3.171 \(\int \frac {c e+d e x}{(a+b \sinh ^{-1}(c+d x))^3} \, dx\)

Optimal. Leaf size=156 \[ -\frac {e \sinh \left (\frac {2 a}{b}\right ) \text {Chi}\left (\frac {2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{b^3 d}+\frac {e \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 \left (a+b \sinh ^{-1}(c+d x)\right )}{b}\right )}{b^3 d}-\frac {e (c+d x)^2}{b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e}{2 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e \sqrt {(c+d x)^2+1} (c+d x)}{2 b d \left (a+b \sinh ^{-1}(c+d x)\right )^2} \]

[Out]

-1/2*e/b^2/d/(a+b*arcsinh(d*x+c))-e*(d*x+c)^2/b^2/d/(a+b*arcsinh(d*x+c))+e*cosh(2*a/b)*Shi(2*(a+b*arcsinh(d*x+
c))/b)/b^3/d-e*Chi(2*(a+b*arcsinh(d*x+c))/b)*sinh(2*a/b)/b^3/d-1/2*e*(d*x+c)*(1+(d*x+c)^2)^(1/2)/b/d/(a+b*arcs
inh(d*x+c))^2

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Rubi [A]  time = 0.33, antiderivative size = 156, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 10, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.476, Rules used = {5865, 12, 5667, 5774, 5669, 5448, 3303, 3298, 3301, 5675} \[ -\frac {e \sinh \left (\frac {2 a}{b}\right ) \text {Chi}\left (\frac {2 a}{b}+2 \sinh ^{-1}(c+d x)\right )}{b^3 d}+\frac {e \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \sinh ^{-1}(c+d x)\right )}{b^3 d}-\frac {e (c+d x)^2}{b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e}{2 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e \sqrt {(c+d x)^2+1} (c+d x)}{2 b d \left (a+b \sinh ^{-1}(c+d x)\right )^2} \]

Antiderivative was successfully verified.

[In]

Int[(c*e + d*e*x)/(a + b*ArcSinh[c + d*x])^3,x]

[Out]

-(e*(c + d*x)*Sqrt[1 + (c + d*x)^2])/(2*b*d*(a + b*ArcSinh[c + d*x])^2) - e/(2*b^2*d*(a + b*ArcSinh[c + d*x]))
- (e*(c + d*x)^2)/(b^2*d*(a + b*ArcSinh[c + d*x])) - (e*CoshIntegral[(2*a)/b + 2*ArcSinh[c + d*x]]*Sinh[(2*a)
/b])/(b^3*d) + (e*Cosh[(2*a)/b]*SinhIntegral[(2*a)/b + 2*ArcSinh[c + d*x]])/(b^3*d)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 3298

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(I*SinhIntegral[(c*f*fz)
/d + f*fz*x])/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*e - c*f*fz*I, 0]

Rule 3301

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CoshIntegral[(c*f*fz)/d
+ f*fz*x]/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*(e - Pi/2) - c*f*fz*I, 0]

Rule 3303

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Dist[Cos[(d*e - c*f)/d], Int[Sin[(c*f)/d + f*x]
/(c + d*x), x], x] + Dist[Sin[(d*e - c*f)/d], Int[Cos[(c*f)/d + f*x]/(c + d*x), x], x] /; FreeQ[{c, d, e, f},
x] && NeQ[d*e - c*f, 0]

Rule 5448

Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int
[ExpandTrigReduce[(c + d*x)^m, Sinh[a + b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n,
0] && IGtQ[p, 0]

Rule 5667

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(x^m*Sqrt[1 + c^2*x^2]*(a + b*ArcSi
nh[c*x])^(n + 1))/(b*c*(n + 1)), x] + (-Dist[(c*(m + 1))/(b*(n + 1)), Int[(x^(m + 1)*(a + b*ArcSinh[c*x])^(n +
1))/Sqrt[1 + c^2*x^2], x], x] - Dist[m/(b*c*(n + 1)), Int[(x^(m - 1)*(a + b*ArcSinh[c*x])^(n + 1))/Sqrt[1 + c
^2*x^2], x], x]) /; FreeQ[{a, b, c}, x] && IGtQ[m, 0] && LtQ[n, -2]

Rule 5669

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Dist[1/c^(m + 1), Subst[Int[(a + b*x)^n*
Sinh[x]^m*Cosh[x], x], x, ArcSinh[c*x]], x] /; FreeQ[{a, b, c, n}, x] && IGtQ[m, 0]

