Optimal. Leaf size=146 \[ -\frac {2 b^5 \tan ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{a^5 \sqrt {a-b} \sqrt {a+b}}-\frac {b \sinh (x) \cosh ^2(x)}{3 a^2}-\frac {b \left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^4}+\frac {\left (3 a^2+4 b^2\right ) \sinh (x) \cosh (x)}{8 a^3}+\frac {x \left (3 a^4+4 a^2 b^2+8 b^4\right )}{8 a^5}+\frac {\sinh (x) \cosh ^3(x)}{4 a} \]
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Rubi [A] time = 0.66, antiderivative size = 146, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.462, Rules used = {3853, 4104, 3919, 3831, 2659, 205} \[ \frac {x \left (4 a^2 b^2+3 a^4+8 b^4\right )}{8 a^5}-\frac {b \left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^4}-\frac {2 b^5 \tan ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{a^5 \sqrt {a-b} \sqrt {a+b}}+\frac {\left (3 a^2+4 b^2\right ) \sinh (x) \cosh (x)}{8 a^3}-\frac {b \sinh (x) \cosh ^2(x)}{3 a^2}+\frac {\sinh (x) \cosh ^3(x)}{4 a} \]
Antiderivative was successfully verified.
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Rule 205
Rule 2659
Rule 3831
Rule 3853
Rule 3919
Rule 4104
Rubi steps
\begin {align*} \int \frac {\cosh ^4(x)}{a+b \text {sech}(x)} \, dx &=\frac {\cosh ^3(x) \sinh (x)}{4 a}+\frac {\int \frac {\cosh ^3(x) \left (-4 b+3 a \text {sech}(x)+3 b \text {sech}^2(x)\right )}{a+b \text {sech}(x)} \, dx}{4 a}\\ &=-\frac {b \cosh ^2(x) \sinh (x)}{3 a^2}+\frac {\cosh ^3(x) \sinh (x)}{4 a}-\frac {\int \frac {\cosh ^2(x) \left (-3 \left (3 a^2+4 b^2\right )-a b \text {sech}(x)+8 b^2 \text {sech}^2(x)\right )}{a+b \text {sech}(x)} \, dx}{12 a^2}\\ &=\frac {\left (3 a^2+4 b^2\right ) \cosh (x) \sinh (x)}{8 a^3}-\frac {b \cosh ^2(x) \sinh (x)}{3 a^2}+\frac {\cosh ^3(x) \sinh (x)}{4 a}+\frac {\int \frac {\cosh (x) \left (-8 b \left (2 a^2+3 b^2\right )+a \left (9 a^2-4 b^2\right ) \text {sech}(x)+3 b \left (3 a^2+4 b^2\right ) \text {sech}^2(x)\right )}{a+b \text {sech}(x)} \, dx}{24 a^3}\\ &=-\frac {b \left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^4}+\frac {\left (3 a^2+4 b^2\right ) \cosh (x) \sinh (x)}{8 a^3}-\frac {b \cosh ^2(x) \sinh (x)}{3 a^2}+\frac {\cosh ^3(x) \sinh (x)}{4 a}-\frac {\int \frac {-3 \left (3 a^4+4 a^2 b^2+8 b^4\right )-3 a b \left (3 a^2+4 b^2\right ) \text {sech}(x)}{a+b \text {sech}(x)} \, dx}{24 a^4}\\ &=\frac {\left (3 a^4+4 a^2 b^2+8 b^4\right ) x}{8 a^5}-\frac {b \left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^4}+\frac {\left (3 a^2+4 b^2\right ) \cosh (x) \sinh (x)}{8 a^3}-\frac {b \cosh ^2(x) \sinh (x)}{3 a^2}+\frac {\cosh ^3(x) \sinh (x)}{4 a}-\frac {b^5 \int \frac {\text {sech}(x)}{a+b \text {sech}(x)} \, dx}{a^5}\\ &=\frac {\left (3 a^4+4 a^2 b^2+8 b^4\right ) x}{8 a^5}-\frac {b \left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^4}+\frac {\left (3 a^2+4 