3.357 \(\int \frac {e^{\sinh ^{-1}(a+b x)}}{x^5} \, dx\)

Optimal. Leaf size=207 \[ \frac {\left (1-4 a^2\right ) b^2 \left (a^2+a b x+1\right ) \sqrt {a^2+2 a b x+b^2 x^2+1}}{8 \left (a^2+1\right )^3 x^2}-\frac {\left (a^2+2 a b x+b^2 x^2+1\right )^{3/2}}{4 \left (a^2+1\right ) x^4}+\frac {5 a b \left (a^2+2 a b x+b^2 x^2+1\right )^{3/2}}{12 \left (a^2+1\right )^2 x^3}+\frac {\left (1-4 a^2\right ) b^4 \tanh ^{-1}\left (\frac {a^2+a b x+1}{\sqrt {a^2+1} \sqrt {a^2+2 a b x+b^2 x^2+1}}\right )}{8 \left (a^2+1\right )^{7/2}}-\frac {a}{4 x^4}-\frac {b}{3 x^3} \]

[Out]

-1/4*a/x^4-1/3*b/x^3-1/4*(b^2*x^2+2*a*b*x+a^2+1)^(3/2)/(a^2+1)/x^4+5/12*a*b*(b^2*x^2+2*a*b*x+a^2+1)^(3/2)/(a^2
+1)^2/x^3+1/8*(-4*a^2+1)*b^4*arctanh((a*b*x+a^2+1)/(a^2+1)^(1/2)/(b^2*x^2+2*a*b*x+a^2+1)^(1/2))/(a^2+1)^(7/2)+
1/8*(-4*a^2+1)*b^2*(a*b*x+a^2+1)*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)/(a^2+1)^3/x^2

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Rubi [A]  time = 0.17, antiderivative size = 207, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {5907, 14, 744, 806, 720, 724, 206} \[ \frac {\left (1-4 a^2\right ) b^2 \left (a^2+a b x+1\right ) \sqrt {a^2+2 a b x+b^2 x^2+1}}{8 \left (a^2+1\right )^3 x^2}+\frac {5 a b \left (a^2+2 a b x+b^2 x^2+1\right )^{3/2}}{12 \left (a^2+1\right )^2 x^3}-\frac {\left (a^2+2 a b x+b^2 x^2+1\right )^{3/2}}{4 \left (a^2+1\right ) x^4}+\frac {\left (1-4 a^2\right ) b^4 \tanh ^{-1}\left (\frac {a^2+a b x+1}{\sqrt {a^2+1} \sqrt {a^2+2 a b x+b^2 x^2+1}}\right )}{8 \left (a^2+1\right )^{7/2}}-\frac {a}{4 x^4}-\frac {b}{3 x^3} \]

Antiderivative was successfully verified.

[In]

Int[E^ArcSinh[a + b*x]/x^5,x]

[Out]

-a/(4*x^4) - b/(3*x^3) + ((1 - 4*a^2)*b^2*(1 + a^2 + a*b*x)*Sqrt[1 + a^2 + 2*a*b*x + b^2*x^2])/(8*(1 + a^2)^3*
x^2) - (1 + a^2 + 2*a*b*x + b^2*x^2)^(3/2)/(4*(1 + a^2)*x^4) + (5*a*b*(1 + a^2 + 2*a*b*x + b^2*x^2)^(3/2))/(12
*(1 + a^2)^2*x^3) + ((1 - 4*a^2)*b^4*ArcTanh[(1 + a^2 + a*b*x)/(Sqrt[1 + a^2]*Sqrt[1 + a^2 + 2*a*b*x + b^2*x^2
])])/(8*(1 + a^2)^(7/2))

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
&&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 720

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> -Simp[((d + e*x)^(m + 1)*
(d*b - 2*a*e + (2*c*d - b*e)*x)*(a + b*x + c*x^2)^p)/(2*(m + 1)*(c*d^2 - b*d*e + a*e^2)), x] + Dist[(p*(b^2 -
4*a*c))/(2*(m + 1)*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^(m + 2)*(a + b*x + c*x^2)^(p - 1), x], x] /; FreeQ[
{a, b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ[2*c*d - b*e, 0] && EqQ[m +
2*p + 2, 0] && GtQ[p, 0]