Rule 5675

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(a + b*ArcSinh[c*x]
)^(n + 1)/(b*c*Sqrt[d]*(n + 1)), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[e, c^2*d] && GtQ[d, 0] && NeQ[n, -1
]

Rule 5774

Int[(((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*((f_.)*(x_))^(m_.))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp
[((f*x)^m*(a + b*ArcSinh[c*x])^(n + 1))/(b*c*Sqrt[d]*(n + 1)), x] - Dist[(f*m)/(b*c*Sqrt[d]*(n + 1)), Int[(f*x
)^(m - 1)*(a + b*ArcSinh[c*x])^(n + 1), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[e, c^2*d] && LtQ[n, -
1] && GtQ[d, 0]

Rule 5865

Int[((a_.) + ArcSinh[(c_) + (d_.)*(x_)]*(b_.))^(n_.)*((e_.) + (f_.)*(x_))^(m_.), x_Symbol] :> Dist[1/d, Subst[
Int[((d*e - c*f)/d + (f*x)/d)^m*(a + b*ArcSinh[x])^n, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x
]

Rubi steps

\begin {align*} \int \frac {c e+d e x}{\left (a+b \sinh ^{-1}(c+d x)\right )^3} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {e x}{\left (a+b \sinh ^{-1}(x)\right )^3} \, dx,x,c+d x\right )}{d}\\ &=\frac {e \operatorname {Subst}\left (\int \frac {x}{\left (a+b \sinh ^{-1}(x)\right )^3} \, dx,x,c+d x\right )}{d}\\ &=-\frac {e (c+d x) \sqrt {1+(c+d x)^2}}{2 b d \left (a+b \sinh ^{-1}(c+d x)\right )^2}+\frac {e \operatorname {Subst}\left (\int \frac {1}{\sqrt {1+x^2} \left (a+b \sinh ^{-1}(x)\right )^2} \, dx,x,c+d x\right )}{2 b d}+\frac {e \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {1+x^2} \left (a+b \sinh ^{-1}(x)\right )^2} \, dx,x,c+d x\right )}{b d}\\ &=-\frac {e (c+d x) \sqrt {1+(c+d x)^2}}{2 b d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac {e}{2 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e (c+d x)^2}{b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}+\frac {(2 e) \operatorname {Subst}\left (\int \frac {x}{a+b \sinh ^{-1}(x)} \, dx,x,c+d x\right )}{b^2 d}\\ &=-\frac {e (c+d x) \sqrt {1+(c+d x)^2}}{2 b d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac {e}{2 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e (c+d x)^2}{b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}+\frac {(2 e) \operatorname {Subst}\left (\int \frac {\cosh (x) \sinh (x)}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b^2 d}\\ &=-\frac {e (c+d x) \sqrt {1+(c+d x)^2}}{2 b d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac {e}{2 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e (c+d x)^2}{b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}+\frac {(2 e) \operatorname {Subst}\left (\int \frac {\sinh (2 x)}{2 (a+b x)} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b^2 d}\\ &=-\frac {e (c+d x) \sqrt {1+(c+d x)^2}}{2 b d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac {e}{2 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e (c+d x)^2}{b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}+\frac {e \operatorname {Subst}\left (\int \frac {\sinh (2 x)}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b^2 d}\\ &=-\frac {e (c+d x) \sqrt {1+(c+d x)^2}}{2 b d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac {e}{2 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e (c+d x)^2}{b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}+\frac {\left (e \cosh \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \frac {\sinh \left (\frac {2 a}{b}+2 x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b^2 d}-\frac {\left (e \sinh \left (\frac {2 a}{b}\right )\right ) \operatorname {Subst}\left (\int \frac {\cosh \left (\frac {2 a}{b}+2 x\right )}{a+b x} \, dx,x,\sinh ^{-1}(c+d x)\right )}{b^2 d}\\ &=-\frac {e (c+d x) \sqrt {1+(c+d x)^2}}{2 b d \left (a+b \sinh ^{-1}(c+d x)\right )^2}-\frac {e}{2 b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e (c+d x)^2}{b^2 d \left (a+b \sinh ^{-1}(c+d x)\right )}-\frac {e \text {Chi}\left (\frac {2 a}{b}+2 \sinh ^{-1}(c+d x)\right ) \sinh \left (\frac {2 a}{b}\right )}{b^3 d}+\frac {e \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \sinh ^{-1}(c+d x)\right )}{b^3 d}\\ \end {align*}

