3.36 \(\int (a \text {csch}^3(x))^{5/2} \, dx\)

Optimal. Leaf size=135 \[ -\frac {154}{585} a^2 \coth (x) \sqrt {a \text {csch}^3(x)}-\frac {2}{13} a^2 \coth (x) \text {csch}^4(x) \sqrt {a \text {csch}^3(x)}+\frac {22}{117} a^2 \coth (x) \text {csch}^2(x) \sqrt {a \text {csch}^3(x)}+\frac {154}{195} a^2 \sinh (x) \cosh (x) \sqrt {a \text {csch}^3(x)}-\frac {154 i a^2 \sinh ^2(x) E\left (\left .\frac {\pi }{4}-\frac {i x}{2}\right |2\right ) \sqrt {a \text {csch}^3(x)}}{195 \sqrt {i \sinh (x)}} \]

[Out]

-154/585*a^2*coth(x)*(a*csch(x)^3)^(1/2)+22/117*a^2*coth(x)*csch(x)^2*(a*csch(x)^3)^(1/2)-2/13*a^2*coth(x)*csc
h(x)^4*(a*csch(x)^3)^(1/2)+154/195*a^2*cosh(x)*sinh(x)*(a*csch(x)^3)^(1/2)-154/195*I*a^2*(sin(1/4*Pi+1/2*I*x)^
2)^(1/2)/sin(1/4*Pi+1/2*I*x)*EllipticE(cos(1/4*Pi+1/2*I*x),2^(1/2))*sinh(x)^2*(a*csch(x)^3)^(1/2)/(I*sinh(x))^
(1/2)

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Rubi [A]  time = 0.07, antiderivative size = 135, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {4123, 3768, 3771, 2639} \[ -\frac {2}{13} a^2 \coth (x) \text {csch}^4(x) \sqrt {a \text {csch}^3(x)}+\frac {22}{117} a^2 \coth (x) \text {csch}^2(x) \sqrt {a \text {csch}^3(x)}-\frac {154}{585} a^2 \coth (x) \sqrt {a \text {csch}^3(x)}+\frac {154}{195} a^2 \sinh (x) \cosh (x) \sqrt {a \text {csch}^3(x)}-\frac {154 i a^2 \sinh ^2(x) E\left (\left .\frac {\pi }{4}-\frac {i x}{2}\right |2\right ) \sqrt {a \text {csch}^3(x)}}{195 \sqrt {i \sinh (x)}} \]

Antiderivative was successfully verified.

[In]

Int[(a*Csch[x]^3)^(5/2),x]

[Out]

(-154*a^2*Coth[x]*Sqrt[a*Csch[x]^3])/585 + (22*a^2*Coth[x]*Csch[x]^2*Sqrt[a*Csch[x]^3])/117 - (2*a^2*Coth[x]*C
sch[x]^4*Sqrt[a*Csch[x]^3])/13 + (154*a^2*Cosh[x]*Sqrt[a*Csch[x]^3]*Sinh[x])/195 - (((154*I)/195)*a^2*Sqrt[a*C
sch[x]^3]*EllipticE[Pi/4 - (I/2)*x, 2]*Sinh[x]^2)/Sqrt[I*Sinh[x]]

Rule 2639

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticE[(1*(c - Pi/2 + d*x))/2, 2])/d, x] /; FreeQ[{
c, d}, x]

Rule 3768

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> -Simp[(b*Cos[c + d*x]*(b*Csc[c + d*x])^(n - 1))/(d*(n -
1)), x] + Dist[(b^2*(n - 2))/(n - 1), Int[(b*Csc[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1
] && IntegerQ[2*n]

Rule 3771

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Dist[(b*Csc[c + d*x])^n*Sin[c + d*x]^n, Int[1/Sin[c + d
*x]^n, x], x] /; FreeQ[{b, c, d}, x] && EqQ[n^2, 1/4]

Rule 4123

Int[((b_.)*((c_.)*sec[(e_.) + (f_.)*(x_)])^(n_))^(p_), x_Symbol] :> Dist[(b^IntPart[p]*(b*(c*Sec[e + f*x])^n)^
FracPart[p])/(c*Sec[e + f*x])^(n*FracPart[p]), Int[(c*Sec[e + f*x])^(n*p), x], x] /; FreeQ[{b, c, e, f, n, p},
x] &&  !IntegerQ[p]