Rule 724

Int[1/(((d_.) + (e_.)*(x_))*Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2]), x_Symbol] :> Dist[-2, Subst[Int[1/(4*c*d
^2 - 4*b*d*e + 4*a*e^2 - x^2), x], x, (2*a*e - b*d - (2*c*d - b*e)*x)/Sqrt[a + b*x + c*x^2]], x] /; FreeQ[{a,
b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[2*c*d - b*e, 0]

Rule 744

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e*(d + e*x)^(m + 1)
*(a + b*x + c*x^2)^(p + 1))/((m + 1)*(c*d^2 - b*d*e + a*e^2)), x] + Dist[1/((m + 1)*(c*d^2 - b*d*e + a*e^2)),
Int[(d + e*x)^(m + 1)*Simp[c*d*(m + 1) - b*e*(m + p + 2) - c*e*(m + 2*p + 3)*x, x]*(a + b*x + c*x^2)^p, x], x]
/; FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ[2*c*d - b*e
, 0] && NeQ[m, -1] && ((LtQ[m, -1] && IntQuadraticQ[a, b, c, d, e, m, p, x]) || (SumSimplerQ[m, 1] && IntegerQ
[p]) || ILtQ[Simplify[m + 2*p + 3], 0])

Rule 806

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> -Si
mp[((e*f - d*g)*(d + e*x)^(m + 1)*(a + b*x + c*x^2)^(p + 1))/(2*(p + 1)*(c*d^2 - b*d*e + a*e^2)), x] - Dist[(b
*(e*f + d*g) - 2*(c*d*f + a*e*g))/(2*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p, x],
x] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && EqQ[Sim
plify[m + 2*p + 3], 0]

Rule 5907

Int[E^(ArcSinh[u_]*(n_.))*(x_)^(m_.), x_Symbol] :> Int[x^m*(u + Sqrt[1 + u^2])^n, x] /; RationalQ[m] && Intege
rQ[n] && PolynomialQ[u, x]

Rubi steps

\begin {align*} \int \frac {e^{\sinh ^{-1}(a+b x)}}{x^5} \, dx &=\int \frac {a+b x+\sqrt {1+(a+b x)^2}}{x^5} \, dx\\ &=\int \left (\frac {a}{x^5}+\frac {b}{x^4}+\frac {\sqrt {1+a^2+2 a b x+b^2 x^2}}{x^5}\right ) \, dx\\ &=-\frac {a}{4 x^4}-\frac {b}{3 x^3}+\int \frac {\sqrt {1+a^2+2 a b x+b^2 x^2}}{x^5} \, dx\\ &=-\frac {a}{4 x^4}-\frac {b}{3 x^3}-\frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{4 \left (1+a^2\right ) x^4}-\frac {\int \frac {\left (5 a b+b^2 x\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}}{x^4} \, dx}{4 \left (1+a^2\right )}\\ &=-\frac {a}{4 x^4}-\frac {b}{3 x^3}-\frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{4 \left (1+a^2\right ) x^4}+\frac {5 a b \left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{12 \left (1+a^2\right )^2 x^3}-\frac {\left (\left (1-4 a^2\right ) b^2\right ) \int \frac {\sqrt {1+a^2+2 a b x+b^2 x^2}}{x^3} \, dx}{4 \left (1+a^2\right )^2}\\ &=-\frac {a}{4 x^4}-\frac {b}{3 x^3}+\frac {\left (1-4 a^2\right ) b^2 \left (1+a^2+a b x\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}}{8 \left (1+a^2\right )^3 x^2}-\frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{4 \left (1+a^2\right ) x^4}+\frac {5 a b \left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{12 \left (1+a^2\right )^2 x^3}-\frac {\left (\left (1-4 a^2\right ) b^4\right ) \int \frac {1}{x \sqrt {1+a^2+2 a b x+b^2 x^2}} \, dx}{8 \left (1+a^2\right )^3}\\ &=-\frac {a}{4 x^4}-\frac {b}{3 x^3}+\frac {\left (1-4 a^2\right ) b^2 \left (1+a^2+a b x\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}}{8 \left (1+a^2\right )^3 x^2}-\frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{4 \left (1+a^2\right ) x^4}+\frac {5 a b \left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{12 \left (1+a^2\right )^2 x^3}+\frac {\left (\left (1-4 a^2\right ) b^4\right ) \operatorname {Subst}\left (\int \frac {1}{4 \left (1+a^2\right )-x^2} \, dx,x,\frac {2 \left (1+a^2\right )+2 a b x}{\sqrt {1+a^2+2 a b x+b^2 x^2}}\right )}{4 \left (1+a^2\right )^3}\\ &=-\frac {a}{4 x^4}-\frac {b}{3 x^3}+\frac {\left (1-4 a^2\right ) b^2 \left (1+a^2+a b x\right ) \sqrt {1+a^2+2 a b x+b^2 x^2}}{8 \left (1+a^2\right )^3 x^2}-\frac {\left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{4 \left (1+a^2\right ) x^4}+\frac {5 a b \left (1+a^2+2 a b x+b^2 x^2\right )^{3/2}}{12 \left (1+a^2\right )^2 x^3}+\frac {\left (1-4 a^2\right ) b^4 \tanh ^{-1}\left (\frac {1+a^2+a b x}{\sqrt {1+a^2} \sqrt {1+a^2+2 a b x+b^2 x^2}}\right )}{8 \left (1+a^2\right )^{7/2}}\\ \end {align*}