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Mathematica [A]  time = 0.31, size = 120, normalized size = 0.77 \[ \frac {e \left (-\frac {b^2 (c+d x) \sqrt {(c+d x)^2+1}}{\left (a+b \sinh ^{-1}(c+d x)\right )^2}-2 \sinh \left (\frac {2 a}{b}\right ) \text {Chi}\left (2 \left (\frac {a}{b}+\sinh ^{-1}(c+d x)\right )\right )+2 \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (2 \left (\frac {a}{b}+\sinh ^{-1}(c+d x)\right )\right )+\frac {b \left (-2 (c+d x)^2-1\right )}{a+b \sinh ^{-1}(c+d x)}\right )}{2 b^3 d} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*e + d*e*x)/(a + b*ArcSinh[c + d*x])^3,x]

[Out]

(e*(-((b^2*(c + d*x)*Sqrt[1 + (c + d*x)^2])/(a + b*ArcSinh[c + d*x])^2) + (b*(-1 - 2*(c + d*x)^2))/(a + b*ArcS
inh[c + d*x]) - 2*CoshIntegral[2*(a/b + ArcSinh[c + d*x])]*Sinh[(2*a)/b] + 2*Cosh[(2*a)/b]*SinhIntegral[2*(a/b
+ ArcSinh[c + d*x])]))/(2*b^3*d)

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fricas [F]  time = 0.77, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {d e x + c e}{b^{3} \operatorname {arsinh}\left (d x + c\right )^{3} + 3 \, a b^{2} \operatorname {arsinh}\left (d x + c\right )^{2} + 3 \, a^{2} b \operatorname {arsinh}\left (d x + c\right ) + a^{3}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)/(a+b*arcsinh(d*x+c))^3,x, algorithm="fricas")

[Out]

integral((d*e*x + c*e)/(b^3*arcsinh(d*x + c)^3 + 3*a*b^2*arcsinh(d*x + c)^2 + 3*a^2*b*arcsinh(d*x + c) + a^3),
x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {d e x + c e}{{\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)/(a+b*arcsinh(d*x+c))^3,x, algorithm="giac")

[Out]

integrate((d*e*x + c*e)/(b*arcsinh(d*x + c) + a)^3, x)

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maple [A]  time = 0.07, size = 239, normalized size = 1.53 \[ \frac {-\frac {\left (2 \left (d x +c \right )^{2}-2 \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}+1\right ) e \left (2 b \arcsinh \left (d x +c \right )+2 a -b \right )}{8 b^{2} \left (b^{2} \arcsinh \left (d x +c \right )^{2}+2 a b \arcsinh \left (d x +c \right )+a^{2}\right )}+\frac {e \,{\mathrm e}^{\frac {2 a}{b}} \Ei \left (1, 2 \arcsinh \left (d x +c \right )+\frac {2 a}{b}\right )}{2 b^{3}}-\frac {e \left (2 \left (d x +c \right )^{2}+1+2 \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}\right )}{8 b \left (a +b \arcsinh \left (d x +c \right )\right )^{2}}-\frac {e \left (2 \left (d x +c \right )^{2}+1+2 \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}\right )}{4 b^{2} \left (a +b \arcsinh \left (d x +c \right )\right )}-\frac {e \,{\mathrm e}^{-\frac {2 a}{b}} \Ei \left (1, -2 \arcsinh \left (d x +c \right )-\frac {2 a}{b}\right )}{2 b^{3}}}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*e*x+c*e)/(a+b*arcsinh(d*x+c))^3,x)

[Out]

1/d*(-1/8*(2*(d*x+c)^2-2*(d*x+c)*(1+(d*x+c)^2)^(1/2)+1)*e*(2*b*arcsinh(d*x+c)+2*a-b)/b^2/(b^2*arcsinh(d*x+c)^2
+2*a*b*arcsinh(d*x+c)+a^2)+1/2*e/b^3*exp(2*a/b)*Ei(1,2*arcsinh(d*x+c)+2*a/b)-1/8/b*e*(2*(d*x+c)^2+1+2*(d*x+c)*
(1+(d*x+c)^2)^(1/2))/(a+b*arcsinh(d*x+c))^2-1/4/b^2*e*(2*(d*x+c)^2+1+2*(d*x+c)*(1+(d*x+c)^2)^(1/2))/(a+b*arcsi
nh(d*x+c))-1/2/b^3*e*exp(-2*a/b)*Ei(1,-2*arcsinh(d*x+c)-2*a/b))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)/(a+b*arcsinh(d*x+c))^3,x, algorithm="maxima")

[Out]

