3.190 \(\int \text {sech}^p(a-\frac {\log (c x^n)}{n (-2+p)}) \, dx\)

Optimal. Leaf size=65 \[ \frac {(2-p) x \left (e^{-2 a} \left (c x^n\right )^{-\frac {2}{n (2-p)}}+1\right ) \text {sech}^p\left (a+\frac {\log \left (c x^n\right )}{n (2-p)}\right )}{2 (1-p)} \]

[Out]

1/2*(2-p)*x*(1+1/exp(2*a)/((c*x^n)^(2/n/(2-p))))*sech(a+ln(c*x^n)/n/(2-p))^p/(1-p)

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Rubi [A]  time = 0.08, antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {5545, 5549, 264} \[ \frac {(2-p) x \left (e^{-2 a} \left (c x^n\right )^{-\frac {2}{n (2-p)}}+1\right ) \text {sech}^p\left (a+\frac {\log \left (c x^n\right )}{n (2-p)}\right )}{2 (1-p)} \]

Antiderivative was successfully verified.

[In]

Int[Sech[a - Log[c*x^n]/(n*(-2 + p))]^p,x]

[Out]

((2 - p)*x*(1 + 1/(E^(2*a)*(c*x^n)^(2/(n*(2 - p)))))*Sech[a + Log[c*x^n]/(n*(2 - p))]^p)/(2*(1 - p))

Rule 264

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a
*c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 5545

Int[Sech[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Dist[x/(n*(c*x^n)^(1/n)), Subst[Int[
x^(1/n - 1)*Sech[d*(a + b*Log[x])]^p, x], x, c*x^n], x] /; FreeQ[{a, b, c, d, n, p}, x] && (NeQ[c, 1] || NeQ[n
, 1])

Rule 5549

Int[((e_.)*(x_))^(m_.)*Sech[((a_.) + Log[x_]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Dist[(Sech[d*(a + b*Log[x])]^p*
(1 + 1/(E^(2*a*d)*x^(2*b*d)))^p)/x^(-(b*d*p)), Int[(e*x)^m/(x^(b*d*p)*(1 + 1/(E^(2*a*d)*x^(2*b*d)))^p), x], x]
/; FreeQ[{a, b, d, e, m, p}, x] &&  !IntegerQ[p]

Rubi steps

\begin {align*} \int \text {sech}^p\left (a-\frac {\log \left (c x^n\right )}{n (-2+p)}\right ) \, dx &=\frac {\left (x \left (c x^n\right )^{-1/n}\right ) \operatorname {Subst}\left (\int x^{-1+\frac {1}{n}} \text {sech}^p\left (a-\frac {\log (x)}{n (-2+p)}\right ) \, dx,x,c x^n\right )}{n}\\ &=\frac {\left (x \left (c x^n\right )^{-\frac {1}{n}-\frac {p}{n (-2+p)}} \left (1+e^{-2 a} \left (c x^n\right )^{\frac {2}{n (-2+p)}}\right )^p \text {sech}^p\left (a-\frac {\log \left (c x^n\right )}{n (-2+p)}\right )\right ) \operatorname {Subst}\left (\int x^{-1+\frac {1}{n}+\frac {p}{n (-2+p)}} \left (1+e^{-2 a} x^{\frac {2}{n (-2+p)}}\right )^{-p} \, dx,x,c x^n\right )}{n}\\ &=\frac {(2-p) x \left (1+e^{-2 a} \left (c x^n\right )^{-\frac {2}{n (2-p)}}\right ) \text {sech}^p\left (a+\frac {\log \left (c x^n\right )}{n (2-p)}\right )}{2 (1-p)}\\ \end {align*}

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Mathematica [A]  time = 0.88, size = 62, normalized size = 0.95 \[ \frac {e^{-2 a} (p-2) x \left (e^{2 a}+\left (c x^n\right )^{\frac {2}{n (p-2)}}\right ) \text {sech}^p\left (a+\frac {\log \left (c x^n\right )}{2 n-n p}\right )}{2 (p-1)} \]

Antiderivative was successfully verified.