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Mathematica [A]  time = 0.81, size = 192, normalized size = 0.93 \[ \frac {1}{24} \left (\frac {3 (2 a-1) (2 a+1) b^4 \log (x)}{\left (a^2+1\right )^{7/2}}-\frac {3 (2 a-1) (2 a+1) b^4 \log \left (\sqrt {a^2+1} \sqrt {a^2+2 a b x+b^2 x^2+1}+a^2+a b x+1\right )}{\left (a^2+1\right )^{7/2}}-\frac {\sqrt {a^2+2 a b x+b^2 x^2+1} \left (\frac {a \left (2 a^2-13\right ) b^3 x^3}{\left (a^2+1\right )^3}-\frac {\left (2 a^2-3\right ) b^2 x^2}{\left (a^2+1\right )^2}+\frac {2 a b x}{a^2+1}+6\right )}{x^4}-\frac {6 a}{x^4}-\frac {8 b}{x^3}\right ) \]

Warning: Unable to verify antiderivative.

[In]

Integrate[E^ArcSinh[a + b*x]/x^5,x]

[Out]

((-6*a)/x^4 - (8*b)/x^3 - (Sqrt[1 + a^2 + 2*a*b*x + b^2*x^2]*(6 + (2*a*b*x)/(1 + a^2) - ((-3 + 2*a^2)*b^2*x^2)
/(1 + a^2)^2 + (a*(-13 + 2*a^2)*b^3*x^3)/(1 + a^2)^3))/x^4 + (3*(-1 + 2*a)*(1 + 2*a)*b^4*Log[x])/(1 + a^2)^(7/
2) - (3*(-1 + 2*a)*(1 + 2*a)*b^4*Log[1 + a^2 + a*b*x + Sqrt[1 + a^2]*Sqrt[1 + a^2 + 2*a*b*x + b^2*x^2]])/(1 +
a^2)^(7/2))/24

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fricas [A]  time = 0.69, size = 295, normalized size = 1.43 \[ \frac {3 \, {\left (4 \, a^{2} - 1\right )} \sqrt {a^{2} + 1} b^{4} x^{4} \log \left (-\frac {a^{2} b x + a^{3} + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} {\left (a^{2} - \sqrt {a^{2} + 1} a + 1\right )} - {\left (a b x + a^{2} + 1\right )} \sqrt {a^{2} + 1} + a}{x}\right ) - 6 \, a^{9} - {\left (2 \, a^{5} - 11 \, a^{3} - 13 \, a\right )} b^{4} x^{4} - 24 \, a^{7} - 36 \, a^{5} - 24 \, a^{3} - 8 \, {\left (a^{8} + 4 \, a^{6} + 6 \, a^{4} + 4 \, a^{2} + 1\right )} b x - {\left (6 \, a^{8} + {\left (2 \, a^{5} - 11 \, a^{3} - 13 \, a\right )} b^{3} x^{3} + 24 \, a^{6} - {\left (2 \, a^{6} + a^{4} - 4 \, a^{2} - 3\right )} b^{2} x^{2} + 36 \, a^{4} + 2 \, {\left (a^{7} + 3 \, a^{5} + 3 \, a^{3} + a\right )} b x + 24 \, a^{2} + 6\right )} \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} - 6 \, a}{24 \, {\left (a^{8} + 4 \, a^{6} + 6 \, a^{4} + 4 \, a^{2} + 1\right )} x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a+(1+(b*x+a)^2)^(1/2))/x^5,x, algorithm="fricas")