-1/2*((2*a*d^8*e + b*d^8*e)*x^8 + 8*(2*a*c*d^7*e + b*c*d^7*e)*x^7 + (2*(28*c^2*d^6*e + 3*d^6*e)*a + (28*c^2*d^
6*e + 3*d^6*e)*b)*x^6 + 2*(2*(28*c^3*d^5*e + 9*c*d^5*e)*a + (28*c^3*d^5*e + 9*c*d^5*e)*b)*x^5 + (2*(70*c^4*d^4
*e + 45*c^2*d^4*e + 3*d^4*e)*a + (70*c^4*d^4*e + 45*c^2*d^4*e + 3*d^4*e)*b)*x^4 + 4*(2*(14*c^5*d^3*e + 15*c^3*
d^3*e + 3*c*d^3*e)*a + (14*c^5*d^3*e + 15*c^3*d^3*e + 3*c*d^3*e)*b)*x^3 + (2*(28*c^6*d^2*e + 45*c^4*d^2*e + 18
*c^2*d^2*e + d^2*e)*a + (28*c^6*d^2*e + 45*c^4*d^2*e + 18*c^2*d^2*e + d^2*e)*b)*x^2 + ((2*a*d^5*e + b*d^5*e)*x
^5 + 5*(2*a*c*d^4*e + b*c*d^4*e)*x^4 + (2*(10*c^2*d^3*e + d^3*e)*a + (10*c^2*d^3*e + d^3*e)*b)*x^3 + (2*(10*c^
3*d^2*e + 3*c*d^2*e)*a + (10*c^3*d^2*e + 3*c*d^2*e)*b)*x^2 + 2*(c^5*e + c^3*e)*a + (c^5*e + c^3*e)*b + (2*(5*c
^4*d*e + 3*c^2*d*e)*a + (5*c^4*d*e + 3*c^2*d*e)*b)*x)*(d^2*x^2 + 2*c*d*x + c^2 + 1)^(3/2) + (3*(2*a*d^6*e + b*
d^6*e)*x^6 + 18*(2*a*c*d^5*e + b*c*d^5*e)*x^5 + 5*(2*(9*c^2*d^4*e + d^4*e)*a + (9*c^2*d^4*e + d^4*e)*b)*x^4 +
20*(2*(3*c^3*d^3*e + c*d^3*e)*a + (3*c^3*d^3*e + c*d^3*e)*b)*x^3 + (5*(18*c^4*d^2*e + 12*c^2*d^2*e + d^2*e)*a
+ (45*c^4*d^2*e + 30*c^2*d^2*e + 2*d^2*e)*b)*x^2 + (6*c^6*e + 10*c^4*e + 5*c^2*e + e)*a + (3*c^6*e + 5*c^4*e +
2*c^2*e)*b + 2*((18*c^5*d*e + 20*c^3*d*e + 5*c*d*e)*a + (9*c^5*d*e + 10*c^3*d*e + 2*c*d*e)*b)*x)*(d^2*x^2 + 2
*c*d*x + c^2 + 1) + 2*(c^8*e + 3*c^6*e + 3*c^4*e + c^2*e)*a + (c^8*e + 3*c^6*e + 3*c^4*e + c^2*e)*b + 2*(2*(4*
c^7*d*e + 9*c^5*d*e + 6*c^3*d*e + c*d*e)*a + (4*c^7*d*e + 9*c^5*d*e + 6*c^3*d*e + c*d*e)*b)*x + (2*b*d^8*e*x^8
+ 16*b*c*d^7*e*x^7 + 2*(28*c^2*d^6*e + 3*d^6*e)*b*x^6 + 4*(28*c^3*d^5*e + 9*c*d^5*e)*b*x^5 + 2*(70*c^4*d^4*e
+ 45*c^2*d^4*e + 3*d^4*e)*b*x^4 + 8*(14*c^5*d^3*e + 15*c^3*d^3*e + 3*c*d^3*e)*b*x^3 + 2*(28*c^6*d^2*e + 45*c^4
*d^2*e + 18*c^2*d^2*e + d^2*e)*b*x^2 + 4*(4*c^7*d*e + 9*c^5*d*e + 6*c^3*d*e + c*d*e)*b*x + 2*(b*d^5*e*x^5 + 5*
b*c*d^4*e*x^4 + (10*c^2*d^3*e + d^3*e)*b*x^3 + (10*c^3*d^2*e + 3*c*d^2*e)*b*x^2 + (5*c^4*d*e + 3*c^2*d*e)*b*x
+ (c^5*e + c^3*e)*b)*(d^2*x^2 + 2*c*d*x + c^2 + 1)^(3/2) + (6*b*d^6*e*x^6 + 36*b*c*d^5*e*x^5 + 10*(9*c^2*d^4*e
+ d^4*e)*b*x^4 + 40*(3*c^3*d^3*e + c*d^3*e)*b*x^3 + 5*(18*c^4*d^2*e + 12*c^2*d^2*e + d^2*e)*b*x^2 + 2*(18*c^5
