3.568 \(\int \frac {b+c+\sinh (x)}{a+b \cosh (x)} \, dx\)

Optimal. Leaf size=57 \[ \frac {2 (b+c) \tanh ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{\sqrt {a-b} \sqrt {a+b}}+\frac {\log (a+b \cosh (x))}{b} \]

[Out]

ln(a+b*cosh(x))/b+2*(b+c)*arctanh((a-b)^(1/2)*tanh(1/2*x)/(a+b)^(1/2))/(a-b)^(1/2)/(a+b)^(1/2)

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Rubi [A]  time = 0.13, antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {4401, 2659, 208, 2668, 31} \[ \frac {2 (b+c) \tanh ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{\sqrt {a-b} \sqrt {a+b}}+\frac {\log (a+b \cosh (x))}{b} \]

Antiderivative was successfully verified.

[In]

Int[(b + c + Sinh[x])/(a + b*Cosh[x]),x]

[Out]

(2*(b + c)*ArcTanh[(Sqrt[a - b]*Tanh[x/2])/Sqrt[a + b]])/(Sqrt[a - b]*Sqrt[a + b]) + Log[a + b*Cosh[x]]/b

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 2659

Int[((a_) + (b_.)*sin[Pi/2 + (c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> With[{e = FreeFactors[Tan[(c + d*x)/2], x
]}, Dist[(2*e)/d, Subst[Int[1/(a + b + (a - b)*e^2*x^2), x], x, Tan[(c + d*x)/2]/e], x]] /; FreeQ[{a, b, c, d}
, x] && NeQ[a^2 - b^2, 0]

Rule 2668

Int[cos[(e_.) + (f_.)*(x_)]^(p_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.), x_Symbol] :> Dist[1/(b^p*f), S
ubst[Int[(a + x)^m*(b^2 - x^2)^((p - 1)/2), x], x, b*Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, m}, x] && Integer
Q[(p - 1)/2] && NeQ[a^2 - b^2, 0]

Rule 4401

Int[u_, x_Symbol] :> With[{v = ExpandTrig[u, x]}, Int[v, x] /; SumQ[v]] /;  !InertTrigFreeQ[u]

Rubi steps

\begin {align*} \int \frac {b+c+\sinh (x)}{a+b \cosh (x)} \, dx &=\int \left (\frac {b+c}{a+b \cosh (x)}+\frac {\sinh (x)}{a+b \cosh (x)}\right ) \, dx\\ &=(b+c) \int \frac {1}{a+b \cosh (x)} \, dx+\int \frac {\sinh (x)}{a+b \cosh (x)} \, dx\\ &=\frac {\operatorname {Subst}\left (\int \frac {1}{a+x} \, dx,x,b \cosh (x)\right )}{b}+(2 (b+c)) \operatorname {Subst}\left (\int \frac {1}{a+b-(a-b) x^2} \, dx,x,\tanh \left (\frac {x}{2}\right )\right )\\ &=\frac {2 (b+c) \tanh ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{\sqrt {a-b} \sqrt {a+b}}+\frac {\log (a+b \cosh (x))}{b}\\ \end {align*}

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Mathematica [A]  time = 0.10, size = 56, normalized size = 0.98 \[ \frac {\log (a+b \cosh (x))}{b}-\frac {2 (b+c) \tan ^{-1}\left (\frac {(a-b) \tanh \left (\frac {x}{2}\right )}{\sqrt {b^2-a^2}}\right )}{\sqrt {b^2-a^2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(b + c + Sinh[x])/(a + b*Cosh[x]),x]

[Out]

(-2*(b + c)*ArcTan[((a - b)*Tanh[x/2])/Sqrt[-a^2 + b^2]])/Sqrt[-a^2 + b^2] + Log[a + b*Cosh[x]]/b