[Out]

1/24*(3*(4*a^2 - 1)*sqrt(a^2 + 1)*b^4*x^4*log(-(a^2*b*x + a^3 + sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1)*(a^2 - sqrt(
a^2 + 1)*a + 1) - (a*b*x + a^2 + 1)*sqrt(a^2 + 1) + a)/x) - 6*a^9 - (2*a^5 - 11*a^3 - 13*a)*b^4*x^4 - 24*a^7 -
36*a^5 - 24*a^3 - 8*(a^8 + 4*a^6 + 6*a^4 + 4*a^2 + 1)*b*x - (6*a^8 + (2*a^5 - 11*a^3 - 13*a)*b^3*x^3 + 24*a^6
- (2*a^6 + a^4 - 4*a^2 - 3)*b^2*x^2 + 36*a^4 + 2*(a^7 + 3*a^5 + 3*a^3 + a)*b*x + 24*a^2 + 6)*sqrt(b^2*x^2 + 2
*a*b*x + a^2 + 1) - 6*a)/((a^8 + 4*a^6 + 6*a^4 + 4*a^2 + 1)*x^4)

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giac [B]  time = 0.49, size = 1173, normalized size = 5.67 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a+(1+(b*x+a)^2)^(1/2))/x^5,x, algorithm="giac")

[Out]

1/8*(4*a^2*b^4 - b^4)*log(abs(-2*x*abs(b) + 2*sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1) - 2*sqrt(a^2 + 1))/abs(-2*x*ab
s(b) + 2*sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1) + 2*sqrt(a^2 + 1)))/((a^6 + 3*a^4 + 3*a^2 + 1)*sqrt(a^2 + 1)) - 1/1
2*(4*b*x + 3*a)/x^4 + 1/12*(32*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^5*a^6*b^4 + 256*(x*abs(b) - sqrt
(b^2*x^2 + 2*a*b*x + a^2 + 1))^3*a^8*b^4 + 96*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))*a^10*b^4 + 144*(x
*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^4*a^7*b^3*abs(b) + 224*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 +
1))^2*a^9*b^3*abs(b) + 16*a^11*b^3*abs(b) - 12*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^7*a^2*b^4 + 140
*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^5*a^4*b^4 + 716*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))
^3*a^6*b^4 + 372*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))*a^8*b^4 + 432*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b
*x + a^2 + 1))^4*a^5*b^3*abs(b) + 704*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^2*a^7*b^3*abs(b) + 80*a^9
*b^3*abs(b) + 3*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^7*b^4 + 129*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x
+ a^2 + 1))^5*a^2*b^4 + 685*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^3*a^4*b^4 + 543*(x*abs(b) - sqrt(b^
2*x^2 + 2*a*b*x + a^2 + 1))*a^6*b^4 + 432*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^4*a^3*b^3*abs(b) + 76
8*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^2*a^5*b^3*abs(b) + 160*a^7*b^3*abs(b) + 21*(x*abs(b) - sqrt(b
^2*x^2 + 2*a*b*x + a^2 + 1))^5*b^4 + 246*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^3*a^2*b^4 + 357*(x*abs
(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))*a^4*b^4 + 144*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^4*a*b^3*
abs(b) + 320*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^2*a^3*b^3*abs(b) + 160*a^5*b^3*abs(b) + 21*(x*abs(
b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^3*b^4 + 93*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))*a^2*b^4 + 32
*(x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1))^2*a*b^3*abs(b) + 80*a^3*b^3*abs(b) + 3*(x*abs(b) - sqrt(b^2*x^
2 + 2*a*b*x + a^2 + 1))*b^4 + 16*a*b^3*abs(b))/((a^6 + 3*a^4 + 3*a^2 + 1)*((x*abs(b) - sqrt(b^2*x^2 + 2*a*b*x
+ a^2 + 1))^2 - a^2 - 1)^4)