*d*e + 20*c^3*d*e + 5*c*d*e)*b*x + (6*c^6*e + 10*c^4*e + 5*c^2*e + e)*b)*(d^2*x^2 + 2*c*d*x + c^2 + 1) + 2*(c^
8*e + 3*c^6*e + 3*c^4*e + c^2*e)*b + (6*b*d^7*e*x^7 + 42*b*c*d^6*e*x^6 + 14*(9*c^2*d^5*e + d^5*e)*b*x^5 + 70*(
3*c^3*d^4*e + c*d^4*e)*b*x^4 + (210*c^4*d^3*e + 140*c^2*d^3*e + 11*d^3*e)*b*x^3 + (126*c^5*d^2*e + 140*c^3*d^2
*e + 33*c*d^2*e)*b*x^2 + (42*c^6*d*e + 70*c^4*d*e + 33*c^2*d*e + 3*d*e)*b*x + (6*c^7*e + 14*c^5*e + 11*c^3*e +
3*c*e)*b)*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1))*log(d*x + c + sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)) + (3*(2*a*d^7*e
+ b*d^7*e)*x^7 + 21*(2*a*c*d^6*e + b*c*d^6*e)*x^6 + 7*(2*(9*c^2*d^5*e + d^5*e)*a + (9*c^2*d^5*e + d^5*e)*b)*x
^5 + 35*(2*(3*c^3*d^4*e + c*d^4*e)*a + (3*c^3*d^4*e + c*d^4*e)*b)*x^4 + ((210*c^4*d^3*e + 140*c^2*d^3*e + 11*d
^3*e)*a + 5*(21*c^4*d^3*e + 14*c^2*d^3*e + d^3*e)*b)*x^3 + ((126*c^5*d^2*e + 140*c^3*d^2*e + 33*c*d^2*e)*a + (
63*c^5*d^2*e + 70*c^3*d^2*e + 15*c*d^2*e)*b)*x^2 + (6*c^7*e + 14*c^5*e + 11*c^3*e + 3*c*e)*a + (3*c^7*e + 7*c^
5*e + 5*c^3*e + c*e)*b + ((42*c^6*d*e + 70*c^4*d*e + 33*c^2*d*e + 3*d*e)*a + (21*c^6*d*e + 35*c^4*d*e + 15*c^2
*d*e + d*e)*b)*x)*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1))/(a^2*b^2*d^7*x^6 + 6*a^2*b^2*c*d^6*x^5 + 3*(5*c^2*d^5 + d
^5)*a^2*b^2*x^4 + 4*(5*c^3*d^4 + 3*c*d^4)*a^2*b^2*x^3 + 3*(5*c^4*d^3 + 6*c^2*d^3 + d^3)*a^2*b^2*x^2 + 6*(c^5*d
^2 + 2*c^3*d^2 + c*d^2)*a^2*b^2*x + (c^6*d + 3*c^4*d + 3*c^2*d + d)*a^2*b^2 + (b^4*d^7*x^6 + 6*b^4*c*d^6*x^5 +
3*(5*c^2*d^5 + d^5)*b^4*x^4 + 4*(5*c^3*d^4 + 3*c*d^4)*b^4*x^3 + 3*(5*c^4*d^3 + 6*c^2*d^3 + d^3)*b^4*x^2 + 6*(
c^5*d^2 + 2*c^3*d^2 + c*d^2)*b^4*x + (c^6*d + 3*c^4*d + 3*c^2*d + d)*b^4 + (b^4*d^4*x^3 + 3*b^4*c*d^3*x^2 + 3*
b^4*c^2*d^2*x + b^4*c^3*d)*(d^2*x^2 + 2*c*d*x + c^2 + 1)^(3/2) + 3*(b^4*d^5*x^4 + 4*b^4*c*d^4*x^3 + (6*c^2*d^3
+ d^3)*b^4*x^2 + 2*(2*c^3*d^2 + c*d^2)*b^4*x + (c^4*d + c^2*d)*b^4)*(d^2*x^2 + 2*c*d*x + c^2 + 1) + 3*(b^4*d^
6*x^5 + 5*b^4*c*d^5*x^4 + 2*(5*c^2*d^4 + d^4)*b^4*x^3 + 2*(5*c^3*d^3 + 3*c*d^3)*b^4*x^2 + (5*c^4*d^2 + 6*c^2*d
