Optimal. Leaf size=531 \[ -\frac {\sqrt {\pi } e^4 e^{a/b} \text {erf}\left (\frac {\sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{30 b^{7/2} d}+\frac {9 \sqrt {3 \pi } e^4 e^{\frac {3 a}{b}} \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{20 b^{7/2} d}-\frac {5 \sqrt {5 \pi } e^4 e^{\frac {5 a}{b}} \text {erf}\left (\frac {\sqrt {5} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{12 b^{7/2} d}+\frac {\sqrt {\pi } e^4 e^{-\frac {a}{b}} \text {erfi}\left (\frac {\sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{30 b^{7/2} d}-\frac {9 \sqrt {3 \pi } e^4 e^{-\frac {3 a}{b}} \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{20 b^{7/2} d}+\frac {5 \sqrt {5 \pi } e^4 e^{-\frac {5 a}{b}} \text {erfi}\left (\frac {\sqrt {5} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{12 b^{7/2} d}-\frac {40 e^4 \sqrt {(c+d x)^2+1} (c+d x)^4}{3 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {32 e^4 \sqrt {(c+d x)^2+1} (c+d x)^2}{5 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {4 e^4 (c+d x)^5}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {16 e^4 (c+d x)^3}{15 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {2 e^4 \sqrt {(c+d x)^2+1} (c+d x)^4}{5 b d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}} \]
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Rubi [A] time = 1.47, antiderivative size = 531, normalized size of antiderivative = 1.00, number of steps used = 34, number of rules used = 9, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.360, Rules used = {5865, 12, 5667, 5774, 5665, 3308, 2180, 2204, 2205} \[ -\frac {\sqrt {\pi } e^4 e^{a/b} \text {Erf}\left (\frac {\sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{30 b^{7/2} d}+\frac {9 \sqrt {3 \pi } e^4 e^{\frac {3 a}{b}} \text {Erf}\left (\frac {\sqrt {3} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{20 b^{7/2} d}-\frac {5 \sqrt {5 \pi } e^4 e^{\frac {5 a}{b}} \text {Erf}\left (\frac {\sqrt {5} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{12 b^{7/2} d}+\frac {\sqrt {\pi } e^4 e^{-\frac {a}{b}} \text {Erfi}\left (\frac {\sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{30 b^{7/2} d}-\frac {9 \sqrt {3 \pi } e^4 e^{-\frac {3 a}{b}} \text {Erfi}\left (\frac {\sqrt {3} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{20 b^{7/2} d}+\frac {5 \sqrt {5 \pi } e^4 e^{-\frac {5 a}{b}} \text {Erfi}\left (\frac {\sqrt {5} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{12 b^{7/2} d}-\frac {4 e^4 (c+d x)^5}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {40 e^4 \sqrt {(c+d x)^2+1} (c+d x)^4}{3 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {16 e^4 (c+d x)^3}{15 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {32 e^4 \sqrt {(c+d x)^2+1} (c+d x)^2}{5 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {2 e^4 \sqrt {(c+d x)^2+1} (c+d x)^4}{5 b d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}} \]
Antiderivative was successfully verified.