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maple [B]  time = 0.01, size = 841, normalized size = 4.06 \[ -\frac {\left (b^{2} x^{2}+2 a b x +a^{2}+1\right )^{\frac {3}{2}}}{4 \left (a^{2}+1\right ) x^{4}}+\frac {5 a b \left (b^{2} x^{2}+2 a b x +a^{2}+1\right )^{\frac {3}{2}}}{12 \left (a^{2}+1\right )^{2} x^{3}}-\frac {5 a^{2} b^{2} \left (b^{2} x^{2}+2 a b x +a^{2}+1\right )^{\frac {3}{2}}}{8 \left (a^{2}+1\right )^{3} x^{2}}+\frac {5 a^{3} b^{3} \left (b^{2} x^{2}+2 a b x +a^{2}+1\right )^{\frac {3}{2}}}{8 \left (a^{2}+1\right )^{4} x}-\frac {5 a^{4} b^{4} \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{4 \left (a^{2}+1\right )^{4}}-\frac {5 a^{5} b^{5} \ln \left (\frac {b^{2} x +a b}{\sqrt {b^{2}}}+\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\right )}{8 \left (a^{2}+1\right )^{4} \sqrt {b^{2}}}+\frac {5 a^{4} b^{4} \ln \left (\frac {2 a^{2}+2+2 a b x +2 \sqrt {a^{2}+1}\, \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{x}\right )}{8 \left (a^{2}+1\right )^{\frac {7}{2}}}-\frac {5 a^{3} b^{5} \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\, x}{8 \left (a^{2}+1\right )^{4}}-\frac {5 a^{3} b^{5} \ln \left (\frac {b^{2} x +a b}{\sqrt {b^{2}}}+\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\right )}{8 \left (a^{2}+1\right )^{4} \sqrt {b^{2}}}+\frac {7 a^{2} b^{4} \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{8 \left (a^{2}+1\right )^{3}}+\frac {3 a^{3} b^{5} \ln \left (\frac {b^{2} x +a b}{\sqrt {b^{2}}}+\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\right )}{4 \left (a^{2}+1\right )^{3} \sqrt {b^{2}}}-\frac {3 a^{2} b^{4} \ln \left (\frac {2 a^{2}+2+2 a b x +2 \sqrt {a^{2}+1}\, \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{x}\right )}{4 \left (a^{2}+1\right )^{\frac {5}{2}}}+\frac {b^{2} \left (b^{2} x^{2}+2 a b x +a^{2}+1\right )^{\frac {3}{2}}}{8 \left (a^{2}+1\right )^{2} x^{2}}-\frac {b^{3} a \left (b^{2} x^{2}+2 a b x +a^{2}+1\right )^{\frac {3}{2}}}{8 \left (a^{2}+1\right )^{3} x}+\frac {b^{5} a \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\, x}{8 \left (a^{2}+1\right )^{3}}+\frac {b^{5} a \ln \left (\frac {b^{2} x +a b}{\sqrt {b^{2}}}+\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\right )}{8 \left (a^{2}+1\right )^{3} \sqrt {b^{2}}}-\frac {b^{4} \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{8 \left (a^{2}+1\right )^{2}}-\frac {b^{5} a \ln \left (\frac {b^{2} x +a b}{\sqrt {b^{2}}}+\sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}\right )}{8 \left (a^{2}+1\right )^{2} \sqrt {b^{2}}}+\frac {b^{4} \ln \left (\frac {2 a^{2}+2+2 a b x +2 \sqrt {a^{2}+1}\, \sqrt {b^{2} x^{2}+2 a b x +a^{2}+1}}{x}\right )}{8 \left (a^{2}+1\right )^{\frac {3}{2}}}-\frac {b}{3 x^{3}}-\frac {a}{4 x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a+(1+(b*x+a)^2)^(1/2))/x^5,x)

