3.11 \(\int e^{2 \tanh ^{-1}(a x)} x^3 \, dx\)

Optimal. Leaf size=44 \[ -\frac {2 \log (1-a x)}{a^4}-\frac {2 x}{a^3}-\frac {x^2}{a^2}-\frac {2 x^3}{3 a}-\frac {x^4}{4} \]

[Out]

-2*x/a^3-x^2/a^2-2/3*x^3/a-1/4*x^4-2*ln(-a*x+1)/a^4

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Rubi [A]  time = 0.04, antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {6126, 77} \[ -\frac {x^2}{a^2}-\frac {2 x}{a^3}-\frac {2 \log (1-a x)}{a^4}-\frac {2 x^3}{3 a}-\frac {x^4}{4} \]

Antiderivative was successfully verified.

[In]

Int[E^(2*ArcTanh[a*x])*x^3,x]

[Out]

(-2*x)/a^3 - x^2/a^2 - (2*x^3)/(3*a) - x^4/4 - (2*Log[1 - a*x])/a^4

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rule 6126

Int[E^(ArcTanh[(a_.)*(x_)]*(n_))*(x_)^(m_.), x_Symbol] :> Int[(x^m*(1 + a*x)^(n/2))/(1 - a*x)^(n/2), x] /; Fre
eQ[{a, m, n}, x] &&  !IntegerQ[(n - 1)/2]

Rubi steps

\begin {align*} \int e^{2 \tanh ^{-1}(a x)} x^3 \, dx &=\int \frac {x^3 (1+a x)}{1-a x} \, dx\\ &=\int \left (-\frac {2}{a^3}-\frac {2 x}{a^2}-\frac {2 x^2}{a}-x^3-\frac {2}{a^3 (-1+a x)}\right ) \, dx\\ &=-\frac {2 x}{a^3}-\frac {x^2}{a^2}-\frac {2 x^3}{3 a}-\frac {x^4}{4}-\frac {2 \log (1-a x)}{a^4}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 44, normalized size = 1.00 \[ -\frac {2 \log (1-a x)}{a^4}-\frac {2 x}{a^3}-\frac {x^2}{a^2}-\frac {2 x^3}{3 a}-\frac {x^4}{4} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(2*ArcTanh[a*x])*x^3,x]

[Out]

(-2*x)/a^3 - x^2/a^2 - (2*x^3)/(3*a) - x^4/4 - (2*Log[1 - a*x])/a^4

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fricas [A]  time = 0.40, size = 42, normalized size = 0.95 \[ -\frac {3 \, a^{4} x^{4} + 8 \, a^{3} x^{3} + 12 \, a^{2} x^{2} + 24 \, a x + 24 \, \log \left (a x - 1\right )}{12 \, a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*x^3,x, algorithm="fricas")

[Out]

-1/12*(3*a^4*x^4 + 8*a^3*x^3 + 12*a^2*x^2 + 24*a*x + 24*log(a*x - 1))/a^4

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giac [A]  time = 0.93, size = 47, normalized size = 1.07 \[ -\frac {3 \, a^{4} x^{4} + 8 \, a^{3} x^{3} + 12 \, a^{2} x^{2} + 24 \, a x}{12 \, a^{4}} - \frac {2 \, \log \left ({\left | a x - 1 \right |}\right )}{a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*x^3,x, algorithm="giac")

[Out]

-1/12*(3*a^4*x^4 + 8*a^3*x^3 + 12*a^2*x^2 + 24*a*x)/a^4 - 2*log(abs(a*x - 1))/a^4

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maple [A]  time = 0.03, size = 40, normalized size = 0.91 \[ -\frac {x^{4}}{4}-\frac {2 x^{3}}{3 a}-\frac {x^{2}}{a^{2}}-\frac {2 x}{a^{3}}-\frac {2 \ln \left (a x -1\right )}{a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)^2/(-a^2*x^2+1)*x^3,x)

[Out]

-1/4*x^4-2/3*x^3/a-x^2/a^2-2*x/a^3-2/a^4*ln(a*x-1)

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maxima [A]  time = 0.31, size = 43, normalized size = 0.98 \[ -\frac {3 \, a^{3} x^{4} + 8 \, a^{2} x^{3} + 12 \, a x^{2} + 24 \, x}{12 \, a^{3}} - \frac {2 \, \log \left (a x - 1\right )}{a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*x^3,x, algorithm="maxima")

[Out]

-1/12*(3*a^3*x^4 + 8*a^2*x^3 + 12*a*x^2 + 24*x)/a^3 - 2*log(a*x - 1)/a^4

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mupad [B]  time = 0.05, size = 39, normalized size = 0.89 \[ -\frac {2\,\ln \left (a\,x-1\right )}{a^4}-\frac {2\,x}{a^3}-\frac {x^4}{4}-\frac {2\,x^3}{3\,a}-\frac {x^2}{a^2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(x^3*(a*x + 1)^2)/(a^2*x^2 - 1),x)

[Out]

- (2*log(a*x - 1))/a^4 - (2*x)/a^3 - x^4/4 - (2*x^3)/(3*a) - x^2/a^2

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sympy [A]  time = 0.11, size = 39, normalized size = 0.89 \[ - \frac {x^{4}}{4} - \frac {2 x^{3}}{3 a} - \frac {x^{2}}{a^{2}} - \frac {2 x}{a^{3}} - \frac {2 \log {\left (a x - 1 \right )}}{a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)**2/(-a**2*x**2+1)*x**3,x)

[Out]

-x**4/4 - 2*x**3/(3*a) - x**2/a**2 - 2*x/a**3 - 2*log(a*x - 1)/a**4

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