Optimal. Leaf size=40 \[ \frac {\tanh ^4(a+b x)}{4 b}-\frac {\tanh ^2(a+b x)}{b}+\frac {\log (\tanh (a+b x))}{b} \]
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Rubi [A] time = 0.03, antiderivative size = 40, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2620, 266, 43} \[ \frac {\tanh ^4(a+b x)}{4 b}-\frac {\tanh ^2(a+b x)}{b}+\frac {\log (\tanh (a+b x))}{b} \]
Antiderivative was successfully verified.
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Rule 43
Rule 266
Rule 2620
Rubi steps
\begin {align*} \int \text {csch}(a+b x) \text {sech}^5(a+b x) \, dx &=\frac {\operatorname {Subst}\left (\int \frac {\left (1+x^2\right )^2}{x} \, dx,x,i \tanh (a+b x)\right )}{b}\\ &=\frac {\operatorname {Subst}\left (\int \frac {(1+x)^2}{x} \, dx,x,-\tanh ^2(a+b x)\right )}{2 b}\\ &=\frac {\operatorname {Subst}\left (\int \left (2+\frac {1}{x}+x\right ) \, dx,x,-\tanh ^2(a+b x)\right )}{2 b}\\ &=\frac {\log (\tanh (a+b x))}{b}-\frac {\tanh ^2(a+b x)}{b}+\frac {\tanh ^4(a+b x)}{4 b}\\ \end {align*}
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Mathematica [A] time = 0.10, size = 46, normalized size = 1.15 \[ -\frac {-\text {sech}^4(a+b x)-2 \text {sech}^2(a+b x)-4 \log (\sinh (a+b x))+4 \log (\cosh (a+b x))}{4 b} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.45, size = 1073, normalized size = 26.82 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.15, size = 122, normalized size = 3.05 \[ \frac {\frac {3 \, {\left (e^{\left (2 \, b x + 2 \, a\right )} + e^{\left (-2 \, b x - 2 \, a\right )}\right )}^{2} + 20 \, e^{\left (2 \, b x + 2 \, a\right )} + 20 \, e^{\left (-2 \, b x - 2 \, a\right )} + 44}{{\left (e^{\left (2 \, b x + 2 \, a\right )} + e^{\left (-2 \, b x - 2 \, a\right )} + 2\right )}^{2}} - 2 \, \log \left (e^{\left (2 \, b x + 2 \, a\right )} + e^{\left (-2 \, b x - 2 \, a\right )} + 2\right ) + 2 \, \log \left (e^{\left (2 \, b x + 2 \, a\right )} + e^{\left (-2 \, b x - 2 \, a\right )} - 2\right )}{4 \, b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.17, size = 39, normalized size = 0.98 \[ \frac {1}{4 b \cosh \left (b x +a \right )^{4}}+\frac {1}{2 b \cosh \left (b x +a \right )^{2}}+\frac {\ln \left (\tanh \left (b x +a \right )\right )}{b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.41, size = 131, normalized size = 3.28 \[ \frac {\log \left (e^{\left (-b x - a\right )} + 1\right )}{b} + \frac {\log \left (e^{\left (-b x - a\right )} - 1\right )}{b} - \frac {\log \left (e^{\left (-2 \, b x - 2 \, a\right )} + 1\right )}{b} + \frac {2 \, {\left (e^{\left (-2 \, b x - 2 \, a\right )} + 4 \, e^{\left (-4 \, b x - 4 \, a\right )} + e^{\left (-6 \, b x - 6 \, a\right )}\right )}}{b {\left (4 \, e^{\left (-2 \, b x - 2 \, a\right )} + 6 \, e^{\left (-4 \, b x - 4 \, a\right )} + 4 \, e^{\left (-6 \, b x - 6 \, a\right )} + e^{\left (-8 \, b x - 8 \, a\right )} + 1\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.46, size = 169, normalized size = 4.22 \[ \frac {2}{b\,\left ({\mathrm {e}}^{2\,a+2\,b\,x}+1\right )}-\frac {2\,\mathrm {atan}\left (\frac {{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}\,\sqrt {-b^2}}{b}\right )}{\sqrt {-b^2}}+\frac {2}{b\,\left (2\,{\mathrm {e}}^{2\,a+2\,b\,x}+{\mathrm {e}}^{4\,a+4\,b\,x}+1\right )}-\frac {8}{b\,\left (3\,{\mathrm {e}}^{2\,a+2\,b\,x}+3\,{\mathrm {e}}^{4\,a+4\,b\,x}+{\mathrm {e}}^{6\,a+6\,b\,x}+1\right )}+\frac {4}{b\,\left (4\,{\mathrm {e}}^{2\,a+2\,b\,x}+6\,{\mathrm {e}}^{4\,a+4\,b\,x}+4\,{\mathrm {e}}^{6\,a+6\,b\,x}+{\mathrm {e}}^{8\,a+8\,b\,x}+1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \operatorname {csch}{\left (a + b x \right )} \operatorname {sech}^{5}{\left (a + b x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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