b^2\right ) \cosh (x) \sinh (x)}{8 a^3}-\frac {b \cosh ^2(x) \sinh (x)}{3 a^2}+\frac {\cosh ^3(x) \sinh (x)}{4 a}-\frac {b^4 \int \frac {1}{1+\frac {a \cosh (x)}{b}} \, dx}{a^5}\\ &=\frac {\left (3 a^4+4 a^2 b^2+8 b^4\right ) x}{8 a^5}-\frac {b \left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^4}+\frac {\left (3 a^2+4 b^2\right ) \cosh (x) \sinh (x)}{8 a^3}-\frac {b \cosh ^2(x) \sinh (x)}{3 a^2}+\frac {\cosh ^3(x) \sinh (x)}{4 a}-\frac {\left (2 b^4\right ) \operatorname {Subst}\left (\int \frac {1}{1+\frac {a}{b}-\left (1-\frac {a}{b}\right ) x^2} \, dx,x,\tanh \left (\frac {x}{2}\right )\right )}{a^5}\\ &=\frac {\left (3 a^4+4 a^2 b^2+8 b^4\right ) x}{8 a^5}-\frac {2 b^5 \tan ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{a^5 \sqrt {a-b} \sqrt {a+b}}-\frac {b \left (2 a^2+3 b^2\right ) \sinh (x)}{3 a^4}+\frac {\left (3 a^2+4 b^2\right ) \cosh (x) \sinh (x)}{8 a^3}-\frac {b \cosh ^2(x) \sinh (x)}{3 a^2}+\frac {\cosh ^3(x) \sinh (x)}{4 a}\\ \end {align*}
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Mathematica [A] time = 0.28, size = 126, normalized size = 0.86 \[ \frac {3 a^4 \sinh (4 x)-8 a^3 b \sinh (3 x)-24 a b \left (3 a^2+4 b^2\right ) \sinh (x)+24 a^2 \left (a^2+b^2\right ) \sinh (2 x)+\frac {192 b^5 \tan ^{-1}\left (\frac {(b-a) \tanh \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{\sqrt {a^2-b^2}}+12 x \left (3 a^4+4 a^2 b^2+8 b^4\right )}{96 a^5} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.47, size = 2402, normalized size = 16.45 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.12, size = 182, normalized size = 1.25 \[ -\frac {2 \, b^{5} \arctan \left (\frac {a e^{x} + b}{\sqrt {a^{2} - b^{2}}}\right )}{\sqrt {a^{2} - b^{2}} a^{5}} + \frac {3 \, a^{3} e^{\left (4 \, x\right )} - 8 \, a^{2} b e^{\left (3 \, x\right )} + 24 \, a^{3} e^{\left (2 \, x\right )} + 24 \, a b^{2} e^{\left (2 \, x\right )} - 72 \, a^{2} b e^{x} - 96 \, b^{3} e^{x}}{192 \, a^{4}} + \frac {{\left (3 \, a^{4} + 4 \, a^{2} b^{2} + 8 \, b^{4}\right )} x}{8 \, a^{5}} + \frac {{\left (8 \, a^{3} b e^{x} - 3 \, a^{4} + 24 \, {\left (3 \, a^{3} b + 4 \, a b^{3}\right )} e^{\left (3 \, x\right )} - 24 \, {\left (a^{4} + a^{2} b^{2}\right )} e^{\left (2 \, x\right )}\right )} e^{\left (-4 \, x\right )}}{192 \, a^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.16, size = 406, normalized size = 2.78 \[ \frac {3 \ln \left (\tanh \left (\frac {x}{2}\right )+1\right )}{8 a}+\frac {7}{8 a \left (\tanh \left (\frac {x}{2}\right )-1\right )^{2}}+\frac {5}{8 a \left (\tanh \left (\frac {x}{2}\right )-1\right )}-\frac {3 \ln \left (\tanh \left (\frac {x}{2}\right )-1\right )}{8 a}-\frac {7}{8 a \left (\tanh \left (\frac {x}{2}\right )+1\right )^{2}}+\frac {5}{8 a \left (\tanh \left (\frac {x}{2}\right )+1\right )}-\frac {2 