Optimal. Leaf size=61 \[ -\frac {b \cosh ^2(x)}{2 a^2}+\frac {b \left (a^2-b^2\right ) \log (a \cosh (x)+b)}{a^4}-\frac {\left (a^2-b^2\right ) \cosh (x)}{a^3}+\frac {\cosh ^3(x)}{3 a} \]
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Rubi [A] time = 0.18, antiderivative size = 61, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {3872, 2837, 12, 772} \[ -\frac {\left (a^2-b^2\right ) \cosh (x)}{a^3}+\frac {b \left (a^2-b^2\right ) \log (a \cosh (x)+b)}{a^4}-\frac {b \cosh ^2(x)}{2 a^2}+\frac {\cosh ^3(x)}{3 a} \]
Antiderivative was successfully verified.
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Rule 12
Rule 772
Rule 2837
Rule 3872
Rubi steps
\begin {align*} \int \frac {\sinh ^3(x)}{a+b \text {sech}(x)} \, dx &=-\int \frac {\cosh (x) \sinh ^3(x)}{-b-a \cosh (x)} \, dx\\ &=\frac {\operatorname {Subst}\left (\int \frac {x \left (a^2-x^2\right )}{a (-b+x)} \, dx,x,-a \cosh (x)\right )}{a^3}\\ &=\frac {\operatorname {Subst}\left (\int \frac {x \left (a^2-x^2\right )}{-b+x} \, dx,x,-a \cosh (x)\right )}{a^4}\\ &=\frac {\operatorname {Subst}\left (\int \left (a^2 \left (1-\frac {b^2}{a^2}\right )+\frac {-a^2 b+b^3}{b-x}-b x-x^2\right ) \, dx,x,-a \cosh (x)\right )}{a^4}\\ &=-\frac {\left (a^2-b^2\right ) \cosh (x)}{a^3}-\frac {b \cosh ^2(x)}{2 a^2}+\frac {\cosh ^3(x)}{3 a}+\frac {b \left (a^2-b^2\right ) \log (b+a \cosh (x))}{a^4}\\ \end {align*}
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Mathematica [A] time = 0.14, size = 66, normalized size = 1.08 \[ \frac {\left (12 a b^2-9 a^3\right ) \cosh (x)+a^3 \cosh (3 x)-3 a^2 b \cosh (2 x)+12 a^2 b \log (a \cosh (x)+b)-12 b^3 \log (a \cosh (x)+b)}{12 a^4} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.41, size = 490, normalized size = 8.03 \[ \frac {a^{3} \cosh \relax (x)^{6} + a^{3} \sinh \relax (x)^{6} - 3 \, a^{2} b \cosh \relax (x)^{5} + 3 \, {\left (2 \, a^{3} \cosh \relax (x) - a^{2} b\right )} \sinh \relax (x)^{5} - 24 \, {\left (a^{2} b - b^{3}\right )} x \cosh \relax (x)^{3} - 3 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \relax (x)^{4} + 3 \, {\left (5 \, a^{3} \cosh \relax (x)^{2} - 5 \, a^{2} b \cosh \relax (x) - 3 \, a^{3} + 4 \, a b^{2}\right )} \sinh \relax (x)^{4} - 3 \, a^{2} b \cosh \relax (x) + 2 \, {\left (10 \, a^{3} \cosh \relax (x)^{3} - 15 \, a^{2} b \cosh \relax (x)^{2} - 12 \, {\left (a^{2} b - b^{3}\right )} x - 6 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \relax (x)\right )} \sinh \relax (x)^{3} + a^{3} - 3 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \relax (x)^{2} + 3 \, {\left (5 \, a^{3} \cosh \relax (x)^{4} - 10 \, a^{2} b \cosh \relax (x)^{3} - 3 \, a^{3} + 4 \, a b^{2} - 24 \, {\left (a^{2} b - b^{3}\right )} x \cosh \relax (x) - 6 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \relax (x)^{2}\right )} \sinh \relax (x)^{2} + 24 \, {\left ({\left (a^{2} b - b^{3}\right )} \cosh \relax (x)^{3} + 3 \, {\left (a^{2} b - b^{3}\right )} \cosh \relax (x)^{2} \sinh \relax (x) + 3 \, {\left (a^{2} b - b^{3}\right )} \cosh \relax (x) \sinh \relax (x)^{2} + {\left (a^{2} b - b^{3}\right )} \sinh \relax (x)^{3}\right )} \log \left (\frac {2 \, {\left (a \cosh \relax (x) + b\right )}}{\cosh \relax (x) - \sinh \relax (x)}\right ) + 3 \, {\left (2 \, a^{3} \cosh \relax (x)^{5} - 5 \, a^{2} b \cosh \relax (x)^{4} - 24 \, {\left (a^{2} b - b^{3}\right )} x \cosh \relax (x)^{2} - 4 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \relax (x)^{3} - a^{2} b - 2 \, {\left (3 \, a^{3} - 4 \, a b^{2}\right )} \cosh \relax (x)\right )} \sinh \relax (x)}{24 \, {\left (a^{4} \cosh \relax (x)^{3} + 3 \, a^{4} \cosh \relax (x)^{2} \sinh \relax (x) + 3 \, a^{4} \cosh \relax (x) \sinh \relax (x)^{2} + a^{4} \sinh \relax (x)^{3}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.14, size = 87, normalized size = 1.43 \[ \frac {a^{2} {\left (e^{\left (-x\right )} + e^{x}\right )}^{3} - 3 \, a b {\left (e^{\left (-x\right )} + e^{x}\right )}^{2} - 12 \, a^{2} {\left (e^{\left (-x\right )} + e^{x}\right )} + 12 \, b^{2} {\left (e^{\left (-x\right )} + e^{x}\right )}}{24 \, a^{3}} + \frac {{\left (a^{2} b - b^{3}\right )} \log \left ({\left | a {\left (e^{\left (-x\right )} + e^{x}\right )} + 2 \, b \right |}\right )}{a^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.12, size = 361, normalized size = 5.92 \[ -\frac {b \ln \left (\tanh \left (\frac {x}{2}\right )-1\right )}{a^{2}}+\frac {b^{3} \ln \left (\tanh \left (\frac {x}{2}\right )-1\right )}{a^{4}}-\frac {1}{3 a \left (\tanh \left (\frac {x}{2}\right )-1\right )^{3}}-\frac {1}{2 a \left (\tanh \left (\frac {x}{2}\right )-1\right )^{2}}-\frac {b}{2 a^{2} \left (\tanh \left (\frac {x}{2}\right )-1\right )^{2}}+\frac {1}{2 a \left (\tanh \left (\frac {x}{2}\right )-1\right )}-\frac {b}{2 a^{2} \left (\tanh \left (\frac {x}{2}\right )-1\right )}-\frac {b^{2}}{a^{3} \left (\tanh \left (\frac {x}{2}\right )-1\right )}-\frac {1}{2 a \left (\tanh \left (\frac {x}{2}\right )+1\right )}+\frac {b}{2 a^{2} \left (\tanh \left (\frac {x}{2}\right )+1\right )}+\frac {b^{2}}{a^{3} \left (\tanh \left (\frac {x}{2}\right )+1\right )}-\frac {b \ln \left (\tanh \left (\frac {x}{2}\right )+1\right )}{a^{2}}+\frac {b^{3} \ln \left (\tanh \left (\frac {x}{2}\right )+1\right )}{a^{4}}-\frac {1}{2 a \left (\tanh \left (\frac {x}{2}\right )+1\right )^{2}}-\frac {b}{2 a^{2} \left (\tanh \left (\frac {x}{2}\right )+1\right )^{2}}+\frac {1}{3 a \left (\tanh \left (\frac {x}{2}\right )+1\right )^{3}}+\frac {b \ln \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-\left (\tanh ^{2}\left (\frac {x}{2}\right )\right ) b +a +b \right )}{a \left (a -b \right )}-\frac {b^{2} \ln \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-\left (\tanh ^{2}\left (\frac {x}{2}\right )\right ) b +a +b \right )}{a^{2} \left (a -b \right )}-\frac {b^{3} \ln \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-\left (\tanh ^{2}\left (\frac {x}{2}\right )\right ) b +a +b \right )}{a^{3} \left (a -b \right )}+\frac {b^{4} \ln \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-\left (\tanh ^{2}\left (\frac {x}{2}\right )\right ) b +a +b \right )}{a^{4} \left (a -b \right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.32, size = 128, normalized size = 2.10 \[ -\frac {{\left (3 \, a b e^{\left (-x\right )} - a^{2} + 3 \, {\left (3 \, a^{2} - 4 \, b^{2}\right )} e^{\left (-2 \, x\right )}\right )} e^{\left (3 \, x\right )}}{24 \, a^{3}} - \frac {3 \, a b e^{\left (-2 \, x\right )} - a^{2} e^{\left (-3 \, x\right )} + 3 \, {\left (3 \, a^{2} - 4 \, b^{2}\right )} e^{\left (-x\right )}}{24 \, a^{3}} + \frac {{\left (a^{2} b - b^{3}\right )} x}{a^{4}} + \frac {{\left (a^{2} b - b^{3}\right )} \log \left (2 \, b e^{\left (-x\right )} + a e^{\left (-2 \, x\right )} + a\right )}{a^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.60, size = 123, normalized size = 2.02 \[ \frac {{\mathrm {e}}^{-3\,x}}{24\,a}+\frac {{\mathrm {e}}^{3\,x}}{24\,a}-\frac {x\,\left (a^2\,b-b^3\right )}{a^4}-\frac {{\mathrm {e}}^x\,\left (3\,a^2-4\,b^2\right )}{8\,a^3}-\frac {b\,{\mathrm {e}}^{-2\,x}}{8\,a^2}-\frac {b\,{\mathrm {e}}^{2\,x}}{8\,a^2}+\frac {\ln \left (a+2\,b\,{\mathrm {e}}^x+a\,{\mathrm {e}}^{2\,x}\right )\,\left (a^2\,b-b^3\right )}{a^4}-\frac {{\mathrm {e}}^{-x}\,\left (3\,a^2-4\,b^2\right )}{8\,a^3} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sinh ^{3}{\relax (x )}}{a + b \operatorname {sech}{\relax (x )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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