Rubi steps

\begin {align*} \int \left (a \text {csch}^3(x)\right )^{5/2} \, dx &=-\frac {\left (a^2 \sqrt {a \text {csch}^3(x)}\right ) \int (i \text {csch}(x))^{15/2} \, dx}{(i \text {csch}(x))^{3/2}}\\ &=-\frac {2}{13} a^2 \coth (x) \text {csch}^4(x) \sqrt {a \text {csch}^3(x)}-\frac {\left (11 a^2 \sqrt {a \text {csch}^3(x)}\right ) \int (i \text {csch}(x))^{11/2} \, dx}{13 (i \text {csch}(x))^{3/2}}\\ &=\frac {22}{117} a^2 \coth (x) \text {csch}^2(x) \sqrt {a \text {csch}^3(x)}-\frac {2}{13} a^2 \coth (x) \text {csch}^4(x) \sqrt {a \text {csch}^3(x)}-\frac {\left (77 a^2 \sqrt {a \text {csch}^3(x)}\right ) \int (i \text {csch}(x))^{7/2} \, dx}{117 (i \text {csch}(x))^{3/2}}\\ &=-\frac {154}{585} a^2 \coth (x) \sqrt {a \text {csch}^3(x)}+\frac {22}{117} a^2 \coth (x) \text {csch}^2(x) \sqrt {a \text {csch}^3(x)}-\frac {2}{13} a^2 \coth (x) \text {csch}^4(x) \sqrt {a \text {csch}^3(x)}-\frac {\left (77 a^2 \sqrt {a \text {csch}^3(x)}\right ) \int (i \text {csch}(x))^{3/2} \, dx}{195 (i \text {csch}(x))^{3/2}}\\ &=-\frac {154}{585} a^2 \coth (x) \sqrt {a \text {csch}^3(x)}+\frac {22}{117} a^2 \coth (x) \text {csch}^2(x) \sqrt {a \text {csch}^3(x)}-\frac {2}{13} a^2 \coth (x) \text {csch}^4(x) \sqrt {a \text {csch}^3(x)}+\frac {154}{195} a^2 \cosh (x) \sqrt {a \text {csch}^3(x)} \sinh (x)+\frac {\left (77 a^2 \sqrt {a \text {csch}^3(x)}\right ) \int \frac {1}{\sqrt {i \text {csch}(x)}} \, dx}{195 (i \text {csch}(x))^{3/2}}\\ &=-\frac {154}{585} a^2 \coth (x) \sqrt {a \text {csch}^3(x)}+\frac {22}{117} a^2 \coth (x) \text {csch}^2(x) \sqrt {a \text {csch}^3(x)}-\frac {2}{13} a^2 \coth (x) \text {csch}^4(x) \sqrt {a \text {csch}^3(x)}+\frac {154}{195} a^2 \cosh (x) \sqrt {a \text {csch}^3(x)} \sinh (x)-\frac {\left (77 a^2 \sqrt {a \text {csch}^3(x)} \sinh ^2(x)\right ) \int \sqrt {i \sinh (x)} \, dx}{195 \sqrt {i \sinh (x)}}\\ &=-\frac {154}{585} a^2 \coth (x) \sqrt {a \text {csch}^3(x)}+\frac {22}{117} a^2 \coth (x) \text {csch}^2(x) \sqrt {a \text {csch}^3(x)}-\frac {2}{13} a^2 \coth (x) \text {csch}^4(x) \sqrt {a \text {csch}^3(x)}+\frac {154}{195} a^2 \cosh (x) \sqrt {a \text {csch}^3(x)} \sinh (x)-\frac {154 i a^2 \sqrt {a \text {csch}^3(x)} E\left (\left .\frac {\pi }{4}-\frac {i x}{2}\right |2\right ) \sinh ^2(x)}{195 \sqrt {i \sinh (x)}}\\ \end {align*}

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Mathematica [A]  time = 0.18, size = 68, normalized size = 0.50 \[ -\frac {2}{585} a^2 \sinh (x) \sqrt {a \text {csch}^3(x)} \left (-231 \cosh (x)+\coth (x) \text {csch}(x) \left (45 \text {csch}^4(x)-55 \text {csch}^2(x)+77\right )+231 \sqrt {i \sinh (x)} E\left (\left .\frac {1}{4} (\pi -2 i x)\right |2\right )\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[(a*Csch[x]^3)^(5/2),x]

[Out]

(-2*a^2*Sqrt[a*Csch[x]^3]*(-231*Cosh[x] + Coth[x]*Csch[x]*(77 - 55*Csch[x]^2 + 45*Csch[x]^4) + 231*EllipticE[(
Pi - (2*I)*x)/4, 2]*Sqrt[I*Sinh[x]])*Sinh[x])/585

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fricas [F]  time = 0.61, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\sqrt {a \operatorname {csch}\relax (x)^{3}} a^{2} \operatorname {csch}\relax (x)^{6}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*csch(x)^3)^(5/2),x, algorithm="fricas")

[Out]

integral(sqrt(a*csch(x)^3)*a^2*csch(x)^6, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a \operatorname {csch}\relax (x)^{3}\right )^{\frac {5}{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*csch(x)^3)^(5/2),x, algorithm="giac")

[Out]

integrate((a*csch(x)^3)^(5/2), x)

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maple [F]  time = 0.24, size = 0, normalized size = 0.00 \[ \int \left (a \mathrm {csch}\relax (x )^{3}\right )^{\frac {5}{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*csch(x)^3)^(5/2),x)

[Out]

int((a*csch(x)^3)^(5/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a \operatorname {csch}\relax (x)^{3}\right )^{\frac {5}{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*csch(x)^3)^(5/2),x, algorithm="maxima")

[Out]

integrate((a*csch(x)^3)^(5/2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (\frac {a}{{\mathrm {sinh}\relax (x)}^3}\right )}^{5/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a/sinh(x)^3)^(5/2),x)

[Out]

int((a/sinh(x)^3)^(5/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a \operatorname {csch}^{3}{\relax (x )}\right )^{\frac {5}{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*csch(x)**3)**(5/2),x)

[Out]

Integral((a*csch(x)**3)**(5/2), x)

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