b^{5} \arctan \left (\frac {\left (a -b \right ) \tanh \left (\frac {x}{2}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{a^{5} \sqrt {\left (a +b \right ) \left (a -b \right )}}+\frac {1}{4 a \left (\tanh \left (\frac {x}{2}\right )-1\right )^{4}}+\frac {1}{2 a \left (\tanh \left (\frac {x}{2}\right )-1\right )^{3}}+\frac {1}{2 a \left (\tanh \left (\frac {x}{2}\right )+1\right )^{3}}+\frac {b^{3}}{a^{4} \left (\tanh \left (\frac {x}{2}\right )-1\right )}-\frac {\ln \left (\tanh \left (\frac {x}{2}\right )-1\right ) b^{4}}{a^{5}}+\frac {b}{3 a^{2} \left (\tanh \left (\frac {x}{2}\right )-1\right )^{3}}-\frac {b^{2}}{2 a^{3} \left (\tanh \left (\frac {x}{2}\right )+1\right )^{2}}+\frac {b^{3}}{a^{4} \left (\tanh \left (\frac {x}{2}\right )+1\right )}-\frac {1}{4 a \left (\tanh \left (\frac {x}{2}\right )+1\right )^{4}}+\frac {\ln \left (\tanh \left (\frac {x}{2}\right )+1\right ) b^{4}}{a^{5}}+\frac {b}{a^{2} \left (\tanh \left (\frac {x}{2}\right )+1\right )}+\frac {b^{2}}{2 a^{3} \left (\tanh \left (\frac {x}{2}\right )+1\right )}+\frac {b}{3 a^{2} \left (\tanh \left (\frac {x}{2}\right )+1\right )^{3}}+\frac {b^{2}}{2 a^{3} \left (\tanh \left (\frac {x}{2}\right )-1\right )}+\frac {b}{a^{2} \left (\tanh \left (\frac {x}{2}\right )-1\right )}+\frac {b}{2 a^{2} \left (\tanh \left (\frac {x}{2}\right )-1\right )^{2}}+\frac {b^{2}}{2 a^{3} \left (\tanh \left (\frac {x}{2}\right )-1\right )^{2}}-\frac {\ln \left (\tanh \left (\frac {x}{2}\right )-1\right ) b^{2}}{2 a^{3}}-\frac {b}{2 a^{2} \left (\tanh \left (\frac {x}{2}\right )+1\right )^{2}}+\frac {\ln \left (\tanh \left (\frac {x}{2}\right )+1\right ) b^{2}}{2 a^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.85, size = 251, normalized size = 1.72 \[ \frac {{\mathrm {e}}^{4\,x}}{64\,a}-\frac {{\mathrm {e}}^{-4\,x}}{64\,a}+\frac {x\,\left (3\,a^4+4\,a^2\,b^2+8\,b^4\right )}{8\,a^5}-\frac {{\mathrm {e}}^{-2\,x}\,\left (a^2+b^2\right )}{8\,a^3}+\frac {{\mathrm {e}}^{2\,x}\,\left (a^2+b^2\right )}{8\,a^3}+\frac {{\mathrm {e}}^{-x}\,\left (3\,a^2\,b+4\,b^3\right )}{8\,a^4}+\frac {b\,{\mathrm {e}}^{-3\,x}}{24\,a^2}-\frac {b\,{\mathrm {e}}^{3\,x}}{24\,a^2}-\frac {{\mathrm {e}}^x\,\left (3\,a^2\,b+4\,b^3\right )}{8\,a^4}+\frac {b^5\,\ln \left (\frac {2\,b^5\,{\mathrm {e}}^x}{a^6}-\frac {2\,b^5\,\left (a+b\,{\mathrm {e}}^x\right )}{a^6\,\sqrt {a+b}\,\sqrt {b-a}}\right )}{a^5\,\sqrt {a+b}\,\sqrt {b-a}}-\frac {b^5\,\ln \left (\frac {2\,b^5\,{\mathrm {e}}^x}{a^6}+\frac {2\,b^5\,\left (a+b\,{\mathrm {e}}^x\right )}{a^6\,\sqrt {a+b}\,\sqrt {b-a}}\right )}{a^5\,\sqrt {a+b}\,\sqrt {b-a}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cosh ^{4}{\relax (x )}}{a + b \operatorname {sech}{\relax (x )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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