Optimal. Leaf size=195 \[ \frac {d e^{c+d x} \sinh (a+b x)}{8 \left (b^2-d^2\right )}+\frac {d e^{c+d x} \sinh (3 a+3 b x)}{16 \left (9 b^2-d^2\right )}-\frac {d e^{c+d x} \sinh (5 a+5 b x)}{16 \left (25 b^2-d^2\right )}-\frac {b e^{c+d x} \cosh (a+b x)}{8 \left (b^2-d^2\right )}-\frac {3 b e^{c+d x} \cosh (3 a+3 b x)}{16 \left (9 b^2-d^2\right )}+\frac {5 b e^{c+d x} \cosh (5 a+5 b x)}{16 \left (25 b^2-d^2\right )} \]
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Rubi [A] time = 0.14, antiderivative size = 195, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 2, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {5509, 5474} \[ \frac {d e^{c+d x} \sinh (a+b x)}{8 \left (b^2-d^2\right )}+\frac {d e^{c+d x} \sinh (3 a+3 b x)}{16 \left (9 b^2-d^2\right )}-\frac {d e^{c+d x} \sinh (5 a+5 b x)}{16 \left (25 b^2-d^2\right )}-\frac {b e^{c+d x} \cosh (a+b x)}{8 \left (b^2-d^2\right )}-\frac {3 b e^{c+d x} \cosh (3 a+3 b x)}{16 \left (9 b^2-d^2\right )}+\frac {5 b e^{c+d x} \cosh (5 a+5 b x)}{16 \left (25 b^2-d^2\right )} \]
Antiderivative was successfully verified.
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Rule 5474
Rule 5509
Rubi steps
\begin {align*} \int e^{c+d x} \cosh ^2(a+b x) \sinh ^3(a+b x) \, dx &=\int \left (-\frac {1}{8} e^{c+d x} \sinh (a+b x)-\frac {1}{16} e^{c+d x} \sinh (3 a+3 b x)+\frac {1}{16} e^{c+d x} \sinh (5 a+5 b x)\right ) \, dx\\ &=-\left (\frac {1}{16} \int e^{c+d x} \sinh (3 a+3 b x) \, dx\right )+\frac {1}{16} \int e^{c+d x} \sinh (5 a+5 b x) \, dx-\frac {1}{8} \int e^{c+d x} \sinh (a+b x) \, dx\\ &=-\frac {b e^{c+d x} \cosh (a+b x)}{8 \left (b^2-d^2\right )}-\frac {3 b e^{c+d x} \cosh (3 a+3 b x)}{16 \left (9 b^2-d^2\right )}+\frac {5 b e^{c+d x} \cosh (5 a+5 b x)}{16 \left (25 b^2-d^2\right )}+\frac {d e^{c+d x} \sinh (a+b x)}{8 \left (b^2-d^2\right )}+\frac {d e^{c+d x} \sinh (3 a+3 b x)}{16 \left (9 b^2-d^2\right )}-\frac {d e^{c+d x} \sinh (5 a+5 b x)}{16 \left (25 b^2-d^2\right )}\\ \end {align*}
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Mathematica [A] time = 1.17, size = 117, normalized size = 0.60 \[ \frac {1}{16} e^{c+d x} \left (\frac {d \sinh (3 (a+b x))-3 b \cosh (3 (a+b x))}{9 b^2-d^2}+\frac {5 b \cosh (5 (a+b x))-d \sinh (5 (a+b x))}{25 b^2-d^2}+\frac {2 d \sinh (a+b x)-2 b \cosh (a+b x)}{(b-d) (b+d)}\right ) \]
Antiderivative was successfully verified.
