3.871 \(\int F^{c (a+b x)} \sinh ^n(d+e x) \, dx\)

Optimal. Leaf size=95 \[ -\frac {\left (1-e^{2 (d+e x)}\right )^{-n} F^{c (a+b x)} \sinh ^n(d+e x) \, _2F_1\left (-n,-\frac {e n-b c \log (F)}{2 e};\frac {1}{2} \left (-n+\frac {b c \log (F)}{e}+2\right );e^{2 (d+e x)}\right )}{e n-b c \log (F)} \]

[Out]

-F^(c*(b*x+a))*hypergeom([-n, 1/2*(-e*n+b*c*ln(F))/e],[1-1/2*n+1/2*b*c*ln(F)/e],exp(2*e*x+2*d))*sinh(e*x+d)^n/
((1-exp(2*e*x+2*d))^n)/(e*n-b*c*ln(F))

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Rubi [A]  time = 0.15, antiderivative size = 95, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {5482, 2259} \[ -\frac {\left (1-e^{2 (d+e x)}\right )^{-n} F^{c (a+b x)} \sinh ^n(d+e x) \, _2F_1\left (-n,-\frac {e n-b c \log (F)}{2 e};\frac {1}{2} \left (-n+\frac {b c \log (F)}{e}+2\right );e^{2 (d+e x)}\right )}{e n-b c \log (F)} \]

Antiderivative was successfully verified.

[In]

Int[F^(c*(a + b*x))*Sinh[d + e*x]^n,x]

[Out]

-((F^(c*(a + b*x))*Hypergeometric2F1[-n, -(e*n - b*c*Log[F])/(2*e), (2 - n + (b*c*Log[F])/e)/2, E^(2*(d + e*x)
)]*Sinh[d + e*x]^n)/((1 - E^(2*(d + e*x)))^n*(e*n - b*c*Log[F])))

Rule 2259

Int[((a_) + (b_.)*(F_)^((e_.)*((c_.) + (d_.)*(x_))))^(p_)*(G_)^((h_.)*((f_.) + (g_.)*(x_)))*(H_)^((t_.)*((r_.)
+ (s_.)*(x_))), x_Symbol] :> Simp[(G^(h*(f + g*x))*H^(t*(r + s*x))*(a + b*F^(e*(c + d*x)))^p*Hypergeometric2F
1[-p, (g*h*Log[G] + s*t*Log[H])/(d*e*Log[F]), (g*h*Log[G] + s*t*Log[H])/(d*e*Log[F]) + 1, Simplify[-((b*F^(e*(
c + d*x)))/a)]])/((g*h*Log[G] + s*t*Log[H])*((a + b*F^(e*(c + d*x)))/a)^p), x] /; FreeQ[{F, G, H, a, b, c, d,
e, f, g, h, r, s, t, p}, x] &&  !IntegerQ[p]

Rule 5482

Int[(F_)^((c_.)*((a_.) + (b_.)*(x_)))*Sinh[(d_.) + (e_.)*(x_)]^(n_), x_Symbol] :> Dist[(E^(n*(d + e*x))*Sinh[d
+ e*x]^n)/(-1 + E^(2*(d + e*x)))^n, Int[(F^(c*(a + b*x))*(-1 + E^(2*(d + e*x)))^n)/E^(n*(d + e*x)), x], x] /;
FreeQ[{F, a, b, c, d, e, n}, x] &&  !IntegerQ[n]

Rubi steps

\begin {align*} \int F^{c (a+b x)} \sinh ^n(d+e x) \, dx &=\left (e^{n (d+e x)} \left (-1+e^{2 (d+e x)}\right )^{-n} \sinh ^n(d+e x)\right ) \int e^{-n (d+e x)} \left (-1+e^{2 (d+e x)}\right )^n F^{c (a+b x)} \, dx\\ &=-\frac {\left (1-e^{2 (d+e x)}\right )^{-n} F^{c (a+b x)} \, _2F_1\left (-n,-\frac {e n-b c \log (F)}{2 e};\frac {1}{2} \left (2-n+\frac {b c \log (F)}{e}\right );e^{2 (d+e x)}\right ) \sinh ^n(d+e x)}{e n-b c \log (F)}\\ \end {align*}

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Mathematica [A]  time = 0.07, size = 96, normalized size = 1.01 \[ \frac {\left (1-e^{2 (d+e x)}\right )^{-n} F^{c (a+b x)} \sinh ^n(d+e x) \, _2F_1\left (-n,\frac {b c \log (F)-e n}{2 e};\frac {b c \log (F)-e n}{2 e}+1;e^{2 (d+e x)}\right )}{b c \log (F)-e n} \]

Antiderivative was successfully verified.

[In]

Integrate[F^(c*(a + b*x))*Sinh[d + e*x]^n,x]

[Out]

(F^(c*(a + b*x))*Hypergeometric2F1[-n, (-(e*n) + b*c*Log[F])/(2*e), 1 + (-(e*n) + b*c*Log[F])/(2*e), E^(2*(d +
e*x))]*Sinh[d + e*x]^n)/((1 - E^(2*(d + e*x)))^n*(-(e*n) + b*c*Log[F]))

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fricas [F]  time = 0.49, size = 0, normalized size = 0.00 \[ {\rm integral}\left (F^{b c x + a c} \sinh \left (e x + d\right )^{n}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(F^(c*(b*x+a))*sinh(e*x+d)^n,x, algorithm="fricas")

[Out]

integral(F^(b*c*x + a*c)*sinh(e*x + d)^n, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int F^{{\left (b x + a\right )} c} \sinh \left (e x + d\right )^{n}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(F^(c*(b*x+a))*sinh(e*x+d)^n,x, algorithm="giac")

[Out]

integrate(F^((b*x + a)*c)*sinh(e*x + d)^n, x)

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maple [F]  time = 0.11, size = 0, normalized size = 0.00 \[ \int F^{c \left (b x +a \right )} \left (\sinh ^{n}\left (e x +d \right )\right )\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(F^(c*(b*x+a))*sinh(e*x+d)^n,x)

[Out]

int(F^(c*(b*x+a))*sinh(e*x+d)^n,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int F^{{\left (b x + a\right )} c} \sinh \left (e x + d\right )^{n}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(F^(c*(b*x+a))*sinh(e*x+d)^n,x, algorithm="maxima")

[Out]

integrate(F^((b*x + a)*c)*sinh(e*x + d)^n, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int F^{c\,\left (a+b\,x\right )}\,{\mathrm {sinh}\left (d+e\,x\right )}^n \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(F^(c*(a + b*x))*sinh(d + e*x)^n,x)

[Out]

int(F^(c*(a + b*x))*sinh(d + e*x)^n, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int F^{c \left (a + b x\right )} \sinh ^{n}{\left (d + e x \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(F**(c*(b*x+a))*sinh(e*x+d)**n,x)

[Out]

Integral(F**(c*(a + b*x))*sinh(d + e*x)**n, x)

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