Optimal. Leaf size=135 \[ -\frac {6 e^{c+d x} \, _2F_1\left (1,\frac {d}{2 b};\frac {d}{2 b}+1;e^{2 (a+b x)}\right )}{d}+\frac {12 e^{c+d x} \, _2F_1\left (2,\frac {d}{2 b};\frac {d}{2 b}+1;e^{2 (a+b x)}\right )}{d}-\frac {8 e^{c+d x} \, _2F_1\left (3,\frac {d}{2 b};\frac {d}{2 b}+1;e^{2 (a+b x)}\right )}{d}+\frac {e^{c+d x}}{d} \]
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Rubi [A] time = 0.16, antiderivative size = 135, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {5485, 2194, 2251} \[ -\frac {6 e^{c+d x} \, _2F_1\left (1,\frac {d}{2 b};\frac {d}{2 b}+1;e^{2 (a+b x)}\right )}{d}+\frac {12 e^{c+d x} \, _2F_1\left (2,\frac {d}{2 b};\frac {d}{2 b}+1;e^{2 (a+b x)}\right )}{d}-\frac {8 e^{c+d x} \, _2F_1\left (3,\frac {d}{2 b};\frac {d}{2 b}+1;e^{2 (a+b x)}\right )}{d}+\frac {e^{c+d x}}{d} \]
Antiderivative was successfully verified.
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Rule 2194
Rule 2251
Rule 5485
Rubi steps
\begin {align*} \int e^{c+d x} \coth ^3(a+b x) \, dx &=\int \left (e^{c+d x}+\frac {8 e^{c+d x}}{\left (-1+e^{2 (a+b x)}\right )^3}+\frac {12 e^{c+d x}}{\left (-1+e^{2 (a+b x)}\right )^2}+\frac {6 e^{c+d x}}{-1+e^{2 (a+b x)}}\right ) \, dx\\ &=6 \int \frac {e^{c+d x}}{-1+e^{2 (a+b x)}} \, dx+8 \int \frac {e^{c+d x}}{\left (-1+e^{2 (a+b x)}\right )^3} \, dx+12 \int \frac {e^{c+d x}}{\left (-1+e^{2 (a+b x)}\right )^2} \, dx+\int e^{c+d x} \, dx\\ &=\frac {e^{c+d x}}{d}-\frac {6 e^{c+d x} \, _2F_1\left (1,\frac {d}{2 b};1+\frac {d}{2 b};e^{2 (a+b x)}\right )}{d}+\frac {12 e^{c+d x} \, _2F_1\left (2,\frac {d}{2 b};1+\frac {d}{2 b};e^{2 (a+b x)}\right )}{d}-\frac {8 e^{c+d x} \, _2F_1\left (3,\frac {d}{2 b};1+\frac {d}{2 b};e^{2 (a+b x)}\right )}{d}\\ \end {align*}
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Mathematica [A] time = 3.81, size = 176, normalized size = 1.30 \[ \frac {1}{2} e^c \left (-\frac {2 e^{2 a} \left (2 b^2+d^2\right ) \left (\frac {e^{d x} \, _2F_1\left (1,\frac {d}{2 b};\frac {d}{2 b}+1;e^{2 (a+b x)}\right )}{d}-\frac {e^{x (2 b+d)} \, _2F_1\left (1,\frac {d}{2 b}+1;\frac {d}{2 b}+2;e^{2 (a+b x)}\right )}{2 b+d}\right )}{\left (e^{2 a}-1\right ) b^2}+\frac {d \text {csch}(a) e^{d x} \sinh (b x) \text {csch}(a+b x)}{b^2}-\frac {e^{d x} \text {csch}^2(a+b x)}{b}+\frac {2 \coth (a) e^{d x}}{d}\right ) \]
Antiderivative was successfully verified.
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fricas [F] time = 0.49, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\cosh \left (b x + a\right )^{3} \operatorname {csch}\left (b x + a\right )^{3} e^{\left (d x + c\right )}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \cosh \left (b x + a\right )^{3} \operatorname {csch}\left (b x + a\right )^{3} e^{\left (d x + c\right )}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.88, size = 0, normalized size = 0.00 \[ \int {\mathrm e}^{d x +c} \left (\cosh ^{3}\left (b x +a \right )\right ) \mathrm {csch}\left (b x +a \right )^{3}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -48 \, {\left (2 \, b^{3} e^{c} + b d^{2} e^{c}\right )} \int \frac {e^{\left (d x\right )}}{48 \, b^{3} - 44 \, b^{2} d + 12 \, b d^{2} - d^{3} + {\left (48 \, b^{3} - 44 \, b^{2} d + 12 \, b d^{2} - d^{3}\right )} e^{\left (8 \, b x + 8 \, a\right )} - 4 \, {\left (48 \, b^{3} - 44 \, b^{2} d + 12 \, b d^{2} - d^{3}\right )} e^{\left (6 \, b x + 6 \, a\right )} + 6 \, {\left (48 \, b^{3} - 44 \, b^{2} d + 12 \, b d^{2} - d^{3}\right )} e^{\left (4 \, b x + 4 \, a\right )} - 4 \, {\left (48 \, b^{3} - 44 \, b^{2} d + 12 \, b d^{2} - d^{3}\right )} e^{\left (2 \, b x + 2 \, a\right )}}\,{d x} + \frac {{\left (48 \, b^{3} e^{c} + 44 \, b^{2} d e^{c} + 36 \, b d^{2} e^{c} + d^{3} e^{c} - {\left (48 \, b^{3} e^{c} - 44 \, b^{2} d e^{c} + 12 \, b d^{2} e^{c} - d^{3} e^{c}\right )} e^{\left (6 \, b x + 6 \, a\right )} + 3 \, {\left (48 \, b^{3} e^{c} + 4 \, b^{2} d e^{c} - 8 \, b d^{2} e^{c} + d^{3} e^{c}\right )} e^{\left (4 \, b x + 4 \, a\right )} - 3 \, {\left (48 \, b^{3} e^{c} + 28 \, b^{2} d e^{c} - d^{3} e^{c}\right )} e^{\left (2 \, b x + 2 \, a\right )}\right )} e^{\left (d x\right )}}{48 \, b^{3} d - 44 \, b^{2} d^{2} + 12 \, b d^{3} - d^{4} - {\left (48 \, b^{3} d - 44 \, b^{2} d^{2} + 12 \, b d^{3} - d^{4}\right )} e^{\left (6 \, b x + 6 \, a\right )} + 3 \, {\left (48 \, b^{3} d - 44 \, b^{2} d^{2} + 12 \, b d^{3} - d^{4}\right )} e^{\left (4 \, b x + 4 \, a\right )} - 3 \, {\left (48 \, b^{3} d - 44 \, b^{2} d^{2} + 12 \, b d^{3} - d^{4}\right )} e^{\left (2 \, b x + 2 \, a\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\mathrm {cosh}\left (a+b\,x\right )}^3\,{\mathrm {e}}^{c+d\,x}}{{\mathrm {sinh}\left (a+b\,x\right )}^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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