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Rule 12
Rule 2180
Rule 2204
Rule 2205
Rule 3308
Rule 5665
Rule 5667
Rule 5774
Rule 5865
Rubi steps
\begin {align*} \int \frac {(c e+d e x)^4}{\left (a+b \sinh ^{-1}(c+d x)\right )^{7/2}} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {e^4 x^4}{\left (a+b \sinh ^{-1}(x)\right )^{7/2}} \, dx,x,c+d x\right )}{d}\\ &=\frac {e^4 \operatorname {Subst}\left (\int \frac {x^4}{\left (a+b \sinh ^{-1}(x)\right )^{7/2}} \, dx,x,c+d x\right )}{d}\\ &=-\frac {2 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{5 b d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}}+\frac {\left (8 e^4\right ) \operatorname {Subst}\left (\int \frac {x^3}{\sqrt {1+x^2} \left (a+b \sinh ^{-1}(x)\right )^{5/2}} \, dx,x,c+d x\right )}{5 b d}+\frac {\left (2 e^4\right ) \operatorname {Subst}\left (\int \frac {x^5}{\sqrt {1+x^2} \left (a+b \sinh ^{-1}(x)\right )^{5/2}} \, dx,x,c+d x\right )}{b d}\\ &=-\frac {2 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{5 b d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}}-\frac {16 e^4 (c+d x)^3}{15 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {4 e^4 (c+d x)^5}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}+\frac {\left (16 e^4\right ) \operatorname {Subst}\left (\int \frac {x^2}{\left (a+b \sinh ^{-1}(x)\right )^{3/2}} \, dx,x,c+d x\right )}{5 b^2 d}+\frac {\left (20 e^4\right ) \operatorname {Subst}\left (\int \frac {x^4}{\left (a+b \sinh ^{-1}(x)\right )^{3/2}} \, dx,x,c+d x\right )}{3 b^2 d}\\ &=-\frac {2 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{5 b d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}}-\frac {16 e^4 (c+d x)^3}{15 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {4 e^4 (c+d x)^5}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {32 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{5 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {40 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}+\frac {\left (32 e^4\right ) \operatorname {Subst}\left (\int \left (-\frac {\sinh (x)}{4 \sqrt {a+b x}}+\frac {3 \sinh (3 x)}{4 \sqrt {a+b x}}\right ) \, dx,x,\sinh ^{-1}(c+d x)\right )}{5 b^3 d}+\frac {\left (40 e^4\right ) \operatorname {Subst}\left (\int \left (\frac {\sinh (x)}{8 \sqrt {a+b x}}-\frac {9 \sinh (3 x)}{16 \sqrt {a+b x}}+\frac {5 \sinh (5 x)}{16 \sqrt {a+b x}}\right ) \, dx,x,\sinh ^{-1}(c+d x)\right )}{3 b^3 d}\\ &=-\frac {2 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{5 b d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}}-\frac {16 e^4 (c+d x)^3}{15 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {4 e^4 (c+d x)^5}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {32 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{5 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {40 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {\left (8 e^4\right ) \operatorname {Subst}\left (\int \frac {\sinh (x)}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{5 b^3 d}+\frac {\left (5 e^4\right ) \operatorname {Subst}\left (\int \frac {\sinh (x)}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{3 b^3 d}+\frac {\left (25 e^4\right ) \operatorname {Subst}\left (\int \frac {\sinh (5 x)}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{6 b^3 d}+\frac {\left (24 e^4\right ) \operatorname {Subst}\left (\int \frac {\sinh (3 x)}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{5 b^3 d}-\frac {\left (15 e^4\right ) \operatorname {Subst}\left (\int \frac {\sinh (3 x)}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{2 b^3 d}\\ &=-\frac {2 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{5 b d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}}-\frac {16 e^4 (c+d x)^3}{15 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {4 e^4 (c+d x)^5}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {32 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{5 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {40 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}+\frac {\left (4 e^4\right ) \operatorname {Subst}\left (\int \frac {e^{-x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{5 b^3 d}-\frac {\left (4 e^4\right ) \operatorname {Subst}\left (\int \frac {e^x}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{5 b^3 d}-\frac {\left (5 e^4\right ) \operatorname {Subst}\left (\int \frac {e^{-x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{6 b^3 d}+\frac {\left (5 e^4\right ) \operatorname {Subst}\left (\int \frac {e^x}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{6 