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fricas [B]  time = 0.44, size = 289, normalized size = 5.07 \[ \left [\frac {\sqrt {a^{2} - b^{2}} {\left (b^{2} + b c\right )} \log \left (\frac {b^{2} \cosh \relax (x)^{2} + b^{2} \sinh \relax (x)^{2} + 2 \, a b \cosh \relax (x) + 2 \, a^{2} - b^{2} + 2 \, {\left (b^{2} \cosh \relax (x) + a b\right )} \sinh \relax (x) - 2 \, \sqrt {a^{2} - b^{2}} {\left (b \cosh \relax (x) + b \sinh \relax (x) + a\right )}}{b \cosh \relax (x)^{2} + b \sinh \relax (x)^{2} + 2 \, a \cosh \relax (x) + 2 \, {\left (b \cosh \relax (x) + a\right )} \sinh \relax (x) + b}\right ) - {\left (a^{2} - b^{2}\right )} x + {\left (a^{2} - b^{2}\right )} \log \left (\frac {2 \, {\left (b \cosh \relax (x) + a\right )}}{\cosh \relax (x) - \sinh \relax (x)}\right )}{a^{2} b - b^{3}}, -\frac {2 \, \sqrt {-a^{2} + b^{2}} {\left (b^{2} + b c\right )} \arctan \left (-\frac {\sqrt {-a^{2} + b^{2}} {\left (b \cosh \relax (x) + b \sinh \relax (x) + a\right )}}{a^{2} - b^{2}}\right ) + {\left (a^{2} - b^{2}\right )} x - {\left (a^{2} - b^{2}\right )} \log \left (\frac {2 \, {\left (b \cosh \relax (x) + a\right )}}{\cosh \relax (x) - \sinh \relax (x)}\right )}{a^{2} b - b^{3}}\right ] \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b+c+sinh(x))/(a+b*cosh(x)),x, algorithm="fricas")

[Out]

[(sqrt(a^2 - b^2)*(b^2 + b*c)*log((b^2*cosh(x)^2 + b^2*sinh(x)^2 + 2*a*b*cosh(x) + 2*a^2 - b^2 + 2*(b^2*cosh(x
) + a*b)*sinh(x) - 2*sqrt(a^2 - b^2)*(b*cosh(x) + b*sinh(x) + a))/(b*cosh(x)^2 + b*sinh(x)^2 + 2*a*cosh(x) + 2
*(b*cosh(x) + a)*sinh(x) + b)) - (a^2 - b^2)*x + (a^2 - b^2)*log(2*(b*cosh(x) + a)/(cosh(x) - sinh(x))))/(a^2*
b - b^3), -(2*sqrt(-a^2 + b^2)*(b^2 + b*c)*arctan(-sqrt(-a^2 + b^2)*(b*cosh(x) + b*sinh(x) + a)/(a^2 - b^2)) +
(a^2 - b^2)*x - (a^2 - b^2)*log(2*(b*cosh(x) + a)/(cosh(x) - sinh(x))))/(a^2*b - b^3)]

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giac [A]  time = 0.12, size = 60, normalized size = 1.05 \[ \frac {2 \, {\left (b + c\right )} \arctan \left (\frac {b e^{x} + a}{\sqrt {-a^{2} + b^{2}}}\right )}{\sqrt {-a^{2} + b^{2}}} - \frac {x}{b} + \frac {\log \left (b e^{\left (2 \, x\right )} + 2 \, a e^{x} + b\right )}{b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b+c+sinh(x))/(a+b*cosh(x)),x, algorithm="giac")

[Out]

2*(b + c)*arctan((b*e^x + a)/sqrt(-a^2 + b^2))/sqrt(-a^2 + b^2) - x/b + log(b*e^(2*x) + 2*a*e^x + b)/b

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maple [B]  time = 0.13, size = 127, normalized size = 2.23 \[ -\frac {\ln \left (\tanh \left (\frac {x}{2}\right )-1\right )}{b}-\frac {\ln \left (\tanh \left (\frac {x}{2}\right )+1\right )}{b}+\frac {\ln \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-\left (\tanh ^{2}\left (\frac {x}{2}\right )\right ) b -a -b \right )}{b}+\frac {2 b \arctanh \left (\frac {\left (a -b \right ) \tanh \left (\frac {x}{2}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}+\frac {2 \arctanh \left (\frac {\left (a -b \right ) \tanh \left (\frac {x}{2}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right ) c}{\sqrt {\left (a +b \right ) \left (a -b \right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b+c+sinh(x))/(a+b*cosh(x)),x)

[Out]

-1/b*ln(tanh(1/2*x)-1)-1/b*ln(tanh(1/2*x)+1)+1/b*ln(a*tanh(1/2*x)^2-tanh(1/2*x)^2*b-a-b)+2*b/((a+b)*(a-b))^(1/
2)*arctanh((a-b)*tanh(1/2*x)/((a+b)*(a-b))^(1/2))+2/((a+b)*(a-b))^(1/2)*arctanh((a-b)*tanh(1/2*x)/((a+b)*(a-b)
)^(1/2))*c

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b+c+sinh(x))/(a+b*cosh(x)),x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(4*a^2-4*b^2>0)', see `assume?`
for more details)Is 4*a^2-4*b^2 positive or negative?