^2 + d^2)*b^4*x + (c^5*d + 2*c^3*d + c*d)*b^4)*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1))*log(d*x + c + sqrt(d^2*x^2 +
2*c*d*x + c^2 + 1))^2 + (a^2*b^2*d^4*x^3 + 3*a^2*b^2*c*d^3*x^2 + 3*a^2*b^2*c^2*d^2*x + a^2*b^2*c^3*d)*(d^2*x^
2 + 2*c*d*x + c^2 + 1)^(3/2) + 3*(a^2*b^2*d^5*x^4 + 4*a^2*b^2*c*d^4*x^3 + (6*c^2*d^3 + d^3)*a^2*b^2*x^2 + 2*(2
*c^3*d^2 + c*d^2)*a^2*b^2*x + (c^4*d + c^2*d)*a^2*b^2)*(d^2*x^2 + 2*c*d*x + c^2 + 1) + 2*(a*b^3*d^7*x^6 + 6*a*
b^3*c*d^6*x^5 + 3*(5*c^2*d^5 + d^5)*a*b^3*x^4 + 4*(5*c^3*d^4 + 3*c*d^4)*a*b^3*x^3 + 3*(5*c^4*d^3 + 6*c^2*d^3 +
d^3)*a*b^3*x^2 + 6*(c^5*d^2 + 2*c^3*d^2 + c*d^2)*a*b^3*x + (c^6*d + 3*c^4*d + 3*c^2*d + d)*a*b^3 + (a*b^3*d^4
*x^3 + 3*a*b^3*c*d^3*x^2 + 3*a*b^3*c^2*d^2*x + a*b^3*c^3*d)*(d^2*x^2 + 2*c*d*x + c^2 + 1)^(3/2) + 3*(a*b^3*d^5
*x^4 + 4*a*b^3*c*d^4*x^3 + (6*c^2*d^3 + d^3)*a*b^3*x^2 + 2*(2*c^3*d^2 + c*d^2)*a*b^3*x + (c^4*d + c^2*d)*a*b^3
)*(d^2*x^2 + 2*c*d*x + c^2 + 1) + 3*(a*b^3*d^6*x^5 + 5*a*b^3*c*d^5*x^4 + 2*(5*c^2*d^4 + d^4)*a*b^3*x^3 + 2*(5*
c^3*d^3 + 3*c*d^3)*a*b^3*x^2 + (5*c^4*d^2 + 6*c^2*d^2 + d^2)*a*b^3*x + (c^5*d + 2*c^3*d + c*d)*a*b^3)*sqrt(d^2
*x^2 + 2*c*d*x + c^2 + 1))*log(d*x + c + sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)) + 3*(a^2*b^2*d^6*x^5 + 5*a^2*b^2*c
*d^5*x^4 + 2*(5*c^2*d^4 + d^4)*a^2*b^2*x^3 + 2*(5*c^3*d^3 + 3*c*d^3)*a^2*b^2*x^2 + (5*c^4*d^2 + 6*c^2*d^2 + d^
2)*a^2*b^2*x + (c^5*d + 2*c^3*d + c*d)*a^2*b^2)*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)) + integrate(1/2*(4*d^9*e*x^
9 + 36*c*d^8*e*x^8 + 4*c^9*e + 16*c^7*e + 16*(9*c^2*d^7*e + d^7*e)*x^7 + 112*(3*c^3*d^6*e + c*d^6*e)*x^6 + 24*
c^5*e + 24*(21*c^4*d^5*e + 14*c^2*d^5*e + d^5*e)*x^5 + 8*(63*c^5*d^4*e + 70*c^3*d^4*e + 15*c*d^4*e)*x^4 + 16*c
^3*e + 16*(21*c^6*d^3*e + 35*c^4*d^3*e + 15*c^2*d^3*e + d^3*e)*x^3 + 4*(d^5*e*x^5 + 5*c*d^4*e*x^4 + 10*c^2*d^3
*e*x^3 + 10*c^3*d^2*e*x^2 + 5*c^4*d*e*x + c^5*e)*(d^2*x^2 + 2*c*d*x + c^2 + 1)^2 + 48*(3*c^7*d^2*e + 7*c^5*d^2
*e + 5*c^3*d^2*e + c*d^2*e)*x^2 + (16*d^6*e*x^6 + 96*c*d^5*e*x^5 + 16*c^6*e + 16*c^4*e + 16*(15*c^2*d^4*e + d^
4*e)*x^4 + 64*(5*c^3*d^3*e + c*d^3*e)*x^3 + 48*(5*c^4*d^2*e + 2*c^2*d^2*e)*x^2 + 32*(3*c^5*d*e + 2*c^3*d*e)*x
