Optimal. Leaf size=281 \[ \frac {160 b^3 e^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )}{27 d}-\frac {8 b^3 e^2 (c+d x)^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )}{27 d}+\frac {4 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{9 d}-\frac {8 b^2 e^2 (c+d x) \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {8 b e^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}-\frac {4 b e^2 (c+d x)^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^4}{3 d}+\frac {8 b^4 e^2 (c+d x)^3}{81 d}-\frac {160}{27} b^4 e^2 x \]
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Rubi [A] time = 0.48, antiderivative size = 281, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 8, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.348, Rules used = {5865, 12, 5661, 5758, 5717, 5653, 8, 30} \[ \frac {160 b^3 e^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )}{27 d}-\frac {8 b^3 e^2 (c+d x)^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )}{27 d}+\frac {4 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{9 d}-\frac {8 b^2 e^2 (c+d x) \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {8 b e^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}-\frac {4 b e^2 (c+d x)^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^4}{3 d}+\frac {8 b^4 e^2 (c+d x)^3}{81 d}-\frac {160}{27} b^4 e^2 x \]
Antiderivative was successfully verified.
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Rule 8
Rule 12
Rule 30
Rule 5653
Rule 5661
Rule 5717
Rule 5758
Rule 5865
Rubi steps
\begin {align*} \int (c e+d e x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^4 \, dx &=\frac {\operatorname {Subst}\left (\int e^2 x^2 \left (a+b \sinh ^{-1}(x)\right )^4 \, dx,x,c+d x\right )}{d}\\ &=\frac {e^2 \operatorname {Subst}\left (\int x^2 \left (a+b \sinh ^{-1}(x)\right )^4 \, dx,x,c+d x\right )}{d}\\ &=\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^4}{3 d}-\frac {\left (4 b e^2\right ) \operatorname {Subst}\left (\int \frac {x^3 \left (a+b \sinh ^{-1}(x)\right )^3}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{3 d}\\ &=-\frac {4 b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^4}{3 d}+\frac {\left (8 b e^2\right ) \operatorname {Subst}\left (\int \frac {x \left (a+b \sinh ^{-1}(x)\right )^3}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{9 d}+\frac {\left (4 b^2 e^2\right ) \operatorname {Subst}\left (\int x^2 \left (a+b \sinh ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{3 d}\\ &=\frac {4 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{9 d}+\frac {8 b e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}-\frac {4 b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^4}{3 d}-\frac {\left (8 b^2 e^2\right ) \operatorname {Subst}\left (\int \left (a+b \sinh ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{3 d}-\frac {\left (8 b^3 e^2\right ) \operatorname {Subst}\left (\int \frac {x^3 \left (a+b \sinh ^{-1}(x)\right )}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{9 d}\\ &=-\frac {8 b^3 e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{27 d}-\frac {8 b^2 e^2 (c+d x) \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {4 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{9 d}+\frac {8 b e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}-\frac {4 b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^4}{3 d}+\frac {\left (16 b^3 e^2\right ) \operatorname {Subst}\left (\int \frac {x \left (a+b \sinh ^{-1}(x)\right )}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{27 d}+\frac {\left (16 b^3 e^2\right ) \operatorname {Subst}\left (\int \frac {x \left (a+b \sinh ^{-1}(x)\right )}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{3 d}+\frac {\left (8 b^4 e^2\right ) \operatorname {Subst}\left (\int x^2 \, dx,x,c+d x\right )}{27 d}\\ &=\frac {8 b^4 e^2 (c+d x)^3}{81 d}+\frac {160 b^3 e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{27 d}-\frac {8 b^3 e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{27 d}-\frac {8 b^2 e^2 (c+d x) \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {4 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{9 d}+\frac {8 b e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}-\frac {4 b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^4}{3 d}-\frac {\left (16 b^4 e^2\right ) \operatorname {Subst}(\int 1 \, dx,x,c+d x)}{27 d}-\frac {\left (16 b^4 e^2\right ) \operatorname {Subst}(\int 1 \, dx,x,c+d x)}{3 d}\\ &=-\frac {160}{27} b^4 e^2 x+\frac {8 b^4 e^2 (c+d x)^3}{81 d}+\frac {160 b^3 e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{27 d}-\frac {8 b^3 e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )}{27 d}-\frac {8 b^2 e^2 (c+d x) \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {4 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^2}{9 d}+\frac {8 b e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}-\frac {4 b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^3}{9 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^4}{3 d}\\ \end {align*}
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Mathematica [A] time = 0.45, size = 412, normalized size = 1.47 \[ \frac {e^2 \left (-24 b^2 \left (9 a^2+20 b^2\right ) (c+d x)+12 a b \sqrt {(c+d x)^2+1} \left (-\left (3 a^2+2 b^2\right ) (c+d x)^2+6 a^2+40 b^2\right )+18 b^2 \sinh ^{-1}(c+d x)^2 \left (9 a^2 (c+d x)^3-6 a b \sqrt {(c+d x)^2+1} (c+d x)^2+12 a b \sqrt {(c+d x)^2+1}+2 b^2 (c+d x)^3-12 b^2 (c+d x)\right )+\left (27 a^4+36 a^2 b^2+8 b^4\right ) (c+d x)^3+12 b \sinh ^{-1}(c+d x) \left (9 a^3 (c+d x)^3+18 a^2 b \sqrt {(c+d x)^2+1}-9 a^2 b (c+d x)^2 \sqrt {(c+d x)^2+1}+6 a b^2 (c+d x)^3-36 a b^2 (c+d x)-2 b^3 (c+d x)^2 \sqrt {(c+d x)^2+1}+40 b^3 \sqrt {(c+d x)^2+1}\right )-36 b^3 \sinh ^{-1}(c+d x)^3 \left (-3 a (c+d x)^3+b \sqrt {(c+d x)^2+1} (c+d x)^2-2 b \sqrt {(c+d x)^2+1}\right )+27 b^4 (c+d x)^3 \sinh ^{-1}(c+d x)^4\right )}{81 d} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.75, size = 900, normalized size = 3.20 \[ \frac {{\left (27 \, a^{4} + 36 \, a^{2} b^{2} + 8 \, b^{4}\right )} d^{3} e^{2} x^{3} + 3 \, {\left (27 \, a^{4} + 36 \, a^{2} b^{2} + 8 \, b^{4}\right )} c d^{2} e^{2} x^{2} - 3 \, {\left (72 \, a^{2} b^{2} + 160 \, b^{4} - {\left (27 \, a^{4} + 36 \, a^{2} b^{2} + 8 \, b^{4}\right )} c^{2}\right )} d e^{2} x + 27 \, {\left (b^{4} d^{3} e^{2} x^{3} + 3 \, b^{4} c d^{2} e^{2} x^{2} + 3 \, b^{4} c^{2} d e^{2} x + b^{4} c^{3} e^{2}\right )} \log \left (d x + c + \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )^{4} + 36 \, {\left (3 \, a b^{3} d^{3} e^{2} x^{3} + 9 \, a b^{3} c d^{2} e^{2} x^{2} + 9 \, a b^{3} c^{2} d e^{2} x + 3 \, a b^{3} c^{3} e^{2} - {\left (b^{4} d^{2} e^{2} x^{2} + 2 \, b^{4} c d e^{2} x + {\left (b^{4} c^{2} - 2 \, b^{4}\right )} e^{2}\right )} \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )} \log \left (d x + c + \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )^{3} + 18 \, {\left ({\left (9 \, a^{2} b^{2} + 2 \, b^{4}\right )} d^{3} e^{2} x^{3} + 3 \, {\left (9 \, a^{2} b^{2} + 2 \, b^{4}\right )} c d^{2} e^{2} x^{2} - 3 \, {\left (4 \, b^{4} - {\left (9 \, a^{2} b^{2} + 2 \, b^{4}\right )} c^{2}\right )} d e^{2} x - {\left (12 \, b^{4} c - {\left (9 \, a^{2} b^{2} + 2 \, b^{4}\right )} c^{3}\right )} e^{2} - 6 \, {\left (a b^{3} d^{2} e^{2} x^{2} + 2 \, a b^{3} c d e^{2} x + {\left (a b^{3} c^{2} - 2 \, a b^{3}\right )} e^{2}\right )} \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )} \log \left (d x + c + \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )^{2} + 12 \, {\left (3 \, {\left (3 \, a^{3} b + 2 \, a b^{3}\right )} d^{3} e^{2} x^{3} + 9 \, {\left (3 \, a^{3} b + 2 \, a b^{3}\right )} c d^{2} e^{2} x^{2} - 9 \, {\left (4 \, a b^{3} - {\left (3 \, a^{3} b + 2 \, a b^{3}\right )} c^{2}\right )} d e^{2} x - 3 \, {\left (12 \, a b^{3} c - {\left (3 \, a^{3} b + 2 \, a b^{3}\right )} c^{3}\right )} e^{2} - {\left ({\left (9 \, a^{2} b^{2} + 2 \, b^{4}\right )} d^{2} e^{2} x^{2} + 2 \, {\left (9 \, a^{2} b^{2} + 2 \, b^{4}\right )} c d e^{2} x - {\left (18 \, a^{2} b^{2} + 40 \, b^{4} - {\left (9 \, a^{2} b^{2} + 2 \, b^{4}\right )} c^{2}\right )} e^{2}\right )} \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )} \log \left (d x + c + \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right ) - 12 \, {\left ({\left (3 \, a^{3} b + 2 \, a b^{3}\right )} d^{2} e^{2} x^{2} + 2 \, {\left (3 \, a^{3} b + 2 \, a b^{3}\right )} c d e^{2} x - {\left (6 \, a^{3} b + 40 \, a b^{3} - {\left (3 \, a^{3} b + 2 \, a b^{3}\right )} c^{2}\right )} e^{2}\right )} \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}}{81 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (d e x + c e\right )}^{2} {\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{4}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 473, normalized size = 1.68 \[ \frac {\frac {\left (d x +c \right )^{3} e^{2} a^{4}}{3}+e^{2} b^{4} \left (\frac {\left (d x +c \right )^{3} \arcsinh \left (d x +c \right )^{4}}{3}+\frac {8 \arcsinh \left (d x +c \right )^{3} \sqrt {1+\left (d x +c \right )^{2}}}{9}-\frac {4 \left (d x +c \right )^{2} \arcsinh \left (d x +c \right )^{3} \sqrt {1+\left (d x +c \right )^{2}}}{9}-\frac {8 \left (d x +c \right ) \arcsinh \left (d x +c \right )^{2}}{3}+\frac {160 \arcsinh \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}}{27}-\frac {160 d x}{27}-\frac {160 c}{27}+\frac {4 \left (d x +c \right )^{3} \arcsinh \left (d x +c \right )^{2}}{9}-\frac {8 \arcsinh \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}\, \left (d x +c \right )^{2}}{27}+\frac {8 \left (d x +c \right )^{3}}{81}\right )+4 e^{2} a \,b^{3} \left (\frac {\left (d x +c \right )^{3} \arcsinh \left (d x +c \right )^{3}}{3}+\frac {2 \arcsinh \left (d x +c \right )^{2} \sqrt {1+\left (d x +c \right )^{2}}}{3}-\frac {\left (d x +c \right )^{2} \arcsinh \left (d x +c \right )^{2} \sqrt {1+\left (d x +c \right )^{2}}}{3}-\frac {4 \left (d x +c \right ) \arcsinh \left (d x +c \right )}{3}+\frac {40 \sqrt {1+\left (d x +c \right )^{2}}}{27}+\frac {2 \left (d x +c \right )^{3} \arcsinh \left (d x +c \right )}{9}-\frac {2 \left (d x +c \right )^{2} \sqrt {1+\left (d x +c \right )^{2}}}{27}\right )+6 e^{2} a^{2} b^{2} \left (\frac {\left (d x +c \right )^{3} \arcsinh \left (d x +c \right )^{2}}{3}+\frac {4 \arcsinh \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}}{9}-\frac {2 \arcsinh \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}\, \left (d x +c \right )^{2}}{9}-\frac {4 d x}{9}-\frac {4 c}{9}+\frac {2 \left (d x +c \right )^{3}}{27}\right )+4 e^{2} a^{3} b \left (\frac {\left (d x +c \right )^{3} \arcsinh \left (d x +c \right )}{3}-\frac {\left (d x +c \right )^{2} \sqrt {1+\left (d x +c \right )^{2}}}{9}+\frac {2 \sqrt {1+\left (d x +c \right )^{2}}}{9}\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (c\,e+d\,e\,x\right )}^2\,{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^4 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 9.65, size = 1889, normalized size = 6.72 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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