[Out]

-1/4*(b^2*x^2+2*a*b*x+a^2+1)^(3/2)/(a^2+1)/x^4+5/12*a*b*(b^2*x^2+2*a*b*x+a^2+1)^(3/2)/(a^2+1)^2/x^3-5/8*a^2*b^
2/(a^2+1)^3/x^2*(b^2*x^2+2*a*b*x+a^2+1)^(3/2)+5/8*a^3*b^3/(a^2+1)^4/x*(b^2*x^2+2*a*b*x+a^2+1)^(3/2)-5/4*a^4*b^
4/(a^2+1)^4*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)-5/8*a^5*b^5/(a^2+1)^4*ln((b^2*x+a*b)/(b^2)^(1/2)+(b^2*x^2+2*a*b*x+a^
2+1)^(1/2))/(b^2)^(1/2)+5/8*a^4*b^4/(a^2+1)^(7/2)*ln((2*a^2+2+2*a*b*x+2*(a^2+1)^(1/2)*(b^2*x^2+2*a*b*x+a^2+1)^
(1/2))/x)-5/8*a^3*b^5/(a^2+1)^4*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)*x-5/8*a^3*b^5/(a^2+1)^4*ln((b^2*x+a*b)/(b^2)^(1/
2)+(b^2*x^2+2*a*b*x+a^2+1)^(1/2))/(b^2)^(1/2)+7/8*a^2*b^4/(a^2+1)^3*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)+3/4*a^3*b^5/
(a^2+1)^3*ln((b^2*x+a*b)/(b^2)^(1/2)+(b^2*x^2+2*a*b*x+a^2+1)^(1/2))/(b^2)^(1/2)-3/4*a^2*b^4/(a^2+1)^(5/2)*ln((
2*a^2+2+2*a*b*x+2*(a^2+1)^(1/2)*(b^2*x^2+2*a*b*x+a^2+1)^(1/2))/x)+1/8*b^2/(a^2+1)^2/x^2*(b^2*x^2+2*a*b*x+a^2+1
)^(3/2)-1/8*b^3/(a^2+1)^3*a/x*(b^2*x^2+2*a*b*x+a^2+1)^(3/2)+1/8*b^5/(a^2+1)^3*a*(b^2*x^2+2*a*b*x+a^2+1)^(1/2)*
x+1/8*b^5/(a^2+1)^3*a*ln((b^2*x+a*b)/(b^2)^(1/2)+(b^2*x^2+2*a*b*x+a^2+1)^(1/2))/(b^2)^(1/2)-1/8*b^4/(a^2+1)^2*
(b^2*x^2+2*a*b*x+a^2+1)^(1/2)-1/8*b^5/(a^2+1)^2*a*ln((b^2*x+a*b)/(b^2)^(1/2)+(b^2*x^2+2*a*b*x+a^2+1)^(1/2))/(b
^2)^(1/2)+1/8*b^4/(a^2+1)^(3/2)*ln((2*a^2+2+2*a*b*x+2*(a^2+1)^(1/2)*(b^2*x^2+2*a*b*x+a^2+1)^(1/2))/x)-1/3*b/x^
3-1/4*a/x^4