- 3*e)*(d^2*x^2 + 2*c*d*x + c^2 + 1)^(3/2) + 24*(d^7*e*x^7 + 7*c*d^6*e*x^6 + c^7*e + 2*c^5*e + (21*c^2*d^5*e +
2*d^5*e)*x^5 + 5*(7*c^3*d^4*e + 2*c*d^4*e)*x^4 + c^3*e + (35*c^4*d^3*e + 20*c^2*d^3*e + d^3*e)*x^3 + (21*c^5*
d^2*e + 20*c^3*d^2*e + 3*c*d^2*e)*x^2 + (7*c^6*d*e + 10*c^4*d*e + 3*c^2*d*e)*x)*(d^2*x^2 + 2*c*d*x + c^2 + 1)
+ 4*c*e + 4*(9*c^8*d*e + 28*c^6*d*e + 30*c^4*d*e + 12*c^2*d*e + d*e)*x + (16*d^8*e*x^8 + 128*c*d^7*e*x^7 + 16*
c^8*e + 48*c^6*e + 16*(28*c^2*d^6*e + 3*d^6*e)*x^6 + 32*(28*c^3*d^5*e + 9*c*d^5*e)*x^5 + 48*c^4*e + 16*(70*c^4
*d^4*e + 45*c^2*d^4*e + 3*d^4*e)*x^4 + 64*(14*c^5*d^3*e + 15*c^3*d^3*e + 3*c*d^3*e)*x^3 + 19*c^2*e + (448*c^6*
d^2*e + 720*c^4*d^2*e + 288*c^2*d^2*e + 19*d^2*e)*x^2 + 2*(64*c^7*d*e + 144*c^5*d*e + 96*c^3*d*e + 19*c*d*e)*x
+ 3*e)*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1))/(a*b^2*d^8*x^8 + 8*a*b^2*c*d^7*x^7 + 4*(7*c^2*d^6 + d^6)*a*b^2*x^6
+ 8*(7*c^3*d^5 + 3*c*d^5)*a*b^2*x^5 + 2*(35*c^4*d^4 + 30*c^2*d^4 + 3*d^4)*a*b^2*x^4 + 8*(7*c^5*d^3 + 10*c^3*d^
3 + 3*c*d^3)*a*b^2*x^3 + 4*(7*c^6*d^2 + 15*c^4*d^2 + 9*c^2*d^2 + d^2)*a*b^2*x^2 + 8*(c^7*d + 3*c^5*d + 3*c^3*d
+ c*d)*a*b^2*x + (c^8 + 4*c^6 + 6*c^4 + 4*c^2 + 1)*a*b^2 + (a*b^2*d^4*x^4 + 4*a*b^2*c*d^3*x^3 + 6*a*b^2*c^2*d
^2*x^2 + 4*a*b^2*c^3*d*x + a*b^2*c^4)*(d^2*x^2 + 2*c*d*x + c^2 + 1)^2 + 4*(a*b^2*d^5*x^5 + 5*a*b^2*c*d^4*x^4 +
(10*c^2*d^3 + d^3)*a*b^2*x^3 + (10*c^3*d^2 + 3*c*d^2)*a*b^2*x^2 + (5*c^4*d + 3*c^2*d)*a*b^2*x + (c^5 + c^3)*a
*b^2)*(d^2*x^2 + 2*c*d*x + c^2 + 1)^(3/2) + 6*(a*b^2*d^6*x^6 + 6*a*b^2*c*d^5*x^5 + (15*c^2*d^4 + 2*d^4)*a*b^2*
x^4 + 4*(5*c^3*d^3 + 2*c*d^3)*a*b^2*x^3 + (15*c^4*d^2 + 12*c^2*d^2 + d^2)*a*b^2*x^2 + 2*(3*c^5*d + 4*c^3*d + c
*d)*a*b^2*x + (c^6 + 2*c^4 + c^2)*a*b^2)*(d^2*x^2 + 2*c*d*x + c^2 + 1) + (b^3*d^8*x^8 + 8*b^3*c*d^7*x^7 + 4*(7
*c^2*d^6 + d^6)*b^3*x^6 + 8*(7*c^3*d^5 + 3*c*d^5)*b^3*x^5 + 2*(35*c^4*d^4 + 30*c^2*d^4 + 3*d^4)*b^3*x^4 + 8*(7
*c^5*d^3 + 10*c^3*d^3 + 3*c*d^3)*b^3*x^3 + 4*(7*c^6*d^2 + 15*c^4*d^2 + 9*c^2*d^2 + d^2)*b^3*x^2 + 8*(c^7*d + 3
*c^5*d + 3*c^3*d + c*d)*b^3*x + (c^8 + 4*c^6 + 6*c^4 + 4*c^2 + 1)*b^3 + (b^3*d^4*x^4 + 4*b^3*c*d^3*x^3 + 6*b^3
*c^2*d^2*x^2 + 4*b^3*c^3*d*x + b^3*c^4)*(d^2*x^2 + 2*c*d*x + c^2 + 1)^2 + 4*(b^3*d^5*x^5 + 5*b^3*c*d^4*x^4 + (
