3.28 \(\int (b \coth ^3(c+d x))^n \, dx\)

Optimal. Leaf size=55 \[ \frac {\coth (c+d x) \left (b \coth ^3(c+d x)\right )^n \, _2F_1\left (1,\frac {1}{2} (3 n+1);\frac {3 (n+1)}{2};\coth ^2(c+d x)\right )}{d (3 n+1)} \]

[Out]

coth(d*x+c)*(b*coth(d*x+c)^3)^n*hypergeom([1, 1/2+3/2*n],[3/2+3/2*n],coth(d*x+c)^2)/d/(1+3*n)

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Rubi [A]  time = 0.04, antiderivative size = 55, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3658, 3476, 364} \[ \frac {\coth (c+d x) \left (b \coth ^3(c+d x)\right )^n \, _2F_1\left (1,\frac {1}{2} (3 n+1);\frac {3 (n+1)}{2};\coth ^2(c+d x)\right )}{d (3 n+1)} \]

Antiderivative was successfully verified.

[In]

Int[(b*Coth[c + d*x]^3)^n,x]

[Out]

(Coth[c + d*x]*(b*Coth[c + d*x]^3)^n*Hypergeometric2F1[1, (1 + 3*n)/2, (3*(1 + n))/2, Coth[c + d*x]^2])/(d*(1
+ 3*n))

Rule 364

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a^p*(c*x)^(m + 1)*Hypergeometric2F1[-
p, (m + 1)/n, (m + 1)/n + 1, -((b*x^n)/a)])/(c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rule 3476

Int[((b_.)*tan[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Dist[b/d, Subst[Int[x^n/(b^2 + x^2), x], x, b*Tan[c + d
*x]], x] /; FreeQ[{b, c, d, n}, x] &&  !IntegerQ[n]

Rule 3658

Int[(u_.)*((b_.)*tan[(e_.) + (f_.)*(x_)]^(n_))^(p_), x_Symbol] :> With[{ff = FreeFactors[Tan[e + f*x], x]}, Di
st[((b*ff^n)^IntPart[p]*(b*Tan[e + f*x]^n)^FracPart[p])/(Tan[e + f*x]/ff)^(n*FracPart[p]), Int[ActivateTrig[u]
*(Tan[e + f*x]/ff)^(n*p), x], x]] /; FreeQ[{b, e, f, n, p}, x] &&  !IntegerQ[p] && IntegerQ[n] && (EqQ[u, 1] |
| MatchQ[u, ((d_.)*(trig_)[e + f*x])^(m_.) /; FreeQ[{d, m}, x] && MemberQ[{sin, cos, tan, cot, sec, csc}, trig
]])

Rubi steps

\begin {align*} \int \left (b \coth ^3(c+d x)\right )^n \, dx &=\left (\coth ^{-3 n}(c+d x) \left (b \coth ^3(c+d x)\right )^n\right ) \int \coth ^{3 n}(c+d x) \, dx\\ &=-\frac {\left (\coth ^{-3 n}(c+d x) \left (b \coth ^3(c+d x)\right )^n\right ) \operatorname {Subst}\left (\int \frac {x^{3 n}}{-1+x^2} \, dx,x,\coth (c+d x)\right )}{d}\\ &=\frac {\coth (c+d x) \left (b \coth ^3(c+d x)\right )^n \, _2F_1\left (1,\frac {1}{2} (1+3 n);\frac {3 (1+n)}{2};\coth ^2(c+d x)\right )}{d (1+3 n)}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 53, normalized size = 0.96 \[ \frac {\coth (c+d x) \left (b \coth ^3(c+d x)\right )^n \, _2F_1\left (1,\frac {1}{2} (3 n+1);\frac {3 (n+1)}{2};\coth ^2(c+d x)\right )}{3 d n+d} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*Coth[c + d*x]^3)^n,x]

[Out]

(Coth[c + d*x]*(b*Coth[c + d*x]^3)^n*Hypergeometric2F1[1, (1 + 3*n)/2, (3*(1 + n))/2, Coth[c + d*x]^2])/(d + 3
*d*n)

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fricas [F]  time = 0.67, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\left (b \coth \left (d x + c\right )^{3}\right )^{n}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*coth(d*x+c)^3)^n,x, algorithm="fricas")

[Out]

integral((b*coth(d*x + c)^3)^n, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (b \coth \left (d x + c\right )^{3}\right )^{n}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*coth(d*x+c)^3)^n,x, algorithm="giac")

[Out]

integrate((b*coth(d*x + c)^3)^n, x)

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maple [F]  time = 0.63, size = 0, normalized size = 0.00 \[ \int \left (b \left (\coth ^{3}\left (d x +c \right )\right )\right )^{n}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*coth(d*x+c)^3)^n,x)

[Out]

int((b*coth(d*x+c)^3)^n,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (b \coth \left (d x + c\right )^{3}\right )^{n}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*coth(d*x+c)^3)^n,x, algorithm="maxima")

[Out]

integrate((b*coth(d*x + c)^3)^n, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int {\left (b\,{\mathrm {coth}\left (c+d\,x\right )}^3\right )}^n \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*coth(c + d*x)^3)^n,x)

[Out]

int((b*coth(c + d*x)^3)^n, x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (b \coth ^{3}{\left (c + d x \right )}\right )^{n}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*coth(d*x+c)**3)**n,x)

[Out]

Integral((b*coth(c + d*x)**3)**n, x)

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