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maxima [B]  time = 0.45, size = 594, normalized size = 2.87 \[ \frac {5 \, a^{4} b^{4} \operatorname {arsinh}\left (\frac {2 \, a b x}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2 \, a^{2}}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}}\right )}{8 \, {\left (a^{2} + 1\right )}^{\frac {7}{2}}} - \frac {3 \, a^{2} b^{4} \operatorname {arsinh}\left (\frac {2 \, a b x}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2 \, a^{2}}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}}\right )}{4 \, {\left (a^{2} + 1\right )}^{\frac {5}{2}}} + \frac {5 \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} a^{2} b^{4}}{8 \, {\left (a^{2} + 1\right )}^{3}} + \frac {b^{4} \operatorname {arsinh}\left (\frac {2 \, a b x}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2 \, a^{2}}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}} + \frac {2}{\sqrt {-4 \, a^{2} b^{2} + 4 \, {\left (a^{2} + 1\right )} b^{2}} {\left | x \right |}}\right )}{8 \, {\left (a^{2} + 1\right )}^{\frac {3}{2}}} - \frac {\sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} b^{4}}{8 \, {\left (a^{2} + 1\right )}^{2}} + \frac {5 \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} a^{3} b^{3}}{8 \, {\left (a^{2} + 1\right )}^{3} x} - \frac {\sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} a b^{3}}{8 \, {\left (a^{2} + 1\right )}^{2} x} - \frac {5 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac {3}{2}} a^{2} b^{2}}{8 \, {\left (a^{2} + 1\right )}^{3} x^{2}} + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac {3}{2}} b^{2}}{8 \, {\left (a^{2} + 1\right )}^{2} x^{2}} + \frac {5 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac {3}{2}} a b}{12 \, {\left (a^{2} + 1\right )}^{2} x^{3}} - \frac {b}{3 \, x^{3}} - \frac {a}{4 \, x^{4}} - \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2} + 1\right )}^{\frac {3}{2}}}{4 \, {\left (a^{2} + 1\right )} x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a+(1+(b*x+a)^2)^(1/2))/x^5,x, algorithm="maxima")

[Out]

5/8*a^4*b^4*arcsinh(2*a*b*x/(sqrt(-4*a^2*b^2 + 4*(a^2 + 1)*b^2)*abs(x)) + 2*a^2/(sqrt(-4*a^2*b^2 + 4*(a^2 + 1)
*b^2)*abs(x)) + 2/(sqrt(-4*a^2*b^2 + 4*(a^2 + 1)*b^2)*abs(x)))/(a^2 + 1)^(7/2) - 3/4*a^2*b^4*arcsinh(2*a*b*x/(
sqrt(-4*a^2*b^2 + 4*(a^2 + 1)*b^2)*abs(x)) + 2*a^2/(sqrt(-4*a^2*b^2 + 4*(a^2 + 1)*b^2)*abs(x)) + 2/(sqrt(-4*a^
2*b^2 + 4*(a^2 + 1)*b^2)*abs(x)))/(a^2 + 1)^(5/2) + 5/8*sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1)*a^2*b^4/(a^2 + 1)^3
+ 1/8*b^4*arcsinh(2*a*b*x/(sqrt(-4*a^2*b^2 + 4*(a^2 + 1)*b^2)*abs(x)) + 2*a^2/(sqrt(-4*a^2*b^2 + 4*(a^2 + 1)*b
^2)*abs(x)) + 2/(sqrt(-4*a^2*b^2 + 4*(a^2 + 1)*b^2)*abs(x)))/(a^2 + 1)^(3/2) - 1/8*sqrt(b^2*x^2 + 2*a*b*x + a^
2 + 1)*b^4/(a^2 + 1)^2 + 5/8*sqrt(b^2*x^2 + 2*a*b*x + a^2 + 1)*a^3*b^3/((a^2 + 1)^3*x) - 1/8*sqrt(b^2*x^2 + 2*
a*b*x + a^2 + 1)*a*b^3/((a^2 + 1)^2*x) - 5/8*(b^2*x^2 + 2*a*b*x + a^2 + 1)^(3/2)*a^2*b^2/((a^2 + 1)^3*x^2) + 1
/8*(b^2*x^2 + 2*a*b*x + a^2 + 1)^(3/2)*b^2/((a^2 + 1)^2*x^2) + 5/12*(b^2*x^2 + 2*a*b*x + a^2 + 1)^(3/2)*a*b/((
a^2 + 1)^2*x^3) - 1/3*b/x^3 - 1/4*a/x^4 - 1/4*(b^2*x^2 + 2*a*b*x + a^2 + 1)^(3/2)/((a^2 + 1)*x^4)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {a+\sqrt {{\left (a+b\,x\right )}^2+1}+b\,x}{x^5} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + ((a + b*x)^2 + 1)^(1/2) + b*x)/x^5,x)

[Out]

int((a + ((a + b*x)^2 + 1)^(1/2) + b*x)/x^5, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {a + b x + \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}{x^{5}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a+(1+(b*x+a)**2)**(1/2))/x**5,x)

[Out]

Integral((a + b*x + sqrt(a**2 + 2*a*b*x + b**2*x**2 + 1))/x**5, x)

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