b^3 d}-\frac {\left (25 e^4\right ) \operatorname {Subst}\left (\int \frac {e^{-5 x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{12 b^3 d}+\frac {\left (25 e^4\right ) \operatorname {Subst}\left (\int \frac {e^{5 x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{12 b^3 d}-\frac {\left (12 e^4\right ) \operatorname {Subst}\left (\int \frac {e^{-3 x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{5 b^3 d}+\frac {\left (12 e^4\right ) \operatorname {Subst}\left (\int \frac {e^{3 x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{5 b^3 d}+\frac {\left (15 e^4\right ) \operatorname {Subst}\left (\int \frac {e^{-3 x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{4 b^3 d}-\frac {\left (15 e^4\right ) \operatorname {Subst}\left (\int \frac {e^{3 x}}{\sqrt {a+b x}} \, dx,x,\sinh ^{-1}(c+d x)\right )}{4 b^3 d}\\ &=-\frac {2 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{5 b d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}}-\frac {16 e^4 (c+d x)^3}{15 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {4 e^4 (c+d x)^5}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {32 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{5 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {40 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}+\frac {\left (8 e^4\right ) \operatorname {Subst}\left (\int e^{\frac {a}{b}-\frac {x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{5 b^4 d}-\frac {\left (8 e^4\right ) \operatorname {Subst}\left (\int e^{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{5 b^4 d}-\frac {\left (5 e^4\right ) \operatorname {Subst}\left (\int e^{\frac {a}{b}-\frac {x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{3 b^4 d}+\frac {\left (5 e^4\right ) \operatorname {Subst}\left (\int e^{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{3 b^4 d}-\frac {\left (25 e^4\right ) \operatorname {Subst}\left (\int e^{\frac {5 a}{b}-\frac {5 x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{6 b^4 d}+\frac {\left (25 e^4\right ) \operatorname {Subst}\left (\int e^{-\frac {5 a}{b}+\frac {5 x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{6 b^4 d}-\frac {\left (24 e^4\right ) \operatorname {Subst}\left (\int e^{\frac {3 a}{b}-\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{5 b^4 d}+\frac {\left (24 e^4\right ) \operatorname {Subst}\left (\int e^{-\frac {3 a}{b}+\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{5 b^4 d}+\frac {\left (15 e^4\right ) \operatorname {Subst}\left (\int e^{\frac {3 a}{b}-\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{2 b^4 d}-\frac {\left (15 e^4\right ) \operatorname {Subst}\left (\int e^{-\frac {3 a}{b}+\frac {3 x^2}{b}} \, dx,x,\sqrt {a+b \sinh ^{-1}(c+d x)}\right )}{2 b^4 d}\\ &=-\frac {2 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{5 b d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}}-\frac {16 e^4 (c+d x)^3}{15 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {4 e^4 (c+d x)^5}{3 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )^{3/2}}-\frac {32 e^4 (c+d x)^2 \sqrt {1+(c+d x)^2}}{5 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {40 e^4 (c+d x)^4 \sqrt {1+(c+d x)^2}}{3 b^3 d \sqrt {a+b \sinh ^{-1}(c+d x)}}-\frac {e^4 e^{a/b} \sqrt {\pi } \text {erf}\left (\frac {\sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{30 b^{7/2} d}+\frac {9 e^4 e^{\frac {3 a}{b}} \sqrt {3 \pi } \text {erf}\left (\frac {\sqrt {3} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{20 b^{7/2} d}-\frac {5 e^4 e^{\frac {5 a}{b}} \sqrt {5 \pi } \text {erf}\left (\frac {\sqrt {5} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{12 b^{7/2} d}+\frac {e^4 e^{-\frac {a}{b}} \sqrt {\pi } \text {erfi}\left (\frac {\sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{30 b^{7/2} d}-\frac {9 e^4 e^{-\frac {3 a}{b}} \sqrt {3 \pi } \text {erfi}\left (\frac {\sqrt {3} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{20 b^{7/2} d}+\frac {5 e^4 e^{-\frac {5 a}{b}} \sqrt {5 \pi } \text {erfi}\left (\frac {\sqrt {5} \sqrt {a+b \sinh ^{-1}(c+d x)}}{\sqrt {b}}\right )}{12 b^{7/2} d}\\ \end {align*}