10*c^2*d^3 + d^3)*b^3*x^3 + (10*c^3*d^2 + 3*c*d^2)*b^3*x^2 + (5*c^4*d + 3*c^2*d)*b^3*x + (c^5 + c^3)*b^3)*(d^2
*x^2 + 2*c*d*x + c^2 + 1)^(3/2) + 6*(b^3*d^6*x^6 + 6*b^3*c*d^5*x^5 + (15*c^2*d^4 + 2*d^4)*b^3*x^4 + 4*(5*c^3*d
^3 + 2*c*d^3)*b^3*x^3 + (15*c^4*d^2 + 12*c^2*d^2 + d^2)*b^3*x^2 + 2*(3*c^5*d + 4*c^3*d + c*d)*b^3*x + (c^6 + 2
*c^4 + c^2)*b^3)*(d^2*x^2 + 2*c*d*x + c^2 + 1) + 4*(b^3*d^7*x^7 + 7*b^3*c*d^6*x^6 + 3*(7*c^2*d^5 + d^5)*b^3*x^
5 + 5*(7*c^3*d^4 + 3*c*d^4)*b^3*x^4 + (35*c^4*d^3 + 30*c^2*d^3 + 3*d^3)*b^3*x^3 + 3*(7*c^5*d^2 + 10*c^3*d^2 +
3*c*d^2)*b^3*x^2 + (7*c^6*d + 15*c^4*d + 9*c^2*d + d)*b^3*x + (c^7 + 3*c^5 + 3*c^3 + c)*b^3)*sqrt(d^2*x^2 + 2*
c*d*x + c^2 + 1))*log(d*x + c + sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)) + 4*(a*b^2*d^7*x^7 + 7*a*b^2*c*d^6*x^6 + 3*
(7*c^2*d^5 + d^5)*a*b^2*x^5 + 5*(7*c^3*d^4 + 3*c*d^4)*a*b^2*x^4 + (35*c^4*d^3 + 30*c^2*d^3 + 3*d^3)*a*b^2*x^3
+ 3*(7*c^5*d^2 + 10*c^3*d^2 + 3*c*d^2)*a*b^2*x^2 + (7*c^6*d + 15*c^4*d + 9*c^2*d + d)*a*b^2*x + (c^7 + 3*c^5 +
3*c^3 + c)*a*b^2)*sqrt(d^2*x^2 + 2*c*d*x + c^2 + 1)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {c\,e+d\,e\,x}{{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*e + d*e*x)/(a + b*asinh(c + d*x))^3,x)

[Out]

int((c*e + d*e*x)/(a + b*asinh(c + d*x))^3, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ e \left (\int \frac {c}{a^{3} + 3 a^{2} b \operatorname {asinh}{\left (c + d x \right )} + 3 a b^{2} \operatorname {asinh}^{2}{\left (c + d x \right )} + b^{3} \operatorname {asinh}^{3}{\left (c + d x \right )}}\, dx + \int \frac {d x}{a^{3} + 3 a^{2} b \operatorname {asinh}{\left (c + d x \right )} + 3 a b^{2} \operatorname {asinh}^{2}{\left (c + d x \right )} + b^{3} \operatorname {asinh}^{3}{\left (c + d x \right )}}\, dx\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*e*x+c*e)/(a+b*asinh(d*x+c))**3,x)

[Out]

e*(Integral(c/(a**3 + 3*a**2*b*asinh(c + d*x) + 3*a*b**2*asinh(c + d*x)**2 + b**3*asinh(c + d*x)**3), x) + Int
egral(d*x/(a**3 + 3*a**2*b*asinh(c + d*x) + 3*a*b**2*asinh(c + d*x)**2 + b**3*asinh(c + d*x)**3), x))

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