3.193 \(\int \sinh (x) \sinh (3 x) \, dx\)

Optimal. Leaf size=17 \[ \frac {1}{8} \sinh (4 x)-\frac {1}{4} \sinh (2 x) \]

[Out]

-1/4*sinh(2*x)+1/8*sinh(4*x)

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Rubi [A]  time = 0.01, antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {4282} \[ \frac {1}{8} \sinh (4 x)-\frac {1}{4} \sinh (2 x) \]

Antiderivative was successfully verified.

[In]

Int[Sinh[x]*Sinh[3*x],x]

[Out]

-Sinh[2*x]/4 + Sinh[4*x]/8

Rule 4282

Int[sin[(a_.) + (b_.)*(x_)]*sin[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[Sin[a - c + (b - d)*x]/(2*(b - d)), x]
- Simp[Sin[a + c + (b + d)*x]/(2*(b + d)), x] /; FreeQ[{a, b, c, d}, x] && NeQ[b^2 - d^2, 0]

Rubi steps

\begin {align*} \int \sinh (x) \sinh (3 x) \, dx &=-\frac {1}{4} \sinh (2 x)+\frac {1}{8} \sinh (4 x)\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 17, normalized size = 1.00 \[ \frac {1}{8} \sinh (4 x)-\frac {1}{4} \sinh (2 x) \]

Antiderivative was successfully verified.

[In]

Integrate[Sinh[x]*Sinh[3*x],x]

[Out]

-1/4*Sinh[2*x] + Sinh[4*x]/8

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fricas [A]  time = 0.40, size = 22, normalized size = 1.29 \[ \frac {1}{2} \, \cosh \relax (x) \sinh \relax (x)^{3} + \frac {1}{2} \, {\left (\cosh \relax (x)^{3} - \cosh \relax (x)\right )} \sinh \relax (x) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sinh(x)*sinh(3*x),x, algorithm="fricas")

[Out]

1/2*cosh(x)*sinh(x)^3 + 1/2*(cosh(x)^3 - cosh(x))*sinh(x)

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giac [B]  time = 0.13, size = 27, normalized size = 1.59 \[ \frac {1}{16} \, {\left (2 \, e^{\left (2 \, x\right )} - 1\right )} e^{\left (-4 \, x\right )} + \frac {1}{16} \, e^{\left (4 \, x\right )} - \frac {1}{8} \, e^{\left (2 \, x\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sinh(x)*sinh(3*x),x, algorithm="giac")

[Out]

1/16*(2*e^(2*x) - 1)*e^(-4*x) + 1/16*e^(4*x) - 1/8*e^(2*x)

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maple [A]  time = 0.19, size = 14, normalized size = 0.82 \[ -\frac {\sinh \left (2 x \right )}{4}+\frac {\sinh \left (4 x \right )}{8} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sinh(x)*sinh(3*x),x)

[Out]

-1/4*sinh(2*x)+1/8*sinh(4*x)

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maxima [B]  time = 0.30, size = 27, normalized size = 1.59 \[ -\frac {1}{16} \, {\left (2 \, e^{\left (-2 \, x\right )} - 1\right )} e^{\left (4 \, x\right )} + \frac {1}{8} \, e^{\left (-2 \, x\right )} - \frac {1}{16} \, e^{\left (-4 \, x\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sinh(x)*sinh(3*x),x, algorithm="maxima")

[Out]

-1/16*(2*e^(-2*x) - 1)*e^(4*x) + 1/8*e^(-2*x) - 1/16*e^(-4*x)

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mupad [B]  time = 0.06, size = 13, normalized size = 0.76 \[ \frac {\mathrm {sinh}\left (4\,x\right )}{8}-\frac {\mathrm {sinh}\left (2\,x\right )}{4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sinh(3*x)*sinh(x),x)

[Out]

sinh(4*x)/8 - sinh(2*x)/4

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sympy [A]  time = 0.41, size = 20, normalized size = 1.18 \[ \frac {3 \sinh {\relax (x )} \cosh {\left (3 x \right )}}{8} - \frac {\sinh {\left (3 x \right )} \cosh {\relax (x )}}{8} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sinh(x)*sinh(3*x),x)

[Out]

3*sinh(x)*cosh(3*x)/8 - sinh(3*x)*cosh(x)/8

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