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Mathematica [A] time = 2.72, size = 701, normalized size = 1.32 \[ \frac {e^4 \left (e^{-\sinh ^{-1}(c+d x)} \left (-8 a^2-4 b (4 a-b) \sinh ^{-1}(c+d x)+8 e^{\frac {a}{b}+\sinh ^{-1}(c+d x)} \sqrt {\frac {a}{b}+\sinh ^{-1}(c+d x)} \left (a+b \sinh ^{-1}(c+d x)\right )^2 \Gamma \left (\frac {1}{2},\frac {a}{b}+\sinh ^{-1}(c+d x)\right )+4 a b-8 b^2 \sinh ^{-1}(c+d x)^2-6 b^2\right )+9 \left (2 e^{-\frac {3 a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right ) \left (e^{3 \left (\frac {a}{b}+\sinh ^{-1}(c+d x)\right )} \left (6 a+6 b \sinh ^{-1}(c+d x)+b\right )+6 \sqrt {3} b \left (-\frac {a+b \sinh ^{-1}(c+d x)}{b}\right )^{3/2} \Gamma \left (\frac {1}{2},-\frac {3 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )\right )+b^2 e^{3 \sinh ^{-1}(c+d x)}\right )+9 e^{-3 \sinh ^{-1}(c+d x)} \left (2 \left (a+b \sinh ^{-1}(c+d x)\right ) \left (-6 \sqrt {3} e^{3 \left (\frac {a}{b}+\sinh ^{-1}(c+d x)\right )} \sqrt {\frac {a}{b}+\sinh ^{-1}(c+d x)} \left (a+b \sinh ^{-1}(c+d x)\right ) \Gamma \left (\frac {1}{2},\frac {3 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )+6 a+6 b \sinh ^{-1}(c+d x)-b\right )+b^2\right )-e^{-5 \sinh ^{-1}(c+d x)} \left (10 \left (a+b \sinh ^{-1}(c+d x)\right ) \left (-10 \sqrt {5} e^{5 \left (\frac {a}{b}+\sinh ^{-1}(c+d x)\right )} \sqrt {\frac {a}{b}+\sinh ^{-1}(c+d x)} \left (a+b \sinh ^{-1}(c+d x)\right ) \Gamma \left (\frac {1}{2},\frac {5 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )+10 a+10 b \sinh ^{-1}(c+d x)-b\right )+3 b^2\right )-10 e^{-\frac {5 a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right ) \left (e^{5 \left (\frac {a}{b}+\sinh ^{-1}(c+d x)\right )} \left (10 a+10 b \sinh ^{-1}(c+d x)+b\right )+10 \sqrt {5} b \left (-\frac {a+b \sinh ^{-1}(c+d x)}{b}\right )^{3/2} \Gamma \left (\frac {1}{2},-\frac {5 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )\right )-4 e^{-\frac {a}{b}} \left (a+b \sinh ^{-1}(c+d x)\right ) \left (e^{\frac {a}{b}+\sinh ^{-1}(c+d x)} \left (2 a+2 b \sinh ^{-1}(c+d x)+b\right )+2 b \left (-\frac {a+b \sinh ^{-1}(c+d x)}{b}\right )^{3/2} \Gamma \left (\frac {1}{2},-\frac {a+b \sinh ^{-1}(c+d x)}{b}\right )\right )-6 b^2 e^{\sinh ^{-1}(c+d x)}-3 b^2 e^{5 \sinh ^{-1}(c+d x)}\right )}{240 b^3 d \left (a+b \sinh ^{-1}(c+d x)\right )^{5/2}} \]
Warning: Unable to verify antiderivative.
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fricas [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (d e x + c e\right )}^{4}}{{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F(-2)] time = 180.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (d e x +c e \right )^{4}}{\left (a +b \arcsinh \left (d x +c \right )\right )^{\frac {7}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (d e x + c e\right )}^{4}}{{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (c\,e+d\,e\,x\right )}^4}{{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^{7/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ e^{4} \left (\int \frac {c^{4}}{a^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} + 3 a^{2} b \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}{\left (c + d x \right )} + 3 a b^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{2}{\left (c + d x \right )} + b^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{3}{\left (c + d x \right )}}\, dx + \int \frac {d^{4} x^{4}}{a^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} + 3 a^{2} b \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}{\left (c + d x \right )} + 3 a b^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{2}{\left (c + d x \right )} + b^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{3}{\left (c + d x \right )}}\, dx + \int \frac {4 c d^{3} x^{3}}{a^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} + 3 a^{2} b \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}{\left (c + d x \right )} + 3 a b^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{2}{\left (c + d x \right )} + b^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{3}{\left (c + d x \right )}}\, dx + \int \frac {6 c^{2} d^{2} x^{2}}{a^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} + 3 a^{2} b \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}{\left (c + d x \right )} + 3 a b^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{2}{\left (c + d x \right )} + b^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{3}{\left (c + d x \right )}}\, dx + \int \frac {4 c^{3} d x}{a^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} + 3 a^{2} b \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}{\left (c + d x \right )} + 3 a b^{2} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{2}{\left (c + d x \right )} + b^{3} \sqrt {a + b \operatorname {asinh}{\left (c + d x \right )}} \operatorname {asinh}^{3}{\left (c + d x \right )}}\, dx\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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