3.1043 \(\int e^{2 \tanh ^{-1}(a x)} (c-a^2 c x^2)^3 \, dx\)

Optimal. Leaf size=52 \[ \frac {c^3 (a x+1)^7}{7 a}-\frac {2 c^3 (a x+1)^6}{3 a}+\frac {4 c^3 (a x+1)^5}{5 a} \]

[Out]

4/5*c^3*(a*x+1)^5/a-2/3*c^3*(a*x+1)^6/a+1/7*c^3*(a*x+1)^7/a

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Rubi [A]  time = 0.05, antiderivative size = 52, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {6140, 43} \[ \frac {c^3 (a x+1)^7}{7 a}-\frac {2 c^3 (a x+1)^6}{3 a}+\frac {4 c^3 (a x+1)^5}{5 a} \]

Antiderivative was successfully verified.

[In]

Int[E^(2*ArcTanh[a*x])*(c - a^2*c*x^2)^3,x]

[Out]

(4*c^3*(1 + a*x)^5)/(5*a) - (2*c^3*(1 + a*x)^6)/(3*a) + (c^3*(1 + a*x)^7)/(7*a)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 6140

Int[E^(ArcTanh[(a_.)*(x_)]*(n_.))*((c_) + (d_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[c^p, Int[(1 - a*x)^(p - n/2)*
(1 + a*x)^(p + n/2), x], x] /; FreeQ[{a, c, d, n, p}, x] && EqQ[a^2*c + d, 0] && (IntegerQ[p] || GtQ[c, 0])

Rubi steps

\begin {align*} \int e^{2 \tanh ^{-1}(a x)} \left (c-a^2 c x^2\right )^3 \, dx &=c^3 \int (1-a x)^2 (1+a x)^4 \, dx\\ &=c^3 \int \left (4 (1+a x)^4-4 (1+a x)^5+(1+a x)^6\right ) \, dx\\ &=\frac {4 c^3 (1+a x)^5}{5 a}-\frac {2 c^3 (1+a x)^6}{3 a}+\frac {c^3 (1+a x)^7}{7 a}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 31, normalized size = 0.60 \[ \frac {c^3 (a x+1)^5 \left (15 a^2 x^2-40 a x+29\right )}{105 a} \]

Antiderivative was successfully verified.

[In]

Integrate[E^(2*ArcTanh[a*x])*(c - a^2*c*x^2)^3,x]

[Out]

(c^3*(1 + a*x)^5*(29 - 40*a*x + 15*a^2*x^2))/(105*a)

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fricas [A]  time = 0.73, size = 69, normalized size = 1.33 \[ \frac {1}{7} \, a^{6} c^{3} x^{7} + \frac {1}{3} \, a^{5} c^{3} x^{6} - \frac {1}{5} \, a^{4} c^{3} x^{5} - a^{3} c^{3} x^{4} - \frac {1}{3} \, a^{2} c^{3} x^{3} + a c^{3} x^{2} + c^{3} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^3,x, algorithm="fricas")

[Out]

1/7*a^6*c^3*x^7 + 1/3*a^5*c^3*x^6 - 1/5*a^4*c^3*x^5 - a^3*c^3*x^4 - 1/3*a^2*c^3*x^3 + a*c^3*x^2 + c^3*x

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giac [A]  time = 0.18, size = 69, normalized size = 1.33 \[ \frac {1}{7} \, a^{6} c^{3} x^{7} + \frac {1}{3} \, a^{5} c^{3} x^{6} - \frac {1}{5} \, a^{4} c^{3} x^{5} - a^{3} c^{3} x^{4} - \frac {1}{3} \, a^{2} c^{3} x^{3} + a c^{3} x^{2} + c^{3} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^3,x, algorithm="giac")

[Out]

1/7*a^6*c^3*x^7 + 1/3*a^5*c^3*x^6 - 1/5*a^4*c^3*x^5 - a^3*c^3*x^4 - 1/3*a^2*c^3*x^3 + a*c^3*x^2 + c^3*x

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maple [A]  time = 0.03, size = 52, normalized size = 1.00 \[ c^{3} \left (\frac {1}{7} x^{7} a^{6}+\frac {1}{3} x^{6} a^{5}-\frac {1}{5} a^{4} x^{5}-x^{4} a^{3}-\frac {1}{3} x^{3} a^{2}+a \,x^{2}+x \right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^3,x)

[Out]

c^3*(1/7*x^7*a^6+1/3*x^6*a^5-1/5*a^4*x^5-x^4*a^3-1/3*x^3*a^2+a*x^2+x)

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maxima [A]  time = 0.33, size = 69, normalized size = 1.33 \[ \frac {1}{7} \, a^{6} c^{3} x^{7} + \frac {1}{3} \, a^{5} c^{3} x^{6} - \frac {1}{5} \, a^{4} c^{3} x^{5} - a^{3} c^{3} x^{4} - \frac {1}{3} \, a^{2} c^{3} x^{3} + a c^{3} x^{2} + c^{3} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)^2/(-a^2*x^2+1)*(-a^2*c*x^2+c)^3,x, algorithm="maxima")

[Out]

1/7*a^6*c^3*x^7 + 1/3*a^5*c^3*x^6 - 1/5*a^4*c^3*x^5 - a^3*c^3*x^4 - 1/3*a^2*c^3*x^3 + a*c^3*x^2 + c^3*x

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mupad [B]  time = 0.04, size = 69, normalized size = 1.33 \[ \frac {a^6\,c^3\,x^7}{7}+\frac {a^5\,c^3\,x^6}{3}-\frac {a^4\,c^3\,x^5}{5}-a^3\,c^3\,x^4-\frac {a^2\,c^3\,x^3}{3}+a\,c^3\,x^2+c^3\,x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-((c - a^2*c*x^2)^3*(a*x + 1)^2)/(a^2*x^2 - 1),x)

[Out]

c^3*x + a*c^3*x^2 - (a^2*c^3*x^3)/3 - a^3*c^3*x^4 - (a^4*c^3*x^5)/5 + (a^5*c^3*x^6)/3 + (a^6*c^3*x^7)/7

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sympy [A]  time = 0.09, size = 70, normalized size = 1.35 \[ \frac {a^{6} c^{3} x^{7}}{7} + \frac {a^{5} c^{3} x^{6}}{3} - \frac {a^{4} c^{3} x^{5}}{5} - a^{3} c^{3} x^{4} - \frac {a^{2} c^{3} x^{3}}{3} + a c^{3} x^{2} + c^{3} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x+1)**2/(-a**2*x**2+1)*(-a**2*c*x**2+c)**3,x)

[Out]

a**6*c**3*x**7/7 + a**5*c**3*x**6/3 - a**4*c**3*x**5/5 - a**3*c**3*x**4 - a**2*c**3*x**3/3 + a*c**3*x**2 + c**
3*x

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