2} + c} \right |}\right )}{8 \, {\left | a \right |}} + \frac {2 \, a^{2} \sqrt {-c} c^{3}}{{\left ({\left (\sqrt {-a^{2} c} x - \sqrt {-a^{2} c x^{2} + c}\right )}^{2} - c\right )} {\left | a \right |}} + \frac {1}{24} \, \sqrt {-a^{2} c x^{2} + c} {\left (64 \, a c^{2} + {\left (3 \, a^{2} c^{2} - 2 \, {\left (3 \, a^{4} c^{2} x + 8 \, a^{3} c^{2}\right )} x\right )} x\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^(5/2)/x^2,x, algorithm="giac")

[Out]

4*a*c^3*arctan(-(sqrt(-a^2*c)*x - sqrt(-a^2*c*x^2 + c))/sqrt(-c))/sqrt(-c) - 9/8*a^2*sqrt(-c)*c^2*log(abs(-sqr
t(-a^2*c)*x + sqrt(-a^2*c*x^2 + c)))/abs(a) + 2*a^2*sqrt(-c)*c^3/(((sqrt(-a^2*c)*x - sqrt(-a^2*c*x^2 + c))^2 -
c)*abs(a)) + 1/24*sqrt(-a^2*c*x^2 + c)*(64*a*c^2 + (3*a^2*c^2 - 2*(3*a^4*c^2*x + 8*a^3*c^2)*x)*x)

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maple [B]  time = 0.04, size = 367, normalized size = 2.60 \[ \frac {2 a \left (-a^{2} c \,x^{2}+c \right )^{\frac {5}{2}}}{5}+\frac {2 a c \left (-a^{2} c \,x^{2}+c \right )^{\frac {3}{2}}}{3}-2 a \,c^{\frac {5}{2}} \ln \left (\frac {2 c +2 \sqrt {c}\, \sqrt {-a^{2} c \,x^{2}+c}}{x}\right )+2 a \sqrt {-a^{2} c \,x^{2}+c}\, c^{2}-\frac {\left (-a^{2} c \,x^{2}+c \right )^{\frac {7}{2}}}{c x}-a^{2} x \left (-a^{2} c \,x^{2}+c \right )^{\frac {5}{2}}-\frac {5 a^{2} c x \left (-a^{2} c \,x^{2}+c \right )^{\frac {3}{2}}}{4}-\frac {15 a^{2} c^{2} x \sqrt {-a^{2} c \,x^{2}+c}}{8}-\frac {15 a^{2} c^{3} \arctan \left (\frac {\sqrt {a^{2} c}\, x}{\sqrt {-a^{2} c \,x^{2}+c}}\right )}{8 \sqrt {a^{2} c}}-\frac {2 a \left (-\left (x -\frac {1}{a}\right )^{2} a^{2} c -2 a c \left (x -\frac {1}{a}\right )\right )^{\frac {5}{2}}}{5}+\frac {a^{2} c \left (-\left (x -\frac {1}{a}\right )^{2} a^{2} c -2 a c \left (x -\frac {1}{a}\right )\right )^{\frac {3}{2}} x}{2}+\frac {3 a^{2} c^{2} \sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2} c -2 a c \left (x -\frac {1}{a}\right )}\, x}{4}+\frac {3 a^{2} c^{3} \arctan \left (\frac {\sqrt {a^{2} c}\, x}{\sqrt {-\left (x -\frac {1}{a}\right )^{2} a^{2} c -2 a c \left (x -\frac {1}{a}\right )}}\right )}{4 \sqrt {a^{2} c}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^(5/2)/x^2,x)

[Out]

2/5*a*(-a^2*c*x^2+c)^(5/2)+2/3*a*c*(-a^2*c*x^2+c)^(3/2)-2*a*c^(5/2)*ln((2*c+2*c^(1/2)*(-a^2*c*x^2+c)^(1/2))/x)
+2*a*(-a^2*c*x^2+c)^(1/2)*c^2-1/c/x*(-a^2*c*x^2+c)^(7/2)-a^2*x*(-a^2*c*x^2+c)^(5/2)-5/4*a^2*c*x*(-a^2*c*x^2+c)
^(3/2)-15/8*a^2*c^2*x*(-a^2*c*x^2+c)^(1/2)-15/8*a^2*c^3/(a^2*c)^(1/2)*arctan((a^2*c)^(1/2)*x/(-a^2*c*x^2+c)^(1
/2))-2/5*a*(-(x-1/a)^2*a^2*c-2*a*c*(x-1/a))^(5/2)+1/2*a^2*c*(-(x-1/a)^2*a^2*c-2*a*c*(x-1/a))^(3/2)*x+3/4*a^2*c
^2*(-(x-1/a)^2*a^2*c-2*a*c*(x-1/a))^(1/2)*x+3/4*a^2*c^3/(a^2*c)^(1/2)*arctan((a^2*c)^(1/2)*x/(-(x-1/a)^2*a^2*c
-2*a*c*(x-1/a))^(1/2))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\int \frac {{\left (-a^{2} c x^{2} + c\right )}^{\frac {5}{2}} {\left (a x + 1\right )}^{2}}{{\left (a^{2} x^{2} - 1\right )} x^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^(5/2)/x^2,x, algorithm="maxima")

[Out]

-integrate((-a^2*c*x^2 + c)^(5/2)*(a*x + 1)^2/((a^2*x^2 - 1)*x^2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ -\int \frac {{\left (c-a^2\,c\,x^2\right )}^{5/2}\,{\left (a\,x+1\right )}^2}{x^2\,\left (a^2\,x^2-1\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-((c - a^2*c*x^2)^(5/2)*(a*x + 1)^2)/(x^2*(a^2*x^2 - 1)),x)