[In]

Integrate[Sech[a - Log[c*x^n]/(n*(-2 + p))]^p,x]

[Out]

((-2 + p)*x*(E^(2*a) + (c*x^n)^(2/(n*(-2 + p))))*Sech[a + Log[c*x^n]/(2*n - n*p)]^p)/(2*E^(2*a)*(-1 + p))

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fricas [B]  time = 0.45, size = 538, normalized size = 8.28 \[ \frac {{\left (p - 2\right )} x \cosh \left (p \log \left (\frac {2 \, {\left (\cosh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right ) + \sinh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right )\right )}}{\cosh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right )^{2} + 2 \, \cosh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right ) \sinh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right ) + \sinh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right )^{2} + 1}\right )\right ) \cosh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right ) + {\left (p - 2\right )} x \cosh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right ) \sinh \left (p \log \left (\frac {2 \, {\left (\cosh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right ) + \sinh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right )\right )}}{\cosh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right )^{2} + 2 \, \cosh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right ) \sinh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right ) + \sinh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right )^{2} + 1}\right )\right )}{{\left (p - 1\right )} \cosh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right ) - {\left (p - 1\right )} \sinh \left (-\frac {a n p - 2 \, a n - n \log \relax (x) - \log \relax (c)}{n p - 2 \, n}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(a-log(c*x^n)/n/(-2+p))^p,x, algorithm="fricas")

[Out]

((p - 2)*x*cosh(p*log(2*(cosh(-(a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n)) + sinh(-(a*n*p - 2*a*n - n*log
(x) - log(c))/(n*p - 2*n)))/(cosh(-(a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n))^2 + 2*cosh(-(a*n*p - 2*a*n
- n*log(x) - log(c))/(n*p - 2*n))*sinh(-(a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n)) + sinh(-(a*n*p - 2*a
*n - n*log(x) - log(c))/(n*p - 2*n))^2 + 1)))*cosh(-(a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n)) + (p - 2)
*x*cosh(-(a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n))*sinh(p*log(2*(cosh(-(a*n*p - 2*a*n - n*log(x) - log(
c))/(n*p - 2*n)) + sinh(-(a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n)))/(cosh(-(a*n*p - 2*a*n - n*log(x) -
log(c))/(n*p - 2*n))^2 + 2*cosh(-(a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n))*sinh(-(a*n*p - 2*a*n - n*log
(x) - log(c))/(n*p - 2*n)) + sinh(-(a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n))^2 + 1))))/((p - 1)*cosh(-(
a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n)) - (p - 1)*sinh(-(a*n*p - 2*a*n - n*log(x) - log(c))/(n*p - 2*n
)))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \operatorname {sech}\left (a - \frac {\log \left (c x^{n}\right )}{n {\left (p - 2\right )}}\right )^{p}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(a-log(c*x^n)/n/(-2+p))^p,x, algorithm="giac")

[Out]

integrate(sech(a - log(c*x^n)/(n*(p - 2)))^p, x)

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maple [F]  time = 0.62, size = 0, normalized size = 0.00 \[ \int \mathrm {sech}\left (a -\frac {\ln \left (c \,x^{n}\right )}{n \left (-2+p \right )}\right )^{p}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sech(a-ln(c*x^n)/n/(-2+p))^p,x)

[Out]

int(sech(a-ln(c*x^n)/n/(-2+p))^p,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \operatorname {sech}\left (-a + \frac {\log \left (c x^{n}\right )}{n {\left (p - 2\right )}}\right )^{p}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(a-log(c*x^n)/n/(-2+p))^p,x, algorithm="maxima")

[Out]

integrate(sech(-a + log(c*x^n)/(n*(p - 2)))^p, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int {\left (\frac {1}{\mathrm {cosh}\left (a-\frac {\ln \left (c\,x^n\right )}{n\,\left (p-2\right )}\right )}\right )}^p \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1/cosh(a - log(c*x^n)/(n*(p - 2))))^p,x)

[Out]

int((1/cosh(a - log(c*x^n)/(n*(p - 2))))^p, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \operatorname {sech}^{p}{\left (a - \frac {\log {\left (c x^{n} \right )}}{n \left (p - 2\right )} \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sech(a-ln(c*x**n)/n/(-2+p))**p,x)

[Out]

Integral(sech(a - log(c*x**n)/(n*(p - 2)))**p, x)

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