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mupad [B]  time = 1.81, size = 198, normalized size = 3.47 \[ \frac {\ln \left (b\,\sqrt {\left (a+b\right )\,\left (a-b\right )}+a^2\,{\mathrm {e}}^x-b^2\,{\mathrm {e}}^x+a\,{\mathrm {e}}^x\,\sqrt {\left (a+b\right )\,\left (a-b\right )}\right )\,\left (b^2\,\sqrt {\left (a+b\right )\,\left (a-b\right )}+a^2-b^2+b\,c\,\sqrt {\left (a+b\right )\,\left (a-b\right )}\right )}{a^2\,b-b^3}-\frac {x}{b}-\frac {\ln \left (b\,\sqrt {\left (a+b\right )\,\left (a-b\right )}-a^2\,{\mathrm {e}}^x+b^2\,{\mathrm {e}}^x+a\,{\mathrm {e}}^x\,\sqrt {\left (a+b\right )\,\left (a-b\right )}\right )\,\left (b^2\,\sqrt {\left (a+b\right )\,\left (a-b\right )}-a^2+b^2+b\,c\,\sqrt {\left (a+b\right )\,\left (a-b\right )}\right )}{a^2\,b-b^3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b + c + sinh(x))/(a + b*cosh(x)),x)

[Out]

(log(b*((a + b)*(a - b))^(1/2) + a^2*exp(x) - b^2*exp(x) + a*exp(x)*((a + b)*(a - b))^(1/2))*(b^2*((a + b)*(a
- b))^(1/2) + a^2 - b^2 + b*c*((a + b)*(a - b))^(1/2)))/(a^2*b - b^3) - x/b - (log(b*((a + b)*(a - b))^(1/2) -
a^2*exp(x) + b^2*exp(x) + a*exp(x)*((a + b)*(a - b))^(1/2))*(b^2*((a + b)*(a - b))^(1/2) - a^2 + b^2 + b*c*((
a + b)*(a - b))^(1/2)))/(a^2*b - b^3)

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sympy [A]  time = 30.82, size = 840, normalized size = 14.74 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b+c+sinh(x))/(a+b*cosh(x)),x)

[Out]

Piecewise((zoo*(2*c*atan(tanh(x/2)) + x - 2*log(tanh(x/2) + 1) + log(tanh(x/2)**2 + 1)), Eq(a, 0) & Eq(b, 0)),
(-1/tanh(x/2) - c/(b*tanh(x/2)) + x/b - 2*log(tanh(x/2) + 1)/b + 2*log(tanh(x/2))/b, Eq(a, -b)), ((c*x + cosh
(x))/a, Eq(b, 0)), (tanh(x/2) + c*tanh(x/2)/b + x/b - 2*log(tanh(x/2) + 1)/b, Eq(a, b)), (a*x*sqrt(a/(a - b) +
b/(a - b))/(a*b*sqrt(a/(a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))) + a*sqrt(a/(a - b) + b/(a - b
))*log(-sqrt(a/(a - b) + b/(a - b)) + tanh(x/2))/(a*b*sqrt(a/(a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a
- b))) + a*sqrt(a/(a - b) + b/(a - b))*log(sqrt(a/(a - b) + b/(a - b)) + tanh(x/2))/(a*b*sqrt(a/(a - b) + b/(
a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))) - 2*a*sqrt(a/(a - b) + b/(a - b))*log(tanh(x/2) + 1)/(a*b*sqrt(a/(
a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))) - b**2*log(-sqrt(a/(a - b) + b/(a - b)) + tanh(x/2))/(
a*b*sqrt(a/(a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))) + b**2*log(sqrt(a/(a - b) + b/(a - b)) + t
anh(x/2))/(a*b*sqrt(a/(a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))) - b*c*log(-sqrt(a/(a - b) + b/(
a - b)) + tanh(x/2))/(a*b*sqrt(a/(a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))) + b*c*log(sqrt(a/(a
- b) + b/(a - b)) + tanh(x/2))/(a*b*sqrt(a/(a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))) - b*x*sqrt
(a/(a - b) + b/(a - b))/(a*b*sqrt(a/(a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))) - b*sqrt(a/(a - b
) + b/(a - b))*log(-sqrt(a/(a - b) + b/(a - b)) + tanh(x/2))/(a*b*sqrt(a/(a - b) + b/(a - b)) - b**2*sqrt(a/(a
- b) + b/(a - b))) - b*sqrt(a/(a - b) + b/(a - b))*log(sqrt(a/(a - b) + b/(a - b)) + tanh(x/2))/(a*b*sqrt(a/(
a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))) + 2*b*sqrt(a/(a - b) + b/(a - b))*log(tanh(x/2) + 1)/(
a*b*sqrt(a/(a - b) + b/(a - b)) - b**2*sqrt(a/(a - b) + b/(a - b))), True))

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