[Out]

-int(((c - a^2*c*x^2)^(5/2)*(a*x + 1)^2)/(x^2*(a^2*x^2 - 1)), x)

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sympy [C]  time = 69.47, size = 483, normalized size = 3.43 \[ - a^{4} c^{2} \left (\begin {cases} \frac {i a^{2} \sqrt {c} x^{5}}{4 \sqrt {a^{2} x^{2} - 1}} - \frac {3 i \sqrt {c} x^{3}}{8 \sqrt {a^{2} x^{2} - 1}} + \frac {i \sqrt {c} x}{8 a^{2} \sqrt {a^{2} x^{2} - 1}} - \frac {i \sqrt {c} \operatorname {acosh}{\left (a x \right )}}{8 a^{3}} & \text {for}\: \left |{a^{2} x^{2}}\right | > 1 \\- \frac {a^{2} \sqrt {c} x^{5}}{4 \sqrt {- a^{2} x^{2} + 1}} + \frac {3 \sqrt {c} x^{3}}{8 \sqrt {- a^{2} x^{2} + 1}} - \frac {\sqrt {c} x}{8 a^{2} \sqrt {- a^{2} x^{2} + 1}} + \frac {\sqrt {c} \operatorname {asin}{\left (a x \right )}}{8 a^{3}} & \text {otherwise} \end {cases}\right ) - 2 a^{3} c^{2} \left (\begin {cases} 0 & \text {for}\: c = 0 \\\frac {\sqrt {c} x^{2}}{2} & \text {for}\: a^{2} = 0 \\- \frac {\left (- a^{2} c x^{2} + c\right )^{\frac {3}{2}}}{3 a^{2} c} & \text {otherwise} \end {cases}\right ) + 2 a c^{2} \left (\begin {cases} i \sqrt {c} \sqrt {a^{2} x^{2} - 1} - \sqrt {c} \log {\left (a x \right )} + \frac {\sqrt {c} \log {\left (a^{2} x^{2} \right )}}{2} + i \sqrt {c} \operatorname {asin}{\left (\frac {1}{a x} \right )} & \text {for}\: \left |{a^{2} x^{2}}\right | > 1 \\\sqrt {c} \sqrt {- a^{2} x^{2} + 1} + \frac {\sqrt {c} \log {\left (a^{2} x^{2} \right )}}{2} - \sqrt {c} \log {\left (\sqrt {- a^{2} x^{2} + 1} + 1 \right )} & \text {otherwise} \end {cases}\right ) + c^{2} \left (\begin {cases} - \frac {i a^{2} \sqrt {c} x}{\sqrt {a^{2} x^{2} - 1}} + i a \sqrt {c} \operatorname {acosh}{\left (a x \right )} + \frac {i \sqrt {c}}{x \sqrt {a^{2} x^{2} - 1}} & \text {for}\: \left |{a^{2} x^{2}}\right | > 1 \\\frac {a^{2} \sqrt {c} x}{\sqrt {- a^{2} x^{2} + 1}} - a \sqrt {c} \operatorname {asin}{\left (a x \right )} - \frac {\sqrt {c}}{x \sqrt {- a^{2} x^{2} + 1}} & \text {otherwise} \end {cases}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)**2/(-a**2*x**2+1)*(-a**2*c*x**2+c)**(5/2)/x**2,x)

[Out]

-a**4*c**2*Piecewise((I*a**2*sqrt(c)*x**5/(4*sqrt(a**2*x**2 - 1)) - 3*I*sqrt(c)*x**3/(8*sqrt(a**2*x**2 - 1)) +
I*sqrt(c)*x/(8*a**2*sqrt(a**2*x**2 - 1)) - I*sqrt(c)*acosh(a*x)/(8*a**3), Abs(a**2*x**2) > 1), (-a**2*sqrt(c)
*x**5/(4*sqrt(-a**2*x**2 + 1)) + 3*sqrt(c)*x**3/(8*sqrt(-a**2*x**2 + 1)) - sqrt(c)*x/(8*a**2*sqrt(-a**2*x**2 +
1)) + sqrt(c)*asin(a*x)/(8*a**3), True)) - 2*a**3*c**2*Piecewise((0, Eq(c, 0)), (sqrt(c)*x**2/2, Eq(a**2, 0))
, (-(-a**2*c*x**2 + c)**(3/2)/(3*a**2*c), True)) + 2*a*c**2*Piecewise((I*sqrt(c)*sqrt(a**2*x**2 - 1) - sqrt(c)
*log(a*x) + sqrt(c)*log(a**2*x**2)/2 + I*sqrt(c)*asin(1/(a*x)), Abs(a**2*x**2) > 1), (sqrt(c)*sqrt(-a**2*x**2
+ 1) + sqrt(c)*log(a**2*x**2)/2 - sqrt(c)*log(sqrt(-a**2*x**2 + 1) + 1), True)) + c**2*Piecewise((-I*a**2*sqrt
(c)*x/sqrt(a**2*x**2 - 1) + I*a*sqrt(c)*acosh(a*x) + I*sqrt(c)/(x*sqrt(a**2*x**2 - 1)), Abs(a**2*x**2) > 1), (
a**2*sqrt(c)*x/sqrt(-a**2*x**2 + 1) - a*sqrt(c)*asin(a*x) - sqrt(c)/(x*sqrt(-a**2*x**2 + 1)), True))

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