3.417 \(\int \frac {\cosh ^2(a+b x) \coth (a+b x)}{x^2} \, dx\)

Optimal. Leaf size=52 \[ \text {Int}\left (\frac {\coth (a+b x)}{x^2},x\right )+b \cosh (2 a) \text {Chi}(2 b x)+b \sinh (2 a) \text {Shi}(2 b x)-\frac {\sinh (2 a+2 b x)}{2 x} \]

[Out]

b*Chi(2*b*x)*cosh(2*a)+b*Shi(2*b*x)*sinh(2*a)-1/2*sinh(2*b*x+2*a)/x+Unintegrable(coth(b*x+a)/x^2,x)

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Rubi [A]  time = 0.13, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\cosh ^2(a+b x) \coth (a+b x)}{x^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[(Cosh[a + b*x]^2*Coth[a + b*x])/x^2,x]

[Out]

b*Cosh[2*a]*CoshIntegral[2*b*x] - Sinh[2*a + 2*b*x]/(2*x) + b*Sinh[2*a]*SinhIntegral[2*b*x] + Defer[Int][Coth[
a + b*x]/x^2, x]

Rubi steps

\begin {align*} \int \frac {\cosh ^2(a+b x) \coth (a+b x)}{x^2} \, dx &=\int \frac {\coth (a+b x)}{x^2} \, dx+\int \frac {\cosh (a+b x) \sinh (a+b x)}{x^2} \, dx\\ &=\int \frac {\coth (a+b x)}{x^2} \, dx+\int \frac {\sinh (2 a+2 b x)}{2 x^2} \, dx\\ &=\frac {1}{2} \int \frac {\sinh (2 a+2 b x)}{x^2} \, dx+\int \frac {\coth (a+b x)}{x^2} \, dx\\ &=-\frac {\sinh (2 a+2 b x)}{2 x}+b \int \frac {\cosh (2 a+2 b x)}{x} \, dx+\int \frac {\coth (a+b x)}{x^2} \, dx\\ &=-\frac {\sinh (2 a+2 b x)}{2 x}+(b \cosh (2 a)) \int \frac {\cosh (2 b x)}{x} \, dx+(b \sinh (2 a)) \int \frac {\sinh (2 b x)}{x} \, dx+\int \frac {\coth (a+b x)}{x^2} \, dx\\ &=b \cosh (2 a) \text {Chi}(2 b x)-\frac {\sinh (2 a+2 b x)}{2 x}+b \sinh (2 a) \text {Shi}(2 b x)+\int \frac {\coth (a+b x)}{x^2} \, dx\\ \end {align*}

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Mathematica [A]  time = 16.85, size = 0, normalized size = 0.00 \[ \int \frac {\cosh ^2(a+b x) \coth (a+b x)}{x^2} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[(Cosh[a + b*x]^2*Coth[a + b*x])/x^2,x]

[Out]

Integrate[(Cosh[a + b*x]^2*Coth[a + b*x])/x^2, x]

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fricas [A]  time = 0.49, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\cosh \left (b x + a\right )^{3} \operatorname {csch}\left (b x + a\right )}{x^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)^3*csch(b*x+a)/x^2,x, algorithm="fricas")

[Out]

integral(cosh(b*x + a)^3*csch(b*x + a)/x^2, x)

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giac [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cosh \left (b x + a\right )^{3} \operatorname {csch}\left (b x + a\right )}{x^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)^3*csch(b*x+a)/x^2,x, algorithm="giac")

[Out]

integrate(cosh(b*x + a)^3*csch(b*x + a)/x^2, x)

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maple [A]  time = 0.72, size = 0, normalized size = 0.00 \[ \int \frac {\left (\cosh ^{3}\left (b x +a \right )\right ) \mathrm {csch}\left (b x +a \right )}{x^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cosh(b*x+a)^3*csch(b*x+a)/x^2,x)

[Out]

int(cosh(b*x+a)^3*csch(b*x+a)/x^2,x)

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maxima [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{2} \, b e^{\left (-2 \, a\right )} \Gamma \left (-1, 2 \, b x\right ) + \frac {1}{2} \, b e^{\left (2 \, a\right )} \Gamma \left (-1, -2 \, b x\right ) - \frac {1}{x} - \int \frac {1}{x^{2} e^{\left (b x + a\right )} + x^{2}}\,{d x} + \int \frac {1}{x^{2} e^{\left (b x + a\right )} - x^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)^3*csch(b*x+a)/x^2,x, algorithm="maxima")

[Out]

1/2*b*e^(-2*a)*gamma(-1, 2*b*x) + 1/2*b*e^(2*a)*gamma(-1, -2*b*x) - 1/x - integrate(1/(x^2*e^(b*x + a) + x^2),
 x) + integrate(1/(x^2*e^(b*x + a) - x^2), x)

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mupad [A]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {{\mathrm {cosh}\left (a+b\,x\right )}^3}{x^2\,\mathrm {sinh}\left (a+b\,x\right )} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cosh(a + b*x)^3/(x^2*sinh(a + b*x)),x)

[Out]

int(cosh(a + b*x)^3/(x^2*sinh(a + b*x)), x)

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sympy [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cosh ^{3}{\left (a + b x \right )} \operatorname {csch}{\left (a + b x \right )}}{x^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cosh(b*x+a)**3*csch(b*x+a)/x**2,x)

[Out]

Integral(cosh(a + b*x)**3*csch(a + b*x)/x**2, x)

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