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fricas [B] time = 0.45, size = 919, normalized size = 4.71 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.15, size = 132, normalized size = 0.68 \[ \frac {e^{\left (5 \, b x + d x + 5 \, a + c\right )}}{32 \, {\left (5 \, b + d\right )}} - \frac {e^{\left (3 \, b x + d x + 3 \, a + c\right )}}{32 \, {\left (3 \, b + d\right )}} - \frac {e^{\left (b x + d x + a + c\right )}}{16 \, {\left (b + d\right )}} - \frac {e^{\left (-b x + d x - a + c\right )}}{16 \, {\left (b - d\right )}} - \frac {e^{\left (-3 \, b x + d x - 3 \, a + c\right )}}{32 \, {\left (3 \, b - d\right )}} + \frac {e^{\left (-5 \, b x + d x - 5 \, a + c\right )}}{32 \, {\left (5 \, b - d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.52, size = 278, normalized size = 1.43 \[ \frac {\sinh \left (a -c +\left (b -d \right ) x \right )}{16 b -16 d}-\frac {\sinh \left (a +c +\left (b +d \right ) x \right )}{16 \left (b +d \right )}+\frac {\sinh \left (3 a -c +\left (3 b -d \right ) x \right )}{96 b -32 d}-\frac {\sinh \left (3 a +c +\left (3 b +d \right ) x \right )}{32 \left (3 b +d \right )}-\frac {\sinh \left (\left (5 b -d \right ) x +5 a -c \right )}{32 \left (5 b -d \right )}+\frac {\sinh \left (\left (5 b +d \right ) x +5 a +c \right )}{160 b +32 d}-\frac {\cosh \left (a -c +\left (b -d \right ) x \right )}{16 \left (b -d \right )}-\frac {\cosh \left (a +c +\left (b +d \right ) x \right )}{16 \left (b +d \right )}-\frac {\cosh \left (3 a -c +\left (3 b -d \right ) x \right )}{32 \left (3 b -d \right )}-\frac {\cosh \left (3 a +c +\left (3 b +d \right ) x \right )}{32 \left (3 b +d \right )}+\frac {\cosh \left (\left (5 b -d \right ) x +5 a -c \right )}{160 b -32 d}+\frac {\cosh \left (\left (5 b +d \right ) x +5 a +c \right )}{160 b +32 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.49, size = 395, normalized size = 2.03 \[ \frac {3\,{\mathrm {cosh}\left (a+b\,x\right )}^3\,{\mathrm {e}}^{c+d\,x}\,{\mathrm {sinh}\left (a+b\,x\right )}^2\,\left (25\,b^5-10\,b^3\,d^2+b\,d^4\right )}{225\,b^6-259\,b^4\,d^2+35\,b^2\,d^4-d^6}-\frac {{\mathrm {cosh}\left (a+b\,x\right )}^5\,{\mathrm {e}}^{c+d\,x}\,\left (30\,b^5-6\,b^3\,d^2\right )}{225\,b^6-259\,b^4\,d^2+35\,b^2\,d^4-d^6}+\frac {6\,{\mathrm {cosh}\left (a+b\,x\right )}^4\,{\mathrm {e}}^{c+d\,x}\,\mathrm {sinh}\left (a+b\,x\right )\,\left (5\,b^4\,d-b^2\,d^3\right )}{225\,b^6-259\,b^4\,d^2+35\,b^2\,d^4-d^6}-\frac {{\mathrm {cosh}\left (a+b\,x\right )}^2\,{\mathrm {e}}^{c+d\,x}\,{\mathrm {sinh}\left (a+b\,x\right )}^3\,\left (65\,b^4\,d-18\,b^2\,d^3+d^5\right )}{225\,b^6-259\,b^4\,d^2+35\,b^2\,d^4-d^6}+\frac {2\,b^2\,d\,{\mathrm {e}}^{c+d\,x}\,{\mathrm {sinh}\left (a+b\,x\right )}^5\,\left (13\,b^2-d^2\right )}{225\,b^6-259\,b^4\,d^2+35\,b^2\,d^4-d^6}-\frac {2\,b\,d^2\,\mathrm {cosh}\left (a+b\,x\right )\,{\mathrm {e}}^{c+d\,x}\,{\mathrm {sinh}\left (a+b\,x\right )}^4\,\left (13\,b^2-d^2\right )}{225\,b^6-259\,b^4\,d^2+35\,b^2\,d^4-d^6} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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