3.395 \(\int \frac {\tanh ^3(a+b x)}{x} \, dx\)

Optimal. Leaf size=15 \[ \text {Int}\left (\frac {\tanh ^3(a+b x)}{x},x\right ) \]

[Out]

Unintegrable(tanh(b*x+a)^3/x,x)

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Rubi [A]  time = 0.03, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\tanh ^3(a+b x)}{x} \, dx \]

Verification is Not applicable to the result.

[In]

Int[Tanh[a + b*x]^3/x,x]

[Out]

Defer[Int][Tanh[a + b*x]^3/x, x]

Rubi steps

\begin {align*} \int \frac {\tanh ^3(a+b x)}{x} \, dx &=\int \frac {\tanh ^3(a+b x)}{x} \, dx\\ \end {align*}

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Mathematica [A]  time = 14.11, size = 0, normalized size = 0.00 \[ \int \frac {\tanh ^3(a+b x)}{x} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[Tanh[a + b*x]^3/x,x]

[Out]

Integrate[Tanh[a + b*x]^3/x, x]

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fricas [A]  time = 0.64, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\operatorname {sech}\left (b x + a\right )^{3} \sinh \left (b x + a\right )^{3}}{x}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(b*x+a)^3*sinh(b*x+a)^3/x,x, algorithm="fricas")

[Out]

integral(sech(b*x + a)^3*sinh(b*x + a)^3/x, x)

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giac [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {sech}\left (b x + a\right )^{3} \sinh \left (b x + a\right )^{3}}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(b*x+a)^3*sinh(b*x+a)^3/x,x, algorithm="giac")

[Out]

integrate(sech(b*x + a)^3*sinh(b*x + a)^3/x, x)

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maple [A]  time = 1.31, size = 0, normalized size = 0.00 \[ \int \frac {\mathrm {sech}\left (b x +a \right )^{3} \left (\sinh ^{3}\left (b x +a \right )\right )}{x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sech(b*x+a)^3*sinh(b*x+a)^3/x,x)

[Out]

int(sech(b*x+a)^3*sinh(b*x+a)^3/x,x)

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maxima [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {{\left (2 \, b x e^{\left (2 \, a\right )} - e^{\left (2 \, a\right )}\right )} e^{\left (2 \, b x\right )} - 1}{b^{2} x^{2} e^{\left (4 \, b x + 4 \, a\right )} + 2 \, b^{2} x^{2} e^{\left (2 \, b x + 2 \, a\right )} + b^{2} x^{2}} - \int \frac {2 \, {\left (b^{2} x^{2} + 1\right )}}{b^{2} x^{3} e^{\left (2 \, b x + 2 \, a\right )} + b^{2} x^{3}}\,{d x} + \log \relax (x) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(b*x+a)^3*sinh(b*x+a)^3/x,x, algorithm="maxima")

[Out]

((2*b*x*e^(2*a) - e^(2*a))*e^(2*b*x) - 1)/(b^2*x^2*e^(4*b*x + 4*a) + 2*b^2*x^2*e^(2*b*x + 2*a) + b^2*x^2) - in
tegrate(2*(b^2*x^2 + 1)/(b^2*x^3*e^(2*b*x + 2*a) + b^2*x^3), x) + log(x)

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mupad [A]  time = 0.00, size = -1, normalized size = -0.07 \[ \int \frac {{\mathrm {sinh}\left (a+b\,x\right )}^3}{x\,{\mathrm {cosh}\left (a+b\,x\right )}^3} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sinh(a + b*x)^3/(x*cosh(a + b*x)^3),x)

[Out]

int(sinh(a + b*x)^3/(x*cosh(a + b*x)^3), x)

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sympy [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sinh ^{3}{\left (a + b x \right )} \operatorname {sech}^{3}{\left (a + b x \right )}}{x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(b*x+a)**3*sinh(b*x+a)**3/x,x)

[Out]

Integral(sinh(a + b*x)**3*sech(a + b*x)**3/x, x)

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