Optimal. Leaf size=106 \[ -\frac {2 \cosh ^{\frac {5}{2}}(a+b x)}{5 b \sinh ^{\frac {5}{2}}(a+b x)}-\frac {2 \sqrt {\cosh (a+b x)}}{b \sqrt {\sinh (a+b x)}}-\frac {\tan ^{-1}\left (\frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}}\right )}{b}+\frac {\tanh ^{-1}\left (\frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}}\right )}{b} \]
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Rubi [A] time = 0.11, antiderivative size = 106, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {2567, 2574, 298, 203, 206} \[ -\frac {2 \cosh ^{\frac {5}{2}}(a+b x)}{5 b \sinh ^{\frac {5}{2}}(a+b x)}-\frac {2 \sqrt {\cosh (a+b x)}}{b \sqrt {\sinh (a+b x)}}-\frac {\tan ^{-1}\left (\frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}}\right )}{b}+\frac {\tanh ^{-1}\left (\frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}}\right )}{b} \]
Antiderivative was successfully verified.
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Rule 203
Rule 206
Rule 298
Rule 2567
Rule 2574
Rubi steps
\begin {align*} \int \frac {\cosh ^{\frac {7}{2}}(a+b x)}{\sinh ^{\frac {7}{2}}(a+b x)} \, dx &=-\frac {2 \cosh ^{\frac {5}{2}}(a+b x)}{5 b \sinh ^{\frac {5}{2}}(a+b x)}+\int \frac {\cosh ^{\frac {3}{2}}(a+b x)}{\sinh ^{\frac {3}{2}}(a+b x)} \, dx\\ &=-\frac {2 \cosh ^{\frac {5}{2}}(a+b x)}{5 b \sinh ^{\frac {5}{2}}(a+b x)}-\frac {2 \sqrt {\cosh (a+b x)}}{b \sqrt {\sinh (a+b x)}}+\int \frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}} \, dx\\ &=-\frac {2 \cosh ^{\frac {5}{2}}(a+b x)}{5 b \sinh ^{\frac {5}{2}}(a+b x)}-\frac {2 \sqrt {\cosh (a+b x)}}{b \sqrt {\sinh (a+b x)}}-\frac {2 \operatorname {Subst}\left (\int \frac {x^2}{-1+x^4} \, dx,x,\frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}}\right )}{b}\\ &=-\frac {2 \cosh ^{\frac {5}{2}}(a+b x)}{5 b \sinh ^{\frac {5}{2}}(a+b x)}-\frac {2 \sqrt {\cosh (a+b x)}}{b \sqrt {\sinh (a+b x)}}+\frac {\operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}}\right )}{b}-\frac {\operatorname {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}}\right )}{b}\\ &=-\frac {\tan ^{-1}\left (\frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}}\right )}{b}+\frac {\tanh ^{-1}\left (\frac {\sqrt {\sinh (a+b x)}}{\sqrt {\cosh (a+b x)}}\right )}{b}-\frac {2 \cosh ^{\frac {5}{2}}(a+b x)}{5 b \sinh ^{\frac {5}{2}}(a+b x)}-\frac {2 \sqrt {\cosh (a+b x)}}{b \sqrt {\sinh (a+b x)}}\\ \end {align*}
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Mathematica [C] time = 0.04, size = 59, normalized size = 0.56 \[ -\frac {2 \cosh ^2(a+b x)^{3/4} \, _2F_1\left (-\frac {5}{4},-\frac {5}{4};-\frac {1}{4};-\sinh ^2(a+b x)\right )}{5 b \sinh ^{\frac {5}{2}}(a+b x) \cosh ^{\frac {3}{2}}(a+b x)} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.47, size = 1001, normalized size = 9.44 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cosh \left (b x + a\right )^{\frac {7}{2}}}{\sinh \left (b x + a\right )^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.18, size = 0, normalized size = 0.00 \[ \int \frac {\cosh ^{\frac {7}{2}}\left (b x +a \right )}{\sinh \left (b x +a \right )^{\frac {7}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cosh \left (b x + a\right )^{\frac {7}{2}}}{\sinh \left (b x + a\right )^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\mathrm {cosh}\left (a+b\,x\right )}^{7/2}}{{\mathrm {sinh}\left (a+b\